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  • Oracle Magazine, July/August 2008

    Oracle Magazine July/August features articles on business intelligence, Linux, green technology, Oracle OpenWorld, Oracle Advanced Compression, Oracle Total Recall, managing files, using database advisors, Linux kernel, page template consistency, handling exceptions, client result cache, and much more.

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  • Django install on a shared host, .htaccess help

    - by redconservatory
    I am trying to install Django on a shared host using the following instructions: docs.google.com/View?docid=dhhpr5xs_463522g My problem is with the following line on my root .htaccess: RewriteRule ^(.*)$ /cgi-bin/wcgi.py/$1 [QSA,L] When I include this line I get a 500 error with almost all of my domains on this account. My cgi-bin directory is home/my-username/public_html/cgi-bin/ The wcgi.py file contains: #!/usr/local/bin/python import os, sys sys.path.insert(0, "/home/username/django/") sys.path.insert(0, "/home/username/django/projects") sys.path.insert(0, "/home/username/django/projects/newprojects") import django.core.handlers.wsgi os.chdir("/home/username/django/projects/newproject") # optional os.environ['DJANGO_SETTINGS_MODULE'] = "newproject.settings" def runcgi(): environ = dict(os.environ.items()) environ['wsgi.input'] = sys.stdin environ['wsgi.errors'] = sys.stderr environ['wsgi.version'] = (1,0) environ['wsgi.multithread'] = False environ['wsgi.multiprocess'] = True environ['wsgi.run_once'] = True application = django.core.handlers.wsgi.WSGIHandler() if environ.get('HTTPS','off') in ('on','1'): environ['wsgi.url_scheme'] = 'https' else: environ['wsgi.url_scheme'] = 'http' headers_set = [] headers_sent = [] def write(data): if not headers_set: raise AssertionError("write() before start_response()") elif not headers_sent: # Before the first output, send the stored headers status, response_headers = headers_sent[:] = headers_set sys.stdout.write('Status: %s\r\n' % status) for header in response_headers: sys.stdout.write('%s: %s\r\n' % header) sys.stdout.write('\r\n') sys.stdout.write(data) sys.stdout.flush() def start_response(status,response_headers,exc_info=None): if exc_info: try: if headers_sent: # Re-raise original exception if headers sent raise exc_info[0], exc_info[1], exc_info[2] finally: exc_info = None # avoid dangling circular ref elif headers_set: raise AssertionError("Headers already set!") headers_set[:] = [status,response_headers] return write result = application(environ, start_response) try: for data in result: if data: # don't send headers until body appears write(data) if not headers_sent: write('') # send headers now if body was empty finally: if hasattr(result,'close'): result.close() runcgi() Only I changed the "username" to my username...

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  • Remove part of the URL with .htaccess

    - by Gabriel Bianconi
    Hello. I've changed some settings in my website, and now I need to redirect from: www.plugb.com/home/game/a www.plugb.com/home/something/else www.plugb.com/home/game/b ... to www.plugb.com/game/a www.plugb.com/something/else www.plugb.com/game/b ... I don't know how to do this with .htaccess. BTW, I'm using CodeIgniter. Thanks in advance.

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  • putting <%=yield %> in a partial for ajax jquery calls

    - by odpogn
    I'm trying to make the "home" link in my <%= render 'layouts/header' %> do an ajax/jquery call to change the <%= yield %> in a partial inside my content div. all i get are blanks in the view.. <%= yield %> works fine when put in a partial without ajax, but it doesn't display anything when using ajax... can yield not be used this way? all I'm really looking for is the ability to click on my sites navigation links without having to reload the entire page... my application.html.erb file looks like so: <head> $(function() { $("#home").live("click", function() { $.get(this.href, null, null, "script"); return false; }); }); </head> <body> <div id="container"> <%= render 'layouts/header' %> <div id="content"> <%= render 'layouts/content' %> </div> <%= render 'layouts/footer' %> </div> </body> my <%= render 'layouts/header' %> contains: <%= link_to "Home", root_path, :id => "home" %> my <%= render 'layouts/content' %> only contains: <%= yield %> home.js.erb $("#content").html("<%= escape_javascript(render("layouts/content")) %>");

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  • How to structure a multilingual website for search engines?

    - by Nirmal
    I have this website which decides on the display language by a GET parameter. http://www.mysite.com/index.php?page=home&locale=en which is rewritten as http://www.mysite.com/en/home When no language is specified, the system defaults to English (en). Now how do I tell the search engines that many versions of the website exist? When the search bot enters the site, it will trigger the default English Language and after finishing, will just leave the site without considering other languages. I can very well have a sitemap with links to the default pages of each language, so the bot can navigate from there. But how do I say the bot that the entry in the sitemap is the home page for that language? Like if someone searches for 'mi sitio', they should be presented with the result http://www.mysite.com/es/home and not some other internal page. Any light on this? Thanks.

