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  • Distributing a bundle of files across an extranet

    - by John Zwinck
    I want to be able to distribute bundles of files, about 500 MB per bundle, to all machines on a corporate "extranet" (which is basically a few LANs connected using various private mechanisms, including leased lines and VPN). The total number of hosts is roughly 100, and the goal is to get a copy of the bundle from one host onto all the other hosts reliably, quickly, and efficiently. One important issue is that some hosts are grouped together on single fast LANs in which case the network I/O should be done once from one group to the next and then within each group between all the peers. This is as opposed to a strict central server system where multiple hosts might each fetch the same bundle over a slow link, rather than once via the slow link and then between each other quickly. A new bundle will be produced every few days, and occasionally old bundles will be deleted (but that problem can be solved separately). The machines in question happen to run recent Linuxes, but bonus points will go to solutions which are at least somewhat cross-platform (in which case the bundle might differ per platform but maybe the same mechanism can be used). That's pretty much it. I'm not opposed to writing some code to handle this, but it would be preferable if it were one of bash, Python, Ruby, Lua, C, or C++.

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  • NoClassDefFoundError: HttpClient 4 (APACHE)

    - by Pujan Srivastava
    Hello All, I am using HC APACHE. I have added both httpcore-4.0.1.jar and httpclient-4.0.1.jar in the classpath of netbeans. I am getting error: java.lang.NoClassDefFoundError: org/apache/http/impl/client/DefaultHttpClient My Code is as follows. Please help. import org.apache.http.client.HttpClient; import org.apache.http.client.ResponseHandler; import org.apache.http.client.methods.HttpGet; import org.apache.http.impl.client.BasicResponseHandler; import org.apache.http.impl.client.DefaultHttpClient; public class HttpClientManager { public HttpClient httpclient; public HttpClientManager() { this.init(); } public void init() { try { httpclient = new DefaultHttpClient(); } catch (Exception e) { e.printStackTrace(); } } public void getCourseList() { String url = "http://exnet.in.th/api.php?username=demoinst&ha=2b62560&type=instructor"; HttpGet httpget = new HttpGet(url); ResponseHandler<String> responseHandler = new BasicResponseHandler(); try { String responseBody = httpclient.execute(httpget, responseHandler); System.out.println(responseBody); } catch (Exception e) { } } }

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  • Simple jQuery code contains a syntax error that I can't find

    - by inkedmn
    I've got this (remarkably) simple JavaScript function that is called when a user clicks a "Cancel" link: function hideNewUserPanel(){ $('#create_user_panel').slideUp('slow'); $('.right_interior_panel').slideDown('slow'); } And the code to add the handler: $(function(){ $('#cancel_create_user_btn').live('click', function(){ hideNewUserPanel(); } }); Functionally, everything works as expected. Trouble is, when I click the "Cancel" link, Firebug shows an error in the console: uncaught exception: Syntax error, unrecognized expression: # I've stepped through the code several times and the error appears at some point before the call to hideNewUserPanel(). At the risk of sounding like one of "those programmers" (the kind that claim to have found a bug in GCC and assume their own code is perfect), the exception is being thrown from somewhere within jQuery proper, so I assume the issue is in there. I'm using jQuery 1.3.2 (this is a legacy project using many jQuery plugins that will break if we update to 1.4.x). Is there anything obviously wrong with my code that I'm simply not seeing? This code is, frankly, very simple and I don't really see what the issue could be. Thanks!

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  • insert Query is not executing, help me in tracking the problem

