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  • READING stderr from within Awk

    - by Dave
    I want to keep SSH debug info separate (and logged) from other input. However, if I simply redirect stderr to a log file, I risk combining output from SSH and output from the remote process on the host machine (that might send something to stderr): $ ssh -v somemachine 2 file.log So, I want to filter out only those lines that match "debug1": $ ssh -v somemachine | awk '/debug1/ {print "file.log"; next} {print}' Good so far, BUT ssh's debug output goes to stderr. So... $ ssh -v somemachine 2& | awk '/debug1/ {print "file.log"; next} {print}' Foiled again! I don't want to mix stdout and stderr. BAD! What does a kid like me do? I was about to go the route of named pipes or some such wildeness, but really, all I need to know is how to get awk to match patterns from stderr ONLY.

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  • Python's asyncore to periodically send data using a variable timeout. Is there a better way?

    - by Nick Sonneveld
    I wanted to write a server that a client could connect to and receive periodic updates without having to poll. The problem I have experienced with asyncore is that if you do not return true when dispatcher.writable() is called, you have to wait until after the asyncore.loop has timed out (default is 30s). The two ways I have tried to work around this is 1) reduce timeout to a low value or 2) query connections for when they will next update and generate an adequate timeout value. However if you refer to 'Select Law' in 'man 2 select_tut', it states, "You should always try to use select() without a timeout." Is there a better way to do this? Twisted maybe? I wanted to try and avoid extra threads. I'll include the variable timeout example here: #!/usr/bin/python import time import socket import asyncore # in seconds UPDATE_PERIOD = 4.0 class Channel(asyncore.dispatcher): def __init__(self, sock, sck_map): asyncore.dispatcher.__init__(self, sock=sock, map=sck_map) self.last_update = 0.0 # should update immediately self.send_buf = '' self.recv_buf = '' def writable(self): return len(self.send_buf) > 0 def handle_write(self): nbytes = self.send(self.send_buf) self.send_buf = self.send_buf[nbytes:] def handle_read(self): print 'read' print 'recv:', self.recv(4096) def handle_close(self): print 'close' self.close() # added for variable timeout def update(self): if time.time() >= self.next_update(): self.send_buf += 'hello %f\n'%(time.time()) self.last_update = time.time() def next_update(self): return self.last_update + UPDATE_PERIOD class Server(asyncore.dispatcher): def __init__(self, port, sck_map): asyncore.dispatcher.__init__(self, map=sck_map) self.port = port self.sck_map = sck_map self.create_socket(socket.AF_INET, socket.SOCK_STREAM) self.bind( ("", port)) self.listen(16) print "listening on port", self.port def handle_accept(self): (conn, addr) = self.accept() Channel(sock=conn, sck_map=self.sck_map) # added for variable timeout def update(self): pass def next_update(self): return None sck_map = {} server = Server(9090, sck_map) while True: next_update = time.time() + 30.0 for c in sck_map.values(): c.update() # <-- fill write buffers n = c.next_update() #print 'n:',n if n is not None: next_update = min(next_update, n) _timeout = max(0.1, next_update - time.time()) asyncore.loop(timeout=_timeout, count=1, map=sck_map)

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  • How can I send email attachment without using an additional library in Perl?

    - by CheeseConQueso
    Hey, I was wondering if there is a way to attach files (specifically .csv files) to a mail message in Perl without using MIME::Lite or any other libraries. Right now, I have a 'mailer function' that works fine, but I'm not sure how to adapt it into attaching files. Here is what I have: open(MAIL, "|/usr/sbin/sendmail -t"); print MAIL "To: cheese\@yahoo.com\n"; print MAIL "From: queso\@what.com\n"; print MAIL "Subject: Attached is $filename\n\n"; print MAIL "$message"; close(MAIL); I think this is specific for UNIX.

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  • super function doesn't work inside a maya python module

    - by sfjedi
    Somehow, this works fine in the Maya/Python script editor, but fails when it's inside of my module code. Anyone have any ideas? class ControlShape(object): def __init__(self, *args, **kwargs): print 'Inside ControlShape...' class Cross(ControlShape): def __init__(self, *args, **kwargs): print 'Entering Cross...' super(Cross, self).__init__(*args, **kwargs) print 'Leaving Cross...' x = Cross() This gives me a TypeError: super(type, obj): obj must be an instance or subtype of type.

