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  • How can I make smoother upwards/downwards controls in pygame?

    - by Zolani13
    This is a loop I use to interpret key events in a python game. # Event Loop for event in pygame.event.get(): if event.type == QUIT: pygame.quit() sys.exit() if event.type == pygame.KEYDOWN: if event.key == pygame.K_a: my_speed = -10; if event.key == pygame.K_d: my_speed = 10; if event.type == pygame.KEYUP: if event.key == pygame.K_a: my_speed = 0; if event.key == pygame.K_d: my_speed = 0; The 'A' key represents up, while the 'D' key represents down. I use this loop within a larger drawing loop, that moves the sprite using this: Paddle1.rect.y += my_speed; I'm just making a simple pong game (as my first real code/non-gamemaker game) but there's a problem between moving upwards <= downwards. Essentially, if I hold a button upwards (or downwards), and then press downwards (or upwards), now holding both buttons, the direction will change, which is a good thing. But if I then release the upward button, then the sprite will stop. It won't continue in the direction of my second input. This kind of key pressing is actually common with WASD users, when changing directions quickly. Few people remember to let go of the first button before pressing the second. But my program doesn't accommodate the habit. I think I understand the reason, which is that when I let go of my first key, the KEYUP event still triggers, setting the speed to 0. I need to make sure that if a key is released, it only sets the speed to 0 if another key isn't being pressed. But the interpreter will only go through one event at a time, I think, so I can't check if a key has been pressed if it's only interpreting the commands for a released key. This is my dilemma. I want set the key controls so that a player doesn't have to press one button at a time to move upwards <= downwards, making it smoother. How can I do that?

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  • Ubuntu 12.04 // Likewise Open // Unable to ever authenticate AD users

    - by Rob
    So Ubuntu 12.04, Likewise latest from the beyondtrust website. Joins domain fine. Gets proper information from lw-get-status. Can use lw-find-user-by-name to retrieve/locate users. Can use lw-enum-users to get all users. Attempting to login with an AD user via SSH generates the following errors in the auth.log file: Nov 28 19:15:45 hostname sshd[2745]: PAM unable to dlopen(pam_winbind.so): /lib/security/pam_winbind.so: cannot open shared object file: No such file or directory Nov 28 19:15:45 hostname sshd[2745]: PAM adding faulty module: pam_winbind.so Nov 28 19:15:51 hostname sshd[2745]: error: PAM: Authentication service cannot retrieve authentication info for DOMAIN\\user.name from remote.hostname Nov 28 19:16:06 hostname sshd[2745]: Connection closed by 10.1.1.84 [preauth] Attempting to login via the LightDM itself generates similar errors in the auth.log file. Nov 28 19:19:29 hostname lightdm: PAM unable to dlopen(pam_winbind.so): /lib/security/pam_winbind.so: cannot open shared object file: No such file or directory Nov 28 19:19:29 hostname lightdm: PAM adding faulty module: pam_winbind.so Nov 28 19:19:47 hostname lightdm: pam_succeed_if(lightdm:auth): requirement "user ingroup nopasswdlogin" not met by user "DOMAIN\user.name" Nov 28 19:19:52 hostname lightdm: [lsass-pam] [module:pam_lsass]pam_sm_authenticate error [login:DOMAIN\user.name][error code:40022] Nov 28 19:19:54 hostname lightdm: PAM unable to dlopen(pam_winbind.so): /lib/security/pam_winbind.so: cannot open shared object file: No such file or directory Nov 28 19:19:54 hostname lightdm: PAM adding faulty module: pam_winbind.so Attempting to login via a console on the system itself generates slightly different errors: Nov 28 19:31:09 hostname login[997]: PAM unable to dlopen(pam_winbind.so): /lib/security/pam_winbind.so: cannot open shared object file: No such file or directory Nov 28 19:31:09 hostname login[997]: PAM adding faulty module: pam_winbind.so Nov 28 19:31:11 hostname login[997]: [lsass-pam] [module:pam_lsass]pam_sm_authenticate error [login:DOMAIN\user.name][error code:40022] Nov 28 19:31:14 hostname login[997]: FAILED LOGIN (1) on '/dev/tty2' FOR 'DOMAIN\user.name', Authentication service cannot retrieve authentication info Nov 28 19:31:31 hostname login[997]: FAILED LOGIN (2) on '/dev/tty2' FOR 'DOMAIN\user.name', Authentication service cannot retrieve authentication info I am baffled. The errors obviously are correct, the file /lib/security/pam_winbind.so does not exist. If its a dependancy/required, surely it should be part of the package? I've installed/reinstalled, I've used the downloaded package from the beyondtrust website, i've used the repository, nothing seems to work, every method of installing this application generates the same errors for me. UPDATE : Hrmm, I thought likewise didn't use native winbind but its own modules. Installing winbind from apt-get uninstalls pbis-open (likewise) and generates failures when installing if pbis-open is installed first. Uninstalled winbind, reinstalled pbis-open, same issue as above. The file pam_winbind.so does not exist in that location. Setting up pbis-open-legacy (7.0.1.918) ... Installing Packages was successful This computer is joined to DOMAIN.LOCAL New libraries and configurations have been installed for PAM and NSS. Clearly it thinks it has installed it, but it hasn't. It may be a legacy issue with the previous attempt to configure domain integration manually with winbind. Does anyone have a working likewise-open installation and does the /etc/nsswitch.conf include references to winbind? Or do the /etc/pam.d/common-account or /etc/pam.d/common-password reference pam_winbind.so? I'm unsure if those entries are just legacy or setup by likewise. UPDATE 2 : Complete reinstall of OS fixed it and it worked seamlessly, like it was meant to and those 2 PAM files did NOT include entries for pam_winbind.so, so that was the underlying problem. Thanks for the assist.

