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  • Image sharing from mysite to facebook profile using php

    - by Stalin
    Good morning.Myself stalin. am a php developer.am new to facebook integration. My requirement is, I need to share the images from mysite to facebook user profiles. ie, i have a page that list the images in mysite. if i click any one image , i need facebook login pop-up from ther i have to enter username ans password after clicking the login button my clicked images have to be post in user's album using php and facebook api. this is my urgent requirement. need help from your side. Thanks.

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  • log in to web-app through less secure website [on hold]

    - by martijnve
    We are worried about the security of our website containing the login-button to our saas-application. Security measures put in place for our application won't do us much good if the website is hacked. The login button could be redirected to some malicious copy of our app. The product website is maintained by people outside the dev team. Those people are not too knowledgable concerning security. We (dev-team) could mantain the website ourselves but that would be a large burden on our small team. How is this usually handled?

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  • "(401)Authorization Required" when making a web service call using Axis

    - by Arun P Johny
    Hi, I'm using apache axis to connect to my sugar crm instance. When I'm trying to connect to the instance it is throwing the following exception Exception in thread "main" AxisFault faultCode: {http://xml.apache.org/axis/}HTTP faultSubcode: faultString: (401)Authorization Required faultActor: faultNode: faultDetail: {}:return code: 401 &lt;!DOCTYPE HTML PUBLIC &quot;-//IETF//DTD HTML 2.0//EN&quot;&gt; &lt;html&gt;&lt;head&gt; &lt;title&gt;401 Authorization Required&lt;/title&gt; &lt;/head&gt;&lt;body&gt; &lt;h1&gt;Authorization Required&lt;/h1&gt; &lt;p&gt;This server could not verify that you are authorized to access the document requested. Either you supplied the wrong credentials (e.g., bad password), or your browser doesn't understand how to supply the credentials required.&lt;/p&gt; &lt;/body&gt;&lt;/html&gt; {http://xml.apache.org/axis/}HttpErrorCode:401 (401)Authorization Required at org.apache.axis.transport.http.HTTPSender.readFromSocket(HTTPSender.java:744) at org.apache.axis.transport.http.HTTPSender.invoke(HTTPSender.java:144) at org.apache.axis.strategies.InvocationStrategy.visit(InvocationStrategy.java:32) at org.apache.axis.SimpleChain.doVisiting(SimpleChain.java:118) at org.apache.axis.SimpleChain.invoke(SimpleChain.java:83) at org.apache.axis.client.AxisClient.invoke(AxisClient.java:165) at org.apache.axis.client.Call.invokeEngine(Call.java:2784) at org.apache.axis.client.Call.invoke(Call.java:2767) at org.apache.axis.client.Call.invoke(Call.java:2443) at org.apache.axis.client.Call.invoke(Call.java:2366) at org.apache.axis.client.Call.invoke(Call.java:1812) at org.beanizer.sugarcrm.SugarsoapBindingStub.get_server_info(SugarsoapBindingStub.java:1115) at com.greytip.sugarcrm.GreytipCrm.main(GreytipCrm.java:42) This basically says that I do not have the authorization to the resource. The same code is working fine in my testing environment. Sugarsoap service = new SugarsoapLocator(); SugarsoapPortType port = service.getsugarsoapPort(new java.net.URL( SUGAR_CRM_LOCATION + "/soap.php")); System.out.println(port.get_server_info().getVersion()); User_auth userAuth = new User_auth(); userAuth.setUser_name("user_name"); MessageDigest md = MessageDigest.getInstance("MD5"); String password = getHexString(md.digest("password".getBytes())); userAuth.setPassword(password); // userAuth.setVersion("0.1"); Entry_value login = port.login(userAuth, "myAppName", null); String sessionID = login.getId(); Above code is used to connect to the Sugar CRM installation. here line "System.out.println(port.get_server_info().getVersion());" is throwing the exception. One difference I noticed between the test and production environment is when I used the soap url in the browser the production site pops up a 'Authentication Required' popup. When I gives my proxy username and password in this popup, it shows the soap request details. The same is applicable for the login url also. First it will ask for the 'Authentication' then it will take to the sugar crm login page? Is it a server security setting? If it is then how to set this user name and password using java in a web service call. The authentication required popup is same as the one which comes when we try to access the tomcat manager through a browser. Thanks

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  • ASP.NET MVC 2 - ViewModel Prefix

    - by Cosmo
    I want to use RenderPartial twice in my view with different models associated. The problem is that some properties are present in both models (nickname, password). They have no prefix, so even the id's or names are equal in the output. Now, if I have model errors for nickname or password, both fields get highlighted. Main View: <div> <% Html.RenderPartial("Register", Model.RegisterModel); %> </div> <div> <% Html.RenderPartial("Login", Model.LoginModel); %> </div> Login PartialView: <% using (Html.BeginForm("Login", "Member")) { %> <fieldset> <legend>Login</legend> <p> <%= Html.LabelFor(x => x.Nickname) %> <%= Html.TextBoxFor(x => x.Nickname) %> </p> <p> <%= Html.LabelFor(x => x.Password) %> <%= Html.PasswordFor(x => x.Password) %> </p> <input type="submit" value="Login" /> </fieldset> <% } % Register PartialView: <% using (Html.BeginForm("Register", "Member")) { %> <fieldset> <legend>Register</legend> <p> <%= Html.LabelFor(x => x.Nickname) %> <%= Html.TextBoxFor(x => x.Nickname) %> </p> <p> <%= Html.LabelFor(x => x.Email) %> <%= Html.TextBoxFor(x => x.Email) %> </p> <p> <%= Html.LabelFor(x => x.Password) %> <%= Html.PasswordFor(x => x.Password) %> </p> <p> <%= Html.LabelFor(x => x.PasswordRepeat) %> <%= Html.PasswordFor(x => x.PasswordRepeat) %> </p> <input type="submit" value="Register" /> </fieldset> <% } % How can I change this?

