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  • check if a table exsist in where

    - by Luca Romagnoli
    This query generates an error because table2 doesn't exist: Select * FROM table WHERE table2.id IS NOT NULL Is there anything like this for check the table2 before apply the check on the id? Select * FROM table WHERE (EXIST(table2) AND table2.id IS NOT NULL) or not EXIST(table2) Thanks

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  • Inserting Record into multiple tables No Common ID

    - by the_
    OK so I have two tables, MEDIA and BUSINESS. I want it set up so the forms to input into them are on the same page. MEDIA has a row that is biz_id that is the id of BUSINESS. So MEDIA is really a part of BUSINESS. HOW do I insert/add these into their tables without a common ID because I haven't yet made the record for business? I'm sorry I didn't really word this very much... You might need more clarification to answer properly and I'll be glad to give any more info. Any help would be greatly appreciated, thanks!

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  • indexing question

    - by user522962
    I have a table w/ 3 columns: name, phone, date. I have 3 indexes: 1 on phone, 1 on date and 1 on phone and date. I have the following statement: SELECT * FROM ( SELECT * FROM people WHERE phone IS NOT NULL ORDER BY date DESC) as t GROUP BY phone Basically, I want to get all unique phone numbers ordered by date. This table has about 2.5 million rows but takes forever to execute....are my indexes right? UPDATE: My EXPLAIN statement comes back with 2 rows: 1 for primary table and 1 for derived table. It says I am using temporary and using filesort for my primary table. For my derived table, it says my possible keys are (phone), and (phone, date) but it is using filesort.

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  • How to properly design a simple favorites and blocked table?

    - by Nils Riedemann
    Hey, i am currently writing a webapp in rails where users can mark items as favorites and also block them. I came up two ways and wondered which one is more common/better way. 1. Separate join tables Would it be wise to have 2 tables for this? Like: users_favorites - user_id - item_id users_blocked - user_id - item_id 2. single table users_marks (or so) - users_id - item_id - type (["fav", "blk"]) Both ways seem to have advantages. Which one would you use and why?

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  • Drupal 6: moving localhost to server | clear cached data

    - by artmania
    Hi friends, I worked on localhost to build my drupal site. then, I moved to server. Steps: Clear cache tables (Site Configuration Performance Clear Cached Data button) on localhost Export db and then import on live server Move files/folders to live server Edit settings.php to reflect live server config everything is working great until I make Clear Cached Data on Server. than my custom theme, custom front page, etc... all mess up :( What can be the problem? I appreciate helps so much!! Thanks! !!SORTED!! I used a subtheme for Zen, named mgf . then I had taken a back-up as mgf- somehow after I make Clear Cached Data, Drupal links to this mgf- which is old and doesnt have latest stylings. I just removed this folder from themes, and it linked to the right-latest mgf.

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  • How would I go about writing a conditional statement to check if visitor is coming from a particular

    - by Matthew
    Hello guys, What I have in mind is this... We are going to have people come from a particular site during a acquisition campaign and was wondering how I could conditionalize a certain section of my site to display a thank you message instead of the sign up form as they would have had the opportunity to fill this out before coming to my landing page. I have seen solutions like: $referal = mysql_real_escape_string($_SERVER['HTTP_REFERER']); I would like to know if this is the best way to get this to work??? - okay this is what i think might work. The third party website that is referring people to our landing page once the form on that site has been filled out can push into the record a hidden input value of "www.sample.com" or whatever... then I can have something check the for that particular value and fire off the conidtional. Does that even sound right?

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  • PHP - displaying 1 random record for each week

    - by mike
    I want to display 1 random record from a database based on the week. I need to determine if it's a new, and if it is a new week, then select the record and display the new record. I'm thinking I can just use a single day of the week to generate the new record, either way will work. I'm really having a hard time conceptualizing how I'll store the record id and not select a new one when someone visits again the same day or refreshes the page. Any ideas? Let me know if I wasn't clear enough.

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  • select field information with min time value

    - by Scarface
    Hey guys quick question, I thought I was doing the right thing but I keep getting the wrong result. I am trying to simply find the id of the entry with the min time, but I am not getting that entry. $qryuserscount1="SELECT id,min(entry_time) FROM scrusersonline WHERE topic_id='$topic_id'"; $userscount1=mysql_query($qryuserscount1); while ($row2 = mysql_fetch_assoc($userscount1)) { echo $onlineuser= $row2['id']; } That is my query, and it does not work. This however does work which does not make sense to me SELECT id FROM scrusersonline WHERE topic_id='$topic_id' ORDER by entry_time LIMIT 1, can anyone quickly point out what I am doing wrong?