    - by Parth
    I tried the below query but it didnt executed giving error as : 1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ')' at line 1 INSERT INTO `jos_menu` SET params = 'orderby= show_noauth= show_title= link_titles= show_intro= show_section= link_section= show_category= link_category= show_author= show_create_date= show_modify_date= show_item_navigation= show_readmore= show_vote= show_icons= show_pdf_icon= show_print_icon= show_email_icon= show_hits= feed_summary= page_title= show_page_title=1 pageclass_sfx= menu_image=-1 secure=0 ', checked_out_time = '0000-00-00 00:00:00', ordering = '13', componentid = '20', published = '1', id = '152', menutype = 'accmenu', name = 'IPL', alias = 'ipl', link = 'index.php?option=com_content&view=archive', type = 'component') then i used mysql_real_escape_string() on the query containing variable which gives me the query as : INSERT INTO `jos_menu` SET params = \'orderby=\nshow_noauth=\nshow_title=\nlink_titles=\nshow_intro=\nshow_section=\nlink_section=\nshow_category=\nlink_category=\nshow_author=\nshow_create_date=\nshow_modify_date=\nshow_item_navigation=\nshow_readmore=\nshow_vote=\nshow_icons=\nshow_pdf_icon=\nshow_print_icon=\nshow_email_icon=\nshow_hits=\nfeed_summary=\npage_title=\nshow_page_title=1\npageclass_sfx=\nmenu_image=-1\nsecure=0\n\n\', checked_out_time = \'0000-00-00 00:00:00\', ordering = \'13\', componentid = \'20\', published = \'1\', id = \'152\', menutype = \'accmenu\', name = \'IPL\', alias = \'ipl\', link = \'index.php?option=com_content&view=archive\', type = \'component\') And on executing the above query I get an error as : 1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '\'orderby=\nshow_noauth=\nshow_title=\nlink_titles=\nshow_intro=\nshow_section=\' at line 1 Can Someone guide me to track the problem in it? Thanks In Advance....

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  • Which is more secure GET or POST sending parameters with cURL at PHP

    - by Steve
    I want to connect in a secure way with an API and I am using cURL to do it using HTTPS and SSL. Now, i was wondering what is better in terms of security, sending the data through GET or POST: $ch = curl_init("http://api.website.com/connect.php?user=xxx&pass=xxxx); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE); curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 2); $result = curl_exec($ch); curl_close($ch); Or $param['user'] = 'xxxx'; $param['pass'] = 'xxxx'; $ch = curl_init("http://api.website.com/connect.php); curl_setopt($ch, CURLOPT_POST, true); curl_setopt($ch, CURLOPT_POSTFIELDS, $Parameters); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE); curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 2); $result = curl_exec($ch); curl_close($ch); I also realized that POST is much more slower retrieving the data.

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  • WPF-Can a XAML object be a source as well as a target for bindings?

    - by iambic77
    I was wondering if it's possible to have a TextBlock as a target and a source? Basically I have a bunch of entities which have simple relationships to other entities (like Entity1 Knows Entity3, Entity3 WorksAt Entity2 etc.) I have a Link class that stores SourceEntity, Relationship and TargetEntity details. What I want to be able to do is to select an entity then display the relationships related to that entity, with the target entities of each relationship listed underneath the relationship names. When an entity is selected, an ObservableCollection is populated with the Links for that particular entity (SelectedEntityLinks<Link>). Because each entity could have the same relationship to more than one target entity (Entity1 could know both Entity3 and Entity4 for eg.), I've created a method GetThisRelationshipEntities() that takes a relationship name as a parameter, looks through SelectedEntityLinks for relationship names that match the parameter, and returns an ObservableCollection with the target entities of that relationship. Hope I'm making this clear. In my xaml I have a WrapPanel to display each relationship name in a TextBlock: <TextBlock x:Name="relationship" Text="{Binding Path=Relationship.Name}" /> Then underneath that another Textblock which should display the results of GetThisRelationshipEntities(String relationshipName). So I want the "relationship" TextBlock to both get its Text from the binding I've shown above, but also to provide its Text as a parameter to the GetThisRelationshipEntities() method which I've added to <UserControl.Resources> as an ObjectDataProvider. Sorry if this is a bit wordy but I hope it's clear. Any pointers/advice would be great. Many thanks.

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  • PHP & cUrl - POST problems in while loop.