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  • Nightmare: Upgrading Tomcat 5.5 to 6.0

    - by pavanlimo
    I'm trying to upgrade a perfectly running embedded Tomcat 5.5 to Tomcat 6.0. I understand that all I need to do is replace Tomcat 5.5 jars with 6.0. That's what I did. So I replaced the following jars: catalina-5.0.28.jar catalina-5.5.9.jar catalina-optional-5.5.9.jar commons-el.jar commons-modeler-1.1.0.jar jasper-compiler-jdt.jar jasper-compiler.jar jasper-runtime.jar jmx-5.0.28.jar jsp-api-2.0.jar naming-factory.jar naming-resources.jar servlet-api-2.4.jar servlets-default.jar tomcat-coyote.jar tomcat-http.jar tomcat-util.jar with: annotations-api.jar catalina.jar jasper.jar tomcat-dbcp.jar catalina-ant.jar el-api.jar jsp-api.jar tomcat-i18n-es.jar catalina-ha.jar jasper-el.jar servlet-api.jar tomcat-i18n-fr.jar catalina-tribes.jar jasper-jdt.jar tomcat-coyote.jar tomcat-i18n-ja.jar tomcat-juli.jar As soon as I start the server, I get the following message in the logs at INFO level: INFO: Starting Servlet Engine: Apache Tomcat/6.0.29 Dec 31, 2010 6:04:18 AM org.apache.catalina.loader.WebappClassLoader validateJarFile INFO: validateJarFile(/usr/local/blah/blue/./WEB-INF/lib/servlet-api.jar) - jar not loaded. See Servlet Spec 2.3, section 9.7.2. Offending class: javax/servlet/Servlet.class Based on the this explanation, I need to remove a jar file which has a conflicting Servlet.class. I swear to God, there is no other conflicting jar file, I grepped system wide for Servlet.class, it matched only servlet-api.jar. I also downloaded javaee.jar and replaced it by servlet-api.jar, to same avail. Having tried lot of these stuff, I did not have much to look upto, so set the tomcat logging level to ALL. In the log I could see that it is trying to check for Servlet.class in each and every jar it is loading until it finds servlet-api.jar and throws "jar not loaded" message as soon as it finds servlet-api.jar. See below: FINE: Checking for javax/servlet/Servlet.class Jan 2, 2011 7:39:33 AM org.apache.catalina.loader.WebappLoader setRepositories FINE: Deploy JAR /WEB-INF/lib/servlet-api.jar to /usr/local/blah/blue/./WEB-INF/lib/servlet-api.jar Jan 2, 2011 7:39:33 AM org.apache.catalina.loader.WebappClassLoader addJar FINE: addJar(/WEB-INF/lib/servlet-api.jar) Jan 2, 2011 7:39:33 AM org.apache.catalina.loader.WebappClassLoader validateJarFile FINE: Checking for javax/servlet/Servlet.class Jan 2, 2011 7:39:33 AM org.apache.catalina.loader.WebappClassLoader validateJarFile INFO: validateJarFile(/usr/local/blah/blue/./WEB-INF/lib/servlet-api.jar) - jar not loaded. See Servlet Spec 2.3, section 9.7.2. Offending class: javax/servlet/Servlet.class Jan 2, 2011 7:39:33 AM org.apache.catalina.loader.WebappLoader setRepositories Please note however, that Tomcat starts successfully! And as soon as I hit the URL on the browser, I get blank page(this may be in my case only, I guess 'cuz of my web.xml, sorta different from most. Other people on the internet have got Error 404 instead.) with following log statements(at finest level) Jan 2, 2011 9:40:01 AM org.apache.catalina.connector.CoyoteAdapter parseSessionCookiesId FINE: Requested cookie session id is 0FBA716E3F9B0147C3AF7ABAE3B1C27B Jan 2, 2011 9:40:01 AM org.apache.catalina.authenticator.AuthenticatorBase invoke FINE: Security checking request GET /login.jsp Jan 2, 2011 9:40:01 AM org.apache.catalina.realm.RealmBase findSecurityConstraints FINE: Checking constraint 'SecurityConstraint[protected]' against GET /login.jsp --> false Jan 2, 2011 9:40:01 AM org.apache.catalina.realm.RealmBase findSecurityConstraints FINE: Checking constraint 'SecurityConstraint[protected]' against GET /login.jsp --> false Jan 2, 2011 9:40:01 AM org.apache.catalina.realm.RealmBase findSecurityConstraints FINE: Checking constraint 'SecurityConstraint[protected]' against GET /login.jsp --> false Jan 2, 2011 9:40:01 AM org.apache.catalina.realm.RealmBase findSecurityConstraints FINE: Checking constraint 'SecurityConstraint[protected]' against GET /login.jsp --> false Jan 2, 2011 9:40:01 AM org.apache.catalina.realm.RealmBase findSecurityConstraints FINE: No applicable constraint located Jan 2, 2011 9:40:01 AM org.apache.catalina.authenticator.AuthenticatorBase invoke FINE: Not subject to any constraint Jan 2, 2011 9:40:01 AM org.apache.catalina.core.StandardWrapper allocate FINEST: Returning non-STM instance I'm not sure if the above log message is important, but I'm for all-out disclosure here. One interesting thing though, I manually created a dummy jsp file containing only "helloooo" just outside WEB-INF folder(no security constraints for this file). This file was accessible and could be displayed. But, all my jsp's and classes are inside WEB-INF(ofcourse). Sick and tired of this issue, please help me solve it. I've already spent 20-24 hours on this unsuccessfully. Any pointers directions hints leads?

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  • performing authorisation/authentication between webservices

