Search Results

Search found 55195 results on 2208 pages for 'model first'.

Page 159/2208 | < Previous Page | 155 156 157 158 159 160 161 162 163 164 165 166  | Next Page >

  • What is the best way to create related types at runtime?

    - by SniperSmiley
    How do I determine the type of a class that is related to another class at runtime? I have figured out a solution, the only problem is that I ended up having to use a define that has to be used in all of the derived classes. Is there a simpler way to do this that doesn't need the define or a copy paste? Things to note: both the class and the related class will always have their respective base class, the different classes can share a related class, and as in the example I would like the control class to own the view. #include <iostream> #include <string> class model; class view { public: view( model *m ) {} virtual std::string display() { return "view"; } }; #define RELATED_CLASS(RELATED)\ typedef RELATED relatedType;\ virtual relatedType*createRelated(){\ return new relatedType(this);} class model { public: RELATED_CLASS(view) model() {} }; class otherView : public view { public: otherView( model *m ) : view(m) {} std::string display() { return "otherView"; } }; class otherModel : public model { public: RELATED_CLASS(otherView) otherModel() {} }; class control { public: control( model *m ) : m_(m), v_( m->createRelated() ) {} ~control() { delete v_; } std::string display() { return v_->display(); } model *m_; view *v_; }; int main( void ) { model m; otherModel om; model *pm = &om; control c1( &m ); control c2( &om ); control c3( pm ); std::cout << c1.display() << std::endl; std::cout << c2.display() << std::endl; std::cout << c3.display() << std::endl; }

    Read the article

  • How do I aggregate activerecord model data for a specific time period?

    - by gsiener
    I'm collecting data from a system every ~10s (this time difference varies due to communication time with networked devices). I'd like to calculate averages and sums of the stored values for this activerecord model on a daily basis. All records are stored in UTC. What's the correct way to sum and average values for, e.g., the previous day from midnight to midnight EST? I can do this in sql but don't know the "rails way" to make this calculation.

    Read the article

  • What should be done first: Code reviews or Unit tests?

    - by goldenmean
    Hello, If a developer implements code for some module and wants to get it reviewed. What should be the order : *First unit test the module after designing test cases for the module, debugging and fixing the bugs and then give the modified code for peer code review (Pros- Code to be reviewed is 'clean' to a good extent. Reduces some avoidable review comments and rework. Cons- Developer might spend large time debugging/fixing a bug which could have pointed/anticipated in peer code reviews) Or *First do the code review with peers and then go for unit testing. What are your thoughts/experience on this? I believe this approach for unit testing, code reviewing should be programming language agnostic, but it would be interesting to know otherwise(if applicable) with specific examples. -AD

    Read the article

  • Inactive users in windows server after some time according to first login instead of defining a solid expiration date

    - by smhnaji
    We want to give access to some Windows Server users so they can remotely have access to our server and download from a special folder of the server. The licenses we give to users, are time base. There should be 1 month, 2 month, ..., 1 year, ... licenses. CURRENT SITUATION (WHAT I DON'T WANT): When users are created and added to the OS, a solid expiration date is given. WHAT I WANT: Users' expiration date should be calculated automatically after first login. The user might not need his account right when purchases the license. In another words: When a license of the user we create is purchased at Jan 1st, he should use the license until Feb 1st. No matter whether he really logs in or not. He cannot come Feb 5th and begin using his license because that has expired then. What I want is that when he comes at Feb 5th and begins using, the license update until March 5th. CLARIFICATION (Update after MDMarra's comment) Working environment is Windows Server 2012. By the word 'user', I mean Native Windows Server Users. Whenever a new person purchases a license with me, I create them manually using net user command like this: net user ali pass /add /expires:2013-12-25

    Read the article

  • How do I use an Entity Framework 4 model without a real database?

    - by Ivan
    I don't need any data to be stored. I'd like an application to start, create an Entity Framework entities container based on the model I've designed but having no data records in it, then generate some data (from user input and other input sources), work with it and discard all the data on close, without propagating any data operations made with EF contect to a real database hosted on server or in a file. How do I implement such a pattern? I use Entity Framework 4 and Visual Studio 2010.

