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  • how to find the last instance of a setting in a config file

    - by Glenn Kelley
    I am trying to figure out how to find the last entry of a string in multiple config files across a server. Each of the strings will be in the /home/***usernamewouldbehere/public_html/typo3conf/localconf.php file In short - the last entry in the config files will point to the database server the application is utilizing - and we need to know which accounts point to which db server. While I can run something like this - grep "$_db_host" /home/*/public_html/conf/localconf.php It does not really help much because it gives us way to much information ... and not what we really need. What i really need to know is the last entry of this string $_db_host = 'xx'; and to sort them out in an export file Since the config files may have multiple entries (example below) $_db_host = 'localhost'; $_db_host = '10.0.1.234'; It would be great to list in a file all of those that have the entry for 'localhost' and then list all of those that have the entry for '10.0.1.234' (or whichever server there may be there) but even if I need to do that manually that would be great. I am not sure how to get to it using Awk - ... and really stuck What I am hoping for is something that would be piped as follows db_host = localhost /home/username1/www/conf/localconf.php db_host = localhost / home/username2/public_html/conf/localconf.php db_host= '10.1.2.23' /home/username55/public_html/conf/localconf.php hoping that helps you help me :-)

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  • Suggestions of the easiest algorithms for some Graph operations

    - by Nazgulled
    Hi, The deadline for this project is closing in very quickly and I don't have much time to deal with what it's left. So, instead of looking for the best (and probably more complicated/time consuming) algorithms, I'm looking for the easiest algorithms to implement a few operations on a Graph structure. The operations I'll need to do is as follows: List all users in the graph network given a distance X List all users in the graph network given a distance X and the type of relation Calculate the shortest path between 2 users on the graph network given a type of relation Calculate the maximum distance between 2 users on the graph network Calculate the most distant connected users on the graph network A few notes about my Graph implementation: The edge node has 2 properties, one is of type char and another int. They represent the type of relation and weight, respectively. The Graph is implemented with linked lists, for both the vertices and edges. I mean, each vertex points to the next one and each vertex also points to the head of a different linked list, the edges for that specific vertex. What I know about what I need to do: I don't know if this is the easiest as I said above, but for the shortest path between 2 users, I believe the Dijkstra algorithm is what people seem to recommend pretty often so I think I'm going with that. I've been searching and searching and I'm finding it hard to implement this algorithm, does anyone know of any tutorial or something easy to understand so I can implement this algorithm myself? If possible, with C source code examples, it would help a lot. I see many examples with math notations but that just confuses me even more. Do you think it would help if I "converted" the graph to an adjacency matrix to represent the links weight and relation type? Would it be easier to perform the algorithm on that instead of the linked lists? I could easily implement a function to do that conversion when needed. I'm saying this because I got the feeling it would be easier after reading a couple of pages about the subject, but I could be wrong. I don't have any ideas about the other 4 operations, suggestions?

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  • ASP.NET MVC Action with ApplicationPath

    - by Leandro
    Hi, i'm creating a mvc application and i'll use under subdomain like _http://myapp.mycompany.com, this subdomain is pointing to app subdirectory, but my actions are generated with applicationPath (subdirectory) always: _http://myapp.mycompany.com/myapp/Home/About. i want _http://myapp.mycompany.com/Home/About only, without applicationPath prefix. Exists any configuration for this?? I'm using the correct methods: <%= Html.ActionLink("About", "About", "Home") % Actions rendered without ApplicationPath prefix, is possible in asp.net routing? * Please, ignore undescore prefix in urls, but i'm novice in stackoverflow and i can't post valid urls =/

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  • Oracle Magazine, May/June 2010

    Oracle Magazine May/June features articles on cloud computing, Oracle Data Mining, Oracle and Sun, java, StorageTek Enterprise Backup software, Oracle Application Development Framework libraries, Oracle Database with Oracle Developer Tools for Visual Studio, Steven Feuerstein on PL/SQL best practices, Oracle Warehouse builder 11g release 2, Tom Kyte on Edition-Based Redefinition (part 3) and much more.

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  • SSH into Ubuntu Linux on a box without a static IP address

    - by Steven Xu
    Basically, how do I do it? I'd like to connect to my home computer from work, but my internet is routed through my apartment building's network, so I don't have the static IP address I'm accustomed to having. How do I go about accessing my home computer through SSH (I'll be using Putty at work if it matters) if my home computer doesn't have a static IP address?