    - by mary
    Hi, i am developing webservices.In that i want to maintain state information so that all WebMethods could be access only after Login. I have tried but getting problem. I am attaching my code. Any other alternative will also be welcomed. [ WebService(Namespace = "http://amSubfah.org/")] [ WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)] // To allow this Web Service to be called from script, using ASP.NET AJAX, uncomment the following line. // [System.Web.Script.Services.ScriptService] public class Login : System.Web.Services.WebService { Message msgObj = new Message(); BaseClass b = new BaseClass(); PasswordEncryptionDecryption pedObj = new PasswordEncryptionDecryption(); public AuthHeader Authentication=new AuthHeader (); public Login () { //Uncomment the following line if using designed components //InitializeComponent(); } [ SoapHeader("Authentication", Required = true)] [System.Web.Services. WebMethod(EnableSession = true)] public string checkUserLogin(string user, string pwd) { DataSet dsLogin = new DataSet(); List sqlParams = new List(); SqlParameter sqlParam1 = new SqlParameter("@UserName", SqlDbType.NVarChar); sqlParam1.Value = user; sqlParams.Add(sqlParam1); SqlParameter sqlParam2 = new SqlParameter("@Password", SqlDbType.NVarChar); string pass = pedObj.encryptPassword(pwd); sqlParam2.Value = pass; sqlParams.Add(sqlParam2); try { b.initializeDBConnection(); dsLogin = b.execSelectLoginQuery( Query.strSelectLoginData, sqlParams); } catch (SqlException sqlEx) { string str = msgObj.msgErrorMessage + sqlEx.Message + sqlEx.StackTrace; } {if ((dsLogin != null) && (dsLogin.Tables[0].Rows.Count != 0)) { Session[ "username"] = user; string sessionId = System.Guid.NewGuid().ToString(); Authentication.sessionId = sessionId; Authentication.Username = user; return msgObj.msgLoginSuccess; } else return msgObj .msgLoginFail ; } //webmethod for registration [ SoapHeader("Authentication", Required = true)] [System .Web .Services . WebMethod (EnableSession =true )] public string insertRegistrationDetails(string fName,string lName,string email,string pwd) { //string u = Session["username"].ToString(); //if (u == "") //{ // //checkUserLogin(fName,pwd ); // return "Please login first"; //} if (Authentication.Username == null || Authentication.sessionId == null) { return "Please Login first"; } List sqlParams = new List(); int insert = 0; string msg = "" ; SqlParameter sqlParam = new SqlParameter("@FName", SqlDbType.NVarChar); sqlParam.Value = fName; sqlParam.Size = 50; sqlParams.Add(sqlParam); SqlParameter sqlParam1 = new SqlParameter("@LName", SqlDbType.NVarChar); sqlParam1.Value = lName; sqlParam1.Size = 50; sqlParams.Add(sqlParam1); SqlParameter sqlParam5 = new SqlParameter("@Email", SqlDbType.NVarChar); sqlParam5.Value = email; sqlParam5.Size = 50; sqlParams.Add(sqlParam5); SqlParameter sqlParam7 = new SqlParameter("@Password", SqlDbType.NVarChar); sqlParam7.Value = pedObj .encryptPassword (pwd); sqlParam7.Size = 50; sqlParams.Add(sqlParam7); try { b.initializeDBConnection(); insert = b.execByKeyParams( Query.strInsertIntoRegistrationTable1, sqlParams); if (insert !=0) { msg = msgObj .msgRecInsertedSuccess ; } } catch (SqlException sqlEx) { string str = msgObj.msgErrorMessage + sqlEx.Message + sqlEx.StackTrace; } return msg; } public class AuthHeader : SoapHeader { public string Username; public string sessionId; } }

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  • Input string was not in the correct format using int.Parse

    - by JDWebs
    I have recently been making a login 'representation' which is not secure. So before answering, please note I am aware of security risks etc., and this will not be on a live site. Also note I am a beginner :P. For my login representation, I am using LINQ to compare values of a DDL to select a username and a Textbox to enter a password, when a login button is clicked. However, an error is thrown 'Input string was not in the correct format', when using int.Parse. Front End: <%@ Page Language="C#" AutoEventWireup="true" CodeFile="Login_Test.aspx.cs" Inherits="Login_Login_Test" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <title>Login Test</title> </head> <body> <form id="LoginTest" runat="server"> <div> <asp:DropDownList ID="DDL_Username" runat="server" Height="20px" DataTextField="txt"> </asp:DropDownList> <br /> <asp:TextBox ID="TB_Password" runat="server" TextMode="Password"></asp:TextBox> <br /> <asp:Button ID="B_Login" runat="server" onclick="B_Login_Click" Text="Login" /> <br /> <asp:Literal ID="LI_Result" runat="server"></asp:Literal> </div> </form> </body> </html> Back End: using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.UI; using System.Web.UI.WebControls; public partial class Login_Login_Test : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { if (!Page.IsPostBack) { Binder(); } } private void Binder() { using (DataClassesDataContext db = new DataClassesDataContext()) { DDL_Username.DataSource = from x in db.DT_Honeys select new { id = x.UsernameID, txt = x.Username }; DDL_Username.DataValueField = "id"; DDL_Username.DataTextField = "txt"; DDL_Username.DataBind(); } } protected void B_Login_Click(object sender, EventArgs e) { if (TB_Password.Text != "") { using (DataClassesDataContext db = new DataClassesDataContext()) { DT_Honey blah = new DT_Honey(); blah = db.DT_Honeys.SingleOrDefault(x => x.UsernameID == int.Parse(DDL_Username.SelectedValue.ToString())); if (blah == null) { LI_Result.Text = "Something went wrong :/"; } if (blah.Password == TB_Password.Text) { LI_Result.Text = "Credentials recognised :-)"; } else { LI_Result.Text = "Error with credentials :-("; } } } } } I am aware this problem is very common, but none of the help I have found online is useful/relevant. Any help/suggestions appreciated; thank you for your time :-).

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  • Losing sessions on GlassFish

    - by synti
    I have a web application that logs users in a @SessionScoped managed bean. It's all the basic stuff, pretty much like this: users logs in using regular http form and gets redirect to user area (wich is protected using a filter). But if any resource on that area is accessed, the request somehow uses a new session, wich has no managed bean, no user, and the filter does his job, redirecting him to login page. Here's the login form: <h:form> <h:outputLabel for="email" value="Email "/> <p:inputText id="email" size="30" value="#{loginManager.email}"/> <h:outputLabel for="password" value="Password "/> <p:password id="password" size="12" value="#{loginManager.password}"/> <p:commandButton value="Login" action="#{loginManager.login()}"/> </h:form> The loginManager managed bean: @ManagedBean @SessionScoped public class LoginManager implements Serializable { @EJB private UserService userService; private User user; private String email; private String password; public String login() { user = userService.findBy(email, password); if (user == null) { // FacesMessage stuff } else { return "/user/welcome.xhtml?faces-redirect=true"; } } public String logout() { FacesContext.getCurrentInstance().getExternalContext().invalidateSession(); return "/index.xhtml?faces-redirect=true"; } // Getters, setters (no setter for user) and serialVersionUID And then comes the filter that protects the user area: @WebFilter(urlPatterns="/user/*", displayName="UserFilter") public class UserFilter implements Filter { @Override public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException { HttpSession session = ((HttpServletRequest)request).getSession(false); LoginManager loginManager = (LoginManager) session.getAttribute("loginManager"); if (loginManager == null || !loginManager.hasUser()) { HttpServletResponse resp = (HttpServletResponse) response; resp.sendRedirect("index.xhtml"); } final User user = loginManager.getUser(); if (user.isValid()) { chain.doFilter(request, response); } else { HttpServletResponse resp = (HttpServletResponse) response; resp.sendRedirect("index.xhtml"); } } The UserService is just a stateless EJB that handles persistence. Part of the JSF for user area: <h:form> <p:panelMenu> <p:submenu label="Items"> <p:menuitem value="Add item" action="#{userItens.addItems}" ajax="false"/> <p:menuitem value="My items" /> </p:submenu> </p:panelMenu> </h:form> And finally the userItens managed bean. @ManagedBean @RequestScoped public class UserItens { private User user; @PostConstruct private void init() { HttpSession session = (HttpSession) FacesContext.getCurrentInstance() .getExternalContext().getSession(false); LoginManager loginManager = (LoginManager) session.getAttribute("loginManager"); if (loginManager != null) user = loginManager.getUser(); } public String addItems() { // Doesn't get here. Seems like UserFilter comes first, doesn't find // an user and redirects. } I'm using glassfish and session timeout is now on 0.

