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  • Install the Ajax Control Toolkit from NuGet

    - by Stephen Walther
    The Ajax Control Toolkit is now available from NuGet. This makes it super easy to add the latest version of the Ajax Control Toolkit to any Web Forms application. If you haven’t used NuGet yet, then you are missing out on a great tool which you can use with Visual Studio to add new features to an application. You can use NuGet with both ASP.NET MVC and ASP.NET Web Forms applications. NuGet is compatible with both Websites and Web Applications and it works with both C# and VB.NET applications. For example, I habitually use NuGet to add the latest version of ELMAH, Entity Framework, jQuery, jQuery UI, and jQuery Templates to applications that I create. To download NuGet, visit the NuGet website at: http://NuGet.org Imagine, for example, that you want to take advantage of the Ajax Control Toolkit RoundedCorners extender to create cross-browser compatible rounded corners in a Web Forms application. Follow these steps. Right click on your project in the Solution Explorer window and select the option Add Library Package Reference. In the Add Library Package Reference dialog, select the Online tab and enter AjaxControlToolkit in the search box: Click the Install button and the latest version of the Ajax Control Toolkit will be installed. Installing the Ajax Control Toolkit makes several modifications to your application. First, a reference to the Ajax Control Toolkit is added to your application. In a Web Application Project, you can see the new reference in the References folder: Installing the Ajax Control Toolkit NuGet package also updates your Web.config file. The tag prefix ajaxToolkit is registered so that you can easily use Ajax Control Toolkit controls within any page without adding a @Register directive to the page. <configuration> <system.web> <compilation debug="true" targetFramework="4.0" /> <pages> <controls> <add tagPrefix="ajaxToolkit" assembly="AjaxControlToolkit" namespace="AjaxControlToolkit" /> </controls> </pages> </system.web> </configuration> You should do a rebuild of your application by selecting the Visual Studio menu option Build, Rebuild Solution so that Visual Studio picks up on the new controls (You won’t get Intellisense for the Ajax Control Toolkit controls until you do a build). After you add the Ajax Control Toolkit to your application, you can start using any of the 40 Ajax Control Toolkit controls in your application (see http://www.asp.net/ajax/ajaxcontroltoolkit/samples/ for a reference for the controls). <%@ Page Language="C#" AutoEventWireup="true" CodeBehind="WebForm1.aspx.cs" Inherits="WebApplication1.WebForm1" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <title>Rounded Corners</title> <style type="text/css"> #pnl1 { background-color: gray; width: 200px; color:White; font: 14pt Verdana; } #pnl1_contents { padding: 10px; } </style> </head> <body> <form id="form1" runat="server"> <div> <asp:Panel ID="pnl1" runat="server"> <div id="pnl1_contents"> I have rounded corners! </div> </asp:Panel> <ajaxToolkit:ToolkitScriptManager ID="sm1" runat="server" /> <ajaxToolkit:RoundedCornersExtender TargetControlID="pnl1" runat="server" /> </div> </form> </body> </html> The page contains the following three controls: Panel – The Panel control named pnl1 contains the content which appears with rounded corners. ToolkitScriptManager – Every page which uses the Ajax Control Toolkit must contain a single ToolkitScriptManager. The ToolkitScriptManager loads all of the JavaScript files used by the Ajax Control Toolkit. RoundedCornersExtender – This Ajax Control Toolkit extender targets the Panel control. It makes the Panel control appear with rounded corners. You can control the “roundiness” of the corners by modifying the Radius property. Notice that you get Intellisense when typing the Ajax Control Toolkit tags. As soon as you type <ajaxToolkit, all of the available Ajax Control Toolkit controls appear: When you open the page in a browser, then the contents of the Panel appears with rounded corners. The advantage of using the RoundedCorners extender is that it is cross-browser compatible. It works great with Internet Explorer, Opera, Firefox, Chrome, and Safari even though different browsers implement rounded corners in different ways. The RoundedCorners extender even works with an ancient browser such as Internet Explorer 6. Getting the Latest Version of the Ajax Control Toolkit The Ajax Control Toolkit continues to evolve at a rapid pace. We are hard at work at fixing bugs and adding new features to the project. We plan to have a new release of the Ajax Control Toolkit each month. The easiest way to get the latest version of the Ajax Control Toolkit is to use NuGet. You can open the NuGet Add Library Package Reference dialog at any time to update the Ajax Control Toolkit to the latest version.