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  • Oracle Magazine, July/August 2005

    Oracle Magazine July/August 2005 features articles on the IT challenges and solutions of small and midsize businesses, Linux clusters as data warehousing solutions, EJB 3.0, developing PHP applications against Oracle XML DB, Oracle LogMiner, Oracle JDeveloper and Oracle ADF, and much more.

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  • intalling linecache-0.46 gem(I am using rbenv)

    - by user2899281
    While bundle install the error: Gem::Installer::ExtensionBuildError: ERROR: Failed to build gem native extension. /home/launchpad/.rbenv/versions/1.9.3-p448/bin/ruby extconf.rb Can't handle 1.9.x yet * extconf.rb failed * Could not create Makefile due to some reason, probably lack of necessary libraries and/or headers. Check the mkmf.log file for more details. You may need configuration options. Provided configuration options: --with-opt-dir --without-opt-dir --with-opt-include --without-opt-include=${opt-dir}/include --with-opt-lib --without-opt-lib=${opt-dir}/lib --with-make-prog --without-make-prog --srcdir=. --curdir --ruby=/home/launchpad/.rbenv/versions/1.9.3-p448/bin/ruby Gem files will remain installed in /home/launchpad/.rbenv/versions/1.9.3-p448/lib/ruby/gems/1.9.1/gems/linecache-0.46 for inspection. Results logged to /home/launchpad/.rbenv/versions/1.9.3-p448/lib/ruby/gems/1.9.1/gems/linecache-0.46/ext/gem_make.out An error occurred while installing linecache (0.46), and Bundler cannot continue. Make sure that gem install linecache -v '0.46' succeeds before bundling.

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  • foreach() error handling - how do make it do nothing?

    - by Jared
    Hey all, This should be very basic, but I am a little stumped! Here is my array: $menu = array( 'Home', 'Stuff'=>array( 'Losta Stuff', 'Less Stuff', 'Ur moms stuff', 'FAQ' ), 'Public Works' ); Here is my logic: echo "<ol>\n"; foreach( (array)$menu as $header ) { echo ' <li><b>'.$header."</b><br />\n"; echo ' <ol>'; foreach( (array)$header as $headers ) { echo ' <li>'.$headers.".</li>\n"; } echo ' </ol>'; } echo "</ol>\n"; As you can see, Home and Public Works don't have data in the them, so I get a Warning: Invalid argument supplied for foreach() in test.php on line ## If I add (array) to $header like this: foreach( (array)$header as $headers ), It no longer gives me the error, but it just displays the $header as the $headers (i.e. Home - Home, Instead of Home - nothing). Basically, if the data is empty, I want it to do nothing!

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  • Execute a BASH command in Python-- in the same process

    - by Baldur
    I need to execute the command . /home/db2v95/sqllib/db2profile before I can import ibm_db_dbi in Python 2.6. Executing it before I enter Python works: baldurb@gigur:~$ . /home/db2v95/sqllib/db2profile baldurb@gigur:~$ python Python 2.6.4 (r264:75706, Dec 7 2009, 18:45:15) [GCC 4.4.1] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> import ibm_db_dbi >>> but executing it in Python using os.system(". /home/db2v95/sqllib/db2profile") or subprocess.Popen([". /home/db2v95/sqllib/db2profile"]) results in an error. What am I doing wrong? Edit: this is the error I receive: > Traceback (most recent call last): > File "<file>.py", line 8, in > <module> > subprocess.Popen([". /home/db2v95/sqllib/db2profile"]) > File > "/usr/lib/python2.6/subprocess.py", > line 621, in __init__ > errread, errwrite) File "/usr/lib/python2.6/subprocess.py", > line 1126, in _execute_child > raise child_exception OSError: [Errno 2] No such file or directory