    Read the article

  • What first game did you program, and did it make you a better developer?

    - by thenonhacker
    What first game did you program? Name your game, the OS and language, and even a Website URL to get your game. Old DOS Games and Flash Games with ActionScript are allowed. Game kits are allowed, too. ...and did it make you a better developer? Programming games can be addicting, and it will bring out the best in us as we create our first game. What lessons did you learn form most? Algorithm and/or AI's? Graphics? User Interface? File Formats and Data Storage? Project and Time Management? Can you say that because you practiced programming by creating this game, you became more immersed with the programming language you used and helped you become a better developer?

    Read the article

  • why does .replace method use forward slash characters to enclose the first argument?

    - by Phillip Dodd
    I am working through a book about Javascript and have encountered the following example of code designed to replace the value of the class attribute of a table header HTML element: th.className = th.className.replace(/asc/,"dsc"); th.className = th.className.replace(/dsc/,"asc"); Why is the first parameter of .replace, the current value of th.className, enclosed in forward slashes instead of quotation marks? Why not use quotation marks to enclose both parameters, not just the second one? Thank you in advance for any help given. First time posting, apologies if I duplicated a question despite searching the site before posting.

    Read the article

  • MVC2 Data Annotation Buddy Classes Doesn't seem to work when Classes and EOM Model is in separate Project

    - by Danish Ali
    Dear All Iam new to MVC2 and having a little problem with implementing validation via buddy classes. Iam using Repository pattern with dependency injection. My Entity Object Model is in Data Layer Project and Buddy Classes are in Business Layer project and MVC 2 Project as a separate Presentation Layer Project. Can any one help me out with implementing Buddy Classes in this Architecture. Thanks and Regards Dani

    Read the article

  • Can i store a Queue in viewstate? only will store the first item i add to queue

    - by Mausimo
    Hey, as the question states i am trying to store a Queue in a viewstate (to track postbacks and refreshes to stop a form from resubmitting). Here is just the viewstate code: private Queue<string> p_tempQue { set { ViewState["sTemp"] = value; } get { return (Queue<string>)ViewState["sTemp"]; } } //BasePage constructor public BasePage() { //create a Queue of string //sTemp = new Queue(); this.Load += new EventHandler(this.Page_Load); this.Init += new EventHandler(this.Page_Init); } //In the 'page_Init' event we have created a simple hidden field by name 'hdnGuid' which is attached to the page on the first hit itself. protected void Page_Init(object sender, EventArgs e) { //initializing the hidden field //create a hidden field with a ID HiddenField hdnGuid = new HiddenField(); hdnGuid.ID = "hdnGuid"; //if it is the first time the page is loaded, create a new guid and assign it as the hidden field value if (!Page.IsPostBack) hdnGuid.Value = Guid.NewGuid().ToString(); //add the hidden field to the page Page.Form.Controls.Add(hdnGuid); } //In the 'page_Load' event we check if the hidden field value is same as the old value. In case the value is not same that means it's a 'postback' //and if the value is same then its 'refresh'. As per situation we set the 'httpContent.Items["Refresh"]' value. protected void Page_Load(object sender, EventArgs e) { if(p_tempQue != null) sTemp = p_tempQue; else sTemp = new Queue<string>(); //The hdnGuid will be set the first time page is loaded, else the hdnGuid //will be set after each time the form is submitted using javascript. //assign the hidden field currently on the page for manipulation HiddenField h1 = (HiddenField)(Page.Form.FindControl("hdnGuid")); //create an instance of the GuidClass GuidClass currentGuid = new GuidClass(); //set the GuidClass Guid property to the value of the hidden field currentGuid.Guid = h1.Value; //check to see if the Queue of strings contains the string which is the current Guid property of the GuidClass //if the are equal, then the page was refreshed if (sTemp.Contains<string>(currentGuid.Guid)) { //adds item as key/value pair to share data between an System.Web.IHttpModule interface and an System.Web.IHttpHandler interface during an HTTP request. System.Web.HttpContext.Current.Items.Add("IsRefresh", true); } //if they are not requal, the page is not refreshed else { //if the current Guid property in the GuidClass is not null or not an empty string //add the new Guid to the Queue if (!(currentGuid.Guid.Equals(null) || currentGuid.Guid.Equals(""))) sTemp.Enqueue(currentGuid.Guid); System.Web.HttpContext.Current.Items.Add("IsRefresh", false); } p_tempQue = sTemp; }