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  • problem in printing fonts

    - by user1400
    hello i have a application on php that i show a report in the table , i want to print this page i can see my page fine in print preview , but when i send thuis page to printer ,the fonts are small and diffrent fonts that i set in css file this is my css file @page { size: A4 landscape; margin-top:2cm; margin-bottom:1cm; margin-left:1cm; margin-right:1cm; } table.print{ text-align:right; border:#999 1px solid; } table.print td.e1{ border-top:#999 1px solid; padding:5px 2px; text-align: right; font-size: 20pt; font-family:"stencil"; } table.print td.e2{ border-top:#999 1px solid; padding:5px 2px; text-align: right; font-size: 120%; font-family:"tahoma"; } thanks

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  • How do I include a frameset under CGI.pm?

    - by neversaint
    I want to have a cgi-script that does two things. Take the input from a form. Generate results base on the input values on a frame. I also want the frame to exist only after the result is generated/printed. Below is the simplified code of what I want to do. But somehow it doesn't work. What's the right way to do it? #!/usr/local/bin/perl use CGI ':standard'; print header; print start_html('A Simple Example'), h1('A Simple Example'), start_form, "What's your name? ",textfield('name'), p, "What's the combination?", p, checkbox_group(-name=>'words', -values=>['eenie','meenie','minie','moe'], -defaults=>['eenie','minie']), p, "What's your favorite color? ", popup_menu(-name=>'color', -values=>['red','green','blue','chartreuse']), p, submit, end_form, hr; if (param()) { # begin create the frame print <<EOF; <html><head><title>$TITLE</title></head> <frameset rows="10,90"> <frame src="$script_name/query" name="query"> <frame src="$script_name/response" name="response"> </frameset> EOF # Finish creating frame print "Your name is: ",em(param('name')), p, "The keywords are: ",em(join(", ",param('words'))), p, "Your favorite color is: ",em(param('color')), hr; } print end_html;

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  • Indent or comment several text lines with VI

    - by Werner
    Hi, can vim or vim be used to comment or indent at the same time a number of lines? For instance: for item in Lista: ind = int(floor(1.0*(item-lmin)/width)) if ind==nintervals: ind=ind-1 print item,ind comment it to: #for item in Lista: #ind = int(floor(1.0*(item-lmin)/width)) #if ind==nintervals: #ind=ind-1 #print item,ind or indent it to: for item in Lista: ind = int(floor(1.0*(item-lmin)/width)) if ind==nintervals: ind=ind-1 print item,ind Thanks P.D. Is relevant the difference between VI and VIM?

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  • PHP Strange error "0:". Possible Object syntax problem?

    - by Michael Stone
    I'm trying to transfer a site from one hosting company to another. I was using 000webhost until the client had hosting and a domain. Now that the client has their domain and hosting, using FatCow.com, I can not for the life of me, debug my PHP code. I'm not getting any errors. I have a successful DB connection. If you procedurally display data, it works, but when I try to use my original objects, something is breaking and just returns "0:". I have all errors on. On old server where the site worked: PHP Version 5.2.11 MySQL Version: 5.0.81 On new server where I get the "0:": PHP Version 5.2.12 MySQL Version 5.0.32 I've setup a test page to test just the output of the variables with the DB connection. Below is my code: <?php error_reporting(E_ALL); ini_set('display_errors', '1'); try { $link = mysql_connect('connectionstring', 'username', 'password'); if (!$link) { die('Could not connect: ' . mysql_error()); } else{ $db = mysql_select_db('a8210422_lit'); } if($db){ include_once('admin/classes/clsPOW.php'); include_once('admin/classes/clsProviders.php'); $pow = new POW(); $prov = new Providers(); $new = $pow->getNew(); $newAr = $new->val(); $get = $prov->getAll($newAr['providerId']); $getAr = $get->val(); $img = $getAr['image']; $name = $getAr['provider']; $desc = $getAr['description']; $zip = $getAr['zip']; $web = $getAr['link']; if($zip==0){ $zip = "Unavailable"; } print $img; print $name; print $desc; print $zip; print $web; } else{ print 'fail!'; } } //catch exception catch(Exception $e) { echo 'Message: ' .$e->getMessage(); } ?>

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  • How to replace the nth column/field in a comma-separated string using sed/awk?

