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  • Django - Better evaluation of relationship at the model level

    - by Brant
    Here's a simple relational pair of models. class Shelf(models.Model): name = models.CharField(max_length=100) def has_books(self): if Book.objects.filter(shelf=self): return True else: return False class Book(models.Model): shelf = models.ForeignKey(Shelf) name = models.CharField(max_length=100) Is there a better (or alternative) way to write the "has_book" method? I'm not a fan of the double database hit but I want to do this at the model level.

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  • MYSQL query to return rows that are NOT in a set

    - by iglurat
    Hi, I have two tables: Contact (id,name) Link (id, contact_id, source_id) I have the following query which works that returns the contacts with the source_id of 8 in the Link table. SELECT name FROM `Contact` LEFT JOIN Link ON Link.contact_id = Contact.id WHERE Link.source_id=8; However I am a little stumped on how to return a list of all the contacts which are NOT associated with source_id of 8. A simple != will not work as contacts without any links are not returned. Thanks.

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  • php upload file function

    - by Jacksta
    I am trying to write a script which uploads a file via a html form. When I click submit nothing happens. file: upload_form.html <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <form action="do_upload.php" method="post" enctype="multipart/form-data"></form> <p><strong>File to upload</strong></p> <p><input name="img1" type="file" size="30" /></p> <p><input name="submit" type="submit" value="Upolad File" /></p> </body> </html> file: do_upload.php <?php if ($_FILES[img1] != "" { @copy($_FILES[img1] [tm_name], "/tmp" .$_FILES[img1][name]) or die("couldnt copy the file"); } else { die("no file specified"); } ?> <HTML> <head> <title>Successfull File Upload</title> </head> <body> <h1>Success</h1> <p>You sent: <? echo $_FILES[img1][name]; ?>, a <? echo $_FILES[img1][size]; ?>byte filw with a mime type of <? echo $_FILES[img1][type]; ?></p> </body> </HTML>

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  • How to successfully implement og:image for the LinkedIn

    - by Sabo
    THE PROBLEM: I am trying, without much success, to implement open graph image on site: http://www.guarenty-group.com/cz/ The homepage is completeply bypassing the og:image tag, where internal pages are reading all images from the site and place og:image as the last option. Other social networks are working fine on both internal pages and homepage. THE CONFIGURATION: I have no share buttons or alike, all I want is to be able to share the link via my profile. The image is well over 300x300px: http://guarenty-group.com/img/gg_seal.png Here is how my head tag looks like: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Guarenty Group : Pojištení pro nájemce a pronajímatelé</title> <meta name="keywords" content="" /> <meta name="description" content="Guarenty Group pojištuje príjem z nájmu pronajímatelum, kauci nájemcum - aby nemuseli platit velkou cástku v hotovostí predem - a dále nájemcum pojištuje príjmy, aby meli na nájem pri nemoci, úrazu ci nezamestnání." /> <meta name="image_src" content="http://guarenty-group.com/img/gg_seal.png" /> <meta name="image_url" content="http://guarenty-group.com/img/gg_seal.png" /> <meta property="og:title" content="Pojištení pro nájemce a pronajímatelé" /> <meta property="og:url" content="http://guarenty-group.com/cz/" /> <meta property="og:image" content="http://guarenty-group.com/img/gg_seal.png" /> <meta property="og:description" content="Guarenty Group pojištuje príjem z nájmu pronajímatelum, kauci nájemcum - aby nemuseli platit velkou cástku v hotovostí predem - a dále nájemcum pojištuje príjmy, aby meli na nájem pri nemoci, úrazu ci nezamestnání [...]" /> ... </head> THE TESTING RESULTS: In order to trick the cache i have tested the site with http://www.guarenty-group.com/cz/?try=N, where I have changed the N every time. The strange thing is that images found for different value of N is different. Sometimes there is no image, sometimes there is 1, 2 or 3 images, but each time there is a different set of images. But, in any case I could not find the image specified in the og:graph! MY QUESTIONS: https://developer.linkedin.com/documents/setting-display-tags-shares is saying one thing, and the personnel on the support forum is saying "over 300" Does anyone know What is the official minimum dimension of the image (both w and h)? Can an image be too large? Should I use the xmlns, should I not use xmlns or it doesn't matter? What are the maximum (and minimum) lengths for og:title and og:description tags? Any other suggestion is of course welcomed :) Thanks in advance, cheers~