    Read the article

  • How to get the first non-null value in Java?

    - by froadie
    Is there a Java equivalent of SQL's COALESCE function? That is, is there any way to return the first non-null value of several variables? e.g. Double a = null; Double b = 4.4; Double c = null; I want to somehow have a statement that will return the first non-null value of a, b, and c - in this case, it would return b, or 4.4. (Something like the sql method - return COALESCE(a,b,c)). I know that I can do it explicitly with something like: return a != null ? a : (b != null ? b : c) But I wondered if there was any built-in, accepted function to accomplish this.

    Read the article

  • What should a conference newbie bring to make the most out of their first conference?

    - by skarnis
    I am planning to attend my first developer conference (Microsoft TechDays 2008 in Toronto). I have been looking around for suggestions so that I can prepare and make the most out of my first developer conference. Many articles make suggestions about asking questions, getting involved, being social. These are great! I am also wondering about physical items. I have seen many conference photos with most of the audience having their laptops. Are they just taking notes? Are they working on a problem during the session? Are these photos just during a break and everyone is catching up on blogs/email/outside contact? Thank you StackOverflow-ers (StackOverflow-ites?)

    Read the article

  • Mercurial - How to stop tracking modified file but keep the first version in repository.

    - by teerapap
    I create the hg repository with my source tree. I want to keep the first version of some files such as Makefile in the repository and then hg don't see it modified even through I modified it. Original problem is that ./configure usually modifies the Makefile but I don't want the build files to committed in the repository. So I want to keep only first version of configure and Makefile in the repository so that everybody who clone my repository can run ./configure by themself and not bother the repository I tried hg remove or hg forget but those are stop tracking and also delete the files in the next revision of reporitory. .hgignore doesn't do the things too. I think of hg revert everytimes I run ./configure or make but it's not efficient way. Are there any better ways?

    Read the article

  • [Python] How do I read binary pickle data first, then unpickle it?

    - by conradlee
    I'm unpickling a NetworkX object that's about 1GB in size on disk. Although I saved it in the binary format (using protocol 2), it is taking a very long time to unpickle this file---at least half an hour. The system I'm running on has plenty of system memory (128 GB), so that's not the bottleneck. I've read here that pickling can be sped up by first reading the entire file into memory, and then unpickling it (that particular thread refers to python 3.0, which I'm not using, but the point should still be true in python 2.6). How do I first read the binary file, and then unpickle it? I have tried: import cPickle as pickle f = open("big_networkx_graph.pickle","rb") bin_data = f.read() graph_data = pickle.load(bin_data) But this returns: TypeError: argument must have 'read' and 'readline' attributes Any ideas?

    Read the article

  • How can a client try to reconnect to a server after a first failed try with WCF?

    - by djerry
    Hey guys, I'm using a client - server app. When a client starts, he gets a login-screen. When the server is not up yet, the call to the server will throw an exception which i catch (EndpointNotFoundException). I show a messagebox telling the user the server is offline. When he tries to reconnect again, it will throw another exception (CommunicationObjectFaultedException), even though the server is online. When a new client starts then, he can connect to the server. But the client who attempted before, still gets the error. My question now is how can the first client login after a failed first try without having to start his program again. So i want to clear the communicationchannel of its faulted state or something like that. Thanks in advance.

    Read the article

  • adding a column dynamically and hiding the first column like jquery slider ..