    - by Max Hoff
    I have a while loop, with cUrl inside. (I can't use curl_multi for various reasons.) The problem is that cUrl seems to save the data it POSTS after each loop traversal. For instance, if parameter X is One the first loop through, and if it's Two the second loop through, cUrl posts: "One,Two". It should just POST "Two".(This is despite closing and unsetting the curl handle.) Here's a simplified version of the code (with unecessary info stripped out): while(true){ // code to form the $url. this code is local to the loop. so the variables should be "erased" and made new for each loop through. $ch = curl_init(); $userAgent = 'Googlebot/2.1 (http://www.googlebot.com/bot.html)'; curl_setopt($ch,CURLOPT_USERAGENT, $userAgent); curl_setopt($ch,CURLOPT_URL,$url); curl_setopt($ch,CURLOPT_POST,count($fields)); curl_setopt($ch,CURLOPT_POSTFIELDS,$fields_string); curl_setopt($ch, CURLOPT_FAILONERROR, true); curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true); curl_setopt($ch, CURLOPT_AUTOREFERER, true); curl_setopt($ch, CURLOPT_RETURNTRANSFER,true); curl_setopt($ch, CURLOPT_TIMEOUT, 10); $html = curl_exec($ch); curl_close($ch); unset($ch); $dom = new DOMDocument(); @$dom->loadHTML($html); $xpath = new DOMXPath($dom); $resultTable = $xpath->evaluate("/html/body//table"); // $resultTable is 20 the first time through the loop, and 0 everytime thereafter becauset he POSTing doesn't work right with the "saved" parameters. What am I doing wrong here?

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  • unable to get data from iphone application

    - by user317192
    Hi, I have made a php web services that takes the username and password from iPhone application and saves the data in the users table. I call that web service from my button touchup event like this: NSLog(userName.text); NSLog(password.text); NSString * dataTOB=[userName.text stringByAppendingString:password.text]; NSLog(dataTOB); NSData * postData=[dataTOB dataUsingEncoding:NSUTF8StringEncoding allowLossyConversion:YES]; NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]]; NSLog(postLength); NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease]; NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"http://localhost:8888/write.php"]]; [request setURL:url]; [request setHTTPMethod:@"POST"]; [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"]; [request setHTTPBody:postData]; NSURLResponse *response; NSError *error; [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error]; if(error==nil) NSLog(@"Error is nil"); else NSLog(@"Error is not nil"); NSLog(@"success!"); I am getting nothing from Iphone side into the web service and I am unable to understand why this is happening. Although i debugged and found that everything is fine at the iphone application level but the call to the web service doesn't works as expected...... Please suggest..... Thanks Ashish

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  • How to start AJAX in Zend?

    - by Awan
    I am working on some projects as a developer(PHP,MySQL) in which AJAX and jQuery is already implemented. But now I want to learn implementation of AJAX and jQuery stuff. Can anyone tell me the exact steps with explanation? I have created a project in Zend. There is only one controller(IndexController) and two actions(a and b) in my project now. Now I want to use ajax in my project. But I don't know how to start. I read some tutorial but unable to completely understand. I have index.phtml like this: <a href='index/a'>Load info A</a> <br/> <a href='index/b'>Load info B</a> <br /> <div id=one>load first here<div> <div id=two>load second here</div> Here index is controller in links. a and b are actions. now I have four files like this: a1.phtml I am a1 a2.phtml I am a2 b1.phtml I am b1 b2.phtml I am b2 I think you have got my point. When user clicks first link (Load info A) then a1.phtml should be loaded into div one and a2.phtml should be loaded into div two When user clicks second link (Load info B) then b1.phtml should be loaded into div one and b2.phtml should be loaded into div two And someone tell me the purpose of JSON in this process and how to use this also? Thanks

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  • PHP: Best solution for links breaking in a mod_rewrite app

    - by psil
    I'm using mod rewrite to redirect all requests targeting non-existent files/directories to index.php?url=* This is surely the most common thing you do with mod_rewrite yet I have a problem: Naturally, if the page url is "mydomain.com/blog/view/1", the browser will look for images, stylesheets and relative links in the "virtual" directory "mydomain.com/blog/view/". Problem 1: Is using the base tag the best solution? I see that none of the PHP frameworks out there use the base tag, though. I'm currently having a regex replace all the relative links to point to the right path before output. Is that "okay"? Problem 2: It is possible that the server doesn't support mod_rewrite. However, all public files like images, stylesheets and the requests collector index.php are located in the directory /myapp/public. Normally mod_rewrite points all request to /public so it seems as if public was actually the root directory too all users. However if there is no mod_rewrite, I then have to point the users to /public from the root directory with a header() call. That means, however that all links are broken again because suddenly all images, etc. have to be called via /public/myimage.jpg Additional info: When there is no mod_rewrite the above request would look like this: mydomain.com/public/index.php/blog/view/1 What would be the best solutions for both problems?

