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  • New Video: Oracle and Intel Collaboration

    - by Cinzia Mascanzoni
    We just published a webcast discussing the technical collaboration between Oracle and Intel. The panel highlights the recent collaborations on elastic computing, Oracle Database In-Memory, and the newly announced products Exadata Database Machine X4-8 and Sun Server X4-8. In addition, panelists reflect on the specific technical advances that have resulted from over twenty years of partnership.

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  • Transforming your Business with Oracle Consulting

    Stephan Scholl Senior Vice President, North America Consulting talks about the role that the 11,000+ professionals in Oracle Consulting play in helping customers transform their businesses and reap the benefits of the latest releases on their Oracle solutions.

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  • Get latest record from second table left joined to first table

    - by codef0rmer
    I have a candidate table say candidates having only id field and i left joined profiles table to it. Table profiles has 2 fields namely, candidate_id & name. e.g. Table candidates: id 1 2 and Table `profiles`: candidate_id name 1 Foobar 1 Foobar2 2 Foobar3 i want the latest name of a candidate in a single query which is given below: SELECT C.id, P.name FROM candidates C LEFT JOIN profiles P ON P.candidate_id = C.id GROUP BY C.id ORDER BY P.name; But this query returns: 1 Foobar 2 Foobar3 Instead of: 1 Foobar2 2 Foobar3

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  • Complex data ordering...

    - by Povylas
    Hi, I have one tables ids in an array and they are ordered in the way I want and I have to select data from another table using those ids and in a order they are listen in the array. Pretty confusing but I was thinking of two solutions giving ORDER BY parameter the array but I do not know if that possible and another is to get all the necessary data and then turn it to array (mysql_fetch_assoc) then compare those two and somehow order the new array using the ids array. But I also do not know how to do this... Any ideas?

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  • Need MYSQL query for finding lowest score per game player

    - by Chris Barnhill
    I have a game on Facebook called Rails Across Europe. I have a Best Scores page where I show the players with the best 20 scores, which in game terms refers to the lowest winning turn. The problem is that there are a small number of players who play frequently, and their scores dominate the page. I'd like to make the scores page open to more players. So I thought that I could display the single lowest winning turn for each player instead of displaying all of the lowest winning turns for all players. The problem is that the query for this eludes me. So I hope that one of you brilliant StackOverflow folks can help me with this. I have included the relevant MYSQL table schemas below. Here are the the table relationships: player_stats contains statistics for either a game in progress or a completed game. If a game is in progress, winning_turn is zero (which means that games with a winning_turn of zero should not be included in the query). player_stats has a game_player table id reference. game_player contains data describing games currently in progress. game_player has a player table id reference. player contains data describing a person who plays the game. Here's the query I'm currently using: 'SELECT p.fb_user_id, ps.winning_turn, gp.difficulty_level, c.name as city_name, g.name as goods_name, d.cost FROM game_player as gp, player as p, player_stats as ps, demand as d, city as c, goods as g WHERE p.status = "ACTIVE" AND gp.player_id = p.id AND ps.game_player_id = gp.id AND d.id = ps.highest_demand_id AND c.id = d.city_id AND g.id = d.goods_id AND ps.winning_turn > 0 ORDER BY ps.winning_turn ASC, d.cost DESC LIMIT '.$limit.';'; Here are the relevant table schemas: -- -- Table structure for table `player_stats` -- CREATE TABLE IF NOT EXISTS `player_stats` ( `id` int(11) NOT NULL auto_increment, `game_player_id` int(11) NOT NULL, `winning_turn` int(11) NOT NULL, `highest_demand_id` int(11) NOT NULL, PRIMARY KEY (`id`), KEY `game_player_id` (`game_player_id`,`highest_demand_id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=3814 ; -- -- Table structure for table `game_player` -- CREATE TABLE IF NOT EXISTS `game_player` ( `id` int(10) unsigned NOT NULL auto_increment, `game_id` int(10) unsigned NOT NULL, `player_id` int(10) unsigned NOT NULL, `player_number` int(11) NOT NULL, `funds` int(10) unsigned NOT NULL, `turn` int(10) unsigned NOT NULL, `difficulty_level` enum('STANDARD','ADVANCED','MASTER','ULTIMATE') NOT NULL, `date_last_used` datetime NOT NULL, PRIMARY KEY (`id`), KEY `game_id` (`game_id`,`player_id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=3814 ; -- -- Table structure for table `player` -- CREATE TABLE IF NOT EXISTS `player` ( `id` int(11) NOT NULL auto_increment, `fb_user_id` char(255) NOT NULL, `fb_proxied_email` text NOT NULL, `first_name` char(255) NOT NULL, `last_name` char(255) NOT NULL, `birthdate` date NOT NULL, `date_registered` datetime NOT NULL, `date_last_logged_in` datetime NOT NULL, `status` enum('ACTIVE','SUSPENDED','CLOSED') NOT NULL, PRIMARY KEY (`id`), KEY `fb_user_id` (`fb_user_id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=1646 ;

