Search Results

Search found 48396 results on 1936 pages for 'first person shooter'.

Page 197/1936 | < Previous Page | 193 194 195 196 197 198 199 200 201 202 203 204  | Next Page >

  • ASP.NET MVC 2 "value" in DataAnnotation attribute passed is null, when incorrect date is submitted.

    - by goldenelf2
    Hello to all! This is my first question here on stack overflow. i need help on a problem i encountered during an ASP.NET MVC2 project i am currently working on. I should note that I'm relatively new to MVC design, so pls bear my ignorance. Here goes : I have a regular form on which various details about a person are shown. One of them is "Date of Birth". My view is like this <div class="form-items"> <%: Html.Label("DateOfBirth", "Date of Birth:") %> <%: Html.EditorFor(m => m.DateOfBirth) %> <%: Html.ValidationMessageFor(m => m.DateOfBirth) %> </div> I'm using an editor template i found, to show only the date correctly : <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<System.DateTime?>"%> <%= Html.TextBox("", (Model.HasValue ? Model.Value.ToShortDateString() : string.Empty))%> I used LinqToSql designer to create my model from an sql database. In order to do some validation i made a partial class Person to extend the one created by the designer (under the same namespace) : [MetadataType(typeof(IPerson))] public partial class Person : IPerson { //To create buddy class } public interface IPerson { [Required(ErrorMessage="Please enter a name")] string Name { get; set; } [Required(ErrorMessage="Please enter a surname")] string Surname { get; set; } [Birthday] DateTime? DateOfBirth { get; set; } [Email(ErrorMessage="Please enter a valid email")] string Email { get; set; } } I want to make sure that a correct date is entered. So i created a custom DataAnnotation attribute in order to validate the date : public class BirthdayAttribute : ValidationAttribute { private const string _errorMessage = "Please enter a valid date"; public BirthdayAttribute() : base(_errorMessage) { } public override bool IsValid(object value) { if (value == null) { return true; } DateTime temp; bool result = DateTime.TryParse(value.ToString(), out temp); return result; } } Well, my problem is this. Once i enter an incorrect date in the DateOfBirth field then no custom message is displayed even if use the attribute like [Birthday(ErrorMessage=".....")]. The message displayed is the one returned from the db ie "The value '32/4/1967' is not valid for DateOfBirth.". I tried to enter some break points around the code, and found out that the "value" in attribute is always null when the date is incorrect, but always gets a value if the date is in correct format. The same ( value == null) is passed also in the code generated by the designer. This thing is driving me nuts. Please can anyone help me deal with this? Also if someone can tell me where exactly is the point of entry from the view to the database. Is it related to the model binder? because i wanted to check exactly what value is passed once i press the "submit" button. Thank you.

    Read the article

  • ASP.NET XML as Datasource error

    - by nekko
    Hello I am trying to use an XML as a datasource in ASP and then display it as a datagrid. The XML has the following format: <?xml version="1.0" encoding="UTF-8"?> <people type="array"> <person> <id type="integer"></id> <first_name></first_name> <last_name></last_name> <title></title> <company></company> <tags> </tags> <locations> <location primary="false" label="work"> <email></email> <website></website> <phone></phone> <cell></cell> <fax></fax> <street_1/> <street_2/> <city/> <state/> <postal_code/> <country/> </location> </locations> <notes></notes> <created_at></created_at> <updated_at></updated_at> </person> </people> When I try to run the simple page I receive the following error Server Error in '/' Application. The data source for GridView with id 'GridView1' did not have any properties or attributes from which to generate columns. Ensure that your data source has content. Here is my page code <%@ Page Language="vb" AutoEventWireup="false" CodeBehind="Default.aspx.vb" Inherits="shout._Default" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" > <head runat="server"> <title>Untitled Page</title> </head> <body> <form id="form1" runat="server"> <div> <asp:XmlDataSource ID="XmlDataSource1" runat="server" DataFile="~/App_Data/people.xml" XPath="people/person"></asp:XmlDataSource> <asp:GridView ID="GridView1" runat="server" AllowPaging="True" DataSourceID="XmlDataSource1"> </asp:GridView> </div> </form> </body> </html> Please help. Thanks in advance.