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  • Apply a Quartz filter while saving PDF under Mac OS X 10.6.3

    - by olpa
    Using Mac OS X API, I'm trying to save a PDF file with a Quartz filter applied, just like it is possible from the "Save As" dialog in the Preview application. So far I've written the following code (using Python and pyObjC, but it isn't important for me): -- filter-pdf.py: begin from Foundation import * from Quartz import * import objc page_rect = CGRectMake (0, 0, 612, 792) fdict = NSDictionary.dictionaryWithContentsOfFile_("/System/Library/Filters/Blue \ Tone.qfilter") in_pdf = CGPDFDocumentCreateWithProvider(CGDataProviderCreateWithFilename ("test .pdf")) url = CFURLCreateWithFileSystemPath(None, "test_out.pdf", kCFURLPOSIXPathStyle, False) c = CGPDFContextCreateWithURL(url, page_rect, fdict) np = CGPDFDocumentGetNumberOfPages(in_pdf) for ip in range (1, np+1): page = CGPDFDocumentGetPage(in_pdf, ip) r = CGPDFPageGetBoxRect(page, kCGPDFMediaBox) CGContextBeginPage(c, r) CGContextDrawPDFPage(c, page) CGContextEndPage(c) -- filter-pdf.py: end Unfortunalte, the filter "Blue Tone" isn't applied, the output PDF looks exactly as the input PDF. Question: what I missed? How to apply a filter? Well, the documentation doesn't promise that such way of creating and using "fdict" should cause that the filter is applied. But I just rewritten (as far as I can) sample code /Developer/Examples/Quartz/Python/filter-pdf.py, which was distributed with older versions of Mac (meanwhile, this code doesn't work too): ----- filter-pdf-old.py: begin from CoreGraphics import * import sys, os, math, getopt, string def usage (): print ''' usage: python filter-pdf.py FILTER INPUT-PDF OUTPUT-PDF Apply a ColorSync Filter to a PDF document. ''' def main (): page_rect = CGRectMake (0, 0, 612, 792) try: opts,args = getopt.getopt (sys.argv[1:], '', []) except getopt.GetoptError: usage () sys.exit (1) if len (args) != 3: usage () sys.exit (1) filter = CGContextFilterCreateDictionary (args[0]) if not filter: print 'Unable to create context filter' sys.exit (1) pdf = CGPDFDocumentCreateWithProvider (CGDataProviderCreateWithFilename (args[1])) if not pdf: print 'Unable to open input file' sys.exit (1) c = CGPDFContextCreateWithFilename (args[2], page_rect, filter) if not c: print 'Unable to create output context' sys.exit (1) for p in range (1, pdf.getNumberOfPages () + 1): #r = pdf.getMediaBox (p) r = pdf.getPage(p).getBoxRect(p) c.beginPage (r) c.drawPDFDocument (r, pdf, p) c.endPage () c.finish () if __name__ == '__main__': main () ----- filter-pdf-old.py: end

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  • Android App - disappearance of app GUI

    - by Radek Šimko
    I'm trying to create a simple app, whose main task is to open the browser on defined URL. I've created first Activity: public class MyActivity extends Activity { @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); //setContentView(R.layout.main); Intent myIntent = new Intent(Intent.ACTION_VIEW, Uri.parse("http://my.url.tld")); startActivity(myIntent); } Here's my AndroidManifest.xml: <manifest ...> <application ...> <activity android:name=".MyActivity" ...> <intent-filter> <action android:name="android.intent.action.MAIN"/> <category android:name="android.intent.category.LAUNCHER"/> </intent-filter> </activity> This code is fully functional, but before it opens the browser, it displays a black background - blank app GUI. I didn't figured out, how to go directly do the browser (without displaying the GUI). Anyone knows?