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  • Please verify the trigger created below for delete is correct or not?

    - by Parth
    Please verify the trigger created below for delete is correct or not? Its for the insertion of every field of deleted row in audit table.. Please reply whether this trigger will work for me? delimiter // CREATE TRIGGER audit_menu BEFORE DELETE ON menu FOR EACH ROW BEGIN INSERT INTO audit (menuid, field, oldvalue, changedone) VALUES (OLD.menuid, 'name', OLD.name, UNIX_TIMESTAMP() ), (OLD.menuid, 'age', OLD.age, UNIX_TIMESTAMP() ), (OLD.menuid, 'address', OLD.address, UNIX_TIMESTAMP() ), (OLD.menuid, 'sex', OLD.sex, UNIX_TIMESTAMP() ), (OLD.menuid, 'town', OLD.town, UNIX_TIMESTAMP() ) END;// delimiter ;

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  • How to concatinate text on existing database entry?

    - by Starx
    I am a table, whose structure is somewhat like this id, name, link the link holds the name of the page like "link" = "index.php". Now I want to update this field and add "page=" in front of "index.php". Using this method I would like to update every entry in my table. My desired SQL syntax need to be something like this UPDATE mytable set link= 'page=' + <existing value of link> WHERE 1; I am using Where 1; to denote every other rows Anyone know what to accomplish this?

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  • Export CSV from Mysql

    - by ss888
    Hi, I'm having a bit of trouble exporting a csv file that is created from one of my mysql tables using php. The code I'm using prints the correct data, but I can't see how to download this data in a csv file, providing a download link to the created file. I thought the browser was supposed to automatically provide the file for download, but it doesn't. (Could it be because the below code is called using ajax?) Any help greatly appreciated - code below, S. include('../config/config.php'); //db connection settings $query = "SELECT * FROM isregistered"; $export = mysql_query ($query ) or die ( "Sql error : " . mysql_error( ) ); $fields = mysql_num_fields ( $export ); for ( $i = 0; $i < $fields; $i++ ) { $header .= mysql_field_name( $export , $i ) . "\t"; } while( $row = mysql_fetch_row( $export ) ) { $line = ''; foreach( $row as $value ) { if ( ( !isset( $value ) ) || ( $value == "" ) ) { $value = "\t"; } else { $value = str_replace( '"' , '""' , $value ); $value = '"' . $value . '"' . "\t"; } $line .= $value; } $data .= trim( $line ) . "\n"; } $data = str_replace( "\r" , "" , $data ); if ( $data == "" ) { $data = "\n(0) Records Found!\n"; } //header("Content-type: application/octet-stream"); //have tried all of these at sometime //header("Content-type: text/x-csv"); header("Content-type: text/csv"); //header("Content-type: application/csv"); header("Content-Disposition: attachment; filename=export.csv"); //header("Content-Disposition: attachment; filename=export.xls"); header("Pragma: no-cache"); header("Expires: 0"); echo '<a href="">Download Exported Data</a>'; //want my link to go in here... print "$header\n$data";

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  • MySQL Hibernate sort on 2 columns

