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  • Conditions of Use dialog for Windows logins

    - by 20th Century Boy
    I need to design a "Conditions of Use" dialog that is presented to users after they logon to Windows XP. It must not allow the user to proceed until they check an "I agree" box. It must not be possible to shut it using Task Manager or any other method. And it should be fullscreen and modal. The "I agree" will remain checked automatically during subsequent logins for the duration of 1 month, after which the user will need to check it again. Also HR want to track who has checked the checkbox. Is such a thing possible using .Net? I can use C# to design it but I'm not sure about how to prevent users from bypassing the dialog. I know Windows Group Policy allows a dialog to be presented before login, but that does not allow a checkbox or any customization. Any thoughts?

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  • My cookies won't stay (PHP).

    - by RemiX
    I'm building an autologin system using cookies, but one fundamental part of the functionality of the cookies fails: they are non-persistent over different sessions - or even pages! In my login script, I set the cookies like this: setcookie('userID', $userID, time()+86400); // (edited after replies) $userID has a value. Then I print the $_COOKIE variable and it says array(['base_usid'] = 1); So that's good, but when I click the home page and print the $_COOKIE variable there, it says NULL. Does anyone see the problem?

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  • The best way to store username and password without a database

    - by Mokuchan
    Hello everyone, I want to build a simple single user login "library" in PHP, but I'm facing the following dilemma: how should I store username and password if I'm not using a database? A simple plain text file could be easily read and then the password could be easily decripted so that's not an option. If I create a php file with just <?php $Username= "username"; $Password= "password"; ?> then no one should be able to read it and I could simply include this file where I need it, but I'm not really sure you can't find a better way to do this! So what's, in your opinion, the best solution to this problem (and why)? Thanks

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  • Keeping track of the action before a login?

    - by soybie
    I'm trying to do the following: User can vote for an item (controller: item, action: vote) 2a. If the user is logged in, then vote action goes through. 2b. If user is not logged in, then user needs to log in/creates an account (handled by user controller), then vote action goes through. How do I do 2b such that once the user logs in/creates account, the vote action automatically goes through without having the user vote for the item again?

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  • How can I login linux using C or C++

    - by jnblue
    I need to programmely switch the current user to another,then the followed code should be executed in the environment(such as path,authority..) of another user. I've find the 'chroot()','setuid()' may be associated with my case, but these functions need the root authority, I don't have root authority, but I have the password of the second user. what should I do? I have tried shell "su - " can switch current user, can this command help me in my C++ code? Don't laugh at me if my question is very stupid, I'm a true freshman on linux. :) Thanks!

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  • How to use Twitter4j With JSF2 for Login? [on hold]

    - by subodh
    I am trying to do login with Twitter and using Twitter4j for that and wrote this code In JSF <h:commandButton id="twitterbutton" value="Sign up with Twitter" action="#{twitterLoginBean.redirectTwitterLogin}" immediate="true" styleClass="twitterbutton"/> In ManagedBean public String redirectTwitterLogin() throws ServletException, IOException, TwitterException { HttpServletRequest request = (HttpServletRequest) FacesContext .getCurrentInstance().getExternalContext().getRequest(); HttpServletResponse response = (HttpServletResponse) FacesContext .getCurrentInstance().getExternalContext().getResponse(); Twitter twitter = TwitterFactory.getSingleton(); twitter.setOAuthConsumer(apiKey, apiSecret); RequestToken requestToken = twitter.getOAuthRequestToken(); if (requestToken != null) { AccessToken accessToken = null; BufferedReader br = new BufferedReader(new InputStreamReader( System.in)); while (null == accessToken) { try { String pin = br.readLine(); accessToken = twitter .getOAuthAccessToken(requestToken, pin); } catch (TwitterException te) { System.out .println("Failed to get access token, caused by: " + te.getMessage()); System.out.println("Retry input PIN"); } } request.setAttribute(IS_AUTHENTICATED, true); if (accessToken != null) { LOGGER.debug("We have a valid oauth token! Make the facebook request"); doApiCall(twitter, request, response); return null; } } else { LOGGER.debug("We don't have auth code yet, fetching the Authorization URL..."); String authorizationUrl = requestToken.getAuthorizationURL(); LOGGER.debug("Redirecting to the Authorization URL: {}", authorizationUrl); request.setAttribute(IS_AUTHENTICATED, false); redirect(authorizationUrl, response); return null; } return null; } In above code i want first Login window of twitter will show and then again same method will call and after user will login i can show user information userId,Handel,location etc. Redirect private void redirect(String url, HttpServletResponse response) throws IOException { String urlWithSessionID = response.encodeRedirectURL(url); response.sendRedirect(urlWithSessionID); } But this code is not working Can anyone tell better Solution for this ?