    Read the article

  • JAVA: Sort ArrayList<ArrayList<Integer>> on multiple columns

    - by Bob
    First, I did do my homework searching before posting here. My requirement seems to be slightly different compared to questions posted out there. I have a matrix like ArrayList<ArrayList<Integer>> in the following form | id1 | id2 | score | |-----|-----|-------| | 1 | 3 | 95% | | 1 | 2 | 100% | | 1 | 4 | 85% | | 1 | 5 | 95% | | 2 | 10 | 80% | | 2 | 15 | 99% | I want to sort the matrix column-wise (first using score, then the id1). I already have the id1 in a sorted manner. That means I also need to sort all records with the same id1 first by using score, second by the id2. The reason for doing this is to create a ranking of the id2 in each id1. The result for the above example would be: | q_id | d_id | rank | score | |------|------|------|-------| | 1 | 2 | 1 | 100% | | 1 | 3 | 2 | 95% | | 1 | 5 | 3 | 95% | | 1 | 4 | 4 | 85% | | 2 | 15 | 1 | 99% | | 2 | 10 | 2 | 80% | How can I achieve this in Java using some built-in methods of collections?

    Read the article

  • How to run date picker onclick event?

    - by Nitz
    Hey Guys I am using this date picker from jqueryui. If see on that page, then u will find that they have just written in one function...means this... $(function() { $("#datepicker").datepicker(); }); </script> But i want to open my date picker on one text box click event. so i have written this $("#datepicker").datepicker(); in one function which i am calling on textbox onclick event. but in this there is one problem coming.. i am only get date picker on second time click on text box. if i click first time after page load then date picker will not come but as soon as i click second time then date picker is coming? WHY? AND CAN I DO IT ON FIRST CLICK? yes i know this already happening perfect if i put first code but i want it on my function.

    Read the article

  • XMPP TLS connection with SslStream

    - by Marcom
    I am trying to create a simple xmpp client that connects to Gtalk. The first part of the handshake seems to work. Ror the TLS handshake I created a client SslStream, connected to the intended server (talk.google.com) and successfully got authenticated . The first SSlStream.Read is to receive the greeting reply, it went fine . I do a SslStream.write to send my first command, but when i do my Sslstream.Read() to get the reply , i get this error."System.IO.IOException: Unable to read data from the transport connection: An established connection was aborted by the software in your host machine." Can anyone point me to the right direction? I am using code very similar to the example on msdn http://msdn.microsoft.com/en-us/library/system.net.security.sslstream.aspx except that I switch from a Network stream to a Sslstream when TLS is negotiated. netStream.Flush(); sslStream = new SslStream(netStream, true, new RemoteCertificateValidationCallback(ValidateServerCertificate), null ); sslStream.AuthenticateAsClient("talk.google.com");

    Read the article

  • iPhone: launch image for tab app?

    - by Karsten Silz
    I have a tab-based iPhone app where I want to increase the perceived start-up speed with a launch image. As defined by the iPhone HIG, the launch image is a screenshot of your app (called Default.png) that is displayed immediately and looks very similar to the app's first screen (e.g., the screenshot of an empty table when the app displays a table first). Now the problem with a tab-based app is that users can rearrange the order of tabs so that any of the tabs may be the first tab to show upon launch. I think I read somewhere that you can't change the Default.png programmatically in your app, but I couldn't find that in the HIG (and the "Clock" app seems to do exactly that - having one launch image per tab). So, how do provide a launch image for a tab-based app?

    Read the article

  • Does SQL Server Maintainance Cleanup consider exact times when deleting old backups?

    - by Heinzi
    Let's say I have a daily maintainance task that: Backups all databases and then removes backups that are older than 3 days. Now let's say the first backup at day 1, starting at 10:00, results in the following files db1.bak 2012-01-01 10:04 db2.bak 2012-01-01 10:06 Now let's say at day 4 the first step of the maintainance task (backup the DBs) happens to finish at 10:05. Will SQL Server delete db1.bak and keep db2.bak (would be logical, but might be surprising for the user) or keep both or remove both?

    Read the article

  • Odd SQL Results

    - by Ryan Burnham
    So i have the following query Select id, [First], [Last] , [Business] as contactbusiness, (Case When ([Business] != '' or [Business] is not null) Then [Business] Else 'No Phone Number' END) from contacts The results look like id First Last contactbusiness (No column name) 2 John Smith 3 Sarah Jane 0411 111 222 0411 111 222 6 John Smith 0411 111 111 0411 111 111 8 NULL No Phone Number 11 Ryan B 08 9999 9999 08 9999 9999 14 David F NULL No Phone Number I'd expect record 2 to also show No Phone Number If i change the "[Business] is not null" to [Business] != null then i get the correct results id First Last contactbusiness (No column name) 2 John Smith No Phone Number 3 Sarah Jane 0411 111 222 0411 111 222 6 John Smith 0411 111 111 0411 111 111 8 NULL No Phone Number 11 Ryan B 08 9999 9999 08 9999 9999 14 David F NULL No Phone Number Normally you need to use is not null rather than != null. whats going on here?