    - by sammichy
    I have a table as follows Table item { ID - Primary Key content - String published_date - When the content was published create_date - When this database entry was created } Every hour (or specified time interval) I run a process to update this table with data from different sources (websites). I want to display the results according to the following rules. 1. The entries created each time the process runs should be grouped together. So the entries from the 2nd process run will always be after the entries from the first process run even if the published_date of an entry from the first run is after the published_date of an entry from the 2nd run. 2. Within the grouping by run, the entries by sorted by published_date 3. Another restriction is that I prefer that data from the same source not be grouped together. If I do the sort by create_date, published_date I will end up with data from source a, data from source b etc. I prefer that the data within each hour be mixed up for better presentation If I add a column to this table and store a counter which increments each time the process is run, it is possible to create a query to sort first by counter and then by published_dt. Is there a way to do it without adding a field? I'm using Hibernate over MySQL. e.g. Hour 1 (run 1) 4 rows collected from site a (rows 1-4) 3 rows collected from site b (rows 5-7) hour 2 (run 2) 2 row collected from site a (rows 8-9) 3 rows collected from site b (rows 10-12) ... After each run, new records are added to the database from each website. The create date is the time when the record was created in the database. The published date is part of the content and is read in from the external source. When the results are displayed I would like rows to be grouped together based on the hour they were published in. So rows 1-7 would be displayed before rows 8-12. Within each hourly grouping, I would like to sort the results by published date (timestamp). This is necessary so that the posts from all the sites collected in that hour are not grouped together but rather mixed in with each other.

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  • Oracle CRM On Demand Release 16

    Sandi Main Director, Oracle CRM On Demand Product Management provides an update on the features of this exciting new release. Learn how you can leverage Oracle CRM On Demand Release 16 to increase productivity and maximize your business needs.

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  • How to return null value if the query has no corresponding value?

    - by Holicreature
    Hi i've a query select c.name as companyname, u.name,u.email,u.role,a.date from useraccount u, company c, audittrial a where u.status='active' and u.companyid=c.id and (u.companyid=a.companyID and a.activity like 'User activated%' and a.email=u.email) order by u.companyid desc limit 10 So if the following part doesnt't satisfy, (u.companyid=a.companyID and a.activity like 'User activated%' and a.email=u.email) no rows will be returned.. but i want to return the result of the following query select c.name as companyname, u.name,u.email,u.role,a.date from useraccount u, company c, audittrial a where u.status='active' and u.companyid=c.id order by u.companyid desc limit 10 but to add that, i should return the date if available and return null value if date is not available.. how can i do this?

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  • login not working when changing from mysql to mysqli

    - by user1438647
    I have a code below where it logs a teacher in by matching it's username and password in the database, if correct, then log in, if incorrect, then display a message. <?php session_start(); $username="xxx"; $password="xxx"; $database="mobile_app"; $link = mysqli_connect('localhost',$username,$password); mysqli_select_db($link, $database) or die( "Unable to select database"); foreach (array('teacherusername','teacherpassword') as $varname) { $$varname = (isset($_POST[$varname])) ? $_POST[$varname] : ''; } ?> <form action="<?php echo htmlentities($_SERVER['PHP_SELF']); ?>" method="post" id="teachLoginForm"> <p>Username</p><p><input type="text" name="teacherusername" /></p> <!-- Enter Teacher Username--> <p>Password</p><p><input type="password" name="teacherpassword" /></p> <!-- Enter Teacher Password--> <p><input id="loginSubmit" type="submit" value="Login" name="submit" /></p> </form> <?php if (isset($_POST['submit'])) { $query = " SELECT * FROM Teacher t WHERE (t.TeacherUsername = '".mysqli_real_escape_string($teacherusername)."') AND (t.TeacherPassword = '".mysqli_real_escape_string($teacherpassword)."') "; $result = mysqli_query($link, $query); $num = mysqli_num_rows($result); $loged = false; while($row = mysqli_fetch_array($result)) { if ($_POST['teacherusername'] == ($row['TeacherUsername']) && $_POST['teacherpassword'] == ($row['TeacherPassword'])) { $loged = true; } $_SESSION['teacherforename'] = $row['TeacherForename']; $_SESSION['teachersurname'] = $row['TeacherSurname']; $_SESSION['teacherusername'] = $row['TeacherUsername']; } if ($loged == true){ header( 'Location: menu.php' ) ; }else{ echo "The Username or Password that you Entered is not Valid. Try Entering it Again."; } mysqli_close($link); } ?> Now the problem is that even if the teacher has entered in the correct username and password, it still doesn't let the teacher log in. When the code above was the old mysql() code, it worked fine as teacher was able to login when username and password match, but when trying to change the code into mysqli then it causes login to not work even though username and password match. What am I doing wrong?

