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  • How to convert Beautiful Soup Unicode into a decimal value?

    - by MikeTheCoder
    I'm trying to Use python's Beautiful Soup Library to grab a bunch of divs from an html file, and from there get the string - which is a money value - that's inside the div. Then remove the dollar sign and convert it to a decimal so that I can use a greater than and less than conditional statement to compare values. I have googled the heck out of it and can't seem to come up with a way to convert this unicode string into a decimal value. I really could use some help here. How do I convert unicode into a decimal value? This was my last attempt: import unicodedata from bs4 import BeautifulSoup soup = BeautifulSoup(open("/Users/sm/Documents/python/htmldemo.html")) for tag in soup.findAll("div",attrs={"itemprop":"price"}) : val = tag.string new_val = val[8:] workable = int(new_val) if workable > 250: print(type(workable)) else: print(type(workable)) Edit: When I print the type of new_val I get : print(type(new_val))

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  • Problem overridding virtual function

    - by William
    Okay, I'm writing a game that has a vector of a pairent class (enemy) that s going to be filled with children classes (goomba, koopa, boss1) and I need to make it so when I call update it calls the childclasses respective update. I have managed to create a example of my problem. #include <stdio.h> class A{ public: virtual void print(){printf("Hello from A");} }; class B : public A{ public: void print(){printf("Hello from B");} }; int main(){ A ab = B(); ab.print(); while(true){} } Output wanted: "Hello from B" Output got: "Hello from A" How do I get it to call B's print function?

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  • Why jquery have problem with onbeforeprint event?

    - by Cesar Lopez
    Hi all, I have the following function. $(function() { $(".sectionHeader:gt(0)").click(function() { $(this).next(".fieldset").slideToggle("fast"); }); $("img[alt='minimize']").click(function(e) { $(this).closest("table").next(".fieldset").slideUp("fast"); e.stopPropagation(); return false; }); $("img[alt='maximize']").click(function(e) { $(this).closest("table").next(".fieldset").slideDown("fast"); e.stopPropagation(); return false; }); }); <script type="text/javascript"> window.onbeforeprint = expandAll; function expandAll(){ $(".fieldset:gt(0)").slideDown("fast"); } </script> For this html <table class="sectionHeader" ><tr ><td>Heading 1</td></tr></table> <div style="display:none;" class="fieldset">Content 1</div> <table class="sectionHeader" ><tr ><td>Heading 2</td></tr></table> <div style="display:none;" class="fieldset">Content 2</div> I have several div class="fieldset" over the page, but when I do print preview or print, I can see all divs sliding down before opening the print preview or printing but on the actual print preview or print out they are all collapse. I would appreciate if anyone comes with a solution for this. Anyone have any idea why is this or how to fix it? Thanks. PS:Using a does not work either ( I assume because jquery using toggle) and its not the kind of question I am looking for.

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  • Python Etiquette: Importing Modules

    - by F3AR3DLEGEND
    Say I have two Python modules: module1.py: import module2 def myFunct(): print "called from module1" module2.py: def myFunct(): print "called from module2" def someFunct(): print "also called from module2" If I import module1, is it better etiquette to re-import module2, or just refer to it as module1.module2? For example (someotherfile.py): import module1 module1.myFunct() # prints "called from module1" module1.module2.myFunct() # prints "called from module2" I can also do this: module2 = module1.module2. Now, I can directly call module2.myFunct(). However, I can change module1.py to: from module2 import * def myFunct(): print "called from module1" Now, in someotherfile.py, I can do this: import module1 module1.myFunct() # prints "called from module1"; overrides module2 module1.someFunct() # prints "also called from module2" Also, by importing *, help('module1') shows all of the functions from module2. On the other hand, (assuming module1.py uses import module2), I can do: someotherfile.py: import module1, module2 module1.myFunct() # prints "called from module1" module2.myFunct() # prints "called from module2" Again, which is better etiquette and practice? To import module2 again, or to just refer to module1's importation?

