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  • How can I set a default sort for tables in PHPMyAdmin (i.e. always "Primary key - Descending")

    - by jeremyclarke
    Even though its obnoxious in a lot of ways I use PHPMyAdmin all the time to debug database issues while writing PHP. By default it sorts tables by primary key ascending. 99% of the time I would rather have the newest data (my test data) shown at the top by default rather than the useless first few records ever saved. Is there a way to configure PHPMyAdmin to show the newest records by default? To alter similar behavior?

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  • Find node level in a tree

    - by Álvaro G. Vicario
    I have a tree (nested categories) stored as follows: CREATE TABLE `category` ( `category_id` int(10) unsigned NOT NULL AUTO_INCREMENT, `category_name` varchar(100) NOT NULL, `parent_id` int(10) unsigned DEFAULT NULL, PRIMARY KEY (`category_id`), UNIQUE KEY `category_name_UNIQUE` (`category_name`,`parent_id`), KEY `fk_category_category1` (`parent_id`,`category_id`), CONSTRAINT `fk_category_category1` FOREIGN KEY (`parent_id`) REFERENCES `category` (`category_id`) ON DELETE SET NULL ON UPDATE CASCADE ) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_spanish_ci I need to feed my client-side language (PHP) with node information (child+parent) so it can build the tree in memory. I can tweak my PHP code but I think the operation would be way simpler if I could just retrieve the rows in such an order that all parents come before their children. I could do that if I knew the level for each node: SELECT category_id, category_name, parent_id FROM category ORDER BY level -- No `level` column so far :( Can you think of a way (view, stored routine or whatever...) to calculate the node level? I guess it's okay if it's not real-time and I need to recalculate it on node modification.

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  • SQL Select -> product -> comments -> user

    - by user1492716
    thanks for yout time helping on this ;) I'm new to SQL and wish to solve somethign in just one query and i dont know how to do it.- Basically I've a table of products, a table of users and a table of comments, linked by products.id - comments.pid and user.id - comments.uid , i wish to know what is the best practice to create just 1 query and get all products with child comments, including username.

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  • How can I fake sql data while preserving statements without commenting my server-side code?

    - by Fedor
    I have to use hardcoded values for certain fields because at this moment we don't have access to the real data. When we do get access, I don't want to go through a lot of work uncommenting. Is it possible to keep this statement the way it is, except use '25' as the alias for ratecode? IF(special.ratecode IS NULL, br.ratecode, special.ratecode) AS ratecode, I have about 8 or so IF statements similar to this and I'm just too lazy ( even with vim ) to re-append while commenting out each if statement line by line. I would have to do this: $sql = 'SELECT u.*,'; // IF ( special.ratecode IS NULL, br.ratecode, special.ratecode) AS ratecode $sql.= '25 AS ratecode';

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  • How to structure data... Sequential or Hierarchical?

    - by Ryan
    I'm going through the exercise of building a CMS that will organize a lot of the common documents that my employer generates each time we get a new sales order. Each new sales order gets a 5 digit number (12222,12223,122224, etc...) but internally we have applied a hierarchy to these numbers: + 121XX |--01 |--02 + 122XX |--22 |--23 |--24 In my table for sales orders, is it better to use the 5 digital number as an ID and populate up or would it be better to use the hierarchical structure that we use when referring to jobs in regular conversation? The only benefit to not populating sequentially seems to be formatting the data later on in my view, but that doesn't sound like a good enough reason to go through the extra work. Thanks

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  • Need help with jquery json data transfer from php file