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  • Outlook 2007 Does Not Accept Login Credentials, OWA Webmail Does. Troubleshooting Advice?

    - by Chris
    I am trying to connect Outlook 2007 to Exchange (Hosted Exchange from Rackspace). Soon, I will need to roll this out for our entire office. With the Exchange account added to Outlook, Outlook starts up and asks for the user's username and password. Unfortunately, it doesn't like the password I use for it. I can confirm this username (email address) and password combo works by using Outlook WebMail, and another user (in another network/office) confirmed the Exchange account does work within his Outlook client. In my network/office, I can confirm that an Outlook 2007 client (under Windows 7) can connect to the Hosted Exchange server from Rackspace. However, I have not been able to get Outlook 2007 (under Windows XP SP3) to connect to the very same Exchange server Outlook 2007 (under Windows 7) can connect to. Outlook continuously prompts me for the username and password and does not accept the correct combination. Now, regarding the Outlook client that cannot connect/login to Exchange: The user has full admin rights on the workstation We do not run a domain controller/LDAP The firewall on the workstation has been disabled Real time file scanning in Microsoft Security Essentials has been disabled There are no virus scanning applications that would interface with Outlook or an email server. The Exchange account is setup to run on a newly created Outlook profile The network firewall does not log any blocked attempts A packet capture at the router reveals communication between the workstation and the Exchange server or proxy (though, this is SSL encrypted, so I don't know what the computers are saying) I have applied a fix (Added DWORD value of 0 for DefConnectOpts under HKEY_CURRENT_USER\Software\Microsoft\Office\12.0\Outlook\RPC) that was recommended to make RPC function when the workstation does not have a default gateway set. Workstation is configured as DHCP. This fix did nothing, and it may be worth noting the RPC subkey was not present until I added it. RPC service is running on the workstation The program is not running under any compatibility mode. Side note: Outlook 2007 installs with compatibility mode for XP enabled by default in windows 7. Outlook 2007 will not even try to connect to exchange if this compatibility mode is checked. In windows xp, I tried checking compatibility mode for windows 2000, and was unable to connect to exchange as well. Here is the specific configuration I've used in a blank outlook profile: Microsoft Exchange Server: ##MASKED##-MBX-C18.mex07a.mlsrvr.com Username: (Full Email Address: [email protected]) Password: ##MASKED## Outlook Anywhere: Connect to Microsoft Exchange using HTTP Exchange Proxy Settings: Proxy Server: mex07a.emailsrvr.com Check "Connect using SSL only" Under "Only connect to proxy servers...", enter: msstd:mex07a.emailsrvr.com Check "On fast networks, connect using HTTP first, then connect using TCP/IP" Check "On slow networks, connect using HTTP first, then connect using TCP/IP" Proxy authentication settings: Basic Authentication Notes: mex07a.mlsrvr.com and mex07a.emailsrvr.com may look incorrect at first glance, but this is not a typo - these instructions were handed down from rackspace and are confirmed to be working, just not on this workstation. I have tried to use the RpcPing utility but must have been using it wrong. I got as far as "Bad Interface Descriptor". It would seem to me getting Outlook and Exchange to work together would be a breeze, especially since everything is done over port 80 with web services. Unfortunately, the user is stuck with WebMail access only, because Outlook won't accept the Exchange credentials. Do you have any ideas of other things I could try to debug this issue further? Any and all help is greatly appreciated. Thank you! -Chris

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  • Using HtmlAnchor for anchor tag that navigates in-page named anchor