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  • Trying to get around this Webservice call from Android using AsycTask

    - by Kevin Rave
    I am a fairly beginner in Android Development. I am developing an application that extensively relays on Webservice calls. First screen takes username and password and validates the user by calling the Webservice. If U/P is valid, then I need to fire up the 2nd activity. In that 2nd activity, I need to do 3 calls. But I haven't gotten to the 2nd part yet. In fact, I haven't completed the full coding yet. But I wanted to test if the app is working as far as I've come through. When calling webserivce, I am showing alert dialog. But the app is crashing somewhere. The LoginActivity shows up. When I enter U/P and press Login Button, it crashes. My classes: TaskHandler.java public class TaskHandler { private String URL; private User userObj; private String results; private JSONDownloaderTask task; ; public TaskHandler( String url, User user) { this.URL = url; this.userObj = user; } public String handleTask() { Log.d("Two", "In the function"); task = new JSONDownloaderTask(); Log.d("Three", "In the function"); task.execute(URL); return results; } private class JSONDownloaderTask extends AsyncTask<String, Void, String> { private String username;// = userObj.getUsername(); private String password; //= userObj.getPassword(); public HttpStatus status_code; public JSONDownloaderTask() { Log.d("con", "Success"); this.username = userObj.getUsername(); this.password = userObj.getPassword(); Log.d("User" + this.username , " Pass" + this.password); } private AsyncProgressActivity progressbar = new AsyncProgressActivity(); @Override protected void onPreExecute() { progressbar.showLoadingProgressDialog(); } @Override protected String doInBackground(String... params) { final String url = params[0]; //getString(R.string.api_staging_uri) + "Authenticate/"; // Populate the HTTP Basic Authentitcation header with the username and password HttpAuthentication authHeader = new HttpBasicAuthentication(username, password); HttpHeaders requestHeaders = new HttpHeaders(); requestHeaders.setAuthorization(authHeader); requestHeaders.setAccept(Collections.singletonList(MediaType.APPLICATION_JSON)); // Create a new RestTemplate instance RestTemplate restTemplate = new RestTemplate(); restTemplate.getMessageConverters().add(new MappingJacksonHttpMessageConverter()); try { // Make the network request Log.d(this.getClass().getName(), url); ResponseEntity<Message> response = restTemplate.exchange(url, HttpMethod.GET, new HttpEntity<Object>(requestHeaders), Message.class); status_code = response.getStatusCode(); return response.getBody().toString(); } catch (HttpClientErrorException e) { status_code = e.getStatusCode(); return new Message(0, e.getStatusText(), e.getLocalizedMessage(), "error").toString(); } catch ( Exception e ) { Log.d(this.getClass().getName() ,e.getLocalizedMessage()); return "Unknown Exception"; } } @Override protected void onPostExecute(String result) { progressbar.dismissProgressDialog(); switch ( status_code ) { case UNAUTHORIZED: result = "Invalid username or passowrd"; break; case ACCEPTED: result = "Invalid username or passowrd" + status_code; break; case OK: result = "Successful!"; break; } } } } AsycProgressActivity.java public class AsyncProgressActivity extends Activity { protected static final String TAG = AsyncProgressActivity.class.getSimpleName(); private ProgressDialog progressDialog; private boolean destroyed = false; @Override protected void onDestroy() { super.onDestroy(); destroyed = true; } public void showLoadingProgressDialog() { Log.d("Here", "Progress"); this.showProgressDialog("Authenticating..."); Log.d("Here", "afer p"); } public void showProgressDialog(CharSequence message) { Log.d("Here", "Message"); if (progressDialog == null) { progressDialog = new ProgressDialog(this); progressDialog.setIndeterminate(true); } Log.d("Here", "Message 2"); progressDialog.setMessage(message); progressDialog.show(); } public void dismissProgressDialog() { if (progressDialog != null && !destroyed) { progressDialog.dismiss(); } } } LoginActivity.java public class LoginActivity extends AsyncProgressActivity implements OnClickListener { Button login_button; HttpStatus status_code; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); //this.requestWindowFeature(Window.FEATURE_NO_TITLE); setContentView(R.layout.main); login_button = (Button) findViewById(R.id.btnLogin); login_button.setOnClickListener(this); ViewServer.get(this).addWindow(this); } public void onDestroy() { super.onDestroy(); ViewServer.get(this).removeWindow(this); } public void onResume() { super.onResume(); ViewServer.get(this).setFocusedWindow(this); } public void onClick(View v) { if ( v.getId() == R.id.btnLogin ) { User userobj = new User(); String result; userobj.setUsername( ((EditText) findViewById(R.id.username)).getText().toString()); userobj.setPassword(((EditText) findViewById(R.id.password)).getText().toString() ); TaskHandler handler = new TaskHandler(getString(R.string.api_staging_uri) + "Authenticate/", userobj); Log.d(this.getClass().getName(), "One"); result = handler.handleTask(); Log.d(this.getClass().getName(), "After two"); Utilities.showAlert(result, LoginActivity.this); } } Utilities.java public class Utilities { public static void showAlert(String message, Context context) { AlertDialog.Builder alertDialogBuilder = new AlertDialog.Builder(context); alertDialogBuilder.setTitle("Login"); alertDialogBuilder.setMessage(message) .setCancelable(false) .setPositiveButton("OK",new DialogInterface.OnClickListener() { public void onClick(DialogInterface dialog,int id) { dialog.dismiss(); //dialog.cancel(); } }); alertDialogBuilder.setIcon(drawable.ic_dialog_alert); // create alert dialog AlertDialog alertDialog = alertDialogBuilder.create(); // show it alertDialog.show(); } }

