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  • Leadership Perspective: Using My Oracle Support Community to Increase Productivity

    Your IT organization may know about My Oracle Support Community, but as an IT leader facing tight budgets and increasing SLAs have you considered the operational business benefits Community offers? These benefits include faster problem resolution and increased per capita work capacity. In this podcast, learn how to maximize IT productivity without spending an additional dollar on support, using tools already included in your Oracle Premier Support subscription.

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  • mysql changing delimiter

    - by jimsmith
    I'm trying to add this function using php myadmin, first off I get on error line 5, which is apparently because you need to change the delimiter from ; to something else so i tried this DELIMITER | CREATE FUNCTION LEVENSHTEIN (s1 VARCHAR(255), s2 VARCHAR(255)) RETURNS INT DETERMINISTIC BEGIN DECLARE s1_len, s2_len, i, j, c, c_temp, cost INT; DECLARE s1_char CHAR; DECLARE cv0, cv1 VARBINARY(256); SET s1_len = CHAR_LENGTH(s1), s2_len = CHAR_LENGTH(s2), cv1 = 0x00, j = 1, i = 1, c = 0; IF s1 = s2 THEN RETURN 0; ELSEIF s1_len = 0 THEN RETURN s2_len; ELSEIF s2_len = 0 THEN RETURN s1_len; ELSE WHILE j <= s2_len DO SET cv1 = CONCAT(cv1, UNHEX(HEX(j))), j = j + 1; END WHILE; WHILE i <= s1_len DO SET s1_char = SUBSTRING(s1, i, 1), c = i, cv0 = UNHEX(HEX(i)), j = 1; WHILE j <= s2_len DO SET c = c + 1; IF s1_char = SUBSTRING(s2, j, 1) THEN SET cost = 0; ELSE SET cost = 1; END IF; SET c_temp = CONV(HEX(SUBSTRING(cv1, j, 1)), 16, 10) + cost; IF c > c_temp THEN SET c = c_temp; END IF; SET c_temp = CONV(HEX(SUBSTRING(cv1, j+1, 1)), 16, 10) + 1; IF c > c_temp THEN SET c = c_temp; END IF; SET cv0 = CONCAT(cv0, UNHEX(HEX(c))), j = j + 1; END WHILE; SET cv1 = cv0, i = i + 1; END WHILE; END IF; RETURN c; END DELIMITER ; But I get this error: #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'delimiter | Please help !?

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  • Substitute Items on Internal Sales Orders

    - by ChristineS-Oracle
    Oracle Order Management now enables you to substitute items on internal sales order lines to manage item availability.  Oracle Order Management enables you to substitute items on internal sales order lines to manage item availability. Source organizations can decide to ship a substitute item in case the original item is not available to be shipped. The application supports manual (using Related Items window) and automatic (using ATP functionality) substitutions.To substitute an item on ISO, you must ensure that the value of the Item Substitution on Internal Order system parameter is set to a value other than None. In addition, you must ensure to define substitute item relationships and automatic item substitution setup in the system. The application provides the option to not send the notifications when any change happens on the ISO related to quantity, schedule arrival date, or item. You can control these notifications using the OM: Send Notifications of Internal Order Change profile option. For additional information refer to the Oracle Order Management Release Notes for Release 12.2.4 (Doc ID 1906521.1).

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  • How can I improve this SQL to avoid several problems with its results?

    - by Josh Curren
    I am having some problems with trying to search. Currently this will only return results that have at least 1 row in the maintenance_parts table. I would like it to return results even if there are 0 parts rows. My second problem is that when you search for a vehicle and it should return multiple results (multiple maintenance rows) it will only return 1 result for that vehicle. Some Background Info: The user has 2 fields to fill out. The fields are vehicle and keywords. The vehicle field is meant to allow searching based on the make, model, VIN, truck number (often is 2 - 3 digits or a letter prefix followed by 2 digits), and a few other fields that belong to the truck table. The keywords are meant to search most fields in the maintenance and maintenance_parts tables (things like the description of the work, parts name, parts number). The maintenance_parts table can contain 0, 1, or more rows for each maintenance row. The truck table contains exactly 1 row for every maintenance row. A truck can have multiple maintenance records. "SELECT M.maintenance_id, M.some_id, M.type_code, M.service_date, M.mileage, M.mg_id, M.mg_type, M.comments, M.work_done, MATCH( M.comments, M.work_done) AGAINST( '$keywords' ) + MATCH( P.part_num, P.part_desc, P.part_ref) AGAINST( '$keywords' ) + MATCH( T.truck_number, T.make, T.model, T.engine, T.vin_number, T.transmission_number, T.comments) AGAINST( '$vehicle' ) AS score FROM maintenance M, maintenance_parts P, truck T WHERE M.maintenance_id = P.maintenance_id AND M.some_id = T.truck_id AND M.type_code = 'truck' AND ( (MATCH( T.truck_number, T.make, T.model, T.engine, T.vin_number, T.transmission_number, T.comments) AGAINST( '$vehicle' ) OR T.truck_number LIKE '%$vehicle%') OR MATCH( P.part_num, P.part_desc, P.part_ref) AGAINST( '$keywords' ) OR MATCH( M.comments, M.work_done) AGAINST( '$keywords' ) ) AND M.status = 'A' GROUP BY maintenance_id ORDER BY score DESC, maintenance_id DESC LIMIT 0, $limit"

