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  • How to configure IIS7 to Redirect member of An active Directory group to static page

    - by user1759075
    On IIS, we have disabled Anonymous authentication and enabled Windows Authentication What we need is to only allow users who are members of an Active Directory security group to access the Access Point at all. All other users should be directed to a static web page that will give them instructions on how to request access. By adding the security group to the website permissions, and removing the \Users group, we have almost achieved this. Users in the group are allowed through, those not in the group are asked for a (Windows) username and password. Instead of requesting the username and password, we want IIS to redirect them to the static page. Please advise me on how can this be done.

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  • Empty files generated from running `mysqldump` using PHP

    - by alex
    I keep getting empty files generated from running $command = 'mysqldump --opt -h localhost -u username -p \'password\' dbname > \'backup 2009-04-15 09-57-13.sql\''; command($command); Anyone know what might be causing this? My password has strange characters in it, but works fine with connecting to the db. I've ran exec($command, $return) and outputted the $return array and it is finding the command. I've also ran it with mysqldump > file.sql and the file contains Usage: mysqldump [OPTIONS] database [tables] OR mysqldump [OPTIONS] --databases [OPTIONS] DB1 [DB2 DB3...] OR mysqldump [OPTIONS] --all-databases [OPTIONS] For more options, use mysqldump --help So it would seem like the command is working.

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  • php/mySQL error: mysql_num_rows(): supplied argument is not a valid MySQL result

    - by Michael Robinson
    I'm trying to INSERT INTO a mySQL database and I'm getting this error on: if (mysql_num_rows($login) == 1){ Here is the php, The php does add the user to the database. I can't figure it out. <? session_start(); require("config.php"); $u = $_GET['username']; $pw = $_GET['password']; $pwh = $_GET['passwordhint']; $em = $_GET['email']; $zc = $_GET['zipcode']; $check = "INSERT INTO family (loginName, email, password, passwordhint, location) VALUES ('$u', '$pw', '$pwh', '$em', '$zc')"; $login = mysql_query($check, $link) or die(mysql_error()); if (mysql_num_rows($login) == 1) { $row = mysql_fetch_assoc($login); echo 'Yes';exit; } else { echo 'No';exit; } mysql_close($link); ?> Thanks,

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  • (database) im trying to create a form in access 2007 with 2 drop down boxes to view a report by state or name

    - by jeff orris
    im an intern at a database mngmt company and the boss is training me in access...i took the access tutorials and were definitely not enough info involved to do a what seems a simple task.my problem is this: i have a simple table with contact info with 16 colums (Local_Utility, Requested_User_Type, First_Name, Last_Name, Address 1, Address 2, Country, State, City, Zip, Phone_Number, Username\Email, Password, Confirm Password, and Parcel_Number), with 6 rows of names (keep in mind this is just a test to help me from the boss) I created a form and with 2 drop down boxes (Last Name and State) and im trying to create a view button to view an individual report for a query i made for just simple contact info with 6 colums (Last_Name, First_Name, Address1, City, State, and Phone_Number) Problem1 is that i can view the query with the view by name or state button but cant view a simple individual report from the query using the button Problem2 is that for criteria on the query i put Forms!frmMyparamForm!txtMyStateParamField for the state drop box it works, but when i use Forms!frmMyparamForm!txtMyNameParamField it doesnt and that annoying parameter box pops up Problem3 is that after i close the query, all the states and names in my dropdown box on the form disappear Im a beginner at this please help me

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  • How can I make an iPhone OS 2.1 project with the new Xcode?

    - by Thanks
    Problem: I want to make iPhone OS 2.1 apps, but Xcode now always makes automatically an iPhone OS 3.0 project. I forgot about it and now I have an app which I want to test on my iPod touch, but I need to build OS 2.1. Is there a way to get this working? The dropdown from top left in Xcode only offers to build for OS 3.0 device. However, when I open old projects, there I have OS 2.1 available.

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  • servlet authentication and further reference to the credentials

    - by user553592
    What I got so far: It all begins with an HTML form which prompts the user for a username and password. From there it post the acquired user/pass to a servlet, GateKeeper. GateKeeper determines if the user/pass combination match any records in the MySQL database. Here is the sql I use: SELECT id FROM Users WHERE username='?' AND password=MD5('?') where the ? indicate information provided the previous HTML form. What I need now: I need some way to store the username and id of the record in the database. GateKeeper redirects the user to a control panel upon success. Therefore, I need a method to reference the username to display simple greetings, etc and also the id so it eliminates unnecessary calls to the database. The control panel may make AJAX calls to Servlets that preform some sort of task to the MySQL database.

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  • how toaccess the attributes in another form? c#

    - by Chelsea_cole
    I have a problem in a same namespace: public partial class frmForm1 : Form // Form1 { public class Account { public string Username; public string Password; } public class ListAcc { public static int count = 0; private static List<Account> UserList; public static List<Account> Data() { return UserList; } } } public partial class frmForm2 : Form // Form2 { private void button2_Click(object sender, EventArgs e) { frmForm1.Account A; string m = frmForm1.ListAcc<A>.[0].Username; //ERROR } } How could i access the attributes (Username, Password...) in frmForm1? Someone help me? Thanks!