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  • Image Hover-HTML CSS

    - by LostSchemer
    I am having trouble creating a different image to appear when you place your curser over the original image. Heres my code without the rest of my listed buttons: <nav class="buttons"> <ul> <li class="left"> <a class="home" href="www.google.com"> <img src="img/Home_2.png"></a></li> </ul> </nav> Css: .buttons img{width: 190px; margin:0px; padding:0px; margin:0 auto; margin-top:55px;} .buttons ul{list-style-type: none; margin:0px; padding:0px} .left{float:left} .home:hover {background: url(../img/Home_crack.PNG)} Any suggestions? EDIT: Okay great suggestions, however when I hover over the "home button" now the stuff in the float tweeks out. Heres the code with the full float properties: HTML: <nav class="buttons"> <ul> <li class="left"> <a class="home" href="www.google.com"> <img src="img/Home_2.png"></a></li> <li class="left"> <a href="www.google.com" class="menu"> <img src="img/Menu_2.png"></a></li> <li class="right"> <a href="www.google.com" class="about"> <img src="img/About_2.png"></a></li> <li class="right"> <a href="www.google.com" class="contact"> <img src="img/Contact_2.png"></a></li> </ul> </nav> CSS: .buttons img{width: 190px; margin:0px; padding:0px; margin:0 auto; margin-top:55px;} .buttons ul{list-style-type: none; margin:0px; padding:0px} .left{float:left} .home:hover img{display:none} .home:hover {background: url(../img/Home_crack.PNG);} .right{float:right} Basically i wanted to separate 4 buttons.... one in the left float and one in the right float, then on the hover, the buttons would change to a different image....With the new img{display:none} the left float rapidly flashes.

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  • "You have already activated" message even when using bundle exec

    - by juanpastas
    I am installing gems in my Gemfile in shared path as Capistrano does by default, and when I run: bundle exec rake assets:precompile RAILS_ENV=production I get: You have already activated rake 0.9.2.2, but your Gemfile requires rake 10.0.4. Using bundle exec may solve this. See that: cat Gemfile.lock | grep rake returns: rake (>= 0.8.7) rake (10.0.4) This is my gem environment output: - RUBYGEMS VERSION: 1.8.24 - RUBY VERSION: 1.9.3 (2013-06-27 patchlevel 448) [x86_64-linux] - INSTALLATION DIRECTORY: /home/bitnami/my_app/shared/bundle/ruby/1.9.1/ - RUBY EXECUTABLE: /opt/bitnami/ruby/bin/ruby - EXECUTABLE DIRECTORY: /home/bitnami/my_app/shared/bundle/ruby/1.9.1/bin - RUBYGEMS PLATFORMS: - ruby - x86_64-linux - GEM PATHS: - /home/bitnami/my_app/shared/bundle/ruby/1.9.1/ - GEM CONFIGURATION: - :update_sources => true - :verbose => true - :benchmark => false - :backtrace => false - :bulk_threshold => 1000 - "gemhome" => "/home/bitnami/my_app/shared/bundle/ruby/1.9.1/" - "gempath" => ["/home/bitnami/my_app/shared/bundle/ruby/1.9.1/"] - REMOTE SOURCES: - http://rubygems.org/ Update which -a rake /opt/bitnami/rvm/bin/rake /opt/bitnami/ruby/bin/rake Update 2 I tried giving full path to rake, but same problem

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  • Script to dynamically change the source of an iframe tag

    - by Ukavi
    I want a code that will dynamically change the source of an iframe tag when a hyperlink is clicked for example I have one master page that should load content from other web pages using the iframe tag when a hyperlink is clicked but I don't know how to do it. Here is my code <html> <head> <title> </title> <style type="text/css"> #content{ margin-right:30%; margin-bottom: 10px; padding: 10px; border: 1px solid #000; margin-left:17%; background-repeat:no-repeat; width:686; height:640; } </style> <script type="text/javascript"> function hyperlinkChanger(hyperLink) { switch (hyperLink) { case "home": var url="home.html"; return url; break; case "about_Us": var url="about_us.html"; return url; break; case "contact_Us: var url="contact_us.html"; return url; break; } } </script> </head> <body> <a href="home.html" name="home" onClick="hyperlinkChanger('home')">Home</a> <br /> <a href="about_us.html" name="about_Us" onClick="hyperlinkChanger('about_Us')">About Us</a> <br /> <a href="contact_us.html" name="contact_Us" onClick="hyperlinkChanger('contact_Us')">Contact us</a> <br /> <div name="content"> <!--please help me write a method to call the output of the funcion hyperlinkChanger--> <iframe src="hyprlink function" width="600" height="300"> </iframe> </div> </body> </html>

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