    - by Scarface
    Hey guys I am trying to return the latest 10 results of a query from a php file, through json format, to a jquery getjson function that prints results. I am getting weird problems though. For example I am only getting 8 entries returned, and some are disordered, and sometimes nothing is returned. I am not really sure what I am doing wrong, so if anyone has any ideas I would really appreciate it. This is my query ($res) SELECT time, user, message FROM comments WHERE topic_id='$topic_id' ORDER BY time DESC LIMIT 10 This is the processing of the results while($row = mysql_fetch_array($res)){ $message=$row['message']; $user=$row['user']; if($row['message'] AND $row['time'] > $_GET['time']) $data[] = $row; } $out = json_encode($data); print $out; And this is the retrieval where prepare is just a function that returns information into a div $.getJSON(files+"processing.php?action=load&time="+0+"&topic_id="+topic_id+"&t=" + (new Date()), function(json) { if(json.length) { for(i=0; i < 10; i++) { $('#comment-list').prepend(prepare(json[i])); $('#list-' + count).fadeIn(1500); } } }); function prepare(response) { count++; var string = '<li class="comment-list" id="list-'+count+'">' //organize info into a div +'</li>'; return string; }

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  • indexing question

    - by user522962
    I have a table w/ 3 columns: name, phone, date. I have 3 indexes: 1 on phone, 1 on date and 1 on phone and date. I have the following statement: SELECT * FROM ( SELECT * FROM people WHERE phone IS NOT NULL ORDER BY date DESC) as t GROUP BY phone Basically, I want to get all unique phone numbers ordered by date. This table has about 2.5 million rows but takes forever to execute....are my indexes right? UPDATE: My EXPLAIN statement comes back with 2 rows: 1 for primary table and 1 for derived table. It says I am using temporary and using filesort for my primary table. For my derived table, it says my possible keys are (phone), and (phone, date) but it is using filesort.

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  • Problem while redirecting user after registration

    - by Eternal Learner
    I am creating a simple website . My situation is like this. After registering an user, I want to redirect the user after say 3 seconds to a main page(if the registration succeeds) . The code I have now is as below $query = "INSERT INTO Privileges VALUES('$user','$password1','$role')"; $result = mysql_query($query, $dbcon) or die('Registration Failed: ' . mysql_error()); print 'Thanks for Registering , You will be redirected shortly'; ob_start(); echo "Test"; header("Location: http://www.php.net"); ob_flush() I get the error message Warning: Cannot modify header information - headers already sent by (output started at/home/srinivasa/public_html/ThanksForRegistering.php:27) in /home/srinivasa /public_html/ThanksForRegistering.php on line 35. What do I need to do now ?

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  • PHP & HTML Purifier Error: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given

    - by TaG
    I'm trying to Integrate HTML Purifier http://htmlpurifier.org/ to filter my user submitted data but I get the following error below. And I was wondering how can I fix this problem? I get the following error. on line 22: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given line 22 is. if (mysqli_num_rows($dbc) == 0) { Here is the php code. if (isset($_POST['submitted'])) { // Handle the form. require_once '../../htmlpurifier/library/HTMLPurifier.auto.php'; $config = HTMLPurifier_Config::createDefault(); $config->set('Core.Encoding', 'UTF-8'); // replace with your encoding $config->set('HTML.Doctype', 'XHTML 1.0 Strict'); // replace with your doctype $purifier = new HTMLPurifier($config); $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.*, profile.* FROM users INNER JOIN contact_info ON contact_info.user_id = users.user_id WHERE users.user_id=3"); $about_me = mysqli_real_escape_string($mysqli, $purifier->purify($_POST['about_me'])); $interests = mysqli_real_escape_string($mysqli, $purifier->purify($_POST['interests'])); if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO profile (user_id, about_me, interests) VALUES ('$user_id', '$about_me', '$interests')"); } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE profile SET about_me = '$about_me', interests = '$interests' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { // There was an error...do something about it here... print mysqli_error($mysqli); return; } }

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  • help me with the following sql query

    - by rupeshmalviya
    could somebody correct my following query, i am novice to software development realm, i am to a string builder object in comma separated form to my query but it's not producing desired result qyery is as follows and string cmd = "SELECT * FROM [placed_student] WHERE passout_year=@passout AND company_id=@companyId AND course_id=@courseId AND branch_id IN('" + sb + "')"; StringBuilder sb = new StringBuilder(); foreach (ListItem li in branch.Items) { if (li.Selected == true) { sb.Append(Convert.ToInt32(li.Value) +", "); } } li is integer value of my check box list which are getting generated may be differne at different time ...please also suggest me some good source to learn sql..