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  • Java: Handling cookies when logging in with POST

    - by Cris Carter
    I'm having quite some trouble logging in to any site in Java. I'm using the default URLconnection POST request, but I'm unsure how to handle the cookies properly. I tried this guide: http://www.hccp.org/java-net-cookie-how-to.html But couldn't get it working. I've been trying basically for days now, and I really need help if anyone wants to help me. I'll probably be told that it's messy and that I should use a custom library meant for this stuff. I tried downloading one, but wasn't sure how to get it set up and working. I've been trying various things for hours now, and it just won't work. I'd rather do this with a standard URLconnection, but if anyone can help me get another library working that's better for this, that would be great, too. I would really appreciate if someone could post a working source that I could study. What I need is: POST login data to site - Get and store the cookie from the site - use cookie with next URLconnection requests to get logged-in version of the site. Can anyone help me with this? Would be EXTREMELY appreciated. It really does mean a lot. If anyone wants to actually help me out live, please leave an instant-messenger address. Thank you a lot for your time.

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  • Error 1053: the service did not respond to the start or control request in a timely fashion

    - by deejjaayy
    i know this is very much a "how long is a piece of string" type of question, however i have recently inherited a couple of applications that run as windows services, and i am having problems providing a gui (accessible from a context menu in system tray) with both of them. before you ask, the reason why we need a gui for a windows service is in order to be able to re-configure the behaviour of the windows service(s) without resorting to stopping/re-starting. my code works fine in debug mode, and i get the context menu come up, and everything behaves correctly etc. when i install the service via "installutil" using a named account (i.e., not Local System Account), the service runs fine, but doesn't display the icon in the system tray (i know this is normal behaviour because i don't have the "interact with desktop" option). here is the problem though - when i choose the "LocalSystemAccount" option, and check the "interact with desktop" option, the service takes AGES to start up for no obvious reason, and i just keep getting "Could not start the ... service on Local Computer. Error 1053: the service did not respond to the start or control request in a timely fashion". incidentally, i increased the windows service timeout from the default 30 seconds to 2 minutes via a registry hack (see http://support.microsoft.com/kb/824344, search for TimeoutPeriod in section 3), however the service start up still times out. my first question is - why might the "Local System Account" login takes SOOOOO MUCH LONGER than when the service logs in with the non-LocalSystemAccount, causing the windows service time-out? what's could the difference be between these two to cause such different behaviour at start up? secondly - taking a step back, all i'm trying to achieve, is simply a windows service that provides a gui for configuration - I'd be quite happy to run using the non-Local System Account (with named user/pwd), if I could get the service to interact with the desktop (that is, have a context menu available from the system tray). is this possible, and if so how? any pointers to the above questions would be very much appreciated! thanks in advance for your help.