    Read the article

  • using zend form decorators

    - by pradeep
    <div class="field50Pct"> <div class="fieldItemLabel"> <label for='First Name'>First Name:</label> </div> <div class="fieldItemValue"> <input type="text" id="firstname" name="firstname" value="" /> </div> </div> <div class="clear"></div> I want the code to appear like this in source code . how do i write the same thing in zend using decorators ? The element is like $firstname = new Zend_Form_Element_Text('FirstName'); $firstname->setLabel('FirstName') ->setRequired(true) ->addFilter('StripTags') ->addFilter('StringTrim') ->addErrorMessage('Error in First Name') ->addValidator('NotEmpty');

    Read the article

  • python union of 2 nested lists with index

    - by sbas
    I want to get the union of 2 nested lists plus an index to the common values. I have two lists like A = [[1,2,3],[4,5,6],[7,8,9]] and B = [[1,2,3,4],[3,3,5,7]] but the length of each list is about 100 000. To A belongs an index vector with len(A): I = [2,3,4] What I want is to find all sublists in B where the first 3 elements are equal to a sublist in A. In this example I want to get B[0] returned ([1,2,3,4]) because its first three elements are equal to A[0]. In addition, I also want the index to A[0] in this example, that is I[0]. I tried different things, but nothing worked so far :( First I tried this: Common = [] for i in range(len(B)): if B[i][:3] in A: id = [I[x] for x,y in enumerate(A) if y == B[i][:3]][0] ctdCommon.append([int(id)] + B[i]) But that takes ages, or never finishes Then I transformed A and B into sets and took the union from both, which was very quick, but then I don't know how to get the corresponding indices Does anyone have an idea?

    Read the article

  • Double interpolation of regular expressions in Perl

    - by tomdee
    I have a Perl program that stores regular expressions in configuration files. They are in the form: regex = ^/d+$ Elsewhere, the regex gets parsed from the file and stored in a variable - $regex. I then use the variable when checking the regex, e.g. $lValid = ($valuetocheck =~ /$regex/); I want to be able to include perl variables in the config file, e.g. regex = ^\d+$stored_regex$ But I can't work out how to do it. When regular expressions are parsed by Perl they get interpreted twice. First the variables are expanded, and then the the regular expression itself is parsed. What I need is a three stage process: First interpolate $regex, then interpolate the variables it contains and then parse the resulting regular expression. Both the first two interpolations need to be "regular expression aware". e.g. they should know that the string contain $ as an anchor etc... Any ideas?

    Read the article

  • iPhone:Tabbar item actions are not happening

    - by user187532
    Hello all, I created a window application, which has a tabbar controller with four tabbar items. Each tabbar items are linked with a tableview. I have also set Navigation bar for each tabbar items. I have appdelegate file, which calls the first tableview controller of which is set for first tabbar item. I am trying to retrieve and do an action whenever a tabbar item is clicked. For that, i tried to add "- (void)tabBar:(UITabBar *)tabBar didSelectItem:(UITabBarItem *)item" and "- (void)tabBarController:(UITabBarController *)tabBarController didSelectViewController:(UITableViewController *)viewController" in my first tableview controller, but it is not at all responding whenever i click any tabbar items. My question is, if i create a window based application and added tabbar controller, tableview and navigation bar in .XIB file, is it not possible to access and do an action programatically whenever a tabbar item is clicked? (or) Am i doing anything wrong? Please help me to resolve this and share your ideas. Thanks.

    Read the article

  • How to change Blackberry initial message download limit.

    - by Mikey B
    BES 4.1.6 Blackberry 8300 (curve) Hi guys, I've noticed that handhelds will typically only retrieve the first few KB and then prompt the user to manually retrieve more (or auto-retrieve if they scroll down). The problem is that I have a BB app that needs to see the entire message all at once on the first initial time it's opened. Is there a setting on BES that will allow me to change how much data a handheld initially retrieves per message? Thanks, M