    - by Frank Schwieterman
    I am trying to render a simple hyperlink that links to a named anchor within the page, for example: <a href="#namedAnchor"scroll to down</a <a name="namedAnchor"down</a The problem is that when I use an ASP.NET control like asp:HyperLink or HtmlAnchor, the href="#namedAnchor" is rendered as href="controls/#namedAnchor" (where controls is the subdirectory where the user control containing the anchor is). Here is the code for the control, using two types of anchor controls, which both have the same problem: <%@ Control Language="C#" AutoEventWireup="true" CodeBehind="Test.ascx.cs" Inherits="TestWebApplication1.controls.Test" % <a href="#namedAnchor" runat="server"HtmlAnchor</a <asp:HyperLink NavigateUrl="#namedAnchor" runat="server"HyperLink</asp:HyperLink The generated source looks like: <a href="controls/#namedAnchor"HtmlAnchor</a <a href="controls/#namedAnchor"HyperLink</a I really just want: <a href="#namedAnchor"HtmlAnchor</a <a href="#namedAnchor"HyperLink</a I am using the HtmlAnchor or HyperLink class because I want to make changes to other attributes in the code behind. I do not want to introduce a custom web control for this requirement, as the requirement I'm pursuing is not that important and it would be hard to talk the team into abandoning the traditional ASP.NET link controls. It seems like I should be able to use the ASP.NET link controls to generate the desired link.

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  • jQuery relative positioned hover

    - by danixd
    I want a link to the next or previous image to appear when hovering over the main image, only I want the next link to appear when hovered over the right hand side, and previous on the left. I have looked at jQuery's .position() and I don't think I am understanding it very well. At the moment all I have is general mouseenter/mouseleave events, which show both links when the image is hovered. jQuery(document).ready(function($) { $('.nav-controls a').hide(); $('#slideshow').mouseenter(function() { $('.nav-controls a').fadeIn(500); }); $('#slideshow').mouseleave(function() { $('.nav-controls a').fadeOut(500); }); }); I'd image it to be something like: jQuery(document).ready(function($) { $('.nav-controls a').hide(); var image = $('#slideshow'); var left = image.position().left(0); var right = image.position().left(50%); left.mouseenter(function() { $('.nav-controls a.previous').fadeIn(500); }); left.mouseleave(function() { $('.nav-controls a.previous').fadeOut(500); }); right.mouseenter(function() { $('.nav-controls a.next').fadeIn(500); }); right.mouseleave(function() { $('.nav-controls a.next').fadeOut(500); }); }); Not sure if I should be using position, if I am using it correctly. Any tips would be great. Edit: I do not want to add unnecessary markup in the form of divs, for the left/right selectors.

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  • System.AccessViolationException when calling DLL from WCF on IIS.