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  • Uploading an xml direct to ftp

    - by Joshua Maerten
    i put this direct below a button: XmlDocument doc = new XmlDocument(); XmlElement root = doc.CreateElement("Login"); XmlElement id = doc.CreateElement("id"); id.SetAttribute("userName", usernameTxb.Text); id.SetAttribute("passWord", passwordTxb.Text); XmlElement name = doc.CreateElement("Name"); name.InnerText = nameTxb.Text; XmlElement age = doc.CreateElement("Age"); age.InnerText = ageTxb.Text; XmlElement Country = doc.CreateElement("Country"); Country.InnerText = countryTxb.Text; id.AppendChild(name); id.AppendChild(age); id.AppendChild(Country); root.AppendChild(id); doc.AppendChild(root); // Get the object used to communicate with the server. FtpWebRequest request = (FtpWebRequest)WebRequest.Create("ftp://users.skynet.be"); request.Method = WebRequestMethods.Ftp.UploadFile; request.UsePassive = false; // This example assumes the FTP site uses anonymous logon. request.Credentials = new NetworkCredential("fa490002", "password"); // Copy the contents of the file to the request stream. StreamReader sourceStream = new StreamReader(); byte[] fileContents = Encoding.UTF8.GetBytes(sourceStream.ReadToEnd()); sourceStream.Close(); request.ContentLength = fileContents.Length; Stream requestStream = request.GetRequestStream(); requestStream.Write(fileContents, 0, fileContents.Length); requestStream.Close(); FtpWebResponse response = (FtpWebResponse)request.GetResponse(); response.Close(); MessageBox.Show("Created SuccesFully!"); this.Close(); but i always get an error of the streamreader path, what do i need to place there ? the meening is, creating an account and when i press the button, an xml file is saved to, ftp://users.skynet.be/testxml/ the filename is from usernameTxb.Text + ".xml".

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  • PHP SDK Requires two logins...doesn't recognize first

    - by Jay Konieczny
    I am using the following code to authenticate whether users are logged in or not. While users can log in, they have to click the login button twice. Additionally, sometimes even after they click the log-in button twice, my "user info" part of the page (earlier in the page than the content) shows them as logged out while the actual page shows them as logged in. Here is the code. Could someone suggest a better way of handling log-ins? function isLoggedIn($facebook) { if (isset($facebook) and $facebook->getUser() != 0) { // UserID exists, but user may still not be logged in. Let's check: try { $facebook->api('/me', 'GET'); // If this succeeds, then they are logged in. return true; } catch(FacebookApiException $e) { // Some kind of error, so not logged in. if(session_id() === '') session_destroy(); return false; } } else { if(session_id() === '') session_destroy(); return false; } } Thanks!

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  • How to avoid user keep trying login using Ruby on Rails?

    - by Tattat
    I want to create a login page, it can easy implement using Ruby on Rails. But the login is very simple, but I want more security. I want to stop the user keep trying the password. So, I have some ideas on that. First, stop login feature if the user keep trying the password for 15 mins. After the user login fail 5 times in 15 mins, the system should not allow the user login again in next 15 mins, ever his/her password is correct. Second, I want to add a human verification, after the user tried 5 times. After the user wait for 15 mins to login, I want to add an addition verification to the user. I want the user click the password, and the CAPTCHA image. If one of them is failed, they still can't login the system. He/She have 5 times to try, if he / she failed again, he/she need to want another 15 mins. Third, After the user tried 15 times, and still can't get into the system. I want to lock the user account, the user will receive an email, with a link to assign the password again. So, the question is "Is there any library to implement such authorization easily?" I know it can be implemented using code, but using library is much convenient. Also, I want to ask is there any security suggestion for that? thank u.

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  • PHP Session doesn't get read in next page after login validation, Why?

    - by NetStar
    I have a web site and when my users login it takes them to verify.php (where it connects to the DataBase and matches email and password to the user input and if OK puts client data into sessions and take the client to /memberarea/index.php ELSE back to login page with message "Invalid Email or password!") <?php ob_start(); session_start(); $email=$_POST['email']; $pass=md5($_POST['pass']); include("conn.php"); // connects to Database $sql="SELECT * FROM `user` WHERE email='$email' AND pass='$pass'"; $result=mysql_query($sql); $new=mysql_fetch_array($result); $_SESSION['fname']=$new['fname']; $_SESSION['lname']=$new['lname']; $_SESSION['email1']=$new['email1']; $_SESSION['passwrd']=$new['passwrd']; $no=mysql_num_rows($result); if ($no==1){ header('Location:memberarea/index.php'); }else { header("Location:login.php?m=$msg"); //msg="Invalid Login" } ?> then after email id and password is verified it takes them to ` /memberarea/index.php (This is where the problem happens.) where in index.php it checks if a session has been created in-order to block hackers to enter member area and sends them back to the login page. <? session_start(); isset($_SESSION['email'])` && `isset($_SESSION['passwrd'])` The problem is the client gets verified in verify.php (the code is above) In varify.php only after I put ob_start(); ontop of session_start(); It moves on to /memberarea/index.php , If I remove ob_start() It keeps the client on the verify.php page and displays error header is alredy SENT. after I put ob_start() it goes in to /memberarea/index.php but the session is blank, so it goes back to the login page and displays the error ($msg) "Invalid Login" which I programed to display. Can anyone tell me why the session cant pass values from verify.php to /memberarea/index.php