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  • Javascript Function for related select elements onSubmit

    - by Livingston
    I am trying to create (4) Select elements within a form element. Each select element has a different number of options. So if a user click one option on Select #1 and then click another option on Select #2, after hitting submit they will be taken to www.blah.com/option1/option2 page which will display the filtered results. Or they can chose an option from all 4 select menus and be taken to option1/option2/option3/option4 page. The categories are all related .Select #1 is a category, Select #2 is a subcategory of 1, Select #3 is a subcategory of #2 and Select #4 is a subcategory of #3. A great example would be on (LINK) http://www.safavieh.com/rugs (LINK) except only four Select elements. I would also like to add the "Reset" button next to "Submit." I know I need to construct a function in my header and use onSubmit attribute within the form but other than that I am unsure of what's involved so I'm hoping someone could point me in the right direction. It's important I learn most of this for myself. Thanks for your time Livingston

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  • Google Reader API - feed/[FEEDURL]/ is coming back as Not found

    - by JustinXXVII
    There is one feed I'm subscribed to which always turns up as NOT FOUND when I try to use the API. I return an array of Dictionaries, containing 3 objects. The first in the list represents the user himself, like so: { FeedID = "user/MY_UNIQUE_NUMBER/state/com.google/reading-list"; Timestamp = 1273448807271463; Unread = 59; } The Unread count is very important. My client depends on downloading 59 items from Google before it refreshes. If a feed doesn't download properly, the count is off and the client won't update. An example of a working Feed is here: { FeedID = "feed/http://arstechnica.com/index.rssx"; Timestamp = 1273447158484528; Unread = 13; } The FeedID value combines with a specially formatted URL string and gives back a list of articles. The above example works fine. However, the following feed always returns NOT FOUND on Google, and if I paste the URL verbatim into a browser, it never turns up. See here: { FeedID = "feed/http://www.peopleofwalmart.com/?feed=rss2"; Timestamp = 1273424138183529; Unread = 6; } http://www.google.com/reader/api/0/stream/contents/feed/http://www.peopleofwalmart.com/?feed=rss2?ot=1&r=n&xt=user/-/state/com.google/read&n=6&ck=1273449028&client=testClient If you are at all proficient with the API, can you please help me? Like I said, since Google always says NOT FOUND when I search for that feed, my download count is off by N articles and won't update. I would rather not hack around it, honestly. Thanks!

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  • How to read properties file in Greek using Java

    - by Subhendu Mahanta
    I am trying to read from a properties file which have keys in English & values in greek.My code is like this: public class I18NSample { static public void main(String[] args) { String language; String country; if (args.length != 2) { language = new String("el"); country = new String("GR"); } else { language = new String(args[0]); country = new String(args[1]); } Locale currentLocale; ResourceBundle messages; currentLocale = new Locale(language, country); messages = ResourceBundle.getBundle("MessagesBundle",currentLocale, new CustomClassLoader("E:\\properties")); System.out.println(messages.getString("greetings")); System.out.println(messages.getString("inquiry")); System.out.println(messages.getString("farewell")); } } import java.io.File; import java.net.MalformedURLException; import java.net.URL; public class CustomClassLoader extends ClassLoader { private String path; public CustomClassLoader(String path) { super(); this.path = path; } @Override protected URL findResource(String name) { File f = new File(path + File.separator + name); try { return f.toURL(); } catch (MalformedURLException e) { e.printStackTrace(); } return super.findResource(name); } } MessagesBundle_el_GR.properties greetings=??µ. ?a??et? farewell=ep?f. a?t?? inquiry=t? ???e?s, t? ???ete I am compiling like this javac -encoding UTF8 CustomClassLoader.java javac -encoding UTF8 I18Sample.java When I run this I get garbled output.If the properies file is in English,French or German it works fine. Please help. Regards, Subhendu

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  • UITableView Inactive Until Scroll iPhone