    - by Wodzu
    Hi guys. I've created just a test WCF service in which I need to call an external DLL. Everything works fine under Visutal Studio development server. However, when I try to use my service on IIS I am getting this error: Exception: System.AccessViolationException Message: Attempted to read or write protected memory. This is often an indication that other memory is corrupt. The stack trace leeds to the call of DLL which is presented below. After a lot of reading and experimenting I am almost sure that the error is caused by wrong passing strings to the called function. Here is how the wrapper for DLL looks like: using System; using System.Runtime.InteropServices; using System.Text; using System; using System.Security; using System.Security.Permissions; using System.Runtime.InteropServices; namespace cdn_api_wodzu { public class cdn_api_wodzu { [DllImport("cdn_api.dll", CharSet=CharSet.Ansi)] // [SecurityPermission(SecurityAction.Assert, Unrestricted = true)] public static extern int XLLogin([In, Out] XLLoginInfo _lLoginInfo, ref int _lSesjaID); } [Serializable, StructLayout(LayoutKind.Sequential)] public class XLLoginInfo { public int Wersja; public int UtworzWlasnaSesje; public int Winieta; public int TrybWsadowy; [MarshalAs(UnmanagedType.ByValTStr, SizeConst = 0x29)] public string ProgramID; [MarshalAs(UnmanagedType.ByValTStr, SizeConst = 0x15)] public string Baza; [MarshalAs(UnmanagedType.ByValTStr, SizeConst = 9)] public string OpeIdent; [MarshalAs(UnmanagedType.ByValTStr, SizeConst = 9)] public string OpeHaslo; [MarshalAs(UnmanagedType.ByValTStr, SizeConst = 200)] public string PlikLog; [MarshalAs(UnmanagedType.ByValTStr, SizeConst = 0x65)] public string SerwerKlucza; public XLLoginInfo() { } } } this is how I call the DLL function: int ErrorID = 0; int SessionID = 0; XLLoginInfo Login; Login = new XLLoginInfo(); Login.Wersja = 18; Login.UtworzWlasnaSesje = 1; Login.Winieta = -1; Login.TrybWsadowy = 1; Login.ProgramID = "TestProgram"; Login.Baza = "TestBase"; Login.OpeIdent = "TestUser"; Login.OpeHaslo = "TestPassword"; Login.PlikLog = "C:\\LogFile.txt"; Login.SerwerKlucza = "MyServ\\MyInstance"; ErrorID = cdn_api_wodzu.cdn_api_wodzu.XLLogin(Login, ref SessionID); When I comment all the string field assigments the function works - it returns me an error message that the program ID has not been given. But when I try to assign a ProgramID (or any other string fields, or all at once) then I am getting the mentioned exception. I am using VS2008 SP.1, WinXP and IIS 5.1. Maybe the ISS itself is a problem? I've tried all the workarounds that has been described here: http://forums.asp.net/t/675515.aspx Thansk for your time. After edit: Installing Windows 2003 Server and IIS 6.0 solved the problem.

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  • Why does the interpretted order seem different from what I expect?

    - by inspectorG4dget
    I have a problem that I have not faced before: It seems that the order of interpretation in my program is somehow different from what I expect. I have written a small Twitter client. It takes a few seconds for my program to actually post a tweet after I click the "GO" button (which can also be activated by hitting ENTER on the keyboard). I don't want to click multiple times within this time period thinking that I hadn't clicked it the first time. Therefore, when the button is clicked, I would like the label text to display something that tells me that the button has been clicked. I have implemented this message by altering the label text before I send the tweet across. However, for some reason, the message does not display until the tweet has been attempted. But since I have a confirmation message after the tweet, I never get to see this message and my original problem goes unsolved. I would really appreciate any help. Here is the relevant code: class SimpleTextBoxForm(Form): def init(self): # set window properties self.Text = "Tweeter" self.Width = 235 self.Height = 250 #tweet away self.label = Label() self.label.Text = "Tweet Away..." self.label.Location = Point(10, 10) self.label.Height = 25 self.label.Width = 200 #get the tweet self.tweetBox = TextBox() self.tweetBox.Location = Point(10, 45) self.tweetBox.Width = 200 self.tweetBox.Height = 60 self.tweetBox.Multiline = True self.tweetBox.WordWrap = True self.tweetBox.MaxLength = 140; #ask for the login ID self.askLogin = Label() self.askLogin.Text = "Login:" self.askLogin.Location = Point(10, 120) self.askLogin.Height = 20 self.askLogin.Width = 60 self.login = TextBox() self.login.Text= "" self.login.Location = Point(80, 120) self.login.Height = 40 self.login.Width = 100 #ask for the password self.askPass = Label() self.askPass.Text = "Password:" self.askPass.Location = Point(10, 150) self.askPass.Height = 20 self.askPass.Width = 60 # display password box with character hiding self.password = TextBox() self.password.Location = Point(80, 150) self.password.PasswordChar = "x" self.password.Height = 40 self.password.Width = 100 #submit button self.button1 = Button() self.button1.Text = 'Tweet' self.button1.Location = Point(10, 180) self.button1.Click += self.update self.AcceptButton = self.button1 #pack all the elements of the form self.Controls.Add(self.label) self.Controls.Add(self.tweetBox) self.Controls.Add(self.askLogin) self.Controls.Add(self.login) self.Controls.Add(self.askPass) self.Controls.Add(self.password) self.Controls.Add(self.button1) def update(self, sender, event): if not self.password.Text: self.label.Text = "You forgot to enter your password..." else: self.tweet(self.tweetBox.Text, self.login.Text, self.password.Text) def tweet(self, msg, login, password): self.label.Text = "Attempting Tweet..." # this should be executed before sending the tweet is attempted. But this seems to be executed only after the try block try: success = 'Tweet successfully completed... yay!\n' + 'At: ' + time.asctime().split()[3] ServicePointManager.Expect100Continue = False Twitter().UpdateAsXML(login, password, msg) except: error = 'Unhandled Exception. Tweet unsuccessful' self.label.Text = error else: self.label.Text = success self.tweetBox.Text = ""