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  • Oracle Magazine, January/February 2006

    Oracle Magazine January/February 2006 features articles on Oracle and Microsoft, embedded Oracle, business intelligence, SQL editors, XML Audit, PL/SQL Best Practices, Oracle XML DB, Oracle Data Provider for .NET, Oracle JDeveloper, Oracle ADF, JavaServer Faces, and much more.

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  • Using find and tar with files with special characters in the name

    - by Costi
    I want to archive all .ctl files in a folder, recursively. tar -cf ctlfiles.tar `find /home/db -name "*.ctl" -print` The error message : tar: Removing leading `/' from member names tar: /home/db/dunn/j: Cannot stat: No such file or directory tar: 74.ctl: Cannot stat: No such file or directory I have these files: /home/db/dunn/j 74.ctl and j 75. Notice the extra space. What if the files have other special characters? How do I archive these files recursively?

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  • Grouping a generic list via LINQ in VB.NET

    - by CD Smith
    I need to take a collection and group it via Linq but all the examples I've seen fail in some manner or other with some syntax difference that I can't quite lick. My collection: Dim a As New List(Of ProcessAlert) a.Add(New ProcessAlert("0000112367", "[email protected]", "Alert", 2)) a.Add(New ProcessAlert("0000112367", "[email protected]", "Document", 2)) a.Add(New ProcessAlert("0000112367", "[email protected]", "Note", 2)) a.Add(New ProcessAlert("0000112367", "[email protected]", "Alert", 1)) a.Add(New ProcessAlert("0000112367", "[email protected]", "Document", 1)) a.Add(New ProcessAlert("0000112367", "[email protected]", "Note", 1)) Return a I need to turn this collection into a simple way to give this final outcome: "[email protected]", "Alert, Document, Note" "[email protected]", "Alert, Document, Note" Here's the definition of the ProcessAlert class: Public Class ProcessAlert Public LoanNumber As String Public EmailAddress As String Public AlertType As String Public AlertMethodID As Byte End Class Thanks in advance, CD

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  • Sourcing a shell script, while running with sudo

    - by WishCow
    I would like to write a shell script that sets up a mercurial repository, and allow all users in the group "developers" to execute this script. The script is owned by the user "hg", and works fine when ran. The problem comes when I try to run it with another user, using sudo, the execution halts with a "permission denied" error, when it tries to source another file. The script file in question: create_repo.sh #!/bin/bash source colors.sh REPOROOT="/srv/repository/mercurial/" ... rest of the script .... Permissions of create_repo.sh, and colors.sh: -rwxr--r-- 1 hg hg 551 2011-01-07 10:20 colors.sh -rwxr--r-- 1 hg hg 1137 2011-01-07 11:08 create_repo.sh Sudoers setup: %developer ALL = (hg) NOPASSWD: /home/hg/scripts/create_repo.sh What I'm trying to run: user@nebu:~$ id uid=1000(user) gid=1000(user) groups=4(adm),20(dialout),24(cdrom),46(plugdev),105(lpadmin),113(sambashare),116(admin),1000(user),1001(developer) user@nebu:~$ sudo -l Matching Defaults entries for user on this host: env_reset User user may run the following commands on this host: (ALL) ALL (hg) NOPASSWD: /home/hg/scripts/create_repo.sh user@nebu:~$ sudo -u hg /home/hg/scripts/create_repo.sh /home/hg/scripts/create_repo.sh: line 3: colors.sh: Permission denied So the script is executed, but halts when it tries to include the other script. I have also tried using: user@nebu:~$ sudo -u hg /bin/bash /home/hg/scripts/create_repo.sh Which gives the same result. What is the correct way to include another shell script, if the script may be ran with a different user, through sudo?

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  • Oracle Magazine, July/August 2009

    Oracle Magazine July/August features articles on business efficiency with Oracle data warehousing, business intelligence and enterprise performance management; Oracle Enterprise Linux and Oracle Unbreakable Linux support, Oracle OpenWorld preview, open source, Oracle Application Development Framework, best PL/SQL practices, security for Oracle Application Express applications, Microsoft Visual Studio for .NET and Oracle Database, Oracle Data Pump, Tom Kyte answering your questions and much more.

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  • How can I change the Python that my Django project is using?