    - by Peter Meier
    assume I have a string "1,2,3,4" Now I want to replace, e.g. the 3rd field of the string by some different value. "1,2,NEW,4" I managed to do this with the following command: echo "1,2,3,4" | awk -F, -v OFS=, '{$3="NEW"; print }' Now the index for the column to be replaced should be passed as a variable. So in this case index=3 How can I pass this to awk? Because this won't work: echo "1,2,3,4" | awk -F, -v OFS=, '{$index="NEW"; print }' echo "1,2,3,4" | awk -F, -v OFS=, '{$($index)="NEW"; print }' echo "1,2,3,4" | awk -F, -v OFS=, '{\$$index="NEW"; print }' Thanks for your help!

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  • Calculating the pixel size of a string with Python

    - by Aristide
    I have a Python script which needs to calculate the exact size of arbitrary strings displayed in arbitrary fonts in order to generate simple diagrams. I can easily do it with Tkinter. The problem is the results seem to depend on the version of Python and/or the system. import Tkinter as tk import tkFont root = tk.Tk() times12 = tkFont.Font(family="times",size=12) print times12.metrics("linespace"), print times12.measure("Hello world") times24 = tkFont.Font(family="times",size=24) print times24.metrics("linespace"), print times24.measure("Hello world") Python 2.5 on Mac OS X gives the actual pixel measurements: 12 57 24 116 Python 2.6.1 on Mac OS X gives: 14 58 27 115 Python 2.6.3 on Windows XP gives: 19 71 36 154 Such a need being quite common, I suspect I did something wrong. Any idea?

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  • python multiprocess update dictionary synchronously

    - by user1050325
    I am trying to update one common dictionary through multiple processes. Could you please help me find out what is the problem with this code? I get the following output: inside function {1: 1, 2: -1} comes here inside function {1: 0, 2: 2} comes here {1: 0, 2: -1} Thanks. from multiprocessing import Lock, Process, Manager l= Lock() def computeCopyNum(test,val): l.acquire() test[val]=val print "inside function" print test l.release() return a=dict({1: 0, 2: -1}) procs=list() for i in range(1,3): p = Process(target=computeCopyNum, args=(a,i)) procs.append(p) p.start() for p in procs: p.join() print "comes here" print a

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  • Type problem with Observable.Create from Boo

    - by Tristan
    I'm trying to use Reactive Extensions from Boo and am running into type problems. Here's the basic example: def OnSubscribe(observer as IObservable[of string]) as callable: print "subscribing" def Dispose(): print "disposing" return Dispose observable = System.Linq.Observable.Create[of string](OnSubscribe) observer = System.Linq.Observer.Create[of string]({x as string | print x}) observable.Subscribe(observer) The Subscribe here gives a System.InvalidCastException: Cannot cast from source type to destination type. The issue appears to be with how I'm creating the observable, but I've struggled to see where the type problem arises from. Ideas?

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  • Condensing multiple else if statements, referencing them from a table?

    - by Haskella
    Hi I'm about to type some 500 else if statements into my code (PHP) which have the exact same coding each: if (color=White); rgb = 255-255-255; print rgb; else if (color=Black); rgb = 0-0-0; print rgb; else if (color=Red); rgb = 255-0-0; print rgb; else if (color=Blue); rgb = 0-0-255; print rgb; [the list keeps going] I also (luckily) have a table that displays the color in the first column and rgb value in the next column for 500 of them... how do I use this to save time typing all those else if statements? Some how I have to reference the table file (made in excel, I'm guessing I'll have to save it as .csv?)

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  • Display numbers from 1 to 100 without loops or conditions

    - by Harsha
    Is there a way to print numbers from 1 to 100 without using any loops or conditions like "if"? We can easily do using recursion but that again has an if condition. Is there a way to do without using "if" as well? Also no repetitive print statements,or a single print statement containing all the numbers from 1 to 100. A solution in Java is preferable.

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  • Go - Using a map for its set properties with user defined types

    - by Seth Hoenig
    I'm trying to use the built-in map type as a set for a type of my own (Point, in this case). The problem is, when I assign a Point to the map, and then later create a new, but equal point and use it as a key, the map behaves as though that key is not in the map. Is this not possible to do? // maptest.go package main import "fmt" func main() { set := make(map[*Point]bool) printSet(set) set[NewPoint(0, 0)] = true printSet(set) set[NewPoint(0, 2)] = true printSet(set) _, ok := set[NewPoint(3, 3)] // not in map if !ok { fmt.Print("correct error code for non existent element\n") } else { fmt.Print("incorrect error code for non existent element\n") } c, ok := set[NewPoint(0, 2)] // another one just like it already in map if ok { fmt.Print("correct error code for existent element\n") // should get this } else { fmt.Print("incorrect error code for existent element\n") // get this } fmt.Printf("c: %t\n", c) } func printSet(stuff map[*Point]bool) { fmt.Print("Set:\n") for k, v := range stuff { fmt.Printf("%s: %t\n", k, v) } } type Point struct { row int col int } func NewPoint(r, c int) *Point { return &Point{r, c} } func (p *Point) String() string { return fmt.Sprintf("{%d, %d}", p.row, p.col) } func (p *Point) Eq(o *Point) bool { return p.row == o.row && p.col == o.col }