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  • VS2010: Why do my custom Toolbox tabs and contained controls keep disappearing?

    - by Velika2
    This is how I expected the toolbox to work: Let's say I add a custom Tab to the Toolbox called "Ajaxtoolkit." To add controls to the new tab, I right mouse click and select "Choose Items" and browse to a file, Ajaxtoolkit.dll, that is of a particular version number. I would expect that when I save and reopen the solution, that the Ajax Toolkit custom tab would still be in my Toolbox and that it would contain the same controls that were there last time, the controls that were in the dll that I referenced when the controls were added. If I created a brand new web app, I (possibly) wouldn't expect to see the same Ajax Toolkit custom tab. However, I could perform the same steps as above and add a "Ajax Toolkit" tab and perhaps, this time, select a DIFFERENT VERSION of the tookit, and the state of the toolkit would be retained with each solution file. Another possibility would be for the original Ajaxtoolkit to be retained when the 2nd web solution is created, and perhaps, if I wanted to mix versions of the toolkit across diffreent web sites in my solution, I should start naming my custom toolkit tabs with version specific names like "Ajaxtoolkit 4.0," etc. ...But instead, the Ajaxtoolkit tab disappears when I close VS2010 and reopen it. Why? Is this desirable behavior or a bug?

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  • How do I initialize the controls in an InsertItemTemplate?

    - by Slauma
    I have - for instance - an asp:FormView which supports Read, Insert, Update, Delete and is bound to a DataSource: <asp:FormView ID="FormView1" runat="server" DataSourceID="ObjectDataSource1" > <ItemTemplate> <asp:Label ID="Label1" runat="server" Text='<%# Bind("MyText") %>' /> </ItemTemplate> <EditItemTemplate> <asp:TextBox ID="TextBox1" runat="server" Text='<%# Bind("MyText") %>' /> </EditItemTemplate> <InsertItemTemplate> <asp:TextBox ID="TextBox1" runat="server" Text='<%# Bind("MyText") %>' /> </InsertItemTemplate> </asp:FormView> If I am in Read-Mode or Edit-Mode the control is initialized with the property MyText of the current object which is bound to the FormView. But when I go to Insert-Mode I do not have a "current object" (FormView1.DataItem is indeed null) and the controls are empty. If I want to have my TextBox control initialized with a specific value how can I do that? In which event can I hook in to set default values to the controls in the InsertItemTemplate? Especially I have in mind using an ObjectDataSource. I was expecting that the InsertItemTemplate is initialized with a business object which underlies my ObjectDataSource and which is created by the ASP.NET framework simply by using its default constructor when the InsertItemTemplate gets activated. In the default constructor I would init the class members to the default values I'd like to have in my controls of the InsertItemTemplate. But unfortunately that's not the case: No "default" object is created and bound to the FormView. So it seems I have to initialize all controls separately or to create the default object manually and bind it to the InsertItemTemplate of the FormView. But how and where can I do that? Thanks in advance!

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  • How do I avoid killing the native controls on a html5-video when i've started it programmaticly?

    - by Nils
    OK, so the deal is I've started making a little videoplayer, that works by clicking a div with an image, expanding the div and the image, and then exchanges the image with a html5-videotag. the code is as below. (It's very early on, so i know theres a lot that need improving, as in not using javascript to set styles and so on, but nevertheless, any insigts and tips are welcome, besides the answer to the main question) /*Begin Expander*/ var $videoplayer = $('<video width="640" height="360" preload="none" controls="" tabindex="0" style="position: relative;"><source type="video/mp4" src="/restalive/movies/big_buck_bunny.mp4"></source><source type="video/ogg" src="/restalive/movies/big_buck_bunny.ogv"></source></video>').appendTo('body'); $videoplayer.hide(); $(".ExpandVideo").each(function(i){ var $trigger = $(this); var $image = $trigger.find("img"); $image.css({ "width" : "100%" ,"height" : "auto" }) $trigger.css({ "display" : "block" ,"overflow" : "hidden" ,"width" : "200px" ,"float" : "left" }); $trigger.bind("click", function(e){ $trigger.animate({"width" : "640px"}, "fast", function(){ $image.replaceWith($videoplayer); $videoplayer.show(); $videoplayer.attr("id", "video" + i); var video = document.getElementById("video" + i); video.play(); }) }) }); However, the main problem is that when i've fired of the video like this (video.play()), the native controls stop working, i can no longer pause the video, even though the controls are there, and clickable, the video just starts playing immidiatley again when i trie to pause it. Which is a shame, because i want to use the native controls for simplicity.

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  • What does "error reading login count from pmvarrun" mean?