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  • Does Doctrine 1.2 support importing indexes with Doctrine_Core::generateModelsFromDb function?

    - by Coagulant
    Does Doctrine 1.2 support importing indexes with Doctrine_Core::generateModelsFromDb() function? I need to make a migration between 2 database connections, one of them having unique index on 2 fields and one doesn't. And my migration is empty. It looks like Doctrine doesn't support indexes when importing from databae, other than those tied to relationship foreign keys. $changes = Doctrine_Core::generateMigrationsFromDiff($migrationsPath, array('doctrineOld'), array('doctrine'));

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  • Allow users to pull temporary data then delete table?

    - by JM4
    I don't know the best way to title this question but am trying to accomplish the following goal: When a client logs into their profile, they are presented with a link to download data from an existing database in CSV format. The process works, however, I would like for this data to be 'fresh' each time they click the link so my plan was - once a user has clicked the link and downloaded the CSV file, the database table would 'erase' all of its data and start fresh (be empty) until the next set of data populated it. My EXISTING CSV creation code: <?php $host = 'localhost'; $user = 'username'; $pass = 'password'; $db = 'database'; $table = 'tablename'; $file = 'export'; $link = mysql_connect($host, $user, $pass) or die("Can not connect." . mysql_error()); mysql_select_db($db) or die("Can not connect."); $result = mysql_query("SHOW COLUMNS FROM ".$table.""); $i = 0; if (mysql_num_rows($result) > 0) { while ($row = mysql_fetch_assoc($result)) { $csv_output .= $row['Field'].", "; $i++; } } $csv_output .= "\n"; $values = mysql_query("SELECT * FROM ".$table.""); while ($rowr = mysql_fetch_row($values)) { for ($j=0;$j<$i;$j++) { $csv_output .= '"'.$rowr[$j].'",'; } $csv_output .= "\n"; } $filename = $file."_".date("Y-m-d",time()); header("Content-type: application/vnd.ms-excel"); header("Content-disposition: csv" . date("Y-m-d") . ".csv"); header( "Content-disposition: filename=".$filename.".csv"); print $csv_output; exit; ?> any ideas?

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  • Help constructing query - Compare columns and replace numbers

    - by Tommy
    I have a feeling that this query is pretty easy to construct, I just can't figure it out. I want to replace all numbers in table X column C, with numbers in table Z column A, where numbers from table X column C matches numbers in table Z column B. I hope that makes sense. Perhaps a little background information will make it clearer. I've converted from one CMS to another, and the module I used to convert mapped the ids to the new database. Table X column A is the new id's. Table X column B is the old id's. Table Z is the table for an image gallery that I migrated, and column C contains the id's of the images owners. Can anyone crack this nut?

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  • Django database - how to add this column in raw SQL.

    - by alex
    Suppose I have my models set up already. class books(models.Model): title = models.CharField... ISBN = models.Integer... What if I want to add this column to my table? user = models.ForeignKey(User, unique=True) How would I write the raw SQL in my database so that this column works?

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  • Error during data UPDATE in php

    - by Piyush
    $sql = "UPDATE tblprofile SET name = '$membername' , f_h_name = '$fathername', maritalS = '$mstatus' , dob = '$dob' , occupation = '$occupation' , nominee = '$nominee' , address1 = '$address1' , address2 = '$address2', city = '$city', district = '$district', state = '$state', pin = '$areapin', mobile = '$mobileno', email = '$email', PANno = '$panno', bankname = '$bankname', branch = '$branch', accountno = '$accountno' WHERE userId = '$_SESSION['UserId']' "; //line 212 if(mysql_query($sql)) { echo "Updation Done."; } Error comes in browser : Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in C:\xampp\htdocs\303\saveEditProfile.php on line 212

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  • select query related problem

    - by user222585
    i have interest rate and amount in a table where interest rate are ranged in different values like 4.5,4.6,5.2,5.6 etc. i want to get sum of amounts classified by interest rate where interest rate will be separated by .25. for example all amount having interest rate 1.25,1.3,1.4 will be in one group and 1.5,1.67,1.9 will be in another group how can i write the query?