    Read the article

  • Join 2 children tables with a parent tables without duplicated

    - by user1847866
    Problem I have 3 tables: People, Phones and Emails. Each person has an UNIQUE ID, and each person can have multiple numbers or multiple emails. Simplified it looks like this: +---------+----------+ | ID | Name | +---------+----------+ | 5000003 | Amy | | 5000004 | George | | 5000005 | John | | 5000008 | Steven | | 8000009 | Ashley | +---------+----------+ +---------+-----------------+ | ID | Number | +---------+-----------------+ | 5000005 | 5551234 | | 5000005 | 5154324 | | 5000008 | 2487312 | | 8000009 | 7134584 | | 5000008 | 8451384 | +---------+-----------------+ +---------+------------------------------+ | ID | Email | +---------+------------------------------+ | 5000005 | [email protected] | | 5000005 | [email protected] | | 5000008 | [email protected] | | 5000008 | [email protected] | | 5000008 | [email protected] | | 8000009 | [email protected] | | 5000004 | [email protected] | +---------+------------------------------+ I am trying to joining them together without duplicates. It works great, when I try to join only Emails with People or only Phones with People. SELECT People.Name, People.ID, Phones.Number FROM People LEFT OUTER JOIN Phones ON People.ID=Phones.ID ORDER BY Name, ID, Number; +----------+---------+-----------------+ | Name | ID | Number | +----------+---------+-----------------+ | Steven | 5000008 | 8451384 | | Steven | 5000008 | 24887312 | | John | 5000005 | 5551234 | | John | 5000005 | 5154324 | | George | 5000004 | NULL | | Ashley | 8000009 | 7134584 | | Amy | 5000003 | NULL | +----------+---------+-----------------+ SELECT People.Name, People.ID, Emails.Email FROM People LEFT OUTER JOIN Emails ON People.ID=Emails.ID ORDER BY Name, ID, Email; +----------+---------+------------------------------+ | Name | ID | Email | +----------+---------+------------------------------+ | Steven | 5000008 | [email protected] | | Steven | 5000008 | [email protected] | | Steven | 5000008 | [email protected] | | John | 5000005 | [email protected] | | John | 5000005 | [email protected] | | George | 5000004 | [email protected] | | Ashley | 8000009 | [email protected] | | Amy | 5000003 | NULL | +----------+---------+------------------------------+ However, when I try to join Emails and Phones on People - I get this: SELECT People.Name, People.ID, Phones.Number, Emails.Email FROM People LEFT OUTER JOIN Phones ON People.ID = Phones.ID LEFT OUTER JOIN Emails ON People.ID = Emails.ID ORDER BY Name, ID, Number, Email; +----------+---------+-----------------+------------------------------+ | Name | ID | Number | Email | +----------+---------+-----------------+------------------------------+ | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | John | 5000005 | 5551234 | [email protected] | | John | 5000005 | 5551234 | [email protected] | | John | 5000005 | 5154324 | [email protected] | | John | 5000005 | 5154324 | [email protected] | | George | 5000004 | NULL | [email protected] | | Ashley | 8000009 | 7134584 | [email protected] | | Amy | 5000003 | NULL | NULL | +----------+---------+-----------------+------------------------------+ What happens is - if a Person has 2 numbers, all his emails are shown twice (They can not be sorted! which means they can not be removed by @last) What I want: Bottom line, playing with the @last, I want to end up with somethig like this, but @last won't work if I don't arrange ORDER columns in the righ way - and this seems like a big problem..Orderin the email column. Because seen from the example above: Steven has 2 phone number and 3 emails. The JOIN Emails with Numbers happens with each email - thus duplicated values that can not be sorted (SORT BY does not work on them). **THIS IS WHAT I WANT** +----------+---------+-----------------+------------------------------+ | Name | ID | Number | Email | +----------+---------+-----------------+------------------------------+ | Steven | 5000008 | 8451384 | [email protected] | | | | 24887312 | [email protected] | | | | | [email protected] | | John | 5000005 | 5551234 | [email protected] | | | | 5154324 | [email protected] | | George | 5000004 | NULL | [email protected] | | Ashley | 8000009 | 7134584 | [email protected] | | Amy | 5000003 | NULL | NULL | +----------+---------+-----------------+------------------------------+ Now I'm told that it's best to keep emails and number in separated tables because one can have many emails. So if it's such a common thing to do, what isn't there a simple solution? I'd be happy with a PHP Solution aswell. What I know how to do by now that satisfies it, but is not as pretty. If I do it with GROUP_CONTACT I geat a satisfactory result, but it doesn't look as pretty: I can't put a "Email type = work" next to it. SELECT People.Ime, GROUP_CONCAT(DISTINCT Phones.Number), GROUP_CONCAT(DISTINCT Emails.Email) FROM People LEFT OUTER JOIN Phones ON People.ID=Phones.ID LEFT OUTER JOIN Emails ON People.ID=Emails.ID GROUP BY Name; +----------+----------------------------------------------+---------------------------------------------------------------------+ | Name | GROUP_CONCAT(DISTINCT Phones.Number) | GROUP_CONCAT(DISTINCT Emails.Email) | +----------+----------------------------------------------+---------------------------------------------------------------------+ | Steven | 8451384,24887312 | [email protected],[email protected],[email protected] | | John | 5551234,5154324 | [email protected],[email protected] | | George | NULL | [email protected] | | Ashley | 7134584 | [email protected] | | Amy | NULL | NULL | +----------+----------------------------------------------+---------------------------------------------------------------------+