    - by n3rd
    I have the above mentioned error in my /var/log/auth.log file and just try to figure out if this is a harmelss statement. As far as I understand does pmvarrun tells the system how many active session (e.g. logins) a user has on the system. Full output of auth.log Jan 24 17:44:42 P835 lightdm: pam_unix(lightdm:session): session opened for user lightdm by (uid=0) Jan 24 17:44:42 P835 lightdm: pam_ck_connector(lightdm:session): nox11 mode, ignoring PAM_TTY :0 Jan 24 17:44:49 P835 lightdm: pam_succeed_if(lightdm:auth): requirement "user ingroup nopasswdlogin" not met by user "user" Jan 24 17:44:51 P835 dbus[1289]: [system] Rejected send message, 2 matched rules; type="method_call", sender=":1.31" (uid=104 pid=1882 comm="/usr/lib/indicator-datetime/indicator-datetime-ser") interface="org.freedesktop.DBus.Properties" member="GetAll" error name="(unset)" requested_reply="0" destination=":1.17" (uid=0 pid=1561 comm="/usr/sbin/console-kit-daemon --no-daemon ") Jan 24 17:45:04 P835 lightdm: pam_unix(lightdm:session): session closed for user lightdm Jan 24 17:45:04 P835 lightdm: pam_mount(pam_mount.c:691): received order to close things Jan 24 17:45:04 P835 lightdm: pam_mount(pam_mount.c:693): No volumes to umount Jan 24 17:45:04 P835 lightdm: command: 'pmvarrun' '-u' 'user' '-o' '-1' Jan 24 17:45:04 P835 lightdm: pam_mount(misc.c:38): set_myuid<pre>: (ruid/rgid=0/0, e=0/0) Jan 24 17:45:04 P835 lightdm: pam_mount(misc.c:38): set_myuid<post>: (ruid/rgid=0/0, e=0/0) Jan 24 17:45:04 P835 lightdm: pam_mount(pam_mount.c:438): error reading login count from pmvarrun Jan 24 17:45:04 P835 lightdm: pam_mount(pam_mount.c:728): pam_mount execution complete Jan 24 17:45:08 P835 lightdm: pam_unix(lightdm:session): session opened for user user by (uid=0) Jan 24 17:45:08 P835 lightdm: pam_ck_connector(lightdm:session): nox11 mode, ignoring PAM_TTY :0 Jan 24 17:45:25 P835 polkitd(authority=local): Registered Authentication Agent for unix-session:/org/freedesktop/ConsoleKit/Session2 (system bus name :1.54 [/usr/lib/policykit-1-gnome/polkit-gnome-authentication-agent-1], object path /org/gnome/PolicyKit1/AuthenticationAgent, locale en_US.UTF-8) Jan 24 17:45:47 P835 dbus[1289]: [system] Rejected send message, 2 matched rules; type="method_call", sender=":1.59" (uid=1000 pid=4748 comm="/usr/lib/indicator-datetime/indicator-datetime-ser") interface="org.freedesktop.DBus.Properties" member="GetAll" error name="(unset)" requested_reply="0" destination=":1.17" (uid=0 pid=1561 comm="/usr/sbin/console-kit-daemon --no-daemon ") Thanks for any help

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  • Steam (via Wine) crashes after login - any troubleshooting tips?