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  • issue running a batch script to kill a process

    - by user657064
    I am using the following script on a command line to kill a hypothetical notepad process (using a Korn shell in Windows XP, if that matters): kill $(tasklist | grep -i notepad.exe | awk '{print 2}') Now I take this line, and put it into a batch file c:\temp\testkill.bat, thinking that I should just as well be able to kill the process by running the batch file. However, when I run the batch file, I get the following awk error about unbalanced parentheses: C:/Temp ./testkill.bat C:\Tempkill $(tasklist | grep -i notepad.exe | awk '{print $2}') awk: unbalanced () Context is: {print $2}) <<< C:/Temp So I'm baffled as to why I am getting this error about unbalanced parentheses when I run this script via a batch file, but have no issues when I run the command directly from the command line? (Btw, I'm not necessarily tied to this way of killing a process - as a total noob to shell scripting, I am additionally wondering why if I write the following on the command line: tasklist | grep -i notepad.exe | awk '{print $2}' | kill the process ID that comes out of the tasklist/grep/awk calls doesn't seem to properly get piped to kill...)

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  • Why will this for loop not return one field from list rather than the list?

    - by Dick Eshelman
    import csv """sample row = 10/6/2010,73.42,74.43,72.9,74.15,2993500""" filename_in = 'c:/python27/scripts/fiverows.csv' reader = csv.reader(open(filename_in, "rb"), dialect="excel", delimiter="\t", quoting =csv.QUOTE_MINIMAL) for row in reader: for item in row: print 'row = ',row print 'item = ', item When you run this script and print the row you get the sample row returned in [] as a list. When you print the item you get the sample row as an unquoted string. Why do I not get each field ie, (10/6/2010), (73.42), etc. returned as an item? How do I return a single item?

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  • What's wrong with this statement in perl?

    - by benjamin button
    print "$_", join(',',sort keys %$h),"\n"; It's giving me an error below: Use of uninitialized value in string at missing_months.pl line 36. 1,10,11,12 this print statement is present in a for loop as below: foreach my $num ( sort keys %hash ) { my $h = $hash{$num}; print "$_", join(',',sort keys %$h),"\n"; }

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  • python multiprocessing.Process.Manager not producing consistent results?

    - by COpython
    I've written the following code to illustrate the problem I'm seeing. I'm trying to use a Process.Manager.list() to keep track of a list and increment random indices of that list. Each time there are 100 processes spawned, and each process increments a random index of the list by 1. Therefore, one would expect the SUM of the resulting list to be the same each time, correct? I get something between 203 and 205. from multiprocessing import Process, Manager import random class MyProc(Process): def __init__(self, A): Process.__init__(self) self.A = A def run(self): i = random.randint(0, len(self.A)-1) self.A[i] = self.A[i] + 1 if __name__ == '__main__': procs = [] M = Manager() a = M.list(range(15)) print('A: {0}'.format(a)) print('sum(A) = {0}'.format(sum(a))) for i in range(100): procs.append(MyProc(a)) map(lambda x: x.start(), procs) map(lambda x: x.join(), procs) print('A: {0}'.format(a)) print('sum(A) = {0}'.format(sum(a)))

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  • R matrix handling expressions aren't evaluated in a function or a "for" loop - Column extract doesn't seem to work

    - by Sal Leggio
    I have an R matrix named ddd. When I enter this, everything works fine: i <- 1 shapiro.test(ddd[,y]) ad.test(ddd[,y]) stem(ddd[,y]) print(y) The calls to Shapiro Wilk, Anderson Darling, and stem all work, and extract the same column. If I put this code in a "for" loop, the calls to Shapiro Wilk, and Anderson Darling stop working, while the the stem & leaf call and the print call continue to work. for (y in 7:10) { shapiro.test(ddd[,y]) ad.test(ddd[,y]) stem(ddd[,y]) print(y) } The decimal point is 1 digit(s) to the right of the | 0 | 0 0 | 899999 1 | 0 [1] 7 The same thing happens if I try and write a function. SW & AD do not work. The other calls do. D <- function (y) { + shapiro.test(ddd[,y]) + ad.test(ddd[,y]) + stem(ddd[,y]) + print(y) } D(9) The decimal point is at the | 9 | 000 9 | 10 | 00000 [1] 9 Why don't all the calls behave the same way?

