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  • What is the best script language for n/w programming + web development

    - by Mohanavel
    Hi, I'm interested in developing web application and networking application. For that what is the best script language to learn. Which one is effective for this two. So for, i don't know even a single syntax of any scripting language. Which is the best script for understanding, maintainable, effective and simple (may not). Please don't say what are all you know. Please tell me the best

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  • Eclipse autocomplete not working in some Java files

    - by m_a_khan
    Hi, I have noticed that autocomplete is not working in some of java files in Eclipse. Also, the files where autocomplete is not working, display a hollow "J" as the icon for the Java file. The files where autocomplete is working, icon for java file is a filled "J" I am wondering if someone can point out what went wrong all of suddent, why the change in icons and why autocomplete and syntax highlighting is turned-off in the files with a hollow "J" icon? Thanks.

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  • Calling and writing javascript functions

    - by Ankur
    I think I have not got the syntax correct for writing a javascript function and calling it to assign its return value to a variable. My function is: getObjName(objId){ var objName =""; $.ajax( { type : "GET", url : "Object", dataType: 'json', data : "objId="+objId, success : function(data) { objName = data; } }); return objName; } I am trying to call it and assign it to a variable with: var objName = getObjName(objId); However Eclipse is telling me that "there is no such function getObjName() defined"

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  • how to declare datetime datatype in mysql in a normal pojo class

    - by Rajesh
    How to declare datetime datatype in normal java class Example: I have one SampleUser table, in that for UpdateDate column I declare datatype as datetime, for this table I need to create a pojo class, so how I have declare datetime datatype in Java-bean ?? class User { /* shall we use java.sql.Timestamp for **UpdateDate** field........? */ private Timestamp updateDate; } this Syntax is correct??

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  • Converting a selected date from a datetimepicker into my query, along with subtracting a day

    - by MyHeadHurts
    I am currently using this to get yesterdays date, however i need to do something similar where the user will use a javascript datetimepicker in my asp.net page and i will then use the date they select instead of just yesterdays date Declare @dayselection int set @dayselection = CONVERT(int,DateAdd(year, @YearToGet - Year(getdate() + 1), DateAdd(day, DateDiff(day, 1, @dayToGet), 1) , DateAdd(month, DateDiff(month, 0, @monthToGet), 0) ) but it isnt working i keep getting syntax errors I want the day and year functions to stay the same i just need help with the month part. I need to convert the selected date into an int

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  • Rewrite css/js paths

    - by wooptoo
    So I rewrote my paths to something like: URL/really/nice/paths/ using mod_rewrite rules like this: <IfModule mod_rewrite.c> RewriteEngine On RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ index.php?url=$1 [PT,L] </IfModule> The question is how could I rewrite the paths for js/css/image files too, so when they are requested with a relative path from URL/really/nice/path/ to be served from URL/scripts/, URL/styles/ and URL/images/ folders instead? Can this be done without using RewriteBase?

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  • Passing direct parameters to a Controller#method when testing via RSpec

    - by gmile
    Normally to pass parameters via in RSpec we do: params[:my_key] = my_value get :my_method Where my_method deals with what it received from params. But in my controller I have a method, which takes args directly i.e.: def my_method(*args) ... end How do I call the method with those args from within the test? I've tried get :my_method(args) but Ruby interpreter complains about syntax error.

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  • add array element to row returned from sql query

    - by bert
    I want to add an additional value into an array before passing it to json_encode function, but I can't get the syntax right. $result = db_query($query); // $row is a database query result resource while ($row = db_fetch_object($result)) { $stack[] = $row; // I am trying to 'inject' array element here $stack[]['x'] = "test"; } echo json_encode($stack);

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  • mysql changing delimiter

    - by jimsmith
    I'm trying to add this function using php myadmin, first off I get on error line 5, which is apparently because you need to change the delimiter from ; to something else so i tried this DELIMITER | CREATE FUNCTION LEVENSHTEIN (s1 VARCHAR(255), s2 VARCHAR(255)) RETURNS INT DETERMINISTIC BEGIN DECLARE s1_len, s2_len, i, j, c, c_temp, cost INT; DECLARE s1_char CHAR; DECLARE cv0, cv1 VARBINARY(256); SET s1_len = CHAR_LENGTH(s1), s2_len = CHAR_LENGTH(s2), cv1 = 0x00, j = 1, i = 1, c = 0; IF s1 = s2 THEN RETURN 0; ELSEIF s1_len = 0 THEN RETURN s2_len; ELSEIF s2_len = 0 THEN RETURN s1_len; ELSE WHILE j <= s2_len DO SET cv1 = CONCAT(cv1, UNHEX(HEX(j))), j = j + 1; END WHILE; WHILE i <= s1_len DO SET s1_char = SUBSTRING(s1, i, 1), c = i, cv0 = UNHEX(HEX(i)), j = 1; WHILE j <= s2_len DO SET c = c + 1; IF s1_char = SUBSTRING(s2, j, 1) THEN SET cost = 0; ELSE SET cost = 1; END IF; SET c_temp = CONV(HEX(SUBSTRING(cv1, j, 1)), 16, 10) + cost; IF c > c_temp THEN SET c = c_temp; END IF; SET c_temp = CONV(HEX(SUBSTRING(cv1, j+1, 1)), 16, 10) + 1; IF c > c_temp THEN SET c = c_temp; END IF; SET cv0 = CONCAT(cv0, UNHEX(HEX(c))), j = j + 1; END WHILE; SET cv1 = cv0, i = i + 1; END WHILE; END IF; RETURN c; END DELIMITER ; But I get this error: #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'delimiter | Please help !?