    - by new Thrall
    The Steam client crashes after I login. After submitting my credentials, Steam displays a dialog box informing me the client is 'connecting'. I then see the Steam main page and news page displayed for roughly a second or so before the client crashes. I'm running Ubuntu 10.10 (I think..what's the best way to verify? uname only displays Linux) which I've installed on a usb flash drive using a capser-rw file for persistence. wine-1.3.14 I'm not sure how to troubleshoot. How do I identify if the problem is with wine or steam or the video card driver, or what? Any ideas? hardware: motherboard: ECS Elitegroup 945GCT-M sound: integrated audio video: ATI Radeon X1950 console output: ubuntu@ubuntu:~/.wine/drive_c/Program Files/Steam$ wine Steam.exe fixme:process:GetLogicalProcessorInformation ((nil),0x32e488): stub fixme:process:GetLogicalProcessorInformation (0x1010c00,0x32e488): stub fixme:process:SetProcessShutdownParameters (00000100, 00000000): partial stub. fixme:urlmon:CoInternetSetFeatureEnabled 5, 0x00000002, 1, stub fixme:urlmon:CoInternetSetFeatureEnabled 10, 0x00000002, 1, stub fixme:dwmapi:DwmSetWindowAttribute (0x1009a, 2, 0x32d334, 4) stub fixme:dwmapi:DwmSetWindowAttribute (0x1009a, 3, 0x32d338, 4) stub fixme:dwmapi:DwmSetWindowAttribute (0x1009a, 4, 0x32d33c, 4) stub fixme:dwmapi:DwmSetWindowAttribute (0x100a2, 2, 0x32d964, 4) stub fixme:dwmapi:DwmSetWindowAttribute (0x100a2, 3, 0x32d968, 4) stub fixme:dwmapi:DwmSetWindowAttribute (0x100a2, 4, 0x32d96c, 4) stub err:ole:CoGetClassObject class {77f10cf0-3db5-4966-b520-b7c54fd35ed6} not registered err:ole:CoGetClassObject no class object {77f10cf0-3db5-4966-b520-b7c54fd35ed6} could be created for context 0x1 fixme:wbemprox:wbem_locator_ConnectServer 0x1ab5f0, L"ROOT\CIMV2", (null), (null), (null), 0x00000080, (null), (nil), 0x42bbee8) fixme:dwmapi:DwmSetWindowAttribute (0x100ae, 2, 0x32d8cc, 4) stub fixme:dwmapi:DwmSetWindowAttribute (0x100ae, 3, 0x32d8d0, 4) stub fixme:dwmapi:DwmSetWindowAttribute (0x100ae, 4, 0x32d8d4, 4) stub fixme:dwmapi:DwmSetWindowAttribute (0x100b6, 2, 0x32d80c, 4) stub fixme:dwmapi:DwmSetWindowAttribute (0x100b6, 3, 0x32d810, 4) stub fixme:dwmapi:DwmSetWindowAttribute (0x100b6, 4, 0x32d814, 4) stub fixme:dwmapi:DwmSetWindowAttribute (0x100c0, 2, 0x32d2e4, 4) stub fixme:dwmapi:DwmSetWindowAttribute (0x100c0, 3, 0x32d2e8, 4) stub fixme:dwmapi:DwmSetWindowAttribute (0x100c0, 4, 0x32d2ec, 4) stub fixme:winhttp:WinHttpGetIEProxyConfigForCurrentUser returning no proxy used fixme:dwmapi:DwmSetWindowAttribute (0x100dc, 2, 0x32d94c, 4) stub fixme:dwmapi:DwmSetWindowAttribute (0x100dc, 3, 0x32d950, 4) stub fixme:dwmapi:DwmSetWindowAttribute (0x100dc, 4, 0x32d954, 4) stub fixme:dwmapi:DwmSetWindowAttribute (0x10118, 2, 0x32da8c, 4) stub fixme:dwmapi:DwmSetWindowAttribute (0x10118, 3, 0x32da90, 4) stub fixme:dwmapi:DwmSetWindowAttribute (0x10118, 4, 0x32da94, 4) stub fixme:dwmapi:DwmSetWindowAttribute (0x10122, 2, 0x32d514, 4) stub fixme:dwmapi:DwmSetWindowAttribute (0x10122, 3, 0x32d518, 4) stub fixme:dwmapi:DwmSetWindowAttribute (0x10122, 4, 0x32d51c, 4) stub fixme:dbghelp:elf_search_auxv can't find symbol in module

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  • Feed the Beast Ultimate black screen after login 13.04?

    - by Drew S
    I get a black screen after login feed the beast ultimate splash animation. I have tried the manual LWJGL upgrading, using different versions of java (6 and 7 openJDK). no matter what I get this 2013-06-28 15:23:17 [INFO] [STDERR] Exception in thread "Minecraft main thread" java.lang.ExceptionInInitializerError 2013-06-28 15:23:17 [INFO] [STDERR] at net.minecraft.client.Minecraft.a(Minecraft.java:356) 2013-06-28 15:23:17 [INFO] [STDERR] at asq.a(SourceFile:56) 2013-06-28 15:23:17 [INFO] [STDERR] at net.minecraft.client.Minecraft.run(Minecraft.java:746) 2013-06-28 15:23:17 [INFO] [STDERR] at java.lang.Thread.run(Thread.java:722) 2013-06-28 15:23:17 [INFO] [STDERR] Caused by: java.lang.ArrayIndexOutOfBoundsException: 0 2013-06-28 15:23:17 [INFO] [STDERR] at org.lwjgl.opengl.XRandR$Screen.<init>(XRandR.java:234) 2013-06-28 15:23:17 [INFO] [STDERR] at org.lwjgl.opengl.XRandR$Screen.<init>(XRandR.java:196) 2013-06-28 15:23:17 [INFO] [STDERR] at org.lwjgl.opengl.XRandR.populate(XRandR.java:87) 2013-06-28 15:23:17 [INFO] [STDERR] at org.lwjgl.opengl.XRandR.access$100(XRandR.java:52) 2013-06-28 15:23:17 [INFO] [STDERR] at org.lwjgl.opengl.XRandR$1.run(XRandR.java:110) 2013-06-28 15:23:17 [INFO] [STDERR] at java.security.AccessController.doPrivileged(Native Method) 2013-06-28 15:23:17 [INFO] [STDERR] at org.lwjgl.opengl.XRandR.getConfiguration(XRandR.java:108) 2013-06-28 15:23:17 [INFO] [STDERR] at org.lwjgl.opengl.LinuxDisplay.init(LinuxDisplay.java:618) 2013-06-28 15:23:17 [INFO] [STDERR] at org.lwjgl.opengl.Display.<clinit>(Display.java:135) 2013-06-28 15:23:17 [INFO] [STDERR] ... 4 more

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  • Python Web Applications: What is the way and the method to handle Registrations, Login-Logouts and Cookies? [on hold]