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  • Mongodb using db.help() on a particular db command

    - by user1325696
    When I type db.help() It returns DB methods: db.addUser(username, password[, readOnly=false]) db.auth(username, password) ... ... db.printShardingStatus() ... ... db.fsyncLock() flush data to disk and lock server for backups db.fsyncUnock() unlocks server following a db.fsyncLock() I'd like to find out how to get more detailed help for the particular command. The problem was with the printShardingStatus as it returned "too many chunks to print, use verbose if you want to print" mongos> db.printShardingStatus() --- Sharding Status --- sharding version: { "_id" : 1, "version" : 3 } shards: { "_id" : "shard0000", "host" : "localhost:10001" } { "_id" : "shard0001", "host" : "localhost:10002" } databases: { "_id" : "admin", "partitioned" : false, "primary" : "config" } { "_id" : "dbTest", "partitioned" : true, "primary" : "shard0000" } dbTest.things chunks: shard0001 12 shard0000 19 too many chunks to print, use verbose if you want to for ce print I found that for that particular command I can specify boolean parameter db.printShardingStatus(true) which wasn't shown using db.help().

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  • little java help....

    - by jona
    Hi I am doing some practice problems and trying to print a diagonal line like the example below. I have writen the program you see below and I honestly dont understand what I am doing wrong. I m a java beginner and I cant see how to find the error. Example ( If you only see a straight line of stars...then imagine it diagonally....from top left to bottom right) * * * * * code: class Diagonal{ public static void main(String args[]) { int row, col; for(row = 1; row < 6; row++) { for(col = 1; col <= row; col++) { if(col==row){ System.out.print("*"); } else{ System.out.print(""); } System.out.println(); } } } } I am trying to learn for loops because they really confuse me. Another practice is to print a similar diagonal line but this time from right to left. I cant do that without getting this right however :( I believe they will be pretty similar? Above my reasining is this: As long as the column # is the same as the row number the print the line or otherwise leave a blank....what's wrong with how i did it? THANK YOU!

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  • Printing a string and variable in MIPS

    - by Matt
    Here's the C representation of what I'm trying to do in MIPS assembly: printf ("x=%d\n", x); I know that I can do a syscall to easily print x= and I can also do a syscall to print the int x (which is stored in a register). However, that prints them like this (let's say x is 5): x= 5 How can I make them print on the same line?

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  • Why does Printing from Javascript in Air happen out of order?

    - by Bob Bob
    I am trying to print from an Adobe Air App that embeds an AJAX app. The print function looks like this: function printPage() { asyncSetupForPrint(printCallback); } function asyncSetupForPrint(printCallback) { synchronousMethods(); if (printCallback) printCallback(); } function printCallback() { var pjob = new window.runtime.flash.printing.PrintJob; var psprite = window.htmlLoader; pjob.start(); // etc... } However the print dialog is coming up before the synchronous methods have been executed. Is the AIR JS runtime optimizing something? And if so, is there any way to stop it doing that? (The setup function is doing things like changing the resolution to huge*huge so that the print out looks ok.)

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  • Using Range Function

    - by Michael Alexander Riechmann
    My goal is to make a program that takes an input (Battery_Capacity) and ultimately spits out a list of the (New_Battery_Capacity) and the Number of (Cycle) it takes for it ultimately to reach maximum capacity of 80. Cycle = range (160) Charger_Rate = 0.5 * Cycle Battery_Capacity = float(raw_input("Enter Current Capacity:")) New_Battery_Capacity = Battery_Capacity + Charger_Rate if Battery_Capacity < 0: print 'Battery Reading Malfunction (Negative Reading)' elif Battery_Capacity > 80: print 'Battery Reading Malfunction (Overcharged)' elif float(Battery_Capacity) % 0.5 !=0: print 'Battery Malfunction (Charges Only 0.5 Interval)' while Battery_Capacity >= 0 and Battery_Capacity < 80: print New_Battery_Capacity I was wondering why my Cycle = range(160) isn't working in my program?