    - by paul
    I have a html page with 10 columns but I don't have show all in same page instead I have to show only 4 column moreover I have to render those column on a button click call add column. What is the best approach to render 1-4 column first ? Fist column render first and on clicking button say add will render 2nd column , than 3rd and fourth. Now when i will load 5th column ...I will have to hide 1st column so that i will accommodate 4 columns but data inside that column will stay ....my limit is to show 4 column at a time and hiding leftmost .... any helpful javascript or jquery advice will be appreciated ..thanks!

    Read the article

  • How to give the First image in a gallery a different class than the rest of the images - Carrierwave

    - by ChrisBedoya
    I have a model called "Photo" that belongs to a model called "Shoe". I using Carrierwave to upload multiple images. index.html.erb <% shoes.each do |shoe| %> <div class="shoe"> <div class="gallery"> <% shoe.photos.each do |photo| %> <%= link_to image_tag(photo.photo_file.url(:thumb).to_s), photo.photo_file.url.to_s, :class => 'fancybox', :rel => 'gallery' %> <% end %> </div> </div> <% end %> Outputs this: <div class="shoe"> <div class="gallery"> <a class="fancybox" href="../nike-kd-6-meteorology-2.jpg" rel="gallery"> <img src="../thumb_nike-kd-6-meteorology-2.jpg"> </a> <a class="fancybox" href="../nike-kd-6-meteorology-2.jpg" rel="gallery"> <img src="../thumb_nike-kd-6-meteorology-2.jpg"> </a> <a class="fancybox" href="../nike-kd-6-meteorology-2.jpg" rel="gallery"> <img src="../thumb_nike-kd-6-meteorology-2.jpg"> </a> </div> </div> But I want the first image of each gallery to be able to have its own class and the rest of the images to have their own class. Something like this: <a class="firstclass" href="../nike-kd-6-meteorology-2.jpg" rel="gallery"> <img src="../thumb_nike-kd-6-meteorology-2.jpg"> </a> <a class="fancybox" href="../nike-kd-6-meteorology-2.jpg" rel="gallery"> <img src="../thumb_nike-kd-6-meteorology-2.jpg"> </a> <a class="fancybox" href="../nike-kd-6-meteorology-2.jpg" rel="gallery"> <img src="../thumb_nike-kd-6-meteorology-2.jpg"> </a> How can I do this? Also I want each gallery to have its own unique id but when I try to add this: :rel => 'gallery<%= shoe.id %>' I get a Syntax error. Thanks.

    Read the article

  • Which Happens First? Anyone Know Exactly How The Apache Server Will Handle This Request?

    - by user310594
    Hello, To keep things simple, please allow the "assumption" that some code requires the use of a full URL, even though the domain is on the same server, i.e. a simple file path cannot be used. TCP/IP?? Question: If a form action target = "http://this-full-URL.com/postdata" (for example) and that URL is also on the same server, then which happens first? A) Data is sent "out onto the web", and then returns to the same server, or B) Before sending any (possibly sensitive) data, the server (Linux, Apache, PHP), first "discovers" the target address is local, so (clearly) no data is sent over the net? Thank you.

    Read the article

  • How Do I Remove The First 4 Characters From A String If It Matches A Pattern In Ruby

    - by James
    I have the following string: "h3. My Title Goes Here" I basically want to remove the first 4 characters from the string so that I just get back: "My Title Goes Here". The thing is I am iterating over an array of strings and not all have the h3. part in front so I can't just ditch the first 4 characters blindly. I have checked the docs and the closest think I could find was chomp, but that only works for the end of a string. Right now I am doing this: "h3. My Title Goes Here".reverse.chomp(" .3h").reverse This gives me my desired output, but there has to be a better way right? I mean I don't want to reverse a string twice for no reason. I am new to programming so I might have missed something obvious, but I didn't see the opposite of chomp anywhere in the docs. Is there another method that will work? Thanks!

    Read the article

< Previous Page | 155 156 157 158 159 160 161 162 163 164 165 166  | Next Page >