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  • Why does the interpreted order seem different from what I expect?

    - by inspectorG4dget
    I have a problem that I have not faced before: It seems that the order of interpretation in my program is somehow different from what I expect. I have written a small Twitter client. It takes a few seconds for my program to actually post a tweet after I click the "GO" button (which can also be activated by hitting ENTER on the keyboard). I don't want to click multiple times within this time period thinking that I hadn't clicked it the first time. Therefore, when the button is clicked, I would like the label text to display something that tells me that the button has been clicked. I have implemented this message by altering the label text before I send the tweet across. However, for some reason, the message does not display until the tweet has been attempted. But since I have a confirmation message after the tweet, I never get to see this message and my original problem goes unsolved. I would really appreciate any help. Here is the relevant code: class SimpleTextBoxForm(Form): def __init__(self): # set window properties self.Text = "Tweeter" self.Width = 235 self.Height = 250 #tweet away self.label = Label() self.label.Text = "Tweet Away..." self.label.Location = Point(10, 10) self.label.Height = 25 self.label.Width = 200 #get the tweet self.tweetBox = TextBox() self.tweetBox.Location = Point(10, 45) self.tweetBox.Width = 200 self.tweetBox.Height = 60 self.tweetBox.Multiline = True self.tweetBox.WordWrap = True self.tweetBox.MaxLength = 140; #ask for the login ID self.askLogin = Label() self.askLogin.Text = "Login:" self.askLogin.Location = Point(10, 120) self.askLogin.Height = 20 self.askLogin.Width = 60 self.login = TextBox() self.login.Text= "" self.login.Location = Point(80, 120) self.login.Height = 40 self.login.Width = 100 #ask for the password self.askPass = Label() self.askPass.Text = "Password:" self.askPass.Location = Point(10, 150) self.askPass.Height = 20 self.askPass.Width = 60 # display password box with character hiding self.password = TextBox() self.password.Location = Point(80, 150) self.password.PasswordChar = "x" self.password.Height = 40 self.password.Width = 100 #submit button self.button1 = Button() self.button1.Text = 'Tweet' self.button1.Location = Point(10, 180) self.button1.Click += self.update self.AcceptButton = self.button1 #pack all the elements of the form self.Controls.Add(self.label) self.Controls.Add(self.tweetBox) self.Controls.Add(self.askLogin) self.Controls.Add(self.login) self.Controls.Add(self.askPass) self.Controls.Add(self.password) self.Controls.Add(self.button1) def update(self, sender, event): if not self.password.Text: self.label.Text = "You forgot to enter your password..." else: self.tweet(self.tweetBox.Text, self.login.Text, self.password.Text) def tweet(self, msg, login, password): self.label.Text = "Attempting Tweet..." # this should be executed before sending the tweet is attempted. But this seems to be executed only after the try block try: success = 'Tweet successfully completed... yay!\n' + 'At: ' + time.asctime().split()[3] ServicePointManager.Expect100Continue = False Twitter().UpdateAsXML(login, password, msg) except: error = 'Unhandled Exception. Tweet unsuccessful' self.label.Text = error else: self.label.Text = success self.tweetBox.Text = ""

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  • java.lang.ClassCastException: java.lang.Integer cannot be cast