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  • 2 IP are stored for a visitor : PROXY ?

    - by Tristan
    Hello, on my database i've decided to store IP of the visitors who answoers to polls. It's all working, but there is only 2 cases where not only 1 IP is stored, but there is 2 SAME ip for the same visitor MySQLL output (i replaced 2 numbers by XX) 10.188.XX.129, 10.188.XX.129 Here's the script to recieve the IP of the visitor : <?php function realip() { if (isset($_SERVER)) { if (isset($_SERVER["HTTP_X_FORWARDED_FOR"])) { $realip = $_SERVER["HTTP_X_FORWARDED_FOR"]; } elseif (isset($_SERVER["HTTP_CLIENT_IP"])) { $realip = $_SERVER["HTTP_CLIENT_IP"]; } else { $realip = $_SERVER["REMOTE_ADDR"]; } } else { if ( getenv( 'HTTP_X_FORWARDED_FOR' ) ) { $realip = getenv( 'HTTP_X_FORWARDED_FOR' ); } elseif ( getenv( 'HTTP_CLIENT_IP' ) ) { $realip = getenv( 'HTTP_CLIENT_IP' ); } else { $realip = getenv( 'REMOTE_ADDR' ); } } return $realip; } ? Thanks

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  • Can we use a sql data field as column name instead?

    - by Starx
    First a query SELECT * FROM mytable WHERE id='1' Gives me a certain number of rows For example id | context | cat | value 1 Context 1 1 value 1 1 Context 2 1 value 2 1 Context 1 2 value 3 1 Context 2 2 value 4 Now my problem instead of receiving the result in such way I want it is this way instead id | cat | Context 1 | Context 2 1 1 value 1 value 2 1 2 value 3 value 4

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  • detection of 'flush tables with read lock' in php

    - by theduke0
    I would like to know from my application if a myisam table can accept writes (i.e. not locked). If an exception is thrown, everything is fine as I can catch this and log the failed statement to a file. However, if a 'flush tables with read lock' command has been issued (possibly for backup), the query I send will pretty much hang out forever. If one table is locked at a time, insert delayed works well. But when this global lock is applied, my query just waits. The query I run is an insert statement. If this statement fails or hangs, user experience is degraded. I need a way to send the query to the server and forget about it (pretty much). Does anyone have any suggestions on how to deal with this? -set a query timeout? -run asyncronous request and allow for the lock to expire while application continues? -fork my php process? Please let me know if I can provide and clarification or details.

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  • Why does this properly escaped SQL query fail?

    - by Jason Rhodes
    Here's the query: INSERT INTO jobemails (jobid, to, subject, message, headers, datesent) VALUES ('340', '[email protected]', 'We\'ve received your request for a photo shoot called \'another\'.', 'message', 'headers', '2010-04-22 15:55:06') The datatypes are all correct, it always fails at the subject, so it must be how I'm escaping the values, I assume. I'm sure one of you will see my idiot mistake right away. A little help?

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  • reterview data from two tables using inner join in cakephp

    - by user3593884
    I two tables from database one as user(id,first_name,last_name) and the second table location(id,country). I need to perform inner join with this two tables and the list should display first_name,last_name,country with condition user.id=location.id I have written sql queries in cakephp $this->set('users',$this->User->find('list', array( 'fields' => array('User.id', 'User.first_name','location.country'), array('joins' => array(array('table' => 'location', 'alias' => 'location', 'type' => 'INNER', 'conditions' => array('User.id = location.id'))))))); i get error -Unknown column 'location.country' in 'field list' Please help!