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  • how can I exit from a php script and continue right after the script?

    - by Samir Ghobril
    Hey guys, I have this piece of code, and when I add return after echo(if there is an error and I need to continue right after the script) I can't see the footer, do you know what the problem is? <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <html lang="en" > <head> <title>Login | JM Today </title> <link href="Mainstyles.css" type="text/css" rel="stylesheet" /> </head> <body> <div class="container"> <?php include("header.php"); ?> <?php include("navbar.php"); ?> <?php include("cleanquery.php") ?> <div id="wrap"> <?php ini_set('display_errors', 'On'); error_reporting(E_ALL | E_STRICT); $conn=mysql_connect("localhost", "***", "***") or die(mysql_error()); mysql_select_db('jmtdy', $conn) or die(mysql_error()); if(isset($_POST['sublogin'])){ if(( strlen($_POST['user']) >0) && (strlen($_POST['pass']) >0)) { checklogin($_POST['user'], $_POST['pass']); } elseif((isset($_POST['user']) && empty($_POST['user'])) || (isset($_POST['pass']) && empty($_POST['pass']))){ echo '<p class="statusmsg">You didn\'t fill in the required fields.</p><br/><input type="button" value="Retry" onClick="location.href='."'login.php'\">"; return; } } else{ echo '<p class="statusmsg">You came here by mistake, didn\'t you?</p><br/><input type="button" value="Retry" onClick="location.href='."'login.php'\">"; return; } function checklogin($username, $password){ $username=mysql_real_escape_string($username); $password=mysql_real_escape_string($password); $result=mysql_query("select * from users where username = '$username'"); if($result != false){ $dbArray=mysql_fetch_array($result); $dbArray['password']=mysql_real_escape_string($dbArray['password']); $dbArray['username']=mysql_real_escape_string($dbArray['username']); if(($dbArray['password'] != $password ) || ($dbArray['username'] != $username)){ echo '<p class="statusmsg">The username or password you entered is incorrect. Please try again.</p><br/><input type="button" value="Retry" onClick="location.href='."'login.php'\">"; return; } $_SESSION['username']=$username; $_SESSION['password']=$password; if(isset($_POST['remember'])){ setcookie("jmuser",$_SESSION['username'],time()+60*60*24*356); setcookie("jmpass",$_SESSION['username'],time()+60*60*24*356); } } else{ echo'<p class="statusmsg"> The username or password you entered is incorrect. Please try again.</p><br/>input type="button" value="Retry" onClick="location.href='."'login.php'\">"; return; } } ?> </div> <br/> <br/> <?php include("footer.php") ?> </div> </body> </html>

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  • input field placeholder in jQuery

    - by Hristo
    I'm trying to create a Login page, not worrying about actually logging in yet, but I'm trying to achieve the effect where there is some faded text inside the input field and when you click on it, the text disappears or if you click away the text reappears. I have this working for my "Username" input field, but the "Password" field is giving me problems because I can't just do $("#password").attr("type","password"). Here's my code: <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>Insert title here</title> <!-- Links --> <link rel="stylesheet" type="text/css" href="style.css" /> <!-- Scripts --> <script type="text/javascript" src="jQuery.js"></script> <script> // document script $(document).ready(function(){ // login box event handler $('#login').click(function(){ $('.loginBox').animate({ height: '150px' }, '1000' ); $('#username').show(); // add pw placeholder field $('#password').after('<input type="text" id="placeHolder" value="Password" class="placeHolder" />'); $('#password').hide(); }); // username field focus and blur event handlers $('#username').focus(function() { if($(this).hasClass('placeHolder')){ $(this).val(''); $(this).removeClass('placeHolder'); } }); $('#username').blur(function() { if($(this).val() == '') { $(this).val('Username'); $(this).addClass('placeHolder'); } }); // password field focus and blur event handlers $('#placeHolder').focus(function() { $('#placeHolder').hide(); $('#password').show(); $('#password').focus(); }); $('#password').blur(function() { if($('#password').val() == '') { $('#placeHolder').show(); $('#password').hide(); } }); }); </script> </head> <body> <div id="loginBox" class="loginBox"> <a id="login">Proceed to Login</a><br /> <div id="loginForm"> <form> <input type="text" id="username" class="placeHolder" value="Username" /> <input type="password" id="password" class="placeHolder" value="" /> </form> </div> </div> </body> </html> Right now, I can click on the password input box and type in it, but the text is not disappearing and the "type" doesn't get set to "password"... the new input field I create isn't being hidden, it just stays visible, and I'm not sure where the problem is. Any ideas? Thanks, Hristo

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  • expanding/collapsing div using jQuery