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  • PHP/MySQL Interview - How would you have answered?

    - by martincarlin87
    I was asked this interview question so thought I would post it here to see how other users would answer: Please write some code which connects to a MySQL database (any host/user/pass), retrieves the current date & time from the database, compares it to the current date & time on the local server (i.e. where the application is running), and reports on the difference. The reporting aspect should be a simple HTML page, so that in theory this script can be put on a web server, set to point to a particular database server, and it would tell us whether the two servers’ times are in sync (or close to being in sync). This is what I put: // Connect to database server $dbhost = 'localhost'; $dbuser = 'xxx'; $dbpass = 'xxx'; $dbname = 'xxx'; $conn = mysql_connect($dbhost, $dbuser, $dbpass) or die (mysql_error()); // Select database mysql_select_db($dbname) or die(mysql_error()); // Retrieve the current time from the database server $sql = 'SELECT NOW() AS db_server_time'; // Execute the query $result = mysql_query($sql) or die(mysql_error()); // Since query has now completed, get the time of the web server $php_server_time = date("Y-m-d h:m:s"); // Store query results in an array $row = mysql_fetch_array($result); // Retrieve time result from the array $db_server_time = $row['db_server_time']; echo $db_server_time . '<br />'; echo $php_server_time; if ($php_server_time != $db_server_time) { // Server times are not identical echo '<p>Database server and web server are not in sync!</p>'; // Convert the time stamps into seconds since 01/01/1970 $php_seconds = strtotime($php_server_time); $sql_seconds = strtotime($db_server_time); // Subtract smaller number from biggest number to avoid getting a negative result if ($php_seconds > $sql_seconds) { $time_difference = $php_seconds - $sql_seconds; } else { $time_difference = $sql_seconds - $php_seconds; } // convert the time difference in seconds to a formatted string displaying hours, minutes and seconds $nice_time_difference = gmdate("H:i:s", $time_difference); echo '<p>Time difference between the servers is ' . $nice_time_difference; } else { // Timestamps are exactly the same echo '<p>Database server and web server are in sync with each other!</p>'; } Yes, I know that I have used the deprecated mysql_* functions but that aside, how would you have answered, i.e. what changes would you make and why? Are there any factors I have omitted which I should take into consideration? The interesting thing is that my results always seem to be an exact number of minutes apart when executed on my hosting account: 2012-12-06 11:47:07 2012-12-06 11:12:07

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  • NHibernate and MySql is inserting and Selecting, not updating

    - by Chris Brandsma
    Something strange is going on with NHibernate for me. I can select, and I can insert. But I can't do and update against MySql. Here is my domain class public class UserAccount { public virtual int Id { get; set; } public virtual string UserName { get; set; } public virtual string Password { get; set; } public virtual bool Enabled { get; set; } public virtual string FirstName { get; set; } public virtual string LastName { get; set; } public virtual string Phone { get; set; } public virtual DateTime? DeletedDate { get; set; } public virtual UserAccount DeletedBy { get; set; } } Fluent Mapping public class UserAccountMap : ClassMap<UserAccount> { public UserAccountMap() { Table("UserAccount"); Id(x => x.Id); Map(x => x.UserName); Map(x => x.Password); Map(x => x.FirstName); Map(x => x.LastName); Map(x => x.Phone); Map(x => x.DeletedDate); Map(x => x.Enabled); } } Here is how I'm creating my Session Factory var dbconfig = MySQLConfiguration .Standard .ShowSql() .ConnectionString(a => a.FromAppSetting("MySqlConnStr")); FluentConfiguration config = Fluently.Configure() .Database(dbconfig) .Mappings(m => { var mapping = m.FluentMappings.AddFromAssemblyOf<TransactionDetail>(); mapping.ExportTo(mappingdir); }); and this is my NHibernate code: using (var trans = Session.BeginTransaction()) { var user = GetById(userId); user.Enabled = false; user.DeletedDate = DateTime.Now; user.UserName = "deleted_" + user.UserName; user.Password = "--removed--"; Session.Update(user); trans.Commit(); } No exceptions are being thrown. No queries are being logged. Nothing.