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  • DB access denied with ASP.Net MVC application after switching to windows authentication mode

    - by myotherme
    I have a MVC application that I am now trying to add authentication and authorization to. I want to allow users to get to the site and be automatically authenticated. So I set authentication mode="Windows" in the web.config, and enabled NTLM in the project options. The site now shows my domain name in the top right when I run it, but when I hit a action than needs DB access, it tells me access is denied for my user-name? What step am I missing?

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  • How to Pass a JS Variable to a PHP Variable

    - by dmullins
    Hello: I am working on a web application that currently provides a list of documents in a MySql database. Each document in the list has an onclick event that is suppose to open the specific document, however I am unable to do this. My list gets popluated using Ajax. Here is the code excerpt (JS): function stateChanged() { if (xmlhttp.readyState==4) { //All documents// document.getElementById("screenRef").innerHTML="<font id='maintxt'; name='title'; onclick='fileopen()'; color='#666666';>" + xmlhttp.responseText + "</font>"; } } } The onclick=fileopen event above triggers the next code excerpt, which downloads the file (JS): function stateChanged() { if (xmlhttp.readyState==4) { //Open file var elemIF = document.createElement("iframe"); elemIF.src = url; elemIF.style.display = "none"; document.body.appendChild(elemIF); } } } Lastly, the openfile onclick event triggers the following php code to find the file for downloading (php): $con = mysql_connect("localhost", "root", "password"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("Documents", $con); $query = mysql_query("SELECT name, type, size, content FROM upload WHERE name = NEED JS VARIABLE HERE"); $row = mysql_fetch_array($query); header ("Content-type: ". $row['type']); header ("Content-length: ". $row['size']); header ("Content-Disposition: attachement; filename=". $row['name']); echo $row['content']; This code works well, for downloading a file. If I omit the WHERE portion of the Sql query, the onclick event will download the first file. Somehow, I need to get the screenRef element text and change it into a variable that my php file can read. Does anyone know how to do this? Also, without any page refreshes. I really appreciate everyone's feedback and thank you in advance. DFM

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  • Basic script for VBA

    - by rmdussa
    Hi I need basic script for excel and VBA. for example on sheet1 have table col1(name), col2(netsal),col3(bonus) in sheet1 need a button and want to click that button to get results in sheet2 needs to be col1(name),col2(netsal),col3(bonus), col4(col2+clo3)(total sal) could you please give steps to follow and VBA scripts Thanks

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  • WinForms/Console application on Mono, how to know it runs as root

    - by Lex Li-MSFT
    As we can execute such executables in two ways, such as "sudo mono test.exe", and "mono test.exe". Now I want to know how to detect whether this application is running as root inside the application itself. I tried to check user name like below and see whether they equal to "root", Thread.CurrentPrincipal.Identity.Name Process.GetCurrentProcess().StartInfo.UserName AppDomain.CurrentDomain.ApplicationIdentity.FullName The first two are empty strings always, while the third throws NullReferenceException. Please advise if this is doable on Mono 2.6.

