How would I write a regular expression (C#) which will check a given string to see if any of its characters are characters OTHER than the following:
a-z
A-Z
Æ æ Å å Ø ø - '
I have two table
First table
BID Town
1 ABC
2 ABC2
3 ABC
Second Table
PID BID AmountFirst AmountSecond AmountThird Minority
1__ 1___ 1000_____ 1000________ 1000_____ SC
2__ 2___ 2000_____ 1000_______ 2000_____ ST
3__ 3___ 1000____ 1000_______ 1000_______ SC
BID is foreign key in Second table.
I want sum AmountFirst + AmountSecond +AmountThird for individualTown
e.g for ABC town answer should be : 6000 (summation of PID 1 and PID 2)
I want Linq query for this..Please help
i have a term 1/temperatoA,2/CelcieusB!23/33/44,55/66/77 and i want only extract word temperatoA and CelcieusB, i have this regular expression (\d+/(\w+),?)*!
but i get only 1/temperatoA,2/CelcieusB!
why!!! please
I have the following line of code which works well:
$("a.grouped_elements[href$=.jpg],a.grouped_elements[href$=.png],a.grouped_elements[href$=.gif]").fancybox();
Problem is, if the href is .JPG it doesn't work it only works with .jpg. How can I make the above case insensitive so either all caps or no caps or a mix all match for the file extension?
Thanks
Hi, how can change only the last letter of any word of a string with regular expressions?
I use mb_strtolower() for change strings from upper to lower in Greek language and I have problem with final 's'.
I'm rubbish at Regular Expressions, really!
What I'd like is to split a string containing a CCS property value into an array of [string,value,unit].
For example: if I supplied the .split() method with 1px it'd return ["1px",1,"px"]. If I were to supply, similarly, 10% it'd return ["10%",10,"%"].
Can this be done?
I appreciate all your help!
I'm trying to use a regular expression as below:
preg_match_all('|<table.*</table>|',$html,$matches, PREG_SET_ORDER);
But this is not working, and I think the problem is the new line inside the string $html.
Could someone tell me a work around?
Hy i have to test if a string begins with 00 or with +
Say i have the string 0090 or +41 if the string begins with 0090 return true, elseif string begins with +90 replace the + with 00 else return false
The last two digits can be from 0-9
How do i do that in php?
I hope i could explain my question clear?
I've seen so many misuses of RegExp, I don't really like it :)
I have string (as a result of two str_replaces) that might look something like this:
.?This iš my ".stRiNg."!
|
V
--this-is-my---string---
Is there any way better than
$string = trim(preg_replace('/[-]+/u','-', $string),'-');
to get:
this-is-my-string
?
How can I express "not preceded by" in a Java regular expression? For example I would like to search for ":" but only when it is not directly preceded by "\". How can I do this?
I have a static library that is compiled with gcc 3.4.2. I am building a shared library that relies on this static lib. I will be building this shared library (.so) with gcc 4.2.2. I was wondering what are the potential pitfalls of using the 3.4.2 static library in a gcc 4.2.2 shared library?
I have the following line of code which works well:
$("a.grouped_elements[href$=.jpg],a.grouped_elements[href$=.png],a.grouped_elements[href$=.gif]").fancybox();
Problem is, if the href is .JPG it doesn't work it only works with .jpg. How can I make the above case insensative so either all caps or no caps or a mix all match for the file extenstion?
Thanks
I have a string "one two 9three 52eight four", so I only want to get "one two four", because "three" starts with "9" and "eight" starts with "52".
I tried:
"(?!\d)\w+"
but it's still taking the "three" and "eight". I don't want it.
I'm starting to learn reg exp and i'm just curious to reg exp used by the rest of the people so i can have a thread to look at and learn from. I had started with the eight listed here, i tried to play a little big with firebug and some tutorials and used some in my websites, but i'd like to know some from more experienced people. Thanks!
This code is being used to parse email, it's stored as a table in a mySQL database. I believe it's PHP code. What does the (.+) do?
/A new order has been successfully placed through(.+)Name:(.+)Company:(.+)Email:(.+)Address 1(.+)Order ID:(.+)Date:(.+)Payment Type:(.+)Order Status:(\s*)Accepted(.*)\n(.+)\$([\d\.]+)\s+X/si
Thanks, super-brainiacs!
Got this function for ammending the query string and was wondering what the replacement part of the pre_replace meant (ie- $1$2$4).
function add_querystring_var($url, $key, $value) {
$url = preg_replace('/(.*)(\?|&)' . $key . '=[^&]+?(&)(.*)/i', '$1$2$4', $url . '&');
$url = substr($url, 0, -1);
if (strpos($url, '?') === false) {
return ($url . '?' . $key . '=' . $value);
} else {
return ($url . '&' . $key . '=' . $value);
}
}
Not too familiar with regular expression stuff. I get the various parts to preg_replace but not 100% about the use of '$1$2$4' in the replacement part.
while($row = mysql_fetch_row($result)){
preg_match('#<span id="lblNumerZgloszenia" style="font-weight:bold;font-style:italic;">([^<]*)<\/span>#',$row[1],$matches);
$query2 = 'UPDATE content_pl SET kategoria_data='.$matches[1].' WHERE id='.$row[0].';';
mysql_query($query2);
}
I'm doing this preg_match to get the span contents into $matches array.
When I do a print_r($matches), it shows the right results but when I use $matches[1], it browser tells me that there is no such index.
sed "s/\(.*\)/\t\1/" $filename > $sedTmpFile && mv $sedTmpFile $filename
I am expecting this sed script to insert a tab in font of every line in $filename however it is not. For some reason it is inserting a t instead.. Strange..
Hello!
I have this database table:
id | url
-----------------------------------------
1 | http://stackoverflow.com/
2 | http://www.google.com
3 | http://example.com/somepage
4 | https://another.net?id=88
5 | http://hello.org/index.php?hello=2
6 | http://google.com?q=hello+world
I need to search all fields, where URL belongs to a certain host.
For example, if I give the query 'google.com', it will return rows 2 and 6 (www is ignored).
I get the host using PHP parse_url() function.
How this SQL query would look like?
My pattern looks something like
<xxxx location="file path/level1/level2" xxxx some="xxx">
I am only interested in the part in quotes assigned to location. Shouldn't it be as easy as below without the greedy switch? Does not seem to work :(
/.*location="(.*)".*/
I would like to parse this Gstring with groovy :
Format type : CodeClass, Name, Accession, Count.
def txt = """ <Lane_Attributes>
ID,1
FovCount,600
FovCounted,598
...
</Lane_Attributes> """
And get a map like :
Map = [ID:1, FovCount:600, FovCounted:598]
How can I :
- extract text between tag and ?,
- and convert to a map ?
Let's say I have a string like so:
$file = 'widget-widget-newsletter.php';
I want to use preg_replace() to remove the prefix widget- and to remove the suffix .php . Is it possible to use one regular expression to achieve all this?
The resulting string should be widget-newsletter.
So I need to get value false or true if string contains not only letters of all european and east alphabets and " "(space) and "-" minus. How to do such thing with some $a string?