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  • How to concatenate text on existing database entry?

    - by Starx
    I have a table, whose fields are id, name, link the link holds the name of the page like "link" = "index.php". Now I want to update this field and add "page=" in front of "index.php". Using this method I would like to update every entry in my table. My desired SQL syntax need to be something like this UPDATE mytable set link= 'page=' + <existing value of link> WHERE 1; I am using 'WHERE 1;' to denote every row. Anyone know how to accomplish this?

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  • Create table with PHP and populate from MySQL

    - by typoknig
    Hi all, I am creating a table to display on a web page and that table is populated from data in a MySQL database. I am trying to do a couple of things that are making it difficult for me. First I am trying to have call the PHP code that exists in a separate file in HTML via JavaScript. I think I have that working right but I am not 100% sure (because the table will not display). I think it is working right because some of the code for the table (which is in the PHP file) displays in FireBug. Second I am trying to make it so the rows alternate colors for easy viewing too. My PHP code so far is below. The table does not display at all in any browser. $query = "SELECT * FROM employees"; $result = mysql_query($query); $num = mysql_num_rows($result); echo '<table>'; for ($i = 0; $i < $num; $i++){ $row = mysql_fetch_array($result); $id = $row['id']; $l_name = $row['l_name']; $f_name = $row['f_name']; $ssn = $row['ssn']; $class = (($i % 2) == 0) ? "table_odd_row" : "table_even_row"; echo "<tr>"; echo "<td class=" . $class . ">$wrap_id</td>"; echo "<td class=" . $class . ">$wrap_l_name</td>"; echo "<td class=" . $class . ">$wrap_f_name</td>"; echo "<td class=" . $class . ">$wrap_ssn</td>"; echo "</tr>"; } echo '</table>'; mysql_close($link); }

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  • Drupal - db_fetch_array returns NULL for every row

    - by darudude
    I'm using Drupal's db_fetch_array to fetch rows from my db_query. However, every row returned is equal to NULL. Typing the query into PHP myadmin works, so I have no idea whats going on. db_num_rows returns the number of rows as well. Here is the code: if(count($rebuild_ids)) { $ids=implode(",",$rebuild_ids); $type_stmt = "SELECT * from {" . ItemType::$type_table_name . "} where id IN ($ids)"; $new_items=db_query($type_stmt); if(!$new_items || db_num_rows($new_items) == 0) { return; } while($row = db_fetch_array($new_items)); { if ($row!=NULL) { echo "I work!" $game_items[] = $row['id']; ItemInstance::$nid_to_item_type_code[$row['nid']] = $row['id']; } } } However, it never gets into the third if statement (i.e. never echos "I work!") Any ideas?

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  • Oracle Virtual Compute Appliance Launch Channel Update Webcast - May 28

    - by Roxana Babiciu
    Join us for an Oracle Virtual Compute Appliance (OVCA) launch update for the channel. This training webcast is a follow up to the OVCA launch on April 16. We will provide a brief product overview of OVCA followed by some great OPN program content, resell criteria, OPN Incentive Program and Demo Equipment Program details. There will be two sessions to accommodate each region. Additionally, don’t miss the latest Oracle Virtual Compute Appliance article packed with great information!

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  • Data from two tables without repeating data from the first?

    - by Aran
    I have two tables. Users table and Users Meta Table I am looking for a way to get all the information out of both tables with one query. But without repeating the information from Users table. This is all information relating to the users id number as well. So for example user_id = 1. Is there a way to query the database and collect all the information I from both tables without repeating the information from the first?

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  • What could be the Consequence of inserting "id" in any autoincrementing 'id' containing table?

    - by Parth
    What could be the Consequence of inserting "id" in any autoincrementing 'id' containing table? If I have a Tabe in which I have configured the column "id" as the auto incrmented, But still I am using an INSERT query in which id is defined, like wise INSERT INTO XYZ (id) values ('26'); How does it going to effect the table and the process related to it.. Is it "no issues" to do this? or it should be avoided?

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