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  • Div and tr align

    - by Hulk
    All, I am adding the follwing data to a table dynamically.So when adding this how to make the following appear inline.i.e, now the text area are showing up in new lines. And the images should be appear at the right hand corner of the row. <div bgcolor="black"> <img src="close.gif"> </td></tr> <tr> <td> <div id="catgegory"> </div> <div id="description"> </div> </td> <td> <div id = "div_content_bold"> <textarea name = "point_text_81_1" rows = "8" cols = "18" class = "input" WRAP ></textarea> </div> </td> <td> <div id = "div_content_bold"> <textarea name = "point_text_81_1" rows = "8" cols = "18" class = "input" WRAP ></textarea> </div> </td> <td> <div id = "div_content_bold"> <textarea name = "point_text_81_1" rows = "8" cols = "18" class = "input" WRAP ></textarea> </div> </td> <td> <div id = "div_content_bold"> <textarea name = "point_text_81_1" rows = "8" cols = "18" class = "input" WRAP ></textarea> </div> </td> <td> </td> </tr> </div> Thanks..

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  • use jquery to toggle disabled state with a radio button

    - by hbowman
    I want to toggle two radio buttons and select fields based on which radio button is selected. I have the jQuery working, but want to know if there is a way to make it more efficient. Seems like quite a few lines for the simple goal I am trying to achieve. Here are the requirements: when the page loads, #aircraftType should be checked and #aircraftModelSelect should be grayed out (right now, the "checked" is being ignored by Firefox). If the user clicks either #aircraftType or #aircraftModel, the opposite select field should become disabled (if #aircraftModel is checked, #aircraftTypeSelect should be disabled, and vise versa). Any help on optimizing this code is appreciated. Code is up on jsfiddle too: http://jsfiddle.net/JuRKn/ $("#aircraftType").attr("checked"); $("#aircraftModel").removeAttr("checked"); $("#aircraftModelSelect").attr("disabled","disabled").addClass("disabled"); $("#aircraftType").click(function(){ $("#aircraftModelSelect").attr("disabled","disabled").addClass("disabled"); $("#aircraftTypeSelect").removeAttr("disabled").removeClass("disabled"); }); $("#aircraftModel").click(function(){ $("#aircraftTypeSelect").attr("disabled","disabled").addClass("disabled"); $("#aircraftModelSelect").removeAttr("disabled").removeClass("disabled"); }); HTML <div class="aircraftType"> <input type="radio" id="aircraftType" name="aircraft" checked /> <label for="aircraftType">Aircraft Type</label> <select size="6" multiple="multiple" id="aircraftTypeSelect" name="aircraftType"> <option value="">Light Jet</option> <option value="">Mid-Size Jet</option> <option value="">Super-Mid Jet</option> <option value="">Heavy Jet</option> <option value="">Turbo-Prop</option> </select> </div> <div class="aircraftModel"> <input type="radio" id="aircraftModel" name="aircraft" /> <label for="aircraftModel">Aircraft Model</label> <select size="6" multiple="multiple" id="aircraftModelSelect" name="aircraftModel"> <option value="">Astra SP</option> <option value="">Beechjet 400</option> <option value="">Beechjet 400A</option> <option value="">Challenger 300</option> <option value="">Challenger 600</option> <option value="">Challenger 603</option> <option value="">Challenger 604</option> <option value="">Challenger 605</option> <option value="">Citation Bravo</option> </select> </div>

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  • Getting started with XSD validation with .NET

    - by Rosarch
    Here is my first attempt at validating XML with XSD. The XML file to be validated: <?xml version="1.0" encoding="utf-8" ?> <config xmlns="Schemas" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="config.xsd"> <levelVariant> <filePath>SampleVariant</filePath> </levelVariant> <levelVariant> <filePath>LegendaryMode</filePath> </levelVariant> <levelVariant> <filePath>AmazingMode</filePath> </levelVariant> </config> The XSD, located in "Schemas/config.xsd" relative to the XML file to be validated: <?xml version="1.0" encoding="utf-8" ?> <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" elementFormDefault="qualified"> <xs:element name="config"> <xs:complexType> <xs:sequence> <xs:element name="levelVariant"> <xs:complexType> <xs:sequence> <xs:element name="filePath" type="xs:anyURI"> </xs:element> </xs:sequence> </xs:complexType> </xs:element> </xs:sequence> </xs:complexType> </xs:element> </xs:schema> Right now, I just want to validate the XML file precisely as it appears currently. Once I understand this better, I'll expand more. Do I really need so many lines for something as simple as the XML file as it currently exists? The validation code in C#: public void SetURI(string uri) { XElement toValidate = XElement.Load(Path.Combine(PATH_TO_DATA_DIR, uri) + ".xml"); // begin confusion // exception here string schemaURI = toValidate.Attributes("xmlns").First().ToString() + toValidate.Attributes("xsi:noNamespaceSchemaLocation").First().ToString(); XmlSchemaSet schemas = new XmlSchemaSet(); schemas.Add(null, schemaURI); XDocument toValidateDoc = new XDocument(toValidate); toValidateDoc.Validate(schemas, null); // end confusion root = toValidate; } Running the above code gives this exception: The ':' character, hexadecimal value 0x3A, cannot be included in a name. Any illumination would be appreciated.