    - by Phil
    I am working on a simple Python web application for learning purposes. I have chosen a very minimalistic and simple framework. I have done a significant amount of research but I couldn't find a source clearly explaining what I need, which is as follows: I would like to learn more about: User registration User Log-ins User Log-outs User auto-logins I have successfully handled items 1 and 3 due to their simple nature. However, I am confused with item 2 (log-ins) and item 4 (auto-logins). When a user enters username and password, and after hashing with salts and matching it in the DB; What information should I store in the cookies in order to keep the user logged in during the session? Do I keep username+password but encrypt them? Both or just password? Do I keep username and a generated key matching their password? If I want the user to be able to auto-login (when they leave and come back to the web page), what information then is kept in the cookies? I don't want to use modules or libraries that handle these things automatically. I want to learn basics and why something is the way it is. I would also like to point out that I do not mind reading anything you might offer on the topic that explains hows and whys. Possibly with algorithm diagrams to show the process. Some information: I know about setting headers, cookies, encryption (up to some level, obviously not an expert!), request objects, SQLAlchemy etc. I don't want any data kept in a single web application server's store. I want multiple app-servers to be handle a user, and whatever needs to be kept on the server to be done with a Postgres/MySQL via SQLAlchemy (I think, this is called stateless?) Thank you.

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  • Ubuntu 13.10. After login, no desktop displayed. Two Nvidia Graphics Cards, Four Monitors

    - by jmerkow
    I am working on an issue with my Ubuntu 13.10 installation. I am attempting to get 4 monitors up and running but I am having some trouble. So far, I installed and updated to the latest NVIDIA drivers (331.20). Initially X would not start (after installation) so I replaced my xorg.conf with xorg.conf.failsafe. This fixed that problem, but then I tried to enable the other 2 monitors (other video card) and xorg fails to start once again (after I login there is no desktop). I am fairly new to linux but I am not a complete beginner, but I'm not comfortable poking around too much on my own to troubleshoot yet.... lspci -nn | grep VGA: 03:00.0 VGA compatible controller [0300]: NVIDIA Corporation GF110 [GeForce GTX 570 Rev. 2] [10de:1086] (rev a1) 05:00.0 VGA compatible controller [0300]: NVIDIA Corporation GF110 [GeForce GTX 580] [10de:1080] (rev a1) It seems that the nvidia-settings tool does not result in a good xorg.conf file. Here it is: # nvidia-settings: X configuration file generated by nvidia-settings # nvidia-settings: version 331.20 (buildmeister@swio-display-x86-rhel47-05) Wed Oct 30 18:20:32 PDT 2013 Section "ServerLayout" Identifier "Default Layout" Screen 0 "Screen0" 0 0 Screen 1 "Screen1" RightOf "Screen0" InputDevice "Keyboard0" "CoreKeyboard" InputDevice "Mouse0" "CorePointer" Option "Xinerama" "1" EndSection ... Section "Monitor" Identifier "Configured Monitor" EndSection Section "Monitor" Identifier "Monitor0" VendorName "Unknown" ModelName "SHARP HDMI" HorizSync 15.0 - 68.0 VertRefresh 55.0 - 76.0 EndSection Section "Monitor" Identifier "Monitor1" VendorName "Unknown" ModelName "Samsung SyncMaster" HorizSync 0.0 - 0.0 VertRefresh 0.0 EndSection Section "Device" Identifier "Configured Video Device" Driver "vesa" EndSection Section "Device" Identifier "Device0" Driver "nvidia" VendorName "NVIDIA Corporation" BoardName "GeForce GTX 570" BusID "PCI:3:0:0" EndSection Section "Device" Identifier "Device1" Driver "nvidia" VendorName "NVIDIA Corporation" BoardName "GeForce GTX 580" BusID "PCI:5:0:0" EndSection Section "Screen" Identifier "Default Screen" Device "Configured Video Device" Monitor "Configured Monitor" EndSection Section "Screen" Identifier "Screen0" Device "Device0" Monitor "Monitor0" DefaultDepth 24 Option "Stereo" "0" Option "nvidiaXineramaInfoOrder" "DFP-1" Option "metamodes" "HDMI-0: nvidia-auto-select +640+0, DVI-I-3: nvidia-auto-select +0+1080" Option "SLI" "Off" Option "MultiGPU" "Off" Option "BaseMosaic" "off" SubSection "Display" Depth 24 EndSubSection EndSection Section "Screen" Identifier "Screen1" Device "Device1" Monitor "Monitor1" DefaultDepth 24 Option "Stereo" "0" Option "metamodes" "DVI-I-2: nvidia-auto-select +0+0" Option "SLI" "Off" Option "MultiGPU" "Off" Option "BaseMosaic" "off" SubSection "Display" Depth 24 EndSubSection EndSection Section "Extensions" Option "Composite" "Disable" EndSection

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  • Accessing controls of .aspx file in .aspx.cs without any declaration.!!??

    I am able to access the controls of ".aspx" file in ".aspx.cs" directly without any declaration in ".aspx.cs" or in designer.cs. How is this possible? This is happeing only if I open website as using File System. Create a new ASP.NET web site application with Visual Studio 2008. So following three files will be created automatically              "Default.aspx",              "Default.aspx.cs"              "Default.designer.cs" Now Delete "Default.designer.cs" perminently. Just create a button in Default.aspx file    <asp:Button runat="server" Text="Save Plan" ID="btnSave" />   Close the Solution and open the website as File System.               File -> Open Web Site -> File System -> Select Web Site Folder and Open the project.                   Now btnSave is automatically recognized in Default.aspx.cs without any declaration in Default.aspx.cs as bellow                            System.Web.UI.WebControls.Button btnSave; How btnSave is being recognized by .cs file without defining it anywhere as an object of System.Web.UI.WebControls.Button? Note: This happens only if you open Web Site from File System.           and No Declaration at all for btnSave. Please refer this article on this. span.fullpost {display:none;}

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  • Accessing controls of .aspx file in .aspx.cs without any declaration.!!??

