How to use two parameters pointing to the same structure in one function ?
- by ZaZu
Hey guys,
I have my code below that consits of a structure, a main, and a function. The function is supposed to display two parameters that have certain values, both of which point to the same structure.
The problem I dont know how to add the SECOND parameter onto the following code :
#include<stdio.h>
#define first 500
#define sec 500
struct trial{
int f;
int r;
float what[first][sec];
};
int trialtest(trial *test);
main(){
trial test;
trialtest(&test);
}
int trialtest(trial *test){
int z,x,i;
for(i=0;i<5;i++){
printf("%f,(*test).what[z][x]);
}
return 0;
}
I need to add a new parameter test_2 there (IN THE SAME FUNCTION) using this code :
for(i=0;i<5;i++){
printf("%f,(*test_2).what[z][x]);
How does int trialtest(trial *test) changes ?
and how does it change in main ?
I know that I should declare test_2 as well, like this :
trial test,test_2;
But what about passing the address in the function ? I do not need to edit it right ?
trialtest(&test); --- This will remain the same ?
So please, tell me how would I use test_2 as a parameter pointing to the same structure as test, both in the same function..
Thank you !!
Please tell me if you need more clarification