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  • How to order a HasMany collection by a child property with Fluent NHibernate mapping

    - by Geoff Hardy
    I am using Fluent NHibernate to map the following classes: public abstract class DomainObject { public virtual int Id { get; protected internal set; } } public class Attribute { public virtual string Name { get; set; } } public class AttributeRule { public virtual Attribute Attribute { get; set; } public virtual Station Station { get; set; } public virtual RuleTypeId RuleTypeId { get; set; } } public class Station : DomainObject { public virtual IList<AttributeRule> AttributeRules { get; set; } public Station() { AttributeRules = new List<AttributeRule>(); } } My Fluent NHibernate mappings look like this: public class AttributeMap : ClassMap<Attribute> { public AttributeMap() { Id(o => o.Id); Map(o => o.Name); } } public class AttributeRuleMap : ClassMap<AttributeRule> { public AttributeRuleMap() { Id(o => o.Id); Map(o => o.RuleTypeId); References(o => o.Attribute).Fetch.Join(); References(o => o.Station); } } public class StationMap : ClassMap<Station> { public StationMap() { Id(o => o.Id); HasMany(o => o.AttributeRules).Inverse(); } } I would like to order the AttributeRules list on Station by the Attribute.Name property, but doing the following does not work: HasMany(o => o.AttributeRules).Inverse().OrderBy("Attribute.Name"); I have not found a way to do this yet in the mappings. I could create a IQuery or ICriteria to do this for me, but ideally I would just like to have the AttributeRules list sorted when I ask for it. Any advice on how to do this mapping?

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  • Smarty html_options

    - by SeanJA
    For smarty's html_options function, is there a way to avoid having to do this (other than not using smarty that is)? {if $smarty.post} {html_options name=option_1 optins=$options selected=$smarty.post.option_1} {else} {html_options name=option_1 optins=$options} {/if} I realize that it won't show up in the template, but it seems like a bad practice to leave something that is not defined in the template (it also fills up my error logs with noise about undefined indexes).

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  • Call plugin class in Java

    - by Josh Meredith
    How can I call a class in Java, when the name of the class won't be known at compile time (such as if it were a plugin). For example, from a GUI, a user selects a plugin (a Java class), the application then creates a new instance of the class, and calls one of its methods (the method name would be known at compile time (e.g. "moduleMain")). Thanks for any input.

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  • t-sql grouping query

    - by stackoverflowuser
    Hi based on the following table Name --------- A A A B B C C C I want to add another column to this table called 'OnGoing' and the values should alternate for each group of names. There are only two values 'X' and 'Y'. So the table will look like Name OnGoing ---------------- A X A X A X B Y B Y C X C X C X how to write such a query that can alternate the values for each group of names.

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  • How to update the filename of a Django's FileField instance ?