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  • python popen and mysql import

    - by khelll
    I'm doing the following: from subprocess import PIPE from subprocess import Popen file = 'dump.sql.gz' p1 = Popen(["gzip", "-cd" ,file], stdout=PIPE) print "Importing temporary file %s" % file p2 = Popen(["mysql","--default-character-set=utf8", "--user=root" , "--password=something", "--host=localhost", "--port=3306" , 'my_db'],stdin=p1.stdout, stdout=PIPE,stderr=PIPE) err = p1.communicate()[1] if err: print err err = p2.communicate()[1] if err: print err But the db is not being populated. No errors are shown, also I have checked p1.stdout and it has the file contents. Any ideas?

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  • how I can overcome this error C2679: binary '>>' : no operator found which takes a right-hand oper

    - by hussein abdullah
    #include <iostream> using std::cout; using std::cin; using std::endl; #include <cstring> void initialize(char[],int*); void input(const char[] ,int&); void print ( const char*,const int); void growOlder (const char [], int* ); bool comparePeople(const char* ,const int*,const char*,const int*); int main(){ char name1[25]; char name2[25]; int age1; int age2; initialize (name1,&age1); initialize (name2,&age2); print(name1,age1); print(name2,age2); input(name1,age1); input(name2,age2); print(name1,age1); print(name2,age2); growOlder(name2,&age2); if(comparePeople(name1,&age1,name2,&age2)) cout<<"Both People have the same name and age "<<endl; return 0; } void input(const char name[],int &age) { cout<<"Enter a name :"; cin>>name ; cout<<"Enter an age:"; cin>>age; cout<<endl; } void initialize ( char name[],int *age) { name[0]='\0'; *age=0; } void print ( const char name[],const int age ) { cout<<"The Value stored in variable name is :" <<name<<endl <<"The Value stored in variable age is :" <<age<<endl<<endl; } void growOlder(const char name[],int *age) { cout<< name <<" has grown one year older\n\n"; *age++; } bool comparePeople (const char *name1,const int *age1, const char *name2,const int *age2) { return(*age1==*age2 && !strcmp(name1,name2)); }

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  • Unittest and mock

    - by user1410756
    I'm testing with unittest in python and it's ok. Now, I have introduced mock and I need to resolve a question. This is my code: from mock import Mock import unittest class Matematica(object): def __init__(self, op1, op2): self.op1 = op1 self.op2 = op2 def adder(self): return self.op1 + self.op2 def subs(self): return abs(self.op1 - self.op2) def molt(self): return self.op1 * self.op2 def divid(self): return self.op1 / self.op2 class TestMatematica(unittest.TestCase): """Test della classe Matematica""" def testing(self): """Somma""" mat = Matematica(10,20) self.assertEqual(mat.adder(),30) """Sottrazione""" self.assertEqual(mat.subs(),10) class test_mock(object): def __init__(self, matematica): self.matematica = matematica def execute(self): self.matematica.adder() self.matematica.adder() self.matematica.subs() if __name__ == "__main__": result = unittest.TextTestRunner(verbosity=2).run(TestMatematica('testing')) a = Matematica(10,20) b = test_mock(a) b.execute() mock_foo = Mock(b.execute)#return_value = 'rafa') mock_foo() print mock_foo.called print mock_foo.call_count print mock_foo.method_calls This code is functionally and result of print is: True, 1, [] . Now, I need to count how many times are called self.matematica.adder() and self.matematica.subs() . THANKS

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  • How to define and use a friend function to a temlate class with the same template?

    - by Narek
    I have written the following code: #include <iostream> using namespace std; template <class T> class AA { T a; public: AA() { a = 7; } friend void print(const AA<T> & z); }; template <class T> void print(const AA<T> & z) { cout<<"Print: "<<z.a<<endl; } void main() { AA<int> a; print<int>(a); } And getting the following error: error C2248: 'AA<T>::a' : cannot access private member declared in class 'AA<T>' 1> with 1> [ 1> T=int 1> ] 1> c:\users\narek\documents\visual studio 2008\projects\aaa\aaa\a.cpp(7) : see declaration of 'AA<T>::a' 1> with 1> [ 1> T=int 1> ] 1> c:\users\narek\documents\visual studio 2008\projects\aaa\aaa\a.cpp(30) : see reference to function template instantiation 'void print<int>(const AA<T> &)' being compiled 1> with 1> [ 1> T=int 1> ] What's wrong?

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