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  • Running a sharded DB from a single machine

    - by ming yeow
    This sounds kinda dumb, but I have a sharded DB that I no longer think I need to run on 2 machines, and would like to run on one single machine instead. Any ideas on how that can potentially be done? There are lots of resources on how i can achieve the converse, but very little on how this can be done

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  • SQL with codition on calculated value

    - by user619893
    I have a table with products, their amount and their price. I need to select all entries where the average price per article is between a range. My query so far: SELECT productid,AVG(SUM(price)/SUM(amount)) AS avg FROM stock WHERE avg=$from AND avg<=$to GROUP BY productid If do this, it tells me avg doesnt exist. Also i obviously need to group by because the sum and average need to be per wine

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  • Want to avoid the particular rows from select join query... See description

    - by OM The Eternity
    I have a Select Left Join Query whis displays me the rows for the latest changedone(its a time) column name ("field" should not be equal) column name ("trackid" should not be equal), and column name "Operation should be "UPDATE" ", below is the query I am talking about... SELECT j1. * FROM jos_audittrail j1 LEFT OUTER JOIN jos_audittrail j2 ON ( j1.trackid != j2.trackid AND j1.field != j2.field AND j1.changedone < j2.changedone ) WHERE j1.operation = 'UPDATE' AND j2.id IS NULL Now here I don't want a row to be displayed with a two particular column's value i.e. "field's value" the value is "LastvisitDate" and "hits" Now if if append the condition in the above query that " AND j1.field != 'lastvistDate' AND j1.field != 'hits' " theni do not get any result... The table structure is jos_audittrail: id trackid operation oldvalue newvalue table_name live changedone(its a time) I hope i have given the details properly If u still find something missing I will try to provide it more better way... Pls help me to avoid those two rows with those to mentioned value of "field"

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  • Tracking Votes and only allowing 1 vote per member

    - by MikeAdams
    What I'm trying to do is count the votes when someone votes on a "page". I think I lost myself trying to figure out how to track when a member votes or not. I can't seem to get the code to tell when a member has voted. //Generate code ID $useXID = intval($_GET['id']); $useXrank = $_GET['rank']; //if($useXrank!=null && $useXID!=null) { $rankcheck = mysql_query('SELECT member_id,code_id FROM code_votes WHERE member_id="'.$_MEMBERINFO_ID.'" AND WHERE code_id="'.$useXID.'"'); if(!mysql_fetch_array($rankcheck) && $useXrank=="up"){ $rankset = mysql_query('SELECT * FROM code_votes WHERE member_id="'.$_MEMBERINFO_ID.'"'); $ranksetfetch = mysql_fetch_array($rankset); $rankit = htmlentities($ranksetfetch['ranking']); $rankit+="1"; mysql_query("INSERT INTO code_votes (member_id,code_id) VALUES ('$_MEMBERINFO_ID','$useXID')") or die(mysql_error()); mysql_query("UPDATE code SET ranking = '".$rankit."' WHERE ID = '".$useXID."'"); } elseif(!mysql_fetch_array($rankcheck) && $useXrank=="down"){ $rankset = mysql_query('SELECT * FROM code_votes WHERE member_id="'.$_MEMBERINFO_ID.'"'); $ranksetfetch = mysql_fetch_array($rankset); $rankit = htmlentities($ranksetfetch['ranking']); $rankit-="1"; mysql_query("INSERT INTO code_votes (member_id,code_id) VALUES ('$_MEMBERINFO_ID','$useXID')") or die(mysql_error()); mysql_query("UPDATE code SET ranking = '".$rankit."' WHERE ID = '".$useXID."'"); } // hide vote links since already voted elseif(mysql_fetch_array($rankcheck)){$voted="true";} //}

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  • Database Formatting for Album Tracks

    - by Sev
    I would like to store album's track names in a single field in a database. The number of tracks are arbitrary for each album. Each album is one record in the table. Each track must be linked to a specific URL which also should be stored in the database somewhere. Is it possible to do this by storing them in a single field, or is a relational table for the track names/urls the only way to go?

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  • Should I change $_REQUEST to $_POST

    - by Scarface
    Hey guys quick question, I have a checkbox system where a list of items can be checked and deleted on the click of a button. I currently use request and it does the job but I was wondering if $_REQUEST was some sort of security risk or improper. If anyone has any advice I would appreciate it. Should I change to $_POST? If so, what is the best way to go about it? foreach ($_REQUEST as $key=>$value) { if (substr($key,0,3)==="img") { $id = substr($key,3); if(isset($_REQUEST['Delete'])) { $sql = 'SELECT file_name,username FROM images WHERE id=?'; $stmt = $conn->prepare($sql); $result=$stmt->execute(array($id)); while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) { $image=$row['file_name']; $user=$row['username']; $myFile = "$user/images/$image"; unlink($myFile); } <input id=\"img".$id."\" name=\"img".$id."\" type=\"checkbox\">

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