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  • Obtaining a timestamp every minute from a database

    - by soumen
    This is my table structure: +------------+-----------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +------------+-----------+------+-----+---------+-------+ | uid | char(255) | NO | MUL | NULL | | | cid | char(255) | NO | MUL | NULL | | | ip_address | char(15) | NO | | NULL | | | user_agent | char(255) | YES | | NULL | | | open_date | datetime | NO | MUL | NULL | | | referrer | char(255) | YES | | NULL | | | environ | text | YES | | NULL | | | country | char(255) | NO | MUL | NULL | | +------------+-----------+------+-----+---------+-------+ I want to get a timestamp every minute within a range. select DATE_ADD(open_date,interval 1 minute) as m from open_track.camp_open where open_date between "2009-05-13 00:00:00" and "2009-05-13 23:59:59" limit 10; outputs +---------------------+ | m | +---------------------+ | 2009-05-13 00:01:01 | | 2009-05-13 00:01:02 | | 2009-05-13 00:01:03 | | 2009-05-13 00:01:03 | | 2009-05-13 00:01:04 | | 2009-05-13 00:01:05 | | 2009-05-13 00:01:06 | | 2009-05-13 00:01:08 | | 2009-05-13 00:01:08 | | 2009-05-13 00:01:09 | +---------------------+ Please advise me.

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  • PHP - displaying 1 random record for each week

    - by mike
    I want to display 1 random record from a database based on the week. I need to determine if it's a new, and if it is a new week, then select the record and display the new record. I'm thinking I can just use a single day of the week to generate the new record, either way will work. I'm really having a hard time conceptualizing how I'll store the record id and not select a new one when someone visits again the same day or refreshes the page. Any ideas? Let me know if I wasn't clear enough.

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  • Error during data INSERT in php

    - by nectar
    here my code- $sql = "INSERT INTO tblpin ('pinId', 'ownerId', 'usedby', 'status') VALUES "; for($i=0; $i0) { $sql .= ", "; } $sql .= "('$pin[$i]', '$ownerid', 'Free', '1')"; } $sql .= ";"; echo $sql; mysql_query($sql); if(mysql_affected_rows() 0) { echo "done"; } else { echo "Fail"; } output: ** INSERT INTO tblpin ('pinId', 'ownerId', 'usedby', 'status') VALUES ('13837927', 'admin', 'Free', '1'), ('59576082', 'admin', 'Free', '1'); Fail why it is not inserting values when $sql query is right?

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  • php and SQL_CALC_FOUND_ROWS

    - by Lizard
    I am trying to add the SQL_CALC_FOUND_ROWS into a query (Please note this isn't for pagination) please note I am trying to add this to a cakePHP query the code I currently have is below: return $this->find('all', array( 'conditions' => $conditions, 'fields'=>array('SQL_CALC_FOUND_ROWS','Category.*','COUNT(`Entity`.`id`) as `entity_count`'), 'joins' => array('LEFT JOIN `entities` AS Entity ON `Entity`.`category_id` = `Category`.`id`'), 'group' => '`Category`.`id`', 'order' => $sort, 'limit'=>$params['limit'], 'offset'=>$params['start'], 'contain' => array('Domain' => array('fields' => array('title'))) )); Note the 'fields'=>array('SQL_CALC_FOUND_ROWS',' this obviously doesn't work as It tries to apply the SQL_CALC_FOUND_ROWS to the table e.g. SELECTCategory.SQL_CALC_FOUND_ROWS, Is there anyway of doing this? Any help would be greatly appreciated, thanks.

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  • Inserting Record into multiple tables No Common ID

    - by the_
    OK so I have two tables, MEDIA and BUSINESS. I want it set up so the forms to input into them are on the same page. MEDIA has a row that is biz_id that is the id of BUSINESS. So MEDIA is really a part of BUSINESS. HOW do I insert/add these into their tables without a common ID because I haven't yet made the record for business? I'm sorry I didn't really word this very much... You might need more clarification to answer properly and I'll be glad to give any more info. Any help would be greatly appreciated, thanks!

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