    I am able to access the controls of ".aspx" file in ".aspx.cs" directly without any declaration in ".aspx.cs" or in designer.cs. How is this possible? This is happeing only if I open website as using File System. Create a new ASP.NET web site application with Visual Studio 2008. So following three files will be created automatically              "Default.aspx",              "Default.aspx.cs"              "Default.designer.cs" Now Delete "Default.designer.cs" perminently. Just create a button in Default.aspx file    <asp:Button runat="server" Text="Save Plan" ID="btnSave" />   Close the Solution and open the website as File System.               File -> Open Web Site -> File System -> Select Web Site Folder and Open the project.                   Now btnSave is automatically recognized in Default.aspx.cs without any declaration in Default.aspx.cs as bellow                            System.Web.UI.WebControls.Button btnSave; How btnSave is being recognized by .cs file without defining it anywhere as an object of System.Web.UI.WebControls.Button? Note: This happens only if you open Web Site from File System.           and No Declaration at all for btnSave. Please refer this article on this. span.fullpost {display:none;}

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  • How do I encapsulate form/post/validation[/redirect] in ViewUserControl in ASP.Net MVC 2

    - by paul
    What I am trying to achieve: encapsulate a Login (or any) Form to be reused across site post to self when Login/validation fails, show original page with Validation Summary (some might argue to just post to Login Page and show Validation Summary there; if what I'm trying to achieve isn't possible, I will just go that route) when Login succeeds, redirect to /App/Home/Index also, want to: stick to PRG principles avoid ajax keep Login Form (UserController.Login()) as encapsulated as possible; avoid having to implement HomeController.Login() since the Login Form might appear elsewhere All but the redirect works. My approach thus far has been: Home/Index includes Login Form: <%Html.RenderAction("Login","User");%> User/Login ViewUserControl<UserLoginViewModel> includes: <%=Html.ValidationSummary("") % using(Html.BeginForm()){} includes hidden form field "userlogin"="1" public class UserController : BaseController { ... [AcceptPostWhenFieldExists(FieldName = "userlogin")] public ActionResult Login(UserLoginViewModel model, FormCollection form){ if (ModelState.IsValid) { if(checkUserCredentials()) { setUserCredentials() return this.RedirectToAction<Areas.App.Controllers.HomeController>(x = x.Index()); } else { return View(); } } ... } Works great when: ModelState or User Credentials fail -- return View() does yield to Home/Index and displays appropriate validation summary. (I have a Register Form on the same page, using the same structure. Each form's validation summary only shows when that form is submitted.) Fails when: ModelState and User Credentials valid -- RedirectToAction<>() gives following error: "Child actions are not allowed to perform redirect actions." It seems like in the Classic ASP days, this would've been solved with Response.Buffer=True. Is there an equivalent setting or workaround now? Btw, running: ASP.Net 4, MVC 2, VS 2010, Dev/Debugging Web Server I hope all of that makes sense. So, what are my options? Or where am I going wrong in my approach? tia!

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  • Problem with Spring security's logout

    - by uther-lightbringer
    Hello, I've got a problem logging out in Spring framework. First when I want j_spring_security_logout to handle it for me i get 404 j_spring_security_logout not found: sample-security.xml: <http> <intercept-url pattern="/messageList.htm*" access="ROLE_USER,ROLE_GUEST" /> <intercept-url pattern="/messagePost.htm*" access="ROLE_USER" /> <intercept-url pattern="/messageDelete.htm*" access="ROLE_ADMIN" /> <form-login login-page="/login.jsp" default-target-url="/messageList.htm" authentication-failure-url="/login.jsp?error=true" /> <logout/> </http> Sample url link to logout in JSP page: <a href="<c:url value="/j_spring_security_logout" />">Logout</a> When i try to use a custom JSP page i.e. I use login form for this purpose then I get better result at least it gets to login page, but another problem is that you dont't get logged off as you can diretcly type url that should be guarded buy you get past it anyway. Slightly modified from previous listings: <http> <intercept-url pattern="/messageList.htm*" access="ROLE_USER,ROLE_GUEST" /> <intercept-url pattern="/messagePost.htm*" access="ROLE_USER" /> <intercept-url pattern="/messageDelete.htm*" access="ROLE_ADMIN" /> <form-login login-page="/login.jsp" default-target-url="/messageList.htm" authentication-failure-url="/login.jsp?error=true" /> <logout logout-success-url="/login.jsp" /> </http> <a href="<c:url value="/login.jsp" />">Logout</a> Thank you for help

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  • Preventing DDOS/SYN attacks (as far as possible)