    Read the article

  • Google Chrome OS ISO

    - by Taylor
    First of all, a few questions as I'm a bit confused :P Is the Chrome OS that is shipped on Chromebooks "Chromium"? I'm wanting to buy a Chromebook, but I want to download an ISO or other similar format first so I can try it out in VMware. To be clear, I'm wanting the exact version that ships on Chromebooks, as I want to get a good feel for what I'll be buying Where can I find this? I've found other things but I'm not sure they're the actual Chrome OS

    Read the article

  • Snow Leopard on Core Duo

    - by Brendan Foote
    The first run of MacBook Pros have Core Duo processors, whereas all the ones after that have Core 2 Duos. Apple says Snow Leopard only requires an Intel processor, but will a first-gen MacBook Pro get enough of the improvements to be worth upgrading? This is similar to the question about Snow Leopard on an old iBook, but it differs because this processor is supported by Apple, but seems counter to the 64-bit theme of the upgrade.

    Read the article

  • delphi insert update record´s

    - by ml
    Hi friends what is that im doing wrong because it goes and goes on LOOP var ii: Integer; i: Integer; j: Integer; ie : integer; je : integer; fileSource, fileDest: string; Fo : TSHFileOpStruct; buffer : array[0..4096] of char; p : pchar; dirFile: String; dirFile1: String; dirFile11: String; begin dirFile1 := (Dirlocal + 'Vibrometria\'+ClienteN.text+'\'); dirFile := (localAplicação+ 'Vibrometria\'+ClienteN.text+'\'+NInterv.text ) ; dirFile11:= Dirlocal+'Vibrometria\'; if ForceDirectories(dirFile11) then if ForceDirectories(dirFile1) then //...................................................................... begin ShowMessage('Vai devolver "'+cxDBTextEdit5.Text+'..........' +obra.Text); Sub_TRelFinal.First; Begin ADOTable_casa.First; Begin begin Sub_TRelFinal.Edit; //Tabela1Codoco.Value := Tabela2Codoco.Value; Sub_TRelFinal.FieldByName('Foto1').text := ADOTable_casa.FieldByName('Foto1').text; Sub_TRelFinal.FieldByName('Obra').text := ADOTable_casa.FieldByName('Obra').text; Sub_TRelFinal.FieldByName('OBS1').text := ADOTable_casa.FieldByName('OBS1').text; Sub_TRelFinal.FieldByName('Data_VisitaLocal').text := ADOTable_casa.FieldByName('Data_VisitaLocal').text; Sub_TRelFinal.FieldByName('ContractoN').text := ADOTable_casa .FieldByName('ContractoN').text;; Sub_TRelFinal.FieldByName('Cliente').text := ADOTable_casa .FieldByName('Cliente').text; Sub_TRelFinal.FieldByName('Morada').text := ADOTable_casa .FieldByName('Morada').text; Sub_TRelFinal.FieldByName('localizacao').text:= ADOTable_casa .FieldByName('localizacao').text; Sub_TRelFinal.FieldByName('Intruducao').text:= ADOTable_casa .FieldByName('Intruducao').text; Sub_TRelFinal.FieldByName('Analise').text := ADOTable_casa.FieldByName('Analise').text; Sub_TRelFinal.Post; end; End; end; //iniciar inserção registos sub Sub_TRelFinal_1.First; For j := 1 to Sub_TRelFinal_1.RecordCount do Begin ADOTable_casa_sub_1.First; For i := 1 To ADOTable_casa_sub_1.RecordCount Do Begin begin Sub_TRelFinal_1.Edit; //Tabela1Codoco.Value := Tabela2Codoco.Value; Sub_TRelFinal_1.FieldByName('Foto1').text := ADOTable_casa_sub_1.FieldByName('Foto1').text; Sub_TRelFinal_1.FieldByName('Obra').text := ADOTable_casa_sub_1.FieldByName('Obra').text; Sub_TRelFinal_1.FieldByName('OBS1').text := ADOTable_casa_sub_1.FieldByName('OBS1').text; Sub_TRelFinal_1.FieldByName('Data_VisitaLocal').text := ADOTable_casa_sub_1.FieldByName('Data_VisitaLocal').text; Sub_TRelFinal_1.FieldByName('ContractoN').text := ADOTable_casa_sub_1.FieldByName('ContractoN').text; Sub_TRelFinal_1.FieldByName('Cliente').text := ADOTable_casa_sub_1.FieldByName('Cliente').text; Sub_TRelFinal_1.FieldByName('Morada').text := ADOTable_casa_sub_1.FieldByName('Morada').text; Sub_TRelFinal_1.FieldByName('localizacao_eq').text:= ADOTable_casa_sub_1.FieldByName('localizacao_eq').text; Sub_TRelFinal_1.FieldByName('Equipamento').text:= ADOTable_casa_sub_1.FieldByName('Equipamento').text; Sub_TRelFinal_1.FieldByName('tipo_equip').text := ADOTable_casa_sub_1.FieldByName('tipo_equip').text; Sub_TRelFinal_1.Post; end; //iniciar inserção registos subsub SubTRelFinal_sub.First; For ie := 1 to SubTRelFinal_sub.RecordCount do Begin ADOTable_casa_sub_Sub.First; For je := 1 To ADOTable_casa_sub_Sub.RecordCount Do begin SubTRelFinal_sub.Edit; //Tabela1Codoco.Value := Tabela2Codoco.Value; SubTRelFinal_sub.FieldByName('Foto1').text := ADOTable_casa_sub_Sub.FieldByName('Foto1').text; SubTRelFinal_sub.FieldByName('Foto2').text := ADOTable_casa_sub_Sub.FieldByName('Foto2').text; SubTRelFinal_sub.FieldByName('Analisefoto1').text := ADOTable_casa_sub_Sub.FieldByName('Analisefoto1').text; SubTRelFinal_sub.FieldByName('Observações').text := ADOTable_casa_sub_Sub.FieldByName('Observações').text;; SubTRelFinal_sub.FieldByName('ContractoN').text := ADOTable_casa_sub_Sub.FieldByName('ContractoN').text; SubTRelFinal_sub.FieldByName('OBS3').text := ADOTable_casa_sub_Sub.FieldByName('OBS3').text; SubTRelFinal_sub.FieldByName('OBS4').text := ADOTable_casa_sub_Sub.FieldByName('OBS4').text; SubTRelFinal_sub.FieldByName('OBS2').text := ADOTable_casa_sub_Sub.FieldByName('OBS2').text; SubTRelFinal_sub.FieldByName('OBS1').text := ADOTable_casa_sub_Sub.FieldByName('OBS1').text; SubTRelFinal_sub.FieldByName('Localização').text := ADOTable_casa_sub_Sub.FieldByName('Localização').text; SubTRelFinal_sub.FieldByName('Tipo_equipamento').text:= ADOTable_casa_sub_Sub.FieldByName('Tipo_equipamento').text; SubTRelFinal_sub.FieldByName('Analisefoto101').text:= ADOTable_casa_sub_Sub.FieldByName('Analisefoto101').text; SubTRelFinal_sub.FieldByName('Analisefoto201').text := ADOTable_casa_sub_Sub.FieldByName('Analisefoto201').text; SubTRelFinal_sub.FieldByName('GrauAnomalia').text := ADOTable_casa_sub_Sub.FieldByName('GrauAnomalia').text; SubTRelFinal_sub.Post; end; ADOTable_casa_sub_Sub.Next; End; SubTRelFinal_sub.Next; End; ADOTable_casa_sub_1.Next; End; Sub_TRelFinal_1 .Next;