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  • Partner Webcast – Oracle WebCenter: Digital Transformation with Sites - 14 Nov 2013

    - by Roxana Babiciu
    In order to succeed in today's economy, organizations need to engage with information across all channels to ensure customers, partners and employees have access to the right information in the context of the business process in which they are engaged. The latest release of Oracle WebCenter addresses this challenge with updates across its complete portfolio. Oracle WebCenter Sites enables marketers and business users to easily create and manage contextually relevant social and interactive online experiences across multiple channels on a global scale to drive sales and loyalty. Read more

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  • MySQL search for user and their roles

    - by Jenkz
    I am re-writing the SQL which lets a user search for any other user on our site and also shows their roles. An an example, roles can be "Writer", "Editor", "Publisher". Each role links a User to a Publication. Users can take multiple roles within multiple publications. Example table setup: "users" : user_id, firstname, lastname "publications" : publication_id, name "link_writers" : user_id, publication_id "link_editors" : user_id, publication_id Current psuedo SQL: SELECT * FROM ( (SELECT user_id FROM users WHERE firstname LIKE '%Jenkz%') UNION (SELECT user_id FROM users WHERE lastname LIKE '%Jenkz%') ) AS dt JOIN (ROLES STATEMENT) AS roles ON roles.user_id = dt.user_id At the moment my roles statement is: SELECT dt2.user_id, dt2.publication_id, dt.role FROM ( (SELECT 'writer' AS role, link_writers.user_id, link_writers.publication_id FROM link_writers) UNION (SELECT 'editor' AS role, link_editors.user_id, link_editors.publication_id FROM link_editors) ) AS dt2 The reason for wrapping the roles statement in UNION clauses is that some roles are more complex and require a table join to find the publication_id and user_id. As an example "publishers" might be linked accross two tables "link_publishers": user_id, publisher_group_id "link_publisher_groups": publisher_group_id, publication_id So in that instance, the query forming part of my UNION would be: SELECT 'publisher' AS role, link_publishers.user_id, link_publisher_groups.publication_id FROM link_publishers JOIN link_publisher_groups ON lpg.group_id = lp.group_id I'm pretty confident that my table setup is good (I was warned off the one-table-for-all system when researching the layout). My problem is that there are now 100,000 rows in the users table and upto 70,000 rows in each of the link tables. Initial lookup in the users table is fast, but the joining really slows things down. How can I only join on the relevant roles? -------------------------- EDIT ---------------------------------- Explain above (open in a new window to see full resolution). The bottom bit in red, is the "WHERE firstname LIKE '%Jenkz%'" the third row searches WHERE CONCAT(firstname, ' ', lastname) LIKE '%Jenkz%'. Hence the large row count, but I think this is unavoidable, unless there is a way to put an index accross concatenated fields? The green bit at the top just shows the total rows scanned from the ROLES STATEMENT. You can then see each individual UNION clause (#6 - #12) which all show a large number of rows. Some of the indexes are normal, some are unique. It seems that MySQL isn't optimizing to use the dt.user_id as a comparison for the internal of the UNION statements. Is there any way to force this behaviour? Please note that my real setup is not publications and writers but "webmasters", "players", "teams" etc.

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  • Need help building SQL Query (simple JOIN)

    - by Newbie
    Hello! In my database, I have a "users", a "quests" and a "questings" table. A user can solve a quest. Solving a quest will save the "user_id" and the "quest_id" in my "questings" table. Now, I want to select all quests, a user has NOT solved (meaning there is no entry for this user and quest in "questings" table)! Let's say the user has the id 14. How to write this query? After solving this query, I want to filter the results, too. A quest and a user has a city, too. What to do for writing a query which returns all quests, a user has NOT solved yet, in the users city (user city == quest city)?