    - by theJava
    When i click on login, it checks the DB if there is a value matching then i get this error, else it does print me null. public Login authenticate(Login login) { String query = "SELECT 1 FROM Login AS l WHERE l.email=? AND l.password=?"; Object[] parameters = { login.getEmail(), login.getPassword() }; List resultsList = getHibernateTemplate().find(query,parameters); if (resultsList.isEmpty()) { } else if (resultsList.size() > 1) { } else { Login login1 = (Login) resultsList.get(0); System.out.println("Hello" + login1); return login1; } return null; } Error below Cause: java.lang.ClassCastException: java.lang.Integer cannot be cast to com.intermedix.domain.Login at com.vaadin.event.ListenerMethod.receiveEvent(ListenerMethod.java:507) at com.vaadin.event.EventRouter.fireEvent(EventRouter.java:161) at com.vaadin.ui.AbstractComponent.fireEvent(AbstractComponent.java:1154) at com.vaadin.ui.Button.fireClick(Button.java:371) at com.vaadin.ui.Button.changeVariables(Button.java:193) at com.vaadin.terminal.gwt.server.AbstractCommunicationManager.handleVariables(AbstractCommunicationManager.java:1094) at com.vaadin.terminal.gwt.server.AbstractCommunicationManager.doHandleUidlRequest(AbstractCommunicationManager.java:590) at com.vaadin.terminal.gwt.server.CommunicationManager.handleUidlRequest(CommunicationManager.java:266) at com.vaadin.terminal.gwt.server.AbstractApplicationServlet.service(AbstractApplicationServlet.java:476) at javax.servlet.http.HttpServlet.service(HttpServlet.java:820) at org.mortbay.jetty.servlet.ServletHolder.handle(ServletHolder.java:511) at org.mortbay.jetty.servlet.ServletHandler.handle(ServletHandler.java:390) at org.mortbay.jetty.security.SecurityHandler.handle(SecurityHandler.java:216) at org.mortbay.jetty.servlet.SessionHandler.handle(SessionHandler.java:182) at org.mortbay.jetty.handler.ContextHandler.handle(ContextHandler.java:765) at org.mortbay.jetty.webapp.WebAppContext.handle(WebAppContext.java:418) at org.mortbay.jetty.handler.ContextHandlerCollection.handle(ContextHandlerCollection.java:230) at org.mortbay.jetty.handler.HandlerCollection.handle(HandlerCollection.java:114) at org.mortbay.jetty.handler.HandlerWrapper.handle(HandlerWrapper.java:152) at org.mortbay.jetty.Server.handle(Server.java:326) at org.mortbay.jetty.HttpConnection.handleRequest(HttpConnection.java:542) at org.mortbay.jetty.HttpConnection$RequestHandler.content(HttpConnection.java:943) at org.mortbay.jetty.HttpParser.parseNext(HttpParser.java:756) at org.mortbay.jetty.HttpParser.parseAvailable(HttpParser.java:218) at org.mortbay.jetty.HttpConnection.handle(HttpConnection.java:404) at org.mortbay.io.nio.SelectChannelEndPoint.run(SelectChannelEndPoint.java:410) at org.mortbay.thread.QueuedThreadPool$PoolThread.run(QueuedThreadPool.java:582) Caused by: java.lang.ClassCastException: java.lang.Integer cannot be cast to com.intermedix.domain.Login at com.intermedix.services.LoginService.authenticate(LoginService.java:34) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at org.springframework.aop.support.AopUtils.invokeJoinpointUsingReflection(AopUtils.java:301) at org.springframework.aop.framework.ReflectiveMethodInvocation.invokeJoinpoint(ReflectiveMethodInvocation.java:182) at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:149) at org.springframework.transaction.interceptor.TransactionInterceptor.invoke(TransactionInterceptor.java:106) at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:171) at org.springframework.aop.framework.JdkDynamicAopProxy.invoke(JdkDynamicAopProxy.java:204) at $Proxy32.authenticate(Unknown Source) at com.intermedix.ui.LoginDailog.checkLogin(LoginDailog.java:106) at com.intermedix.ui.LoginDailog.access$0(LoginDailog.java:102) at com.intermedix.ui.LoginDailog$1.buttonClick(LoginDailog.java:52) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at com.vaadin.event.ListenerMethod.receiveEvent(ListenerMethod.java:487) ... 26 more

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  • Screen-scraping a site with a asp.net form login in C#?