    - by Hristo
    I'm trying to expand and collapse a <div> by clicking some text inside the <div>. The behavior right now is very odd. For example, if I click the text after the <div> is expanded... the <div> will collapse and then expand again. Also, if I click somewhere inside the div after it is expanded, it will collapse again, and I think that is because I'm triggering the animation since the <div> being animated is inside the wrapper <div>. Here's the code: <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>Insert title here</title> <!-- Links --> <link rel="stylesheet" type="text/css" href="style.css" /> <!-- Scripts --> <script type="text/javascript" src="jQuery.js"></script> <script> // document script $(function(){ // login box event handler $('#login').click(function() { $('#loginBox').toggle( function() { $('.loginBox').animate({ height: '150px' }, '1000' ); $('#username').show(); $('#password').hide(); $('#placeHolder').show(); }, function() { $('.loginBox').animate({ height: '50px' }, '1000' ); $('#username').hide(); $('#password').hide(); $('#placeHolder').hide(); } ); }); // username field focus and blur event handlers $('#username').focus(function() { if($(this).hasClass('placeHolder')){ $(this).val(''); $(this).removeClass('placeHolder'); } }); $('#username').blur(function() { if($(this).val() == '') { $(this).val('Username'); $(this).addClass('placeHolder'); } }); // password field focus and blur event handlers $('#placeHolder').focus(function() { $(this).hide(); $('#password').show(); $('#password').focus(); $('#password').removeClass('placeHolder'); }); $('#password').blur(function() { if($(this).val() == '') { $('#placeHolder').show(); $(this).hide(); } }); }); </script> </head> <body> <div id="loginBox" class="loginBox"> <a id="login" class="login">Proceed to Login</a><br /> <div> <form> <input type="text" id="username" class="placeHolder" value="Username" /> <input type="password" id="password" class="placeHolder" value="" /> <input type="text" id="placeHolder" class="placeHolder" value="Password" /> </form> </div> </div> </body> </html> Any ideas? Thanks, Hristo

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  • Phonegap / jquery mobile slide transition not workign properly on first call

    - by Alexander Casassovici
    I have an awkward visual glitch. I want nice transition when changing pages on the app. Unfortunately first time i change to another page, Instead of sliding current pagg out and new page in , current page is immediately replaces by the new page, then slides out... and when it's out of view it's the new page is shown... the second time around it works like a charm though !!! This is running on iphone with jquery mobile + phonegap I made a video to make the issue clear: http://www.youtube.com/watch?v=Ybvzh_wTnSE <body style="background-color: #000;"> <div id="container" style="display:none;"> <div id="side-menu" style="display:none;"> <div id="header_top"></div> <a href="#dives" onclick="showdives();"><div id="header_dives" class="selected"></div></a> <div id="header_spacer1"></div> <a href="#explore" onclick="showexplore();"><div id="header_explore"></div></a> <div id="header_spacer2"></div> <a href="#search" onclick="showsearch();"><div id="header_search"></div></a> <div id="header_spacer3"></div> <a href="#settings" onclick="showsettings();"><div id="header_settings"></div></a> <div id="header_bottom"></div> </div> <div id="slide_mask"> <!-- START of LOGIN page --> <div data-role="page" id="login"> <div id="home_frame"> <div id="home_logo"></div> <div id="home_fblogin" onclick="login()"></div> <div class="home_login"> <p>Email: <input type="text" name="user[email]" size="30"/></p> <p>Password: <input type="password" name="user[password]" size="30"/></p> <button onclick="show_page_home();">LOGIN</button> </div> </div> </div> <!-- END of LOGIN page --> <!-- START of LOGIN page --> <div data-role="page" id="dives" class="right_pane"> <p>My dives !</p> </div><!-- /content --> <div data-role="page" id="explore" class="hidden right_pane"> <p>My explore !</p> </div><!-- /content --> <div data-role="page" id="search" class="hidden right_pane"> <p>My search !</p> </div><!-- /content --> <div data-role="page" id="settings" class="hidden right_pane"> <p>My settings !</p> <button onclick="logout_db();">logout</button> </div><!-- /content --> <!-- END of LOGIN page --> </div> </div> <div id="log"></div> <div id="data"></div> </body> And the relevant CSS: body {margin: 0; font: 18px Helvetica; text-align: center; background-color: #000; background: url(../img/bg_big.png) repeat; -webkit-user-select: none; /* prevent copy paste for all elements */ } #container { width:320px; height:460px; overflow: hidden;} input{ -webkit-user-select: text; /* enable copy paste for elements with this class */} a {-webkit-user-select: none; /* prevent copy paste for all elements */} span {-webkit-user-select: none; /* prevent copy paste for all elements */} #side-menu {z-index: 1000 !important; position: fixed; height: 460px; width: 56.5px; background: url(../img/bg_big.png) no-repeat; display: inline-block; overflow: hidden; top: 0px; left: 0px; } #header_top {background: url(../img/header/header_top.png) no-repeat; background-size: 56.5px 48.96px; width: 56.5px; height: 48.96px; display: block;} #header_dives {background: url(../img/header/dives.png) no-repeat; background-size: 56.5px 51.75px; width: 56.5px; height: 51.75px; display: block;} #header_dives.selected{background: url(../img/header/dives_selected.png) no-repeat;} #header_spacer1{background: url(../img/header/header_space1.png) no-repeat; background-size: 56.5px 13.9px; width: 56.5px; height: 13.9px; display: block;} #header_explore{background: url(../img/header/explore.png) no-repeat; background-size: 56.5px 51.75px; width: 56.5px; height: 51.75px; display: block;} #header_explore.selected{background: url(../img/header/explore_selected.png) no-repeat;} #header_spacer2{background: url(../img/header/header_space2.png) no-repeat; background-size: 56.5px 15.33px; width: 56.5px; height: 15.33px; display: block;} #header_search{background: url(../img/header/search.png) no-repeat; background-size: 56.5px 51.75px; width: 56.5px; height: 51.75px; display: block;} #header_search.selected{background: url(../img/header/search_selected.png) no-repeat;} #header_spacer3{background: url(../img/header/header_space3.png) no-repeat; background-size: 56.5px 17.73px; width: 56.5px; height: 17.73px; display: block;} #header_settings{background: url(../img/header/settings.png) no-repeat; background-size: 56.5px 51.75px; width: 56.5px; height: 51.75px; display: block;} #header_settings.selected{background: url(../img/header/settings_selected.png) no-repeat;} #header_bottom{background: url(../img/header/header_bottom.png) no-repeat; background-size: 56.5px 160px; width: 56.5px; height: 160px; display: block;} .hidden {display: none;} .right_pane{width: 263.5px !important; background: url(../img/right_bg.png) no-repeat; background-size:263.5px 460px; width: 263.5px; height: 460px; left: 56.5px !important;} #slide_mask{ display: inline-block; overflow: hidden; padding-left: 56.5px; width: 263.5px; height: 460px; top: 0;} and the bit of JS: /////////////////////////////////// //MENU MECHANICS /////////////////////////////////// function showdives(){ $("#side-menu .selected").removeClass("selected"); $("#header_dives").addClass("selected"); } function showexplore(){ $("#side-menu .selected").removeClass("selected"); $("#header_explore").addClass("selected"); } function showsearch(){ $("#side-menu .selected").removeClass("selected"); $("#header_search").addClass("selected"); } function showsettings(){ $("#side-menu .selected").removeClass("selected"); $("#header_settings").addClass("selected"); } the onclick only add/remove the "selected" class to the menu items so... any hint ? been trying eveything for hours and still can't get it neat .. :(