    Read the article

  • Finding all the shortest paths between two nodes in unweighted directed graphs using BFS algorithm

    - by andra-isan
    Hi All, I am working on a problem that I need to find all the shortest path between two nodes in a given directed unweighted graph. I have used BFS algorithm to do the job, but unfortunately I can only print one shortest path not all of them, for example if they are 4 paths having lenght 3, my algorithm only prints the first one but I would like it to print all the four shortest paths. I was wondering in the following code, how should I change it so that all the shortest paths between two nodes could be printed out? class graphNode{ public: int id; string name; bool status; double weight;}; map<int, map<int,graphNode>* > graph; int Graph::BFS(graphNode &v, graphNode &w){ queue <int> q; map <int, int> map1; // this is to check if the node has been visited or not. std::string str= ""; map<int,int> inQ; // just to check that we do not insert the same iterm twice in the queue map <int, map<int, graphNode>* >::iterator pos; pos = graph.find(v.id); if(pos == graph.end()) { cout << v.id << " does not exists in the graph " <<endl; return 1; } int parents[graph.size()+1]; // this vector keeps track of the parents for the node parents[v.id] = -1; // there is a direct path between these two words, simply print that path as the shortest path if (findDirectEdge(v.id,w.id) == 1 ){ cout << " Shortest Path: " << v.id << " -> " << w.id << endl; return 1; } //if else{ int gn; map <int, map<int, graphNode>* >::iterator pos; q.push(v.id); inQ.insert(make_pair(v.id, v.id)); while (!q.empty()){ gn = q.front(); q.pop(); map<int, int>::iterator it; cout << " Popping: " << gn <<endl; map1.insert(make_pair(gn,gn)); //backtracing to print all the nodes if gn is the same as our target node such as w.id if (gn == w.id){ int current = w.id; cout << current << " - > "; while (current!=v.id){ current = parents[current]; cout << current << " -> "; } cout <<endl; } if ((pos = graph.find(gn)) == graph.end()) { cout << " pos is empty " <<endl; continue; } map<int, graphNode>* pn = pos->second; map<int, graphNode>::iterator p = pn->begin(); while(p != pn->end()) { map<int, int>::iterator it; //map1 keeps track of the visited nodes it = map1.find(p->first); graphNode gn1= p->second; if (it== map1.end()) { map<int, int>::iterator it1; //if the node already exits in the inQ, we do not insert it twice it1 = inQ.find(p->first); if (it1== inQ.end()){ parents[p->first] = gn; cout << " inserting " << p->first << " into the queue " <<endl; q.push(p->first); // add it to the queue } //if } //if p++; } //while } //while } I do appreciate all your great help Thanks, Andra

