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  • Dynamically calling functions - Python

    - by RadiantHex
    Hi folks, I have a list of functions... e.g. def filter_bunnies(pets): ... def filter_turtles(pets): ... def filter_narwhals(pets): ... Is there a way to call these functions by using a string representing their name? e.g. 'filter_bunnies', 'filter_turtles', 'filter_narwhals'

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  • customizing Django look and feel in Python

    - by user248237
    I am learning Django and got it to work with wsgi. I'm following the tutorial here: http://docs.djangoproject.com/en/1.1/intro/tutorial01/ My question is: how can I customize the look and feel of Django? Is there a repository of templates that "look good", kind of like there are for Wordpress, that I can start from? I find the tutorial counterintuitive in that it goes immediately toward customizing the admin page of Django, rather than the main pages visible to users of the site. Is there an example of a "typical" Django site, with a decent template, that I can look at and built on/modify? The polls application is again not very representative since it's so specialized. any references on this would be greatly appreciated. thanks.

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  • regular expression not behaving as expected - Python

    - by philippe
    I have the following function which is supposed to read a .html file and search for <input> tags, and inject a <input type='hidden' > tag into the string to be shown into the page. However, that condition is never met:( e.g the if statement is never executed. ) What's wrong with my regex? def print_choose( params, name ): filename = path + name f = open( filename, 'r' ) records = f.readlines() print "Content-Type: text/html" print page = "" flag = True for record in records: if re.match( '<input*', str(record) ) != None: print record page += record page += "<input type='hidden' name='pagename' value='psychology' />" else: page += record print page Thank you

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  • Python stdout, \r progress bar and sshd with Putty not updating regularly

    - by Kyle MacFarlane
    I have a dead simple progress "bar" using something like the following: import sys from time import sleep current = 0 limit = 50 while current <= limit: sys.stdout.write('\rSynced %s/%s orders' % (current, limit)) current_order += 1 sleep(1) Works fine, except over ssh with Putty. Putty only updates every 3 minutes or if a line ends with \n. Is this a Putty setting, sshd_config, or can I code around it?

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  • Including non-Python files with setup.py

    - by cool-RR
    How do I make setup.py include a file that isn't part of the code? (Specifically, it's a license file, but it could be any other thing.) I want to be able to control the location of the file. In the original source folder, the file is in the root of the package. (i.e. on the same level as the topmost __init__.py.) I want it to stay exactly there when the package is installed, regardless of operating system. How do I do that?

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  • How to parse a directory tree in python?

    - by chutsu
    I have a directory called "notes" within the notes I have categories which are named "science", "maths" ... within those folder are sub-categories, such as "Quantum Mechanics", "Linear Algebra". ./notes --> ./notes/maths ------> ./notes/maths/linear_algebra --> ./notes/physics/ ------> ./notes/physics/quantum_mechanics My problem is that I don't know how to put the categories and subcategories into TWO SEPARATE list/array.

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  • Python and .exe files, another way

    - by Sorush Rabiee
    How to build exe files (compatible with win32)? please don't refer to py2exe. that is blocked service in IRI. for Iranians only: do you know how to download something (like py2exe) from blocked sites? especially from sourceforge ande fontforge?

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  • Skip subdirectory in python import

    - by jstaab
    Ok, so I'm trying to change this: app/ - lib.py - models.py - blah.py Into this: app/ - __init__.py - lib.py - models/ - __init__.py - user.py - account.py - banana.py - blah.py And still be able to import my models using from app.models import User rather than having to change it to from app.models.user import User all over the place. Basically, I want everything to treat the package as a single module, but be able to navigate the code in separate files for development ease. The reason I can't do something like add for file in __all__: from file import * into init.py is I have circular references between the model files. A fix I don't want is to import those models from within the functions that use them. But that's super ugly. Let me give you an example: user.py ... from app.models import Banana ... banana.py ... from app.models import User ... I wrote a quick pre-processing script that grabs all the files, re-writes them to put imports at the top, and puts it into models.py, but that's hardly an improvement, since now my stack traces don't show the line number I actually need to change. Any ideas? I always though init was probably magical but now that I dig into it, I can't find anything that lets me provide myself this really simple convenience.