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  • It says i have an indented block when i dont?

    - by user3728373
    def cave(): global key global response print(''' You find yourself standing infront of a cave. You venture into the cave to find a large door blocking your path. (insert key, turn around''') response = input("Enter a command: ") while response != 'insert key' or response != 'turn around': if response =='insert key' or response == 'turn around': break print('Choose one of the options: ") response = input() if response == 'insert key': if key == 1: win() else: print('''You don't have a key. Get One!!''') elif response == 'turn around' : home()

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  • For improving the join of two wave files

    - by kaki
    i want to get the values of the last 30 frames of the first wav file and first thirty frames of the second wave file in integer format and stored in a list or array. i have written the code for joining but during this manupalation i am getting in byte format and tried to convert it to integer but couldn't. as told before i want to get the frame detail of 1st 30 and last 30 in integer format,and by performing other operations join can be more successful looking for your help in this,please... thanking you, import wave m=['C:/begpython/S0001_0002.wav', 'C:/begpython/S0001_0001.wav'] i=1 a=m[i] infiles = [a] outfile = "C:/begpython/S0001_00367.wav" data= [] data1=[] for infile in infiles: w = wave.open(infile, 'rb') data1=[w.getnframes] #print w.readframes(100) data.append( [w.getparams(), w.readframes(w.getnframes())] ) #print w.readframes(1) #data1 = [ord(character) for character in data1] #print data1 #data1 = ''.join(chr(character) for character in data1) w.close() print data output = wave.open(outfile, 'wb') output.setparams(data[0][0]) output.writeframes(data[0][1]) output.writeframes(data[1][1]) output.writeframes(data[2][1]) output.close()

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  • python - returns incorrect positive #

    - by tekknolagi
    what i'm trying to do is write a quadratic equation solver but when the solution should be -1, as in quadratic(2, 4, 2) it returns 1 what am i doing wrong? #!/usr/bin/python import math def quadratic(a, b, c): #a = raw_input("What\'s your `a` value?\t") #b = raw_input("What\'s your `b` value?\t") #c = raw_input("What\'s your `c` value?\t") a, b, c = float(a), float(b), float(c) disc = (b*b)-(4*a*c) print "Discriminant is:\n" + str(disc) if disc = 0: root = math.sqrt(disc) top1 = b + root top2 = b - root sol1 = top1/(2*a) sol2 = top2/(2*a) if sol1 != sol2: print "Solution 1:\n" + str(sol1) + "\nSolution 2:\n" + str(sol2) if sol1 == sol2: print "One solution:\n" + str(sol1) else: print "No solution!" EDIT: it returns the following... import mathmodules mathmodules.quadratic(2, 4, 2) Discriminant is: 0.0 One solution: 1.0

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  • How to lazy load a data structure (python)