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  • jquery validatie if statement

    - by Mariana Hernandez
    i have this validate function: var validator =$('#form1').validate( { ignore: "", rules: { usu_login: { required: true }, usu_email: { required: true }, usu_nombre1: { required: true }, usu_apellido1: { required: true }, usu_fecha_nac: { required: true }, usu_cedula: { required: true }, usu_telefono1: { required: true }, usu_password: { required: function() { return focusout == true; } }, usu_password2: { required: function() { return focusout == true; } }, usu_password3: { required: function() { return focusout == true; }, equalTo: "#usu_password2" } i need to apply the same if statement in the "equalTo" fuction so this can work as i want to, but i dont know how to do that. Dows anyone knows? Thanks

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  • Float conditional in bash

    - by Werner
    Hi, in bash I need to compare two float numbers, one which I define in the script and the other read as paramter, for that I do: if [[ $aff -gt 0 ]] then a=b echo "xxx "$aff #echo $CX $CY $CZ $aff fi but I get the error: [[: -309.585300: syntax error: invalid arithmetic operator (error token is ".585300") What is wrong? Thanks

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  • Can I have a CASE statement within a WHILE loop?

    - by John
    This is what I'm doing: while (@counter < 3 and @newBalance >0) begin CASE when @counter = 1 then ( @monFee1 = @monthlyFee, @newBalance = @newBalance-@fee) when @counter = 2 then ( @monFee2 = @monthlyFee, @newBalance = @newBalance-@fee) END @counter = @counter +1 end I get this error: Incorrect syntax near the keyword 'CASE'. No idea why. Please help!

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  • PHP array_search nor working?

    - by FFish
    What am I doing wrong here? $array = array('sky'=>'blue', 'grass'=>'green', 'sun'=>'yellow'); $key = array_search('green', $array); echo $key; error: Parse error: syntax error, unexpected T_DOUBLE_ARROW in /Applications/XAMPP/xamppfiles/htdocs/search-array.php on line 2

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  • Is there a good in-browser code editor?

    - by levik
    We've all seen in-browser rich text editors, which allow you to edit colored/styled text in a WYSIWYG manner. But what about code editors, which automatically highlight code based on language rules as you type? Think Eclipse in a textarea (but without the refactoring support). Do such things exist? I imagine scaling would be a problem - larger files would be difficult to edit efficiently.

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  • Switch case in where clause (sql server)

    - by user685565
    I want to use case in sql statement where clause but I have a problem as I want to create a where clause condition on the basis of some value and I want to set a not in clause values on the basis of it here is the query where am facing an issue WHERE CODE = 'x' and ID not in ( case when 'app'='A' then '570','592' when 'Q' then ID 592,90 else 592,90 END but its not syntax

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  • Mysql change column details

    - by Ankur
    I am trying to redefine the number of varchars a column can have (in a MySQL db). I am doing alter table obj_details IMG_SRC IMG_SRC varchar(180); I want to change the number of characters that can be used in the column IMG_SRC to 180 (it is currently 100). But I get an error saying that I should check the syntax near IMG_SRC IMG_SRC varchar(180).

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  • Drupal 7 Install Error

    - by Matthew
    Guys, I was hoping that someone can shed some light on why I am getting this error: Parse error: syntax error, unexpected '{' in /homepages/22/d223624283/htdocs/drupal_new/includes/install.core.inc on line 74 Could it be something that I missed as far as D& configurations? Thanks, Matt

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  • Apache installation in folder with chinese characters in name

    - by Zsolti
    I would like to install an Apache server into a folder like c:\anything\???\anything2\ under windows. When I try to start the service it sais that: httpd: Syntax error on line xx of C:/anything/\xe6\x80\x98\xe6\x80\x99\e6\80\9a/anything2/apache/conf/httpd.conf: ServerRoot must be a valid directory Does anyone have a solution?

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