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  • In Python, are there builtin functions for elementwise map of boolean operators over tuples of lists

    - by bshanks
    For example, if you have n lists of bools of the same length, then elementwise boolean AND should return another list of that length that has True in those positions where all the input lists have True, and False everywhere else. It's pretty easy to write, i just would prefer to use a builtin if one exists (for the sake of standardization/readability). Here's an implementation of elementwise AND: def eAnd(*args): return [all(tuple) for tuple in zip(*args)] example usage: >>> eAnd([True, False, True, False, True], [True, True, False, False, True], [True, True, False, False, True]) [True, False, False, False, True] thx

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  • Finding most recently edited file in python

    - by zztpp5521
    I have a set of folders, and I want to be able to run a function that will find the most recently edited file and tell me the name of the file and the folder it is in. Folder layout: root Folder A File A File B Folder B File C File D etc... Any tips to get me started as i've hit a bit of a wall.

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  • python need some help

    - by maxt0r
    hi i have my codes i have to do a module def subjects but i cant figure out how can u help me thanks. class Enrol: def init(self, dir): def readFiles(, dir, files): for file in files: if file == "classes.txt": class_list = readtable(dir+"/"+file) for item in class_list: Enrol.class_info_dict[item[0]] = item[1:] if item[1] in Enrol.classes_dict: Enrol.classes_dict[item[1]].append(item[0]) else: Enrol.classes_dict[item[1]] = [item[0]] elif file == "subjects.txt": subject_list = readtable(dir+"/"+file) for item in subject_list: Enrol.subjects_dict[item[0]] = item[1] elif file == "venues.txt": venue_list = readtable(dir+"/"+file) for item in venue_list: Enrol.venues_dict[item[0]] = item[1:] elif file.endswith('.roll'): roll_list = readlines(dir+"/"+file) file = os.path.splitext(file)[0] Enrol.class_roll_dict[file] = roll_list for item in roll_list: if item in Enrol.enrolled_dict: Enrol.enrolled_dict[item].append(file) else: Enrol.enrolled_dict[item] = [file] try: os.walk(dir, _readFiles, None) except: print "directory not properly been recognise error" def subjects(what should i write here??): for name in suject_list: print name, out put should look like import enrol e = enrol.Enrol("/path/to/data") e.subjects() ['bw101', 'bw110', 'bw232', 'bw290', 'bw660']

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  • Get class of caller's method (via inspect) in Python

    - by Slava Vishnyakov
    Is it possible to get reference to class B in this example? class A(object): pass class B(A): def test(self): test2() class C(B): pass import inspect def test2(): frame = inspect.currentframe().f_back cls = frame.[?something here?] # cls here should == B (class) c = C() c.test() Basically, C is child of B, B is child of A. Then we create c of type C. Then the call to c.test() actually calls B.test() (via inheritance), which calls to test2(). test2() can get the parent frame frame; code reference to method via frame.f_code; self via frame.f_locals['self']; but type(frame.f_locals['self']) is C (of course), but not B, where method is defined. Any way to get B?