    - by dubbeat
    HI, I'm trying to find the cause of some annoying behaviour with my UITableView. In each cell of my table (10 of them ) I asynchronously load an image. The problem is, is that if I don't touch the app at all the imageviews will permanently show a loading icon. However as soon as I scroll a cell off the screen and back on again the image shows straight away. What could be causing this "stuck in the mud" behaviour? Is there a way to force whatever gets called when the list is scrolled to make the needed update happen? #define ASYNC_IMAGE_TAG 9999 #define LABEL_TAG 8888 // Customize the appearance of table view cells. - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { PromoListItem *promo = [promoList objectAtIndex:indexPath.row]; static NSString *CellIdentifier = @"Cell"; AsyncImageView *asyncImageView = nil; UILabel *label = nil; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease]; CGRect frame; frame.origin.x = 0; frame.origin.y = 0; frame.size.width = 100; frame.size.height = 100; asyncImageView = [[[AsyncImageView alloc] initWithFrame:frame] autorelease]; asyncImageView.tag = ASYNC_IMAGE_TAG; [cell.contentView addSubview:asyncImageView]; frame.origin.x = 110; frame.size.width =100; label = [[[UILabel alloc] initWithFrame:frame] autorelease]; label.tag = LABEL_TAG; [cell.contentView addSubview:label]; cell.accessoryType = UITableViewCellAccessoryDisclosureIndicator; } else { asyncImageView = (AsyncImageView *) [cell.contentView viewWithTag:ASYNC_IMAGE_TAG]; label = (UILabel *) [cell.contentView viewWithTag:LABEL_TAG]; } NSURL *url = [NSURL URLWithString:promo.imgurl]; [asyncImageView loadImageFromURL:url]; label.text = promo.artistname; return cell; }

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  • Replace relative urls to absolute

    - by Rocky Singh
    I have the html source of a page in a form of string with me: <html> <head> <link rel="stylesheet" type="text/css" href="/css/all.css" /> </head> <body> <a href="/test.aspx">Test</a> <a href="http://mysite.com">Test</a> <img src="/images/test.jpg"/> <img src="http://mysite.com/images/test.jpg"/> </body> </html> I want to convert all the relative paths to absolute. I want the output be: <html> <head> <link rel="stylesheet" type="text/css" href="http://mysite.com/css/all.css" /> </head> <body> <a href="http://mysite.com/test.aspx">Test</a> <a href="http://mysite.com">Test</a> <img src="http://mysite.com/images/test.jpg"/> <img src="http://mysite.com/images/test.jpg"/> </body> </html> Note: I want only the relative paths to be converted to absolute ones in that string. The absolute ones which are already in that string should not be touched, they are fine to me as they are already absolute. Can this be done by regex or other means?

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  • parser 2.1 and 2.2

    - by yaniv
    hi i using the follwing Code to retrive XML element text using getElementsByTagName this code success in 2.2 and Failed in 2.1 any idea ? URL metafeedUrl = new URL("http://x..../Y.xml") URLConnection connection ; connection= metafeedUrl.openConnection(); HttpURLConnection httpConnection = (HttpURLConnection)connection ; int resposnseCode= httpConnection.getResponseCode() ; if (resposnseCode == HttpURLConnection.HTTP_OK) { InputStream in = httpConnection.getInputStream(); DocumentBuilderFactory dbf ; dbf = DocumentBuilderFactory.newInstance(); DocumentBuilder db = dbf.newDocumentBuilder(); // Parse the Earthquakes entry Document dom = db.parse(in); Element docEle = dom.getDocumentElement(); //ArrayList<Album> Albums = new ArrayList<Album>(); /* Returns a NodeList of all descendant Elements with a given tag name, in document order.*/ NodeList nl = docEle.getElementsByTagName("entry"); if (nl!=null && nl.getLength() > 0) { for (int i = 0; i < nl.getLength(); i++) { Element entry = (Element)nl.item(i); /* Now on every property in Entry **/ Element title =(Element)entry.getElementsByTagName("title").item(0); *Here i Get an Error* String album_Title = title.getTextContent(); Element id =(Element)entry.getElementsByTagName("id").item(0); String album_id = id.getTextContent(); //

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  • Update database settings in properties file in Spring