    - by Godius
    Recently my CENTOS machine has been under many attacks. I run MRTG and the TCP connections graph shoots up like crazy when an attack is going on. It results in the machine becoming inaccessible. My MRTG graph: mrtg graph This is my current /etc/sysctl.conf config # Kernel sysctl configuration file for Red Hat Linux # # For binary values, 0 is disabled, 1 is enabled. See sysctl(8) and # sysctl.conf(5) for more details. # Controls IP packet forwarding net.ipv4.ip_forward = 0 # Controls source route verification net.ipv4.conf.default.rp_filter = 1 # Do not accept source routing net.ipv4.conf.default.accept_source_route = 0 # Controls the System Request debugging functionality of the kernel kernel.sysrq = 1 # Controls whether core dumps will append the PID to the core filename # Useful for debugging multi-threaded applications kernel.core_uses_pid = 1 # Controls the use of TCP syncookies net.ipv4.tcp_syncookies = 1 # Controls the maximum size of a message, in bytes kernel.msgmnb = 65536 # Controls the default maxmimum size of a mesage queue kernel.msgmax = 65536 # Controls the maximum shared segment size, in bytes kernel.shmmax = 68719476736 # Controls the maximum number of shared memory segments, in pages kernel.shmall = 4294967296 net.ipv4.conf.all.rp_filter = 1 net.ipv4.tcp_syncookies = 1 net.ipv4.icmp_echo_ignore_broadcasts = 1 net.ipv4.conf.all.accept_redirects = 0 net.ipv6.conf.all.accept_redirects = 0 net.ipv4.conf.all.send_redirects = 0 net.ipv4.conf.all.accept_source_route = 0 net.ipv4.conf.all.rp_filter = 1 net.ipv4.tcp_max_syn_backlog = 1280 Futher more in my Iptables file (/etc/sysconfig/iptables ) I only have this setup # Generated by iptables-save v1.3.5 on Mon Feb 14 07:07:31 2011 *filter :INPUT ACCEPT [1139630:287215872] :FORWARD ACCEPT [0:0] :OUTPUT ACCEPT [1222418:555508541] Together with the settings above, there are about 800 IP's blocked via the iptables file by lines like: -A INPUT -s 82.77.119.47 -j DROP These have all been added by my hoster, when Ive emailed them in the past about attacks. Im no expert, but im not sure if this is ideal. My question is, what are some good things to add to the iptables file and possibly other files which would make it harder for the attackers to attack my machine without closing out any non-attacking users. Thanks in advance!

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  • why is Mac OSX Lion losing login/network credentials?

    - by Larry Kyrala
    (moved from stackoverflow...) Symptoms So at work we have OSX 10.7.3 installed and every once in a while I will see the following behaviors: 1) if the screen is locked, then multiple tries of the same user/pass are not accepted. 2) if the screen is unlocked, then opening a new bash term may yield prompts such as: `I have no name$` or lkyrala$ ssh lkyrala@ah-lkyrala2u You don't exist, go away! Even when our macs are working normally, everyone here has to login twice. The first time after boot always fails, but the second time (with the same password, not changing anything, just pressing enter again) succeeds. Weird? Workarounds There are some workarounds that resolve the immediate problem, but don't prevent it from happening again: a) wait (maybe an hour or two) and the problems sometimes go away by themselves. b) kill 'opendirectoryd' and let it restart. (from https://discussions.apple.com/thread/3663559) c) hold the power button to reset the computer Discussion Now, the evidence above points me to something screwy with opendirectory and login credentials. Some other people report having these login problems, but it's hard to determine where the actual problem is (Mac, or network environment?). I should add that most of the network are Windows machines, but we have quite a few Macs and Linux machines as well, but I'm not sure of the details of how the network auth is mapped from various domains to others... all I know is that our network credentials work in Windows domains as well as mac and linux logins -- so something is connecting separate systems, or using the same global auth system.

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  • Office documents on intranet all requiring second login and can't pass auth? Disable webdav?

    - by DOTang
    I am not sure what is going on, but recently all the Office documents on our intranet get prompted a second time for login and according to the error logs it looks like it's trying to use webdav to open (an editable?) version of the document to save directly on the server? We have no sharepoint server setup or anything, but this shouldn't be happening. All I want is for the document to be saved or opened from a local copy in temp like normal. Here is the log: Line 57499: 2011-04-12 15:57:10 (ip) OPTIONS (address) - 443 (username) (user ip) Microsoft-WebDAV-MiniRedir/6.1.7601 - 401 1 1326 1525 238 0 Line 57500: 2011-04-12 15:57:10 (ip) OPTIONS (address) - 443 (username) (user ip) Microsoft-WebDAV-MiniRedir/6.1.7601 - 401 1 1326 1525 238 0 Line 57501: 2011-04-12 15:57:10 (ip) OPTIONS (address) - 443 (username) (user ip) Microsoft-WebDAV-MiniRedir/6.1.7601 - 401 1 1326 1525 238 0 The log basically contains a bunch of these. How can I disable this behavior so that office documents that are downloaded aren't attempted to be used through webdav?? Edit: I should clarify behavior, it asks if you want to save or open it, upon choosing open open, it asks to re-authenicate, you put in the user information and the login box comes up 3 times acting like you entered the wrong password. For some users, after passing the login box the third time, it still opens up, for others their browser just locks up. It also doesn't even look like webdav is installed on our server, I see no config options in IIS for it as outlined on this page: http://learn.iis.net/page.aspx/350/installing-and-configuring-webdav-on-iis-7/#001

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  • Are email addresses mandatory for Windows 8 login names?