    - by Ajit
    Hi Friends, i've created a web application in asp.net so far. where i've tried to get some data(site scraping) from secure page of a web site.I've used the HttpWebRequest class for this functionality but i haven't accessed the secure page yet. Every time the login pages was scraped not secure page.I have the site user id and password and don't know that which language site has been developed in. Please advice what should i do ?

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  • Python - create blacklist file of IP addresses that have more than 5 failed login attempts in the au

    - by oz_babe
    Basically I have an authlog/syslog file with a list of log in attempts and IP addresses - I need to make a Python program that will create a txt file with all the IP addresses that have more than 5 failed login attempts - a sort of "blacklist". So basically something like: if "uniqueipaddress" and "authentication failure" appear more than 5 times, add uniqueipaddress to txt file. Any help would be greatly appreciated - please try and make it simple as I am very, very inexperienced in programming in Python! Thanks.

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  • Do you think it's a good idea to create a login box as a user control?

    - by Sergio Tapia
    Hi there guys! I'm starting out learning some ASP.Net programming and I'm going to be making a little community website for my friends and myself. I'm trying to pick up some good habits along the way. I was thinking of having a usercontrol and have that 'loginBox' shows the appropriate textboxes and login button, but also show his username when he is logged in. Do you think I should handle this as a user control or am I missing something as an ASP.Net newbie?

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  • Using Action Filters for user login in Asp.NET MVC?

    - by ripper234
    I recently built a site using Asp.Net. The way I chose to implement user login is through a base 'UserAwareController' class, that all controllers extend. It contained a reference to the UserRepository, and exposed a protected GetCurrentUser() method that concrete controllers could query. The whole process felt a bit wishy-washy to me. Is Action Filters a good alternative? What are its benefits? Is there something else I might be missing?

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  • Using Nuxeo, how do I lock down a page so that it redirects to the login page if the user is unauthe

    - by Aaron Chambers
    I have been put on to a project using Nuxeo, late in it's lifecycle and need to change a few things before it goes live. I am having trouble finding out where I need to look to lock down a Nuxeo based application so that a user is redirected to the login page if they are unauthorised and access a restricted page. Can someone please shoot my some direction on where this sort of logic is kept or defined?

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  • Mac Safari randomly recreating cookie when I refresh my login screen. Very bizarre

    - by mcintyre321
    We have found an issue in our app where Safari on the Mac randomly recreates a login cookie from a logged off session. I have a fiddler archive with this behaviour here. Note that some stuff has been removed from this to make it easier to get, but nothing which sets a cookie or anything has been taken out - only repetitions of requests 3-8. I'll talk you through the running order Request 1: user logs out via call to /logout.aspx - Set-Cookie returned setting cookie expiry date to 1999 Requests 2-8: user refreshes login page sending calls to root or /res/en-US/s.js - no cookie is sent to server or received back, and access is denied. I have cut out a lot of requests of this nature from the log as they are boring Request 9: request for /res/en-US/s.js - Hv3 authentication cookie has mysteriously reappeared! Wat. There was NO set-cookie! WTFF! Request 10+ : now the cookie has reappeared, the site logs the user in AGAIN The cookie, when examined in Safari looks like <dict> <key>Created</key> <real>259603523.26834899</real> <key>Domain</key> <string>.mysite.dev</string> <key>Expires</key> <date>2010-03-24T16:05:22Z</date> <key>HttpOnly</key> <string>TRUE</string> <key>Name</key> <string>.Hv3</string> <key>Path</key> <string>/</string> </dict> One thing to note is that in Safari, the cookie domain is .mysite.dev not mysite.dev (which is the cookie domain specified in web.config) - however, given that access is denied in requests 2-8, it looks like the cookie has expired OK. If you look in the list of cookies in the browser during 2-8, the .Hv3 cookie is not there. Is this our bug or Safari's? What can I do to stop it happening?

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