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  • Account Lockout with pam_tally2 in RHEL6

    - by Aaron Copley
    I am using pam_tally2 to lockout accounts after 3 failed logins per policy, however, the connecting user does not receive the error indicating pam_tally2's action. (Via SSH.) I expect to see on the 4th attempt: Account locked due to 3 failed logins No combination of required or requisite or the order in the file seems to help. This is under Red Hat 6, and I am using /etc/pam.d/password-auth. The lockout does work as expected but the user does not receive the error described above. This causes a lot of confusion and frustration as they have no way of knowing why authentication fails when they are sure they are using the correct password. Implementation follows NSA's Guide to the Secure Conguration of Red Hat Enterprise Linux 5. (pg.45) It's my understanding that that only thing changed in PAM is that /etc/pam.d/sshd now includes /etc/pam.d/password-auth instead of system-auth. If locking out accounts after a number of incorrect login attempts is required by your security policy, implement use of pam_tally2.so. To enforce password lockout, add the following to /etc/pam.d/system-auth. First, add to the top of the auth lines: auth required pam_tally2.so deny=5 onerr=fail unlock_time=900 Second, add to the top of the account lines: account required pam_tally2.so EDIT: I get the error message by resetting pam_tally2 during one of the login attempts. user@localhost's password: (bad password) Permission denied, please try again. user@localhost's password: (bad password) Permission denied, please try again. (reset pam_tally2 from another shell) user@localhost's password: (good password) Account locked due to ... Account locked due to ... Last login: ... [user@localhost ~]$

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  • pGina with automatic Kerberos ticket and OpenAFS token/ticket

    - by rolands
    I am currently updating our educational Windows lab images from XP to 7, In doing so we are also migrating from Comtarsia to pGina. Unfortunately somewhere in the transition our automation that fetched kerberos and OpenAFS tickets/tokens on login has completely stopped functioning. Basically what used to happen was, using kfw-3.2.2 and the old OpenAFS release (loopback adapter days), either comtarsia would share password or something with the NIM (Network Identity Manager) which would authenticate against the kerberos server gaining a ticket and AFS token needed to access the users file, this was aided by the fact that our ldap database that windows authenticates against is also what kerberos uses to authenticate so usernames/passwords are the same across both services. I have set up all of the tools, albeit newer 64bit versions which seem to have given me less trouble than the previous releases of NIM/OpenAFS/Krb5, as well as setting their configurations back to what we used to use. Unfortunately this seems to be fubar'd in some way, instead all we get now is a OpenAFS token, most likely I assume from the AFScreds tool which operates some kind of integrated login process, although this does not help in getting a kerberos ticket or a afs ticket for which a login box is provided be NIM after the user logs in. Does anyone know IF it is possible to do what we are trying, and if so how? I was considering writing a pGina plugin which would interact with the server itself but this seems slightly like overkill considering that all these applications already exist...

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  • WS2008 subst in Logon script does not "stick"

    - by Frans
    I have a terminal server environment exclusively with Windows Server 2008. My problem is that I need to "map" a drive letter to each users Temp folder. This is due to a legacy app that requries a separate Temp folder for each user but which does not understand %temp%. So, just add "subst t: %temp%" to the logon script, right? The problem is that, even though the command runs, the subst doesn't "stick" and the user doesn't get a T: drive. Here is what I have tried; The simplest version: 'Mapping a temp drive Set WinShell = WScript.CreateObject("WScript.Shell") WinShell.Run "subst T: %temp%", 2, True That didn't work, so tried this for more debug information: 'Mapping a temp drive Set WinShell = WScript.CreateObject("WScript.Shell") Set procEnv = WinShell.Environment("Process") wscript.echo(procEnv("TEMP")) tempDir = procEnv("TEMP") WinShell.Run "subst T: " & tempDir, 3, True This shows me the correct temp path when the user logs in - but still no T: Drive. Decided to resort to brute force and put this in my login script: 'Mapping a temp drive Set WinShell = WScript.CreateObject("WScript.Shell") WinShell.Run "\\domain\sysvol\esl.hosted\scripts\tempdir.cmd", 3, True where \domain\sysvol\esl.hosted\scripts\tempdir.cmd has this content: echo on subst t: %temp% pause When I log in with the above then the command window opens up and I can see the subst command being executed correctly, with the correct path. But still no T: drive. I have tried running all of the above scripts outside of a login script and they always work perfectly - this problem only occurs when doing it from inside a login script. I found a passing reference on an MSFN forum about a similar problem when the user is already logged on to another machine - but I have this problem even without being logged on to another machine. Any suggestion on how to overcome this will be much appreciated.

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  • Couldn't upload files to Sharepoint site while passing through Squid Proxy

    - by Ecio
    Hi all, we have this issue: one of our employees is collaborating with a supplier and he needs to upload documents on a Sharepoint site hosted on the supplier's main site. In our environment we use Squid Proxy to allow people navigate on the net (we have NTLM authentication and users transparently authenticate while using IE and FF). It seems that this specific Sharepoint site is using Integrated Windows Authentication only, and according to some research on the net it seems that this can have troubles with proxies. More specifically, we have tried two Squid versions: with Squid 3.0 we are unable to login to the site (the browser loads an empty page) with Squid 2.7 (that supports "Connection Pinning") we are able to login into the site, move on the different sections BUT.. when we try to upload a file that is bigger than a couple of KiloBytes (i.e. 10KB) the browser loads an error page (i think it's a 401 unauthorized but i must verify it) we've tried changing a couple of Squid options (in 2.7), what we got is that when you try to upload the file you got an authentication box (just like the initial login) and it refuses to go on even if you enter the same authentication credentials. What's really strange is that when you try to upload a small file (i.e. a text or binary 1KB file) the upload succeeds. I initially thought that maybe there was something misconfigured on their Sharepoint site but I've tried also this site: www.xsolive.com (it's a sharepoint 2007 demo site) and I've experienced the same problem. Has any of you experienced such behaviour? Thanks! Of course we've suggested to the supplier to activate also Basic+SSL and we're waiting for their reply..