    - by mvg
    Hi all, I am trying to create a Database Manager page which shows the database details on page load and updates the database settings when the user press submit I followed this tutorial and set the database settings in properties file. I managed to update the database settings in properties file programmatically. When I retrieved the database settings using the following code DriverManagerDataSource databaseSource = (DriverManagerDataSource)context.getBean("dataSource"); databaseSource.getUsername(); I managed to get the old value and unable to get the new value This is the mapping in applicationContext.xml file <bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer"> <property name="location"> <value>classpath:/bundle/database.properties</value> </property> </bean> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="${jdbc.driverClassName}" /> <property name="url" value="${jdbc.url}" /> <property name="username" value="${jdbc.username}" /> <property name="password" value="${jdbc.password}" /> </bean> I checked the properties file and found it to be updated with the latest input. What am I missing? Thanks in advance P.S I am using JSF1.2 with Spring 3 Update Just making my requirement simple. I am creating a setparate dbsettings page, so that when user wishes to connect to different database he/she can just enter the details in dbsettings page and connect

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  • How can I properly handle 404s in ASP.NET MVC?

    - by Brian
    I am just getting started on ASP.NET MVC so bear with me. I've searched around this site and various others and have seen a few implementations of this. EDIT: I forgot to mention I am using RC2 Using URL Routing: routes.MapRoute( "Error", "{*url}", new { controller = "Errors", action = "NotFound" } //404s ); The above seems to take care of requests like this (assuming default route tables setup by initial MVC project): "/blah/blah/blah/blah" Overriding HandleUnknownAction() in the controller itself: //404s - handle here (bad action requested protected override void HandleUnknownAction(string actionName) { ViewData["actionName"] = actionName; View("NotFound").ExecuteResult(this.ControllerContext); } However the previous strategies do not handle a request to a Bad/Unknown controller. For example, I do not have a "/IDoNotExist", if I request this I get the generic 404 page from the web server and not my 404 if I use routing + override. So finally, my question is: Is there any way to catch this type of request using a route or something else in the MVC framework itself? OR should I just default to using Web.Config customErrors as my 404 handler and forget all this? I assume if I go with customErrors I'll have to store the generic 404 page outside of /Views due to the Web.Config restrictions on direct access. Anyway any best practices or guidance is appreciated.

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  • Old fashioned html onclick return false doesnt in IE work when jquery script included

    - by user292662
    Ok, so im quite new to jquery but found this bizzar problem just now, If we ignore jquery for a second and consider this scenario, if i have two links like below both with an href and both with and onclick event. The first link will not follow the href because the onclick returns false, and the second link will because the onclick returns true. <a href="/page.html" onclick="return false;">Dont follow</a> <a href="/page.html" onclick="return false;">Follow</a> This works just hunky dory in every browser as it should, the thing is, as soon as i include the jQuery script on the page this stops working in all versions of IE which then always follows the href whether the onclick returns false or not. (it continues to work fine in other browsers) Now if i add an event using jquery and call .preventDefault() on the event object instead of doing it the old fashioned way this behaves correctly, and you may say, well just do that then? But i have a site with thousands of lines of code and i am adding jquery support, i dont want to run the risk that i might miss an already defined html onclick="" and break the website. I cant see why jQuery should prevent perfectly normal javascript concepts from working, so is this a jQuery bug or am I missing something?

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  • Really frustrated: Help writing a sample twitter app

    - by Jack
    I have installed WAMP. I have enable cURL in php.ini. I want to implement a twitter app that posts a new status message for a user. Here's my code <?php function updateTwitter($status) { $username = 'xxxxxx'; $password = 'xxxx'; $url = 'http://twitter.com/statuses/update.xml'; $postargs = 'status='.urlencode($status); $responseInfo=array(); $ch = curl_init($url); curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 2); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_PROXY,"localhost:80"); curl_setopt ($ch, CURLOPT_POST, true); // Give CURL the arguments in the POST curl_setopt ($ch, CURLOPT_POSTFIELDS, $postargs); // Set the username and password in the CURL call curl_setopt($ch, CURLOPT_USERPWD, $username.':'.$password); // Set some cur flags (not too important) $response = curl_exec($ch); if($response === false) { echo 'Curl error: ' . curl_error($ch); } else { echo 'Operation completed without any errors<br/>'; } // Get information about the response $responseInfo=curl_getinfo($ch); // Close the CURL connection curl_close($ch); // Make sure we received a response from Twitter if(intval($responseInfo['http_code'])==200){ // Display the response from Twitter echo $response; }else{ // Something went wrong echo "Error: " . $responseInfo['http_code']; } curl_close($ch); } updateTwitter("Just finished a sweet tutorial on http://brandontreb.com"); ?> I am getting the following output Operation completed without any errors Error: 404 Please help.