    Read the article

  • icefaces datatable component

    - by chetan
    I have two datatable in two different jspx page but when I call one then i try to call other old one still display what is the problem there. from the old page only datatable is display no other component are displayed. This is one jspx page -- -- <div style="margin-bottom: 20px;"> <div> <div class="page-navi"> <ice:dataPaginator id="dataScroll_3" for="companyDataTable1" paginator="true"> <f:facet name="first"> <ice:graphicImage url="/xmlhttp/css/xp/css-images/arrow-first.gif" title="First Page" /> </f:facet> <f:facet name="last"> <ice:graphicImage url="/xmlhttp/css/xp/css-images/arrow-last.gif" title="Last Page" /> </f:facet> <f:facet name="previous"> <ice:graphicImage url="/xmlhttp/css/xp/css-images/arrow-previous.gif" title="Previous Page" /> </f:facet> <f:facet name="next"> <ice:graphicImage url="/xmlhttp/css/xp/css-images/arrow-next.gif" title="Next Page" /> </f:facet> </ice:dataPaginator> </div> <ice:panelGroup> <ice:dataTable id="companyDataTable1" rendered="#{createLeaveBean.empRender}" binding="#{createLeaveBean.empTable}" value="#{createLeaveBean.lstEmployeeeInfo}" var="currentRow" width="80%" cellpadding="0" cellspacing="0" headerClass="std-table-header" styleClass="std-table" rows="10"> <ice:column style="width: 1%"> <f:facet name="header"> <ice:selectBooleanCheckbox id="selectallemp" partialSubmit="true" value="#{createLeaveBean.selectAll}" valueChangeListener="#{createLeaveBean.toggleSelectedFields}" onkeydown="moveFocus(event,'selectoneemp')" tabindex="8"></ice:selectBooleanCheckbox> </f:facet> <ice:selectBooleanCheckbox id="selectoneemp" value="#{currentRow.notify}" tabindex="9" ></ice:selectBooleanCheckbox> </ice:column> <ice:column style="width: 5%;"> <f:facet name="header"><ice:outputText value="Employee Id" /></f:facet> <ice:outputText value="#{currentRow.employeeInfoId}" /> </ice:column> <ice:column style="width: 34%;"> <f:facet name="header"><ice:outputText value="Employee Name" /></f:facet> <ice:outputText value="#{currentRow.firstName}" /> </ice:column> </ice:dataTable> </ice:panelGroup> </div> <ice:commandButton id="createleave" tabindex="12" value="Create" action="#{createLeaveBean.createLeavePolicyEmp}" styleClass="std-btn" style="margin-right: 10px;margin-left: 50px;margin-top: 15px"></ice:commandButton> <ice:commandButton id="cancelleave" tabindex="13" value="Cancel" action="#{createLeaveBean.cancelLeavePolicyEmp}" rendered="true" styleClass="std-btn" style="margin-top: 15px"></ice:commandButton> </div> This is second jspx page <div class="page-navi"> <ice:dataPaginator id="dataScroll_4" for="companyDataTable2" paginator="true"> <f:facet name="first"> <ice:graphicImage url="/xmlhttp/css/xp/css-images/arrow-first.gif" title="First Page" /> </f:facet> <f:facet name="last"> <ice:graphicImage url="/xmlhttp/css/xp/css-images/arrow-last.gif" title="Last Page" /> </f:facet> <f:facet name="previous"> <ice:graphicImage url="/xmlhttp/css/xp/css-images/arrow-previous.gif" title="Previous Page" /> </f:facet> <f:facet name="next"> <ice:graphicImage url="/xmlhttp/css/xp/css-images/arrow-next.gif" title="Next Page" /> </f:facet> </ice:dataPaginator> </div> <ice:panelGroup> <ice:dataTable id="companyDataTable2" rendered="#{createLeaveBean.deptRender}" binding="#{createLeaveBean.empTable}" value="#{createLeaveBean.lstEmployeeeInfo}" var="currentRowww" width="96%" cellpadding="0" cellspacing="0" headerClass="std-table-header" styleClass="std-table" rows="10"> <ice:column style="width: 5%;"> <f:facet name="header"><ice:outputText value="Employee Id" /></f:facet> <ice:outputText value="#{currentRowww.employeeInfoId}" /> </ice:column> <ice:column style="width: 34%;"> <f:facet name="header"><ice:outputText value="Employee Name" /></f:facet> <ice:outputText value="#{currentRowww.firstName}" /> </ice:column> </ice:dataTable> </ice:panelGroup> <ice:commandButton id="createLeave" value="Create" action="#{createLeaveBean.createLeavePolicyDept}" styleClass="std-btn" tabindex="8" style="margin-right: 10px;margin-left: 40px;margin-top: 15px"></ice:commandButton> <ice:commandButton id="cancelLeave" value="Cancel" action="#{createLeaveBean.cancelLeavePolicyDept}" rendered="true" styleClass="std-btn" tabindex="9" style="margin-top: 15px"></ice:commandButton>