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  • How to run some commands after booting from ArchLinux disk? Or how to change some settings in .iso before booting?

    - by Alexander Ovchinnikov
    How to install Arch Linux with traditional installer with only ssh-access to server? There is nice guide: https://wiki.archlinux.org/index.php/Install_from_SSH I try test this on my home vps: Start VPS with any linux bootable cd and login to remote server (vps) wget http://mirrors.kernel.org/archlinux/iso/latest/archlinux-2010.05-netinstall-x86_64.iso dd if=archlinux-2010.05-netinstall-x86_64.iso of=/dev/sda reboot ... I see, it works but without ssh connection... I need make script, which will send this commands after reboot: aif -p partial-configure-network (and write some information about my server ip etc.) /etc/rc.d/sshd start (need to start sshd) echo "sshd: ALL" /etc/hosts.allow (to allow me login to server, by default deny all) passwd (by default its empty, can't login via ssh with empty password) Can I edit .iso or may be /dev/sda? May be I need write script, which will start after system boot and do this things or may be I can set this settings by default and system will start with correct settings (i think its possible at least in 2. and 3.). Thank you!

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  • OpenAM throwing 302 0 behind haproxy, nginx

    - by Travis
    I'm having some issues with my deployment and was wondering if you can help. My set up is as follows: 2 OpenAM servers are set up behind a load balancer (HAproxy). The load balancer is set up behind two reverse proxies (nginx). The two reverse proxies are ser up behind another load balancer (haproxy). So a request will go through Haproxy nginx Haproxy openam I can access the OpenAM web console through the reverse proxies without a problem. Everything works fine at this level. However when I access openam through the load balancer in front of the reverse proxies Openam throws a 302 error. The funny thing is however I can access the host/openam/UI/Login and login successfully. I even get the cookie and have access to my apps that are set up. However immediately after the login OpenAM throws a 302 redirect. I'm puzzled and cannot figure out what is going wrong. Does anyone have any idea? My config files are below: nginx config : server { listen 443; server_name oamlb1; location / { proxy_pass http://oamlb1.mydomain.com:8080; proxy_set_header X-Real-IP $remote_addr; } location /openam { proxy_pass http://oamlb1.mydomain.com:8080; proxy_set_header X-Real-IP $remote_addr; proxy_set_header Host oamlb1.mydomain.com:8080; } } haproxy config : (This file is for the servers. The file for the reverse proxies is idenical except it points to the reverse proxies) listen http_proxy :8090 mode http balance roundrobin option httpclose option forwardfor server webA oamserver1.mydomain.com:18080 option forwardfor Thanks

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  • cyrus-imapd is not work with sasldb2, but postfix work

    - by Felix Chang
    centos6 64 bits: when i use pop3 for access cyrus-imapd: S: +OK li557-53 Cyrus POP3 v2.3.16-Fedora-RPM-2.3.16-6.el6_2.5 server ready <3176565056.1354071404@li557-53> C: USER [email protected] S: +OK Name is a valid mailbox C: PASS abcabc S: -ERR [AUTH] Invalid login C: QUIT and with USER "abc" failed too. my imapd.conf: configdirectory: /var/lib/imap partition-default: /var/spool/imap admins: cyrus sievedir: /var/lib/imap/sieve sendmail: /usr/sbin/sendmail hashimapspool: true sasl_pwcheck_method: auxprop sasl_mech_list: PLAIN LOGIN tls_cert_file: /etc/pki/cyrus-imapd/cyrus-imapd.pem tls_key_file: /etc/pki/cyrus-imapd/cyrus-imapd.pem tls_ca_file: /etc/pki/tls/certs/ca-bundle.crt allowplaintext: true #defaultdomain: myabc.com loginrealms: myabc.com sasldblistuser2: [email protected]: userPassword but my postfix is ok with same user. /etc/sasl2/smtpd.conf pwcheck_method: auxprop mech_list: plain login log_level:7 saslauthd_path:/var/run/saslauthd/mux /etc/postfix/main.cf queue_directory = /var/spool/postfix command_directory = /usr/sbin daemon_directory = /usr/libexec/postfix data_directory = /var/lib/postfix mail_owner = postfix myhostname = localhost mydomain = myabc.com myorigin = $mydomain inet_interfaces = all inet_protocols = all mydestination = $myhostname, localhost.$mydomain, localhost,$mydomain local_recipient_maps = unknown_local_recipient_reject_code = 550 mynetworks_style = subnet mynetworks = 192.168.0.0/24, 127.0.0.0/8 relay_domains = $mydestination alias_maps = hash:/etc/aliases alias_database = hash:/etc/aliases home_mailbox = Maildir/ mailbox_transport = lmtp:unix:/var/lib/imap/socket/lmtp debug_peer_level = 2 debugger_command = PATH=/bin:/usr/bin:/usr/local/bin:/usr/X11R6/bin ddd $daemon_directory/$process_name $process_id & sleep 5 sendmail_path = /usr/sbin/sendmail.postfix newaliases_path = /usr/bin/newaliases.postfix mailq_path = /usr/bin/mailq.postfix setgid_group = postdrop html_directory = no manpage_directory = /usr/share/man sample_directory = /usr/share/doc/postfix-2.6.6/samples readme_directory = /usr/share/doc/postfix-2.6.6/README_FILES smtpd_sasl_auth_enable = yes smtpd_sasl_local_domain = $myhostname smtpd_sasl_security_options = noanonymous smtpd_recipient_restrictions = permit_mynetworks, permit_sasl_authenticated, reject_unauth_destination smtpd_sasl_security_restrictions = permit_mynetworks, permit_sasl_authenticated, reject_unauth_destination message_size_limit = 15728640 broken_sasl_auth_clients=yes please help.