    - by Anton Geraschenko
    I have some way of building a data structure (out of some file contents, say): def loadfile(FILE): return # some data structure created from the contents of FILE So I can do things like puppies = loadfile("puppies.csv") # wait for loadfile to work kitties = loadfile("kitties.csv") # wait some more print len(puppies) print puppies[32] In the above example, I wasted a bunch of time actually reading kitties.csv and creating a data structure that I never used. I'd like to avoid that waste without constantly checking if not kitties whenever I want to do something. I'd like to be able to do puppies = lazyload("puppies.csv") # instant kitties = lazyload("kitties.csv") # instant print len(puppies) # wait for loadfile print puppies[32] So if I don't ever try to do anything with kitties, loadfile("kitties.csv") never gets called. Is there some standard way to do this? After playing around with it for a bit, I produced the following solution, which appears to work correctly and is quite brief. Are there some alternatives? Are there drawbacks to using this approach that I should keep in mind? class lazyload: def __init__(self,FILE): self.FILE = FILE self.F = None def __getattr__(self,name): if not self.F: print "loading %s" % self.FILE self.F = loadfile(self.FILE) return object.__getattribute__(self.F, name) What might be even better is if something like this worked: class lazyload: def __init__(self,FILE): self.FILE = FILE def __getattr__(self,name): self = loadfile(self.FILE) # this never gets called again # since self is no longer a # lazyload instance return object.__getattribute__(self, name) But this doesn't work because self is local. It actually ends up calling loadfile every time you do anything.

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  • Is there a difference between `==` and `is` in python?

    - by Bernard
    My Google-fu has failed me. In Python, are these: n = 5 # Test one. if n == 5: print 'Yay!' # Test two. if n is 5: print 'Yay!' two tests for equality equivalent (ha!)? Does this hold true for objects where you would be comparing instances (a list say)? Okay, so this kind of answers my question: l = list() l.append(1) if l == [1]: print 'Yay!' # Holds true, but... if l is [1]: print 'Yay!' # Doesn't. So == tests value where is tests to see if they are the same object?

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  • Archive tar files to a different location inperl

    - by user314261
    Hi, I am a newbee in Perl. I am reading a directory having some archive files and uncompressing the archive files one by one. Everything seems well however the files are getting uncompressed in the folder which has the main perl code module which is running the sub modules. I want the archive to be generated in the folder I specify. This is my code: sub ExtractFile { #Read the folder which was copied in the output path recursively and extract if any file is compressed my $dirpath = $_[0]; opendir(D, "$dirpath") || die "Can't open dir $dirpath: $!\n"; my @list = readdir(D); closedir(D); foreach my $f (@list) { print " \$f = $f"; if(-f $dirpath."/$f") { #print " File in directory $dirpath \n ";#is \$f = $f\n"; my($file_name, $file_dirname,$filetype)= fileparse($f,qr{\..*}); #print " \nThe file extension is $filetype"; #print " \nThe file name is is $file_name"; # If compressed file then extract the file if($filetype eq ".tar" or $filetype eq ".tzr.gz") { my $arch_file = $dirpath."/$f"; print "\n file to be extracted is $arch_file"; my $tar = Archive::Tar->new($arch_file); #$tar->extract() or die ("Cannot extract file $arch_file"); #mkdir($dirpath."/$file_name"); $tar->extract_file($arch_file,$dirpath."/$file_name" ) or die ("Cannot extract file $arch_file"); } } if(-d $dirpath."/$f") { if($f eq "." or $f eq "..") { next; } print " Directory\n";# is $f"; ExtractFile($dirpath."/$f"); } } } The method ExtractFile is called recursively to loop all the archives. When using $tar-extract() it uncompresses in the folder which calls this metohd. when I use $tar-extract_file($arch_file,$dirpath."/$file_name" ) I get an error : No such file in archive: '/home/fsang/dante/workspace/output/s.tar' at /home/fsang/dante/lib/Extraction.pm line 80 Please help I have checked that path and input output there is no issue with it. Seems some usage problem I am not aware of for $tar-extract_file(). Many thanks for anyone resolving this issue. Regards, Sakshi

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  • SFINAE and detecting if a C++ function object returns void.