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  • jquery ajax sucess - possible to return JSON instead of string?

    - by Haroldo
    To return an error from a $.ajax call, there's gotta be a better way than echoing an error in the ajax.php file and then trimming it! this seems very clumsy and in-robust: success: function(e){ var e = trim(e); if(e == 'SUCCESS') {alert('your password has been changed!');} if(e == 'ERROR1') {alert('please fill in all inputs!');} if(e == 'ERROR2') {alert('password incorrect!');} if(e == 'ERROR3') {alert('change failed!');} } what should i be doing instead?!

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  • How to specify "PG-USERNAME" in pg_ident.conf so that it'll match any database user ?

    - by felace
    I need to restrict a specific unix user so that it can login with only a few select postgres usernames (with password prompt), but allowing every other user to use whatever pg username they want. Assuming restrUnixUser is the unix user name and restrUser is one of the postgres users it may use, and AllowedDB is the only database they should connect to : pg_hba.conf : local AllowedDB restrUser password local all restrUser reject local all all ident map=exceptrestrUser And pg_ident.conf : exceptrestrUser /^(?!restrUnixUser).*$ user1 exceptrestrUser /^(?!restrUnixUser).*$ user2 exceptrestrUser /^(?!restrUnixUser).*$ postgres does what I exactly want to do right now, however, I'll probably add a lot more users so I wonder if there is something like mapname unixuserpattern allpgusers that'll match with whatever username used to login by any unix user matching the pattern.

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  • How to escalate database user permissions to create new databases?

    - by steelaz
    I created new cPanel account, using this account created new database, new database user and connected user to database, simple stuff. Now, I want this particular user to be able to create new databases, how can I escalate this database user's permissions to allow creating new databases? I still want these databases to be associated with cPanel account, is adding account name prefix (account_) to database name enough to associate it with that cPanel account? Edit: Whoops, forgot to mention - database is MySQL.

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  • Implementing prompts in text-input

    - by AntonAL
    Hi, I have a form with some text-inputs: login, password. If user sees this form the first time, input-texts should "contain" prompts, like "enter login", "enter password". If user clicks text-input, it's prompt should disappear to allow typing. I have seen various examples, that uses background image with prerendered text on it. Those images are appearing with following jQuery: $("form > :text").focus(function(){ // hide image }).blur(function(){ // show image, if text-input is still empty if ( $(this).val() == "" ) // show image with prompt }); This approach has following problems: localization is impossible need to pre-render images for various textual prompts overhead with loading images How do you overcomes such a problems ?

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  • Error with connecting ftp through php ...

    - by Holicreature
    Hi, I'm trying to connect to my server using php script to upload some files... But it doesn't connect... I dont know what is the error... I'm sure that ftp is enable, i checked it through php_info() What may be the error... <?php error_reporting(E_ALL); $ftp_server = "server.com"; //address of ftp server (leave out ftp://) $ftp_user_name = "Username"; // Username $ftp_user_pass = "Password"; // Password $conn_id = ftp_connect($ftp_server); // set up basic connection $login_result = ftp_login($conn_id,$ftp_user_name,$ftp_user_pass); if ($login_result = ftp_login($conn_id,$ftp_user_name,$ftp_user_pass)) { echo "Connected as ,$ftp_user_name,$ftp_user_pass \n"; } else { echo "Couldn't connect \n"; } ..... ..... .... .... ftp_close($conn_id); // close the FTP stream ?>

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  • $.ajax + authentication + `@` in username

    - by Koning Baard XIV
    I am creating a web app which uses jQuery to authenticate: $.ajax({ url: "/session/create?format=json", type: "GET", dataType: "json", cache: false, username: $("#signin-email").val(), password: $("#signin-password").val(), success: function(data) { if(data.success) { success = true; } } }); The problem is that the code only makes the AJAX-request when the username does not include things like an @, which is required in my app. Can anyone help me with how I can do this? I do not mind changing the back-end a little bit, but requiring users to have an @-less email is not an option. Oh, my back-end is a Ruby-on-Rails app

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  • Configuring jdbc-pool (tomcat 7)

    - by john
    i'm having some problems with tomcat 7 for configuring jdbc-pool : i`ve tried to follow this example: http://www.tomcatexpert.com/blog/2010/04/01/configuring-jdbc-pool-high-concurrency so i have: conf/server.xml <GlobalNamingResources> <Resource type="javax.sql.DataSource" name="jdbc/DB" factory="org.apache.tomcat.jdbc.pool.DataSourceFactory" driverClassName="com.mysql.jdbc.Driver" url="jdbc:mysql://localhost:3306/mydb" username="user" password="password" /> </GlobalNamingResources> conf/context.xml <Context> <ResourceLink type="javax.sql.DataSource" name="jdbc/LocalDB" global="jdbc/DB" /> <Context> and when i try to do this: Context initContext = new InitialContext(); Context envContext = (Context)initContext.lookup("java:/comp/env"); DataSource datasource = (DataSource)envContext.lookup("jdbc/LocalDB"); Connection con = datasource.getConnection(); i keep getting this error: javax.naming.NameNotFoundException: Name jdbc is not bound in this Context at org.apache.naming.NamingContext.lookup(NamingContext.java:803) at org.apache.naming.NamingContext.lookup(NamingContext.java:159) pls help tnx

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  • cant get ajax response (JSON) to call 'success' function?