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  • VSFTPD does not allow upload with virtual users

    - by Mr. Squig
    I am attempting to setup VSFTPD with virtual users on a server running Ubuntu 12.04. I have configured the server to allow for virtual users to login, but I am having trouble getting it to allow uploads. My vsftpd.conf is as follows: listen=YES anonymous_enable=NO local_enable=YES write_enable=YES local_umask=022 anon_upload_enable=YES dirmessage_enable=YES use_localtime=YES xferlog_enable=YES connect_from_port_20=YES chroot_local_user=YES virtual_use_local_privs=YES guest_enable=YES guest_username=virtual user_sub_token=$USER local_root=/var/www/$USER hide_ids=YES secure_chroot_dir=/var/run/vsftpd/empty pam_service_name=vsftpd rsa_cert_file=/etc/ssl/private/vsftpd.pem /etc/pam.d/vsftpd contains: auth required pam_pwdfile.so pwdfile /etc/vsftpd.passwd crypt=hash account required pam_permit.so crypt=hash I have two virtual users set up, one of which has the same name as a local user. They each have a directory in /var/www/ owned by 'virtual'. As I understand it, when a virtual user logs in this way they will appear to the system as the user virtual. Using this configuration user can log on, but cannot upload files. The error given in /var/log/vsftpd.log is: Tue Nov 20 19:49:00 2012 [pid 2] CONNECT: Client "96.233.116.53" Tue Nov 20 19:49:07 2012 [pid 1] [zac] OK LOGIN: Client "96.233.116.53" Tue Nov 20 19:49:11 2012 [pid 2] CONNECT: Client "96.233.116.53" Tue Nov 20 19:49:11 2012 [pid 1] [zac] OK LOGIN: Client "96.233.116.53" Tue Nov 20 19:49:11 2012 [pid 3] [zac] FAIL CHMOD: Client "96.233.116.53", "/test.ppm 644" I have tried changing the permissions of these directories in all sorts of ways, but nothing seem to work. I have a feeling that it is something simple related to permissions. Any ideas?

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  • How do I grant a database role execute permissions on a schema? What am I doing wrong?

    - by Lewray
    I am using SQL Server 2008 Express edition. I have created a Login , User, Role and Schema. I have mapped the user to the login, and assigned the role to the user. The schema contains a number of tables and stored procedures. I would like the Role to have execute permissions on the entire schema. I have tried granting execute permission through management studio and through entering the command in a query window. GRANT EXEC ON SCHEMA::schema_name TO role_name But When I connect to the database using SQL management studio (as the login I have created) firstly I cannot see the stored procedures, but more importantly I get a permission denied error when attempting to run them. The stored procedure in question does nothing except select data from a table within the same schema. I have tried creating the stored procedure with and without the line: WITH EXECUTE AS OWNER This doesn't make any difference. I suspect that I have made an error when creating my schema, or there is an ownership issue somewhere, but I am really struggling to get something working. The only way I have successfully managed to execute the stored procedures is by granting control permissions to the role as well as execute, but I don't believe this is the correct, secure way to proceed. Any suggestions/comments would be really appreciated. Thanks.

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  • VSFTP Users and Directories

    - by Mathew
    I'm stuck. I've been working all day on trying to figure out what I'm doing wrong and I've hit wall after wall. What I'm trying to do: Setup FTP in such a way that certain users have access only to their directory, but higher level users have access to all directories. What I've Googled so far: I started with this, but that didn't do what I needed it to. I then used this, but once I created one user, it wouldn't let me create another one. Finally, I decided to follow this, but it wouldn't let me even create one user. I'm using Ubuntu 10. I can login to ftp as a root user and it takes me to the home directory. If I try to login using the user I created in the tutorial it says: Status: Connection established, waiting for welcome message... Response: 220 (vsFTPd 2.2.2) Command: USER mathew Response: 331 Please specify the password. Command: PASS **** Response: 530 Login incorrect. Error: Critical error Error: Could not connect to server

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  • Wicked VNC Viewer acting out on Windows desktop and CentOS 6.3 server

    - by Johnny Lee
    What we have here is the only way to open the TightVNC viewer on this Windows XP desktop is to have a TigerVNC viewer open on the CentOS 6.3 server desktop. I know it sounds really weird and we’re looking for hints to make it go away. Any ideas? Here is the recipe: We are using Putty on the Windows desktop as SSH (Secure Shell) and a Terminal Emulator. We open and login to Putty then open a login to TightVNC viewer. After many failed attempts, much Googling, and lots of reading to no avail I decided to open the TigerVNC viewer on the CentOS 6.3 server by way of the GNOME desktop Application menu -- Internet tab. After opening and logging into the TigerVNC viewer on the CentOS 6.3 Server, Voila!! We have a remote desktop opened on the server. But what was an interesting discovery was that the TigerVNC viewer on the server had a request on the desktop that was not on the server desktop. This turned out to be a login request that once the password was entered it opened the TightVNC viewer on the Windows desktop. Weird huh? -Why is that password request showing up on the CentOS 6.3 server in the TigerVNC viewer as oppose to showing up on the Windows desktop when logging in using TightVNC viewer to the server?

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  • Wrong CSS mime type with Roundcube 0.5 beta and nginx

    - by Julien Vehent
    I'm running into a CSS problem. This is a setup based on Debian Squeeze (nginx/0.7.67, php5/cgi) on which I installed the latest Roundcube 0.5 beta. PHP is properly processed, login works fine but the CSS files are not loaded and Firefox is throwing the following errors: Error: The stylesheet https://webmail.example.net:10443/roundcube/skins/default/common.css?s=1290600165 was not loaded because its MIME type, "text/html", is not "text/css". Source File: https://webmail.example.net:10443/roundcube/?_task=login Line: 0 Error: The stylesheet https://webmail.example.net:10443/roundcube/skins/default/mail.css?s=1290156319 was not loaded because its MIME type, "text/html", is not "text/css". Source File: https://webmail.example.net:10443/roundcube/?_task=login Line: 0 As far as I understand, nginx doesn't see the .css extension (because ofthe ?s= argument) and thus set the mime type with the default value, being text/html. Should I fix this in nginx (and how ?) or is it roundcube's related ? Edit: It seems that it's nginx related. The content-type isn't set for any other type than text/html. I had to include manually the following declarations to force CSS and JS content-types. That's ugly, and I never had the problem before... any idea ? location ~ \.css { add_header Content-Type text/css; } location ~ \.js { add_header Content-Type application/x-javascript; }

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