    - by Tom Swirly
    I've read the various authorities on this, include Dewhurst and yet haven't managed to get anywhere with this seemingly simple question. What I want to do is to call a C++ function object, (basically, anything you can call, a pure function or a class with ()), and return its value, if that is not void, or "true" otherwise. #include <stdio.h> struct Foo { void operator()() {} }; struct Bar { bool operator()() { return false; } }; Foo foo; Bar bar; bool baz() { return false; } void bang() {} const char* print(bool b) { printf(b ? "true, " : "false, "); } template <typename Functor> bool magicCallFunction(Functor f) { return true; // lots of template magic occurs here... } int main(int argc, char** argv) { print(magicCallFunction(foo)); print(magicCallFunction(bar)); print(magicCallFunction(baz)); print(magicCallFunction(bang)); printf("\n"); }

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  • How to write curiously recurring templates with more than 2 layers of inheritance?

    - by Kyle
    All the material I've read on Curiously Recurring Template Pattern seems to one layer of inheritance, ie Base and Derived : Base<Derived>. What if I want to take it one step further? #include <iostream> using std::cout; template<typename LowestDerivedClass> class A { public: LowestDerivedClass& get() { return *static_cast<LowestDerivedClass*>(this); } void print() { cout << "A\n"; } }; template<typename LowestDerivedClass> class B : public A<LowestDerivedClass> { public: void print() { cout << "B\n"; } }; class C : public B<C> { public: void print() { cout << "C\n"; } }; int main() { C c; c.get().print(); // B b; // Intentionally bad syntax, // b.get().print(); // to demonstrate what I'm trying to accomplish return 0; } How can I rewrite this code to compile without errors (and output "C\nB\n")?

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  • PHP: variable not working inside of function?

    - by mathiregister
    hi guys, echo $path; //working function createList($retval) { echo $path; //not working print "<form method='POST' action='' enctype='multipart/form-data'>"; foreach ($retval as $value) { print "<input type='checkbox' name='deletefiles[]' id='$value' value='$value'>$value<br>"; } print "<input class='submit' name='deleteBtn' type='submit' value='Datei(en) löschen'>"; print "</form>"; } what am I doing wrong? why is $path printed corretly outside of the createlist function, but it's not inside of the function?

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  • Error compiling basic java code

    - by Michael Younani
    New to java. Practicing coding by following a book. Heres my code: class Motorcycle { //Three instance variables - make and color are strings. while a boolean refers to TRUE OR FLASE(in this case off or on) String make; String color; boolean engineState; void startEngine() { if (engineState == true) System.out.print("The engine is already on."); else { engineState = true; System.out.print("The engine is now on."); } void showAtts() { System.out.print("This motorcycle is a " + color + " " + make); if (engineState ==true) System.out.print("The engine is on."); else System.out.print("The engine is off."); } } } When I compile I get 2 errors: 1) illegal start of expression 2) ; expected I can't pin point the problem. If anyone can direct me or hint me please do.

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  • How can I send an html email with perl?

    - by alexBrand
    I am trying to send an HTML email using perl. open(MAIL,"|/usr/sbin/sendmail -t"); ## Mail Header print MAIL "To: $to\n"; print MAIL "From: $from\n"; print MAIL "Subject: $subject\n\n"; ## Mail Body print MAIL "Content-Type: text/html; charset=ISO-8859-1\n\n<html><head></head><body>@emailBody"; close(MAIL) Is that the correct way of doing it? It is not working for some reason. Thanks for your help.

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  • Find all occurrences of a substring in Python

    - by cru3l
    Python has string.find() and string.rfind() to get the index of a substring in string. I wonder, maybe there is something like string.find_all() which can return all founded indexes (not only first from beginning or first from end)? For example: string = "test test test test" print string.find('test') # 0 print string.rfind('test') # 15 #that's the goal print string.find_all('test') # [0,5,10,15]

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  • regular expression not behaving as expected - Python

    - by philippe
    I have the following function which is supposed to read a .html file and search for <input> tags, and inject a <input type='hidden' > tag into the string to be shown into the page. However, that condition is never met:( e.g the if statement is never executed. ) What's wrong with my regex? def print_choose( params, name ): filename = path + name f = open( filename, 'r' ) records = f.readlines() print "Content-Type: text/html" print page = "" flag = True for record in records: if re.match( '<input*', str(record) ) != None: print record page += record page += "<input type='hidden' name='pagename' value='psychology' />" else: page += record print page Thank you