    - by Cedric Martin
    I've got a computer running Windows 8 and in the user accounts I can see four accounts (they're in french, here's a rough translation): [email protected] / administrator Veronique YYY / [email protected] ASP.NET Machine Account / local account guest account / the guest account is desactivated I've got several questions but they're all related to email addresses and login names / accounts. Are email addresses mandatory for Windows 8 login names? Can you mix live and non-live user accounts on a Windows 8 system? Is it possible to have a live Windows 8 user account which is not using a @live.xx email address? Is it possible to have a non-live Windows 8 user account which is using a @live.xx email address? If the gmail.com email address of the admin is not a live Windows 8 account, does this mean I can create a "fake" email and use that as the email of a new Windows 8 account? Basically I don't understand very well why there are email addresses displayed on the login screen and why there are both @live.xx and @gmail.com email addresses on the same system and answer to the questions I asked above may help me understand a bit better what is going on (I'm coming from a Linux / OS X background. I literally haven't used Windows in more than a decade).

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  • the brightness controls buttons are not working on my HP Dm3t notebook with windows xp, any suggetio

    - by Karim
    i have an HP dm3t notebook which normally comes with windows 7. after some time i figured out how to install Windows XP on it. but now i am facing a problem that the brightess controls dont work so i am unable to change the brightess. the strange thing is that all the other buttons (sound volume, mute, sleep , etc... ) works but not the 2 brightess controls. i already downloaded the "HP Quick Launch Buttons" so i am asking about suggesitions how can i enable these two buttons in windows XP or even if i can change the brightess using some kind of software. thanks

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  • Right click is disabled on Desktop

    - by RameshKatkam
    I installed elementary OS and e17 on my Ubuntu 12.04 from ppas. After logout and login, right click on desktop is not working in gnome and unity but working in file manger.When I login into Pantheon session, I don't find an option to open Home folder and my login display manager theme is also changed.I want to get back to default Ubuntu login theme.Can i change the login theme with simple-lightdm manager. I dont want to mess up my system.Please hemp me how to fix these.

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  • Where is the Microsoft.Windows.Controls.dll in the Nov 2009 Silverlight Toolkit?

    - by Edward Tanguay
    I want to use WrapPanel in Silverlight 3. It is apparently in the Silverlight Toolkit. All the information I can find on it say to download the toolkit, unzip the download, look in the folder binaries and you will find Microsoft.Windows.Controls.dll. This works for December 2008 version of the Silverlight toolkit just fine, since it is a zip file. But I would like the newest version. However, the November 2009 version of the Silverlight toolkit is an .msi file which installs but doesn't tell me where Microsoft.Windows.Controls.dll is. Nor is it in the Add Service | .NET tab. How can I get the Microsoft.Windows.Controls.dll from the November 2009 Silverlight Toolkit install so I can use WrapPanel in Silverlight 3?

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  • How to localize HeaderText in GridView or validation controls?

    - by Janusz
    I cannot figure out why HeaderText or validation controls always fallback to default culture - even though rest of the controls are in correct culture. I have a gridView with HeaderText specified in this way <asp:BoundField DataField="totalSales" HeaderText="<%$ Resources:Strings,TotalSales %>" /> In the same way I have validation controls and they can't be localized. Only this syntax does work <%= Resources.Strings.Payments %> I set different culture in Master page using this statement in Page_Init Me.Page.Culture = "pl-PL" Me.Page.UICulture = "pl-PL" Can anyone spot what's wrong? I have been Googling it for last few days without success. Thanks!

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  • How can I set controls for a web page ??

    - by Rami Jarrar
    I have this login page with https, and i reach to this approach:: import ClientForm import urllib2 request = urllib2.Request("http://ritaj.birzeit.edu") response = urllib2.urlopen(request) forms = ClientForms.ParseResponseEx(response) response.close() f = forms[0] username = str(raw_input("Username: ")) password = str(raw_input("Password: ")) ## Here What To Do request2 = form.click() i get the controls of that page >>> f = forms[0] >>> [c.name for c in f.controls] ['q', 'sitesearch', 'sa', 'domains', 'form:mode', 'form:id', '__confirmed_p', '__refreshing_p', 'return_url', 'time', 'token_id', 'hash', 'username', 'password', 'persistent_p', 'formbutton:ok'] so how can i set the username and password controls of the "non-form form" f ??? and i have another problem,, how to know if its the right username and password ??

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  • Why does ASP.Net rewrite relative paths for runat=server anchor controls?

    - by Atomiton
    I have my UserControls in a ~/Controls folder in my solution: /Controls/TheControl.ascx If specify the following: <a runat="server" href="./?pg=1">link text</a> ASP.Net seems to want to rewrite the path to point to the absolute location. For example, If the control is on site.com/products/fish/cans.aspx the link href will be rewritten to read <a href="../../Controls/?pg=1>link text</a> Why does Asp.Net rewrite these control paths, and is there an elegant way to fix it? I just want the anchor control to spit out exactly what I tell it to!!! Is that so hard?

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