class classname(value); & class classname=value; difference when constructor is explicit
- by Mahesh
When constructor is explicit, it isn't used for implicit conversions. In the given snippet, constructor is marked as explicit. Then why in case foo obj1(10.25); it is working and in foo obj2=10.25; it isn't working ?
#include <iostream>
class foo
{
int x;
public:
explicit foo( int x ):x(x)
{}
};
int main()
{
foo obj(10.25); // Not an error. Why ?
foo obj2 = 10.25; // Error
getchar();
return 0;
}
error: error C2440: 'initializing' : cannot convert from 'double' to 'foo'