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  • finding a solution to a giving maze txt.file

    - by alberto
    how can i fix this program, the problem is when it print out the coordinate it give me a 7 for the start and finish, i would appreciated you help, thanks start = (len(data)) finish = (len(data)) pos= [] for i in range(len(pos)): for j in range(len(pos[i])): if pos[i][j] == "S": start=(i,j) elif pos[i][j] == "F": finish=(i,j) print "S found in",start, print "\nF found in",finish,"\n"

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  • How can I enable a debugging mode via a command-line switch for my Perl program?

    - by Michael Mao
    I am learning Perl in a "head-first" manner. I am absolutely a newbie in this language: I am trying to have a debug_mode switch from CLI which can be used to control how my script works, by switching certain subroutines "on and off". And below is what I've got so far: #!/usr/bin/perl -s -w # purpose : make subroutine execution optional, # which is depending on a CLI switch flag use strict; use warnings; use constant DEBUG_VERBOSE => "v"; use constant DEBUG_SUPPRESS_ERROR_MSGS => "s"; use constant DEBUG_IGNORE_VALIDATION => "i"; use constant DEBUG_SETPPING_COMPUTATION => "c"; our ($debug_mode); mainMethod(); sub mainMethod # () { if(!$debug_mode) { print "debug_mode is OFF\n"; } elsif($debug_mode) { print "debug_mode is ON\n"; } else { print "OMG!\n"; exit -1; } checkArgv(); printErrorMsg("Error_Code_123", "Parsing Error at..."); verbose(); } sub checkArgv #() { print ("Number of ARGV : ".(1 + $#ARGV)."\n"); } sub printErrorMsg # ($error_code, $error_msg, ..) { if(defined($debug_mode) && !($debug_mode =~ DEBUG_SUPPRESS_ERROR_MSGS)) { print "You can only see me if -debug_mode is NOT set". " to DEBUG_SUPPRESS_ERROR_MSGS\n"; die("terminated prematurely...\n") and exit -1; } } sub verbose # () { if(defined($debug_mode) && ($debug_mode =~ DEBUG_VERBOSE)) { print "Blah blah blah...\n"; } } So far as I can tell, at least it works...: the -debug_mode switch doesn't interfere with normal ARGV the following commandlines work: ./optional.pl ./optional.pl -debug_mode ./optional.pl -debug_mode=v ./optional.pl -debug_mode=s However, I am puzzled when multiple debug_modes are "mixed", such as: ./optional.pl -debug_mode=sv ./optional.pl -debug_mode=vs I don't understand why the above lines of code "magically works". I see both of the "DEBUG_VERBOS" and "DEBUG_SUPPRESS_ERROR_MSGS" apply to the script, which is fine in this case. However, if there are some "conflicting" debug modes, I am not sure how to set the "precedence of debug_modes"? Also, I am not certain if my approach is good enough to Perlists and I hope I am getting my feet in the right direction. One biggest problem is that I now put if statements inside most of my subroutines for controlling their behavior under different modes. Is this okay? Is there a more elegant way? I know there must be a debug module from CPAN or elsewhere, but I want a real minimal solution that doesn't depend on any other module than the "default". And I cannot have any control on the environment where this script will be executed...

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  • Login with Google OAuth api and return url with variable

    - by user2833721
    I am using the Google API for login in my site and I appending my variable with URL and I want that variable in the return URL of OAuth API because of update purpose can I return back that variable For example: <a href="<?php echo($authUrl); ?>&kicker"> I append the kicker in $authUrl and when I return back from Oauth api print $me['displayName']; print $user['email']; print $me['gender']; print $me['id']; with this output I also want my variable "kicker" how can I get it

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