    - by Haroldo
    for some reason the success function isnt being called? javscript: $.ajax({ type: 'POST', url: 'http://localhost/hf_latest_desktop/st_pages/user_area/acc_buttons/pass_change/pass_change_ajax.php', data: data, dataType: 'json', success: function(e){ console.log(e); if(e.status == 'success'){ alert('your password has been changed!'); } if(e.status == 'error1'){ alert('please fill in all inputs!'); } if(e.status == 'error2'){ alert('password incorrect!'); } if(e.status == 'error3'){ alert('change failed!'); } } }); php file ajax is calling to: <?php session_start(); session_cache_limiter('nocache'); header('Expires: ' . gmdate('r', 0)); header('Content-type: application/json'); $status = 'error1'; //for sake of example ?> {'status':'<?php echo $status; ?>'}

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  • require user to login in at login screen before giving access to iPhone app that accesses secure web

    - by MikeN
    On iPhone, how do I show a login screen to get username and password before giving access to iPhone app? Also, does the iPhone store a cookie to the secure website like a web browser? I was thinking of giving users to my website a long API key to store in the settings of their iPhone instead of asking them to login with a username/password (seems to be the Slicehost iPhone app approach.) Which is the best way to get a user to login securely? I have full control over the design of the iPhone app and website so have a lot of flexibility.

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  • Use variables entered in login page usable in multiple pages?

    - by deception1
    I have a Login page that captures User input like this. MD5calc ss = new DBCon.MD5calc(); string gs = ss.CalculateMD5Hash(password.Password); int unitID = Convert.ToInt32(Unit_ID.Text); logBO.UnitID = unitID; logBO.UserID = User_name.Text; logBO.UserPass = gs; How would i make them assignable to any other page i created.My Common sense says that creating a static class would be enough,but will it?If i do create a static class where would i put it and how would i call it?I actually need those variable to use in my Sql Stored procedures.

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  • Interpreter more strict

    - by pacopepe
    Hi, Today, i lost a lot of time fixing a stupid error in my code. Very simplified, the problem was this: def f(): return 2 2 == f I forgot to write the parenthesis in the sentence, so I compared a pointer function with a number. Ok, my question: Is there any way to change the interpreter to be more stricted with the code? Show more warnings for example... Thanks ^^

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  • phpMySql connection

    - by Eiriko Pedroza
    PL = VB.net Issue: format of the initialization string does not conform to specification starting at index 17 connection string: objconn.ConnectionString = ("server=" & txtServer.Text & ";" _ & "user id=" & "'" & txtUserId.Text & ";" _ & "password=" & txtPassword.Text & ";" _ & "database=try") Try objconn.Open() MsgBox("Connected") objconn.Close() Catch ex As Exception MsgBox(ex.ToString) End Try -objconn is declared as new mysqlconnection every time I run the application and try to login, i keep on receiving this error message, I already double checked my line of connection string. im using 'localhost' as server and 'root' as username, password is blank. thank you in advance for your response

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  • Struts2 linking actions

    - by SonOfTheEARTh
    I am working on the Login module of my Struts2 app. I have created the Login Page, and a home Page(which is rendered by Login.action). Now i want to add another feature, forgot password which after performing its business must call the Login.action so that the user need not have to Login explicitly. what should i code and where so that as soon as the ForgotPassword.action finishes its work it passes control to Login.action.

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  • Is it easier to create a chat client using java or PHP?

    - by Mendy
    first off, my goal: Create a chat client that requires the user to log in with a password. Would it be easier to create it with just HTML an PHP or java? EDIT: Sorry, I didn't mention. I have some experience in javascript. I'm afraid that is all. I could and would learn another language. So I want to know which language would be better to learn for this project? also, for the username and password login I'm guessing I would need some mySQL knowledge? Thanks.

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  • Select value from database and store into a temporary variable

    - by user1616230
    I want to select a stored value from database and then put it into a temporary variable. For example, I have a column called category, one value under it is m, so I want to select this m value from the database, let's say from a table of a database called user_info. Then I want to put it into a variable, let's name it $res. After that, I want to do some condition stuff, such as if $res=="m", Can anyone help me write a simple structure here? Here is the code: <?php $sql = "Select category FROM user_info WHERE user_name = '" .$_SESSION['username']."' and password = '".$_SESSION['password']."'"; $res = mysql_query($sql); if($res == "a"){ include('MPIncomeStrategy.php'); } if($res == "b"){ include('MPIncomeStrategy.php'); } But it seems that the code is not able to detect $res =="category value in database". Did I just use the wrong way to store the category value?

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