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  • SQL Query to select upcoming events with a start and end date

    - by Chris T
    I need to display upcoming events from a database. The problem is when I use the query I'm currently using any events with a start day that has passed will show up lower on the list of upcoming events regardless of the fact that they are current My table (yaml): columns: title: type: string(255) notnull: true default: Untitled Event start_time: type: time end_time: type: time start_day: type: date notnull: true end_day: type: date description: type: string(500) default: This event has no description category_id: integer My query (doctrine): $results = Doctrine_Query::create() ->from("sfEventItem e, e.Category c") ->select("e.title, e.start_day, e.description, e.category_id, e.slug") ->addSelect("c.title, c.slug") ->orderBy("e.start_day, e.start_time, e.title") ->limit(5) ->execute(array(), Doctrine_Core::HYDRATE_ARRAY); Basically I'd like any events that is currently going on (so if today is in between start_day and end_day) to be at the top of the list. How would I go about doing this if it's even possible? Raw sql queries are good answers too because they're pretty easy to turn into DQL.

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  • Evaluate column value into rows

    - by Hugo Palma
    I have a column whose value is a json array. For example: [{"att1": "1", "att2": "2"}, {"att1": "3", "att2": "4"}, {"att1": "5", "att2": "6"}] What i would like is to provide a view where each element of the json array is transformed into a row and the attributes of each json object into columns. Keep in mind that the json array doesn't have a fixed size. Any ideas on how i can achieve this ?

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  • one query instead of four - is it possible?

    - by Syom
    i must get data from four tables. i wrote the script with four queries, but i use it in ajax, and i wan't to do it by one query. here is queries... $query1 = "SELECT `id`,`name_ar` FROM `tour_type` ORDER BY `order`"; $query2 = "SELECT `id`,`name_ar` FROM `hotel_type` ORDER BY `order`"; $query3 = "SELECT `id`,`name_ar` FROM `food_type` ORDER BY `order`"; $query4 = "SELECT `id`,`name_ar` FROM `cities` WHERE `id_parrent` = '$id_parrent' ORDER BY `name_ar`"; is it possible to write in one query? thanks

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  • SQL Selecting from one table OR another then joining the two

    - by Cyprus106
    So this is interesting, and apparently beyond my SQL skillset. I need to select a particular record where an ID="0003" (or whatever) from either table1 or table2 if table1 doesn't have that record. Then I need to join table1 and table2 on a mutual field they both have (field name is Product_ID) I was playing with all sorts of variations of the following, (no, it doesn't work) but after 2 days of groping through the internet and a big SQL book I still can't figure anything out. SELECT ProductStock.Product_ID AS PSID, Products.ID AS PID, ProductStock.*, Products.* FROM ProductStock, Products LEFT JOIN (Products AS Pr) ON Pr.ID=ProductStock.Product_ID WHERE (ProductStock.ID="6003" OR Products.ID="6003")

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  • Database Insider - October 2012 issue

    - by Javier Puerta
    The October issue of the Database Insider newsletter is now available. (Full newsletter here) NEWS   Newly Launched Oracle Exadata X3 Redefines Extreme Performance At Oracle OpenWorld 2012, Oracle announced the general availability of Oracle Exadata Database Machine X3, a complete package of servers, storage, networking, and software that is massively scalable, secure, and fully redundant—and ideally suited for the varied and unpredictable workloads of cloud computing. Read More WEBCASTS What Are Oracle Users Doing to Improve Availability and Disaster Recovery? The Independent Oracle Users Group (IOUG) surveyed more than 350 data managers and professionals regarding planned and unplanned downtime, database high availability, and disaster recovery solutions. Download the report and watch the Webcast today.

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  • Query to find all bars that sell three different beers at the same price

    - by Eternal Learner
    Query to find "All bars that sell three different beers at the same price?" My Tables are Sells(bar,beer,price) - bar - foreign Key.. Bars(name,addr) - name primary key. I thought of something like this but that dosent seem to work ... Select A.bar As bar , B.bar as bar From Sells AS A, Sells AS B Where A.bar = B.bar and A.beer <> B.beer Group By(A.beer) Having Count(Distinct A.beer) >= 2 Is this the correct SQL query ?

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  • writting an sql query

    - by Praveen Prasad
    iam having 2 tables table Items Table (this table holds all items iam having) itemId --------- Item1 Item2 Item3 Item4 Item5 table 2 users_item relation UserId || ItemId 1 || Item1 1 || Item2 userId one has stored 2 items Item1,Item2. Now i want to write a query on table1 (Items table) so that it displays all items which user1 has NOT chosen.

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  • Bookmark these Useful Support Notes

    - by DebaChatterjee-Oracle
    I am often asked by customers whether we have a document or paper on frequently asked Multitenant questions ? Since a FAQ type page needs to be frequently updated we have created a note in My Oracle Support. This note is maintained by Oracle Support and is continuously updated as we find new questions from our customers.  You can access the FAQ page here (1511619.1).  In addition to this page we have also created a master note for the Multitenant Option. This note is a good starting point for learning the basics of Oracle Multitenant. The master note can be accessed here (1519699.1).

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