    Read the article

  • Is there a way to link text controls in Word 2007?

    - by Jared Harley
    I am creating a form in Word 2007, using the controls available in the Developer tab. On my first page, I have the user enter a name into a text control. I want to have a control on the second page to automatically fill in with the same text as the first one. Is there any way to link these controls together?

    Read the article

  • a missing variable in a switch statement ?!!

    - by mechhfly
    hi folks, i have a strange issue. a variable seems to be missing during a pass through a case statement i have a function like so function checklink($var0, $var1, $var2) { switch($var0) { case "case1": print $var2; //code uses $var2 successfully case "case2": print $var2; //variable has disappeared! } } essentially what i am doing is constructing a string from the last variable based on the first. if i run the code in which the first case is true, i get the expected results, but when i run the second case, my variable seems to have vanished. these first two case statements are syntactically the same and the variable is gathered from the $_GET array (hard coded into hyperlink). any light on this issue? if more explanation is needed let me know, its late and my brain is getting mushy. thanks my friends.

    Read the article

  • Quaddratic Bezier Curve: Calculate Tangent

    - by stefan.at.wpf
    Hello, I have have a quadratic bezier curve and I want to calculate the slope of the tangent in a given point. For example, let it be the middlepoint of the quadratic bezier curve, therefore t=0.5 (please see the link below for a picture of this). I've calculated the first derivation of the formula for the quadratic bezier curve, however I get 400 as value for the slope, though it should be 0. Maybe I'm using the first derivation in a wrong way? I know I could also calculate the tangents using trigonometric functions, however I'd like to do it using the first derivation, shouldn't this be possible? Thanks for any hint! For clarification / please note: I'm interested in a general way to get the slope in a arbitrary given point on a quadratic bezier curve, not only to get the tangent in the start- and end point. A picture of my problem including the text above: http://cid-0432ee4cfe9c26a0.skydrive.live.com/self.aspx/%c3%96ffentlich/Quadratic%20Bezier%20Curve.pdf Thank you very much for any hint!

    Read the article

  • Comma comes up instead of single quote with single quote key in MS-Word 2007

    - by Nitrodist
    I have a peculiar problem in Microsoft Office 2007 (Word). When I am using single quotes, the first time I type a ' it appears as a , instead. For example, typing ''' translates to ,'' in Word, necessitating me to go back and delete the comma so that I can correctly single-quote words. Is there a solution to this? Also, the dictionary was set to German when I first started using the application, but I set it to US English after that.

    Read the article

  • Java3D getting time problem

    - by Meko
    HI ..I made little Shooter game that on screen two ships firing each other.I ahve method on paintComponent like drawing or moving object.But in some reason it works different speed on each komputer.I searchand made some modification to my game like drawing and moving objects in thread..Now it works on every ?omputer same speed.Also if I change size.But problem is I used J3DTimer.getValue() .For this library I donwnloaded Java3d. Problem is If on machine there is no this library or installation my game doesnot working .How can I solw this problem? I should say every one to setup Java#d? :)) ALso I used standart System.currentTimeMillis(); but now my game works very slow...Any idea?

    Read the article

  • DIV Overlaying DIV, links in backmost DIV non-accessible

    - by Shawn
    I have a photoshop image that is 500x600 that I am using as a background image for the first div. The second div sits over top of the first div and is populated with images. The z-index of the first div is set to 100. The effect is the photoshop image sits over top of all of the smaller images. The photoshop image is a letter with the inner-content of it set to be transparent and the small images create the filling. Each of the small images however is a link, but none of the links are accessible. How can I remedy that? I would post the code here, but I have absolutely no clue how to format it. I quite simply do not understand typing a backtick followed by the tab key and then a dollar sign. All that ends up is I type a backtick here followed by a dollar sign in the Tags section below.

    Read the article

< Previous Page | 193 194 195 196 197 198 199 200 201 202 203 204  | Next Page >