    - by Burak
    I have 2 versions installed in my server. I used virtualenv to install Python 2.7. I am using WSGI to deploy my project. WSGIPythonPath /home/ENV/lib/python2.7/site-packages WSGIScriptAlias / /var/www/html/my_project/wsgi.py My http.conf is like that. python -V gives Python 2.7.3 But in my projects Debug window, it says Django is using 2.6.8. Where am I wrong? UPDATE: Here is my wsgi file import os import sys sys.path.append('/var/www/html') os.environ.setdefault("DJANGO_SETTINGS_MODULE", "myproject.settings") from django.core.wsgi import get_wsgi_application application = get_wsgi_application() Python Version: 2.6.8 Python Path: ['/home/ENV/lib/python2.7/site-packages/setuptools-0.6c11-py2.7.egg', '/home/ENV/lib/python2.7/site-packages/pip-1.1-py2.7.egg', '/home/ENV/lib/python2.7/site-packages/Django-1.4-py2.7.egg', '/home/ENV/lib/python2.7/site-packages', '/usr/lib/python2.6/site-packages/pip-1.1-py2.6.egg', '/usr/lib/python2.6/site-packages/django_transmeta-0.6.7-py2.6.egg', '/usr/lib/python2.6/site-packages/ipython-0.13-py2.6.egg', '/usr/lib/python2.6/site-packages/virtualenv-1.7.2-py2.6.egg', '/usr/lib64/python26.zip', '/usr/lib64/python2.6', '/usr/lib64/python2.6/plat-linux2', '/usr/lib64/python2.6/lib-tk', '/usr/lib64/python2.6/lib-old', '/usr/lib64/python2.6/lib-dynload', '/usr/lib64/python2.6/site-packages', '/usr/lib64/python2.6/site-packages/gtk-2.0', '/usr/lib/python2.6/site-packages', '/usr/lib/python2.6/site-packages/setuptools-0.6c11-py2.6.egg-info', '/var/www/html'] In my error_log of httpd: [Tue Jul 10 20:51:29 2012] [error] python_init: Python version mismatch, expected '2.6.7', found '2.6.8'. [Tue Jul 10 20:51:29 2012] [error] python_init: Python executable found '/usr/bin/python'. [Tue Jul 10 20:51:29 2012] [error] python_init: Python path being used '/usr/lib64/python26.zip:/usr/lib64/python2.6/:/usr/lib64/python2.6/plat-linux2:/usr/lib64/python2.6/lib-tk:/usr/lib64/python2.6/lib-old:/usr/lib64/python2.6/lib-dynload'.

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  • Oracle Magazine, May/June 2006

    Oracle Magazine May/June 2006 features articles on Oracle developer tools, Semantic Web, Lucasfilm, Manpower, PL/SQL Best Practices, SQL Developer, ODP.NET and Oracle Database 10g Release 2, PHP, Oracle Application Express, and much more.

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  • ASP.NET MVC Default URL View

    - by Moose Factory
    I'm trying to set the Default URL of my MVC application to a view within an area of my application. The area is called "Common", the controller "Home" and the view "Index". I've tried setting the defaultUrl in the forms section of web.config to "~/Common/Home/Index" with no success. I've also tried mapping a new route in global.asax, thus: routes.MapRoute( "Area", "{area}/{controller}/{action}/{id}", new { area = "Common", controller = "Home", action = "Index", id = "" } ); Again, to no avail.

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  • Static content not displayed with Zend FW

    - by shin
    I am trying to display a static content with Zend framework. When I go to http://square.localhost/content/services, I get an error message. Could anyone tell me how to fix this please? Thanks in advance. application.ini .... .... resources.layout.layoutPath = APPLICATION_PATH "/layouts" resources.layout.layout = "master" resources.router.routes.home.route = /home resources.router.routes.home.defaults.module = default resources.router.routes.home.defaults.controller = index resources.router.routes.home.defaults.action = index resources.router.routes.static-content.route = /content/:page resources.router.routes.static-content.defaults.module = default resources.router.routes.static-content.defaults.controller = static-content resources.router.routes.static-content.defaults.action = display application/modules/default/controllers/StaticContentController.php class StaticContentController extends Zend_Controller_Action { public function init() { } // display static views public function displayAction() { $page = $this->getRequest()->getParam('page'); if (file_exists($this->view->getScriptPath(null) . "/" . $this->getRequest()->getControllerName() . "/$page." . $this->viewSuffix)) { $this->render($page); } else { throw new Zend_Controller_Action_Exception('Page not found', 404); } } } application/modules/default/views/scripts/static-content/services.phtml some html ... ... Error message An error occurred Page not found Exception information: Message: Page not found Stack trace: #0 /var/www/square/library/Zend/Controller/Action.php(513): StaticContentController->displayAction() #1 /var/www/square/library/Zend/Controller/Dispatcher/Standard.php(295): Zend_Controller_Action->dispatch('displayAction') #2 /var/www/square/library/Zend/Controller/Front.php(954): Zend_Controller_Dispatcher_Standard->dispatch(Object(Zend_Controller_Request_Http), Object(Zend_Controller_Response_Http)) #3 /var/www/square/library/Zend/Application/Bootstrap/Bootstrap.php(97): Zend_Controller_Front->dispatch() #4 /var/www/square/library/Zend/Application.php(366): Zend_Application_Bootstrap_Bootstrap->run() #5 /var/www/square/public/index.php(26): Zend_Application->run() #6 {main} Request Parameters: array ( 'page' => 'services', 'module' => 'default', 'controller' => 'static-content', 'action' => 'display', )

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