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  • Yii user rights extension

    - by jailed abroad
    i have installed the yii rights extension and here is my code after installation, database tables are created after installation. 'modules'=>array( // uncomment the following to enable the Gii tool 'rights'=>array( 'superuserName'=>'Admin', // Name of the role with super user privileges. 'authenticatedName'=>'Authenticated', //// Name of the authenticated user role. 'userIdColumn'=>'id',// Name of the user id column in the database. 'userNameColumn'=>'username', // Name of the user name column in the database. 'enableBizRule'=>true, // Whether to enable authorization item business rules. 'enableBizRuleData'=>false, //Whether to enable data for business rules. 'displayDescription'=>true, // Whether to use item description instead of name. ' // Key to use for setting success flash messages. 'flashErrorKey'=>'RightsError', / Key to use for setting error flash messages. // 'install'=>true, // Whether to install rights. 'baseUrl'=>'/rights', // Base URL for Rights. Change if module is nested. 'layout'=>'rights.views.layouts.main', // Layout to use for displaying Rights. 'appLayout'=>'application.views.layouts.main', //Application layout. 'cssFile'=>'rights.css', // Style sheet file to use for Rights. ' 'install'=>false, // Whether to enable installer. 'debug'=>false, ), 'gii'=>array( 'class'=>'system.gii.GiiModule', 'password'=>'1234', // If removed, Gii defaults to localhost only. Edit carefully to taste. 'ipFilters'=>array('127.0.0.1','::1'), ), ), But when i type url http://localhost/rightsTest/index.php/rights then it says There must be at least one superuser! I have tried many things but unable to find answer. Thanks for your help.

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  • php curl login not work

    - by Massimo Zampieri
    Hi i have a problem with the curl. I watched an old post Remote Login not Working With Curl, but it not work. I followed baba's advice but the code enter in the if statement. Sorry for my bad english. Can anyone help me? This is the code: $url="http://hipfile.com/"; $urllog="http://hipfile.com/login.html"; $postdata = "login=bnnoor&password=########&op=login"; $ch = curl_init(); curl_setopt ($ch, CURLOPT_URL, $url); curl_setopt ($ch, CURLOPT_SSL_VERIFYPEER, FALSE); curl_setopt ($ch, CURLOPT_USERAGENT, "Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1.6) Gecko/20070725 Firefox/2.0.0.6"); curl_setopt ($ch, CURLOPT_TIMEOUT, 60); curl_setopt ($ch, CURLOPT_FOLLOWLOCATION, 1); curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt ($ch, CURLOPT_REFERER, $urllog); curl_setopt ($ch, CURLOPT_POSTFIELDS, $postdata); curl_setopt ($ch, CURLOPT_POST, 1); $result = curl_exec ($ch); if (!$result) { $http_code = curl_getinfo($ch, CURLINFO_HTTP_CODE); curl_close($ch); // make sure we closeany current curl sessions die($http_code.' Unable to connect to server. Please come back later.'); } echo $result; curl_close($ch);

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  • Sorting a list in PHP

    - by Andy
    Alright, so I've just (almost) finished my first little php script. Basically all it does is handling forms. It writes whatever the user put in to the fields of the form to a text file, then I include that text file in the index of the little page I have set up. So, currently it writes to the beginning of the text file (but doesn't overwrite previous data). But, several users wants this list to be alphabetically sorted instead. So what I want to do is make whatever they submit fall into the list in alphabetical order. The thing here is also that all I use in the text file are divs. The list is basically 'divided' into 3 parts. 'Title', 'Link', and 'Poster'. All I have done is positioned them with css. So, can I sort this list (the titles, in this case) alphabetically and still have the 'link' and 'poster' information assigned the way they already are, but just with the titles sorted? It don't use databases at all on my site, so there is no database handling at all used in this script (mainly because I'm not experienced at all in this).

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