    - by pierre-guillaume-degans
    Hello, Here a simple django model: class SomeModel(models.Model): title = models.CharField(max_length=100) video = models.FileField(upload_to='video') I would like to save any instance so that the video's file name would be a valid file name of the title. For example, in the admin interface, I load a new instance with title "Lorem ipsum" and a video called "video.avi". The copy of the file on the server should be "Lorem Ipsum.avi" (or "Lorem_Ipsum.avi"). Thank you :)

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  • Python logger dynamic filename

    - by sharjeel
    I want to configure my Python logger in such a way so that each instance of logger should log in a file having the same name as the name of the logger itself. e.g.: log_hm = logging.getLogger('healthmonitor') log_hm.info("Testing Log") # Should log to /some/path/healthmonitor.log log_sc = logging.getLogger('scripts') log_sc.debug("Testing Scripts") # Should log to /some/path/scripts.log log_cr = logging.getLogger('cron') log_cr.info("Testing cron") # Should log to /some/path/cron.log I want to keep it generic and dont want to hardcode all kind of logger names I can have. Is that possible?

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  • ASP MVC - Getting Controller Level error handling

    - by RP
    How to get Controller-Level error handling: This is my map-route: routes.MapRoute( "Default", // Route name "{controller}/{action}/{id}", // URL with parameters new { controller = "Home", action = "Index", id = "" } // Parameter defaults ); And I have 2 controllers - HomeController and AwayController I want both both controllers to handle their own errors For example, a call to /Home/InvalidAction would be handled by one method and /Away/InvalidAction would be handled by another method Where InvalidAction currently results in a 404 as there's no Action method with that name

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  • HTTP GET: Same GET-Parameter multiple Times, is this allowed by RFCs?

    - by bernhard
    Hello, are all "Standard Compliant (HTTP RFC?)" Web-Servers forced to "somehow" provide some methods to get all Parameters with the same name as some kind of list/array? Or will will using the same parameter name lead to overwriting: Example: http://www.stackoverflow?myparam=value1&myparam=value2 Will this lead to myparam holding the values "value1,value2" or only "value2" (due to overwriting and only using the last one). Is this behaviour mandated by some standard? thanks bernhard

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  • Having to hit the site login button twice after first turning on computer

    - by John
    Hello, The code below is for a login that I'm using. It works fine, but when I first try logging in after turning on my computer, it only works the second time that I hit the "Login" button. Any idea how I can make it not require hitting the "Login" button twice in this situation? Thanks in advance, John function isLoggedIn() { if (session_is_registered('loginid') && session_is_registered('username')) { return true; // the user is loged in } else { return false; // not logged in } return false; } if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { show_userbox(); } function show_loginform($disabled = false) { echo '<form name="login-form" id="login-form" method="post" action="./index.php"> <div class="usernameformtext"><label title="Username">Username: </label></div> <div class="usernameformfield"><input tabindex="1" accesskey="u" name="username" type="text" maxlength="30" id="username" /></div> <div class="passwordformtext"><label title="Password">Password: </label></div> <div class="passwordformfield"><input tabindex="2" accesskey="p" name="password" type="password" maxlength="15" id="password" /></div> <div class="registertext"><a href="http://www...com/sandbox/register.php" title="Register">Register</a></div> <div class="lostpasswordtext"><a href="http://www...com/sandbox/lostpassword.php" title="Lost Password">Lost password?</a></div> <p class="loginbutton"><input tabindex="3" accesskey="l" type="submit" name="cmdlogin" value="Login" '; if ($disabled == true) { echo 'disabled="disabled"'; } echo ' /></p></form>'; } EDIT: Here is another function that is used. function isLoggedIn() { if (session_is_registered('loginid') && session_is_registered('username')) { return true; // the user is loged in } else { return false; // not logged in } return false; }

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  • throws SecurityException when signing with the default debug keystore

    - by Omer
    I am receiving a SecurityException since yesterday when I launch the service using signature protection level for permission with the default debug keystore. The strange thing is I wasn't receiving this error before yesterday and I didn't make any security related change. On the other hand, my own keystore using for releases is still working good. Related AndroidManifest.xml part: <permission android:name="com.my.app.privateservices" android:protectionLevel="signature" /> <service android:name=".MyService" android:permission="com.my.app.privateservices" />

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