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  • How to lazy load a data structure (python)

    - by Anton Geraschenko
    I have some way of building a data structure (out of some file contents, say): def loadfile(FILE): return # some data structure created from the contents of FILE So I can do things like puppies = loadfile("puppies.csv") # wait for loadfile to work kitties = loadfile("kitties.csv") # wait some more print len(puppies) print puppies[32] In the above example, I wasted a bunch of time actually reading kitties.csv and creating a data structure that I never used. I'd like to avoid that waste without constantly checking if not kitties whenever I want to do something. I'd like to be able to do puppies = lazyload("puppies.csv") # instant kitties = lazyload("kitties.csv") # instant print len(puppies) # wait for loadfile print puppies[32] So if I don't ever try to do anything with kitties, loadfile("kitties.csv") never gets called. Is there some standard way to do this? After playing around with it for a bit, I produced the following solution, which appears to work correctly and is quite brief. Are there some alternatives? Are there drawbacks to using this approach that I should keep in mind? class lazyload: def __init__(self,FILE): self.FILE = FILE self.F = None def __getattr__(self,name): if not self.F: print "loading %s" % self.FILE self.F = loadfile(self.FILE) return object.__getattribute__(self.F, name) What might be even better is if something like this worked: class lazyload: def __init__(self,FILE): self.FILE = FILE def __getattr__(self,name): self = loadfile(self.FILE) # this never gets called again # since self is no longer a # lazyload instance return object.__getattribute__(self, name) But this doesn't work because self is local. It actually ends up calling loadfile every time you do anything.

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  • Python script to delete old SVN files lacks permission

    - by Rosarch
    I'm trying to delete old SVN files from directory tree. shutil.rmtree and os.unlink raise WindowsErrors, because the script doesn't have permissions to delete them. How can I get around that? Here is the script: # Delete all files of a certain type from a direcotry import os import shutil dir = "c:\\" verbosity = 0; def printCleanMsg(dir_path): if verbosity: print "Cleaning %s\n" % dir_path def cleandir(dir_path): printCleanMsg(dir_path) toDelete = [] dirwalk = os.walk(dir_path) for root, dirs, files in dirwalk: printCleanMsg(root) toDelete.extend([root + os.sep + dir for dir in dirs if '.svn' == dir]) toDelete.extend([root + os.sep + file for file in files if 'svn' in file]) print "Items to be deleted:" for candidate in toDelete: print candidate print "Delete all %d items? [y|n]" % len(toDelete) choice = raw_input() if choice == 'y': deleted = 0 for filedir in toDelete: if os.path.exists(filedir): # could have been deleted already by rmtree try: if os.path.isdir(filedir): shutil.rmtree(filedir) else: os.unlink(filedir) deleted += 1 except WindowsError: print "WindowsError: Couldn't delete '%s'" % filedir print "\nDeleted %d/%d files." % (deleted, len(toDelete)) exit() if __name__ == "__main__": cleandir(dir) Not a single file is able to be deleted. What am I doing wrong?

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  • How to do elif statments more elegantly if appending to array in python

    - by user1741339
    I am trying to do a more elegant version of this code. This just basically appends a string to categorynumber depending on the number. Would appreciate any help. number = [100,150,200,500] categoryNumber = [] for i in range (0,len(number)): if (number [i] >=1000): categoryNumber.append('number > 1000') elif (number [i] >=200): categoryNumber.append('200 < number < 300') elif (number [i] >=100): categoryNumber.append('100 < number < 200') elif (number [i] >=50): categoryNumber.append('50 < number < 100') elif (number [i] < 50): categoryNumber.append('number < 50') for i in range(0,len(categoryNumber)): print i

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  • Accessing items from a dictionary using pickle efficiently in Python

    - by user248237
    I have a large dictionary mapping keys (which are strings) to objects. I pickled this large dictionary and at certain times I want to pull out only a handful of entries from it. The dictionary has usually thousands of entries total. When I load the dictionary using pickle, as follows: from cPickle import * # my dictionary from pickle, containing thousands of entries mydict = open(load('mypickle.pickle')) # accessing only handful of entries here for entry in relevant_entries: # find relevant entry value = mydict[entry] I notice that it can take up to 3-4 seconds to load the entire pickle, which I don't need, since I access only a tiny subset of the dictionary entries later on (shown above.) How can I make it so pickle only loads those entries that I have from the dictionary, to make this faster? Thanks.

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