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  • Saving images only available when logged in

    - by James
    Hi, I've been having some trouble getting images to download when logged into a website that requires you to be logged in. The images can only be viewed when you are logged in to the site, but you cannot seem to view them directly in the browser if you copy its location into a tab/new window (it redirects to an error page - so I guess the containing folder has be .htaccess-ed). Anyway, the code I have below allows me to log in and grab the HTML content, which works well - but I cannot grab the images ... this is where I need help! <? // curl.php class Curl { public $cookieJar = ""; public function __construct($cookieJarFile = 'cookies.txt') { $this->cookieJar = $cookieJarFile; } function setup() { $header = array(); $header[0] = "Accept: text/xml,application/xml,application/xhtml+xml,"; $header[0] .= "text/html;q=0.9,text/plain;q=0.8,image/gif;q=0.8,image/x-bitmap;q=0.8,image/jpeg;q=0.8,image/png,*/*;q=0.5"; $header[] = "Cache-Control: max-age=0"; $header[] = "Connection: keep-alive"; $header[] = "Keep-Alive: 300"; $header[] = "Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.7"; $header[] = "Accept-Language: en-us,en;q=0.5"; $header[] = "Pragma: "; // browsers keep this blank. curl_setopt($this->curl, CURLOPT_USERAGENT, 'Mozilla/5.0 (Windows; U; Windows NT 5.2; en-US; rv:1.8.1.7) Gecko/20070914 Firefox/2.0.0.7'); curl_setopt($this->curl, CURLOPT_HTTPHEADER, $header); curl_setopt($this->curl, CURLOPT_COOKIEJAR, $this->cookieJar); curl_setopt($this->curl, CURLOPT_COOKIEFILE, $this->cookieJar); curl_setopt($this->curl, CURLOPT_AUTOREFERER, true); curl_setopt($this->curl, CURLOPT_FOLLOWLOCATION, true); curl_setopt($this->curl, CURLOPT_RETURNTRANSFER, true); } function get($url) { $this->curl = curl_init($url); $this->setup(); return $this->request(); } function getAll($reg, $str) { preg_match_all($reg, $str, $matches); return $matches[1]; } function postForm($url, $fields, $referer = '') { $this->curl = curl_init($url); $this->setup(); curl_setopt($this->curl, CURLOPT_URL, $url); curl_setopt($this->curl, CURLOPT_POST, 1); curl_setopt($this->curl, CURLOPT_REFERER, $referer); curl_setopt($this->curl, CURLOPT_POSTFIELDS, $fields); return $this->request(); } function getInfo($info) { $info = ($info == 'lasturl') ? curl_getinfo($this->curl, CURLINFO_EFFECTIVE_URL) : curl_getinfo($this->curl, $info); return $info; } function request() { return curl_exec($this->curl); } } ?> And below is the page that uses it. <? // data.php include('curl.php'); $curl = new Curl(); $url = "http://domain.com/login.php"; $newURL = "http://domain.com/go_here.php"; $username = "user"; $password = "pass"; $fields = "user=$username&pass=$password"; // Calling URL $referer = "http://domain.com/refering_page.php"; $html = $curl->postForm($url, $fields, $referer); $html = $curl->get($newURL); echo $html; ?> I've tried putting the direct URL for the image into $newURL but that doesn't get the image - it simply returns an error saying since that folder is not available to view directly. I've tried varying the above in different ways, but I haven't been successful in getting an image, though I have managed to get a screen through basically saying error 405 and/or 406 (but not the image I want). Any help would be great!

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  • Login failed for user 'sa' because the account is currently locked out. The system administrator can

    - by cabhilash
    Login failed for user 'sa' because the account is currently locked out. The system administrator can unlock it. (Microsoft SQL Server, Error: 18486) SQL server has local password policies. If policy is enabled which locks down the account after X number of failed attempts then the account is automatically locked down.This error with 'sa' account is very common. sa is default administartor login available with SQL server. So there are chances that an ousider has tried to bruteforce your system. (This can cause even if a legitimate tries to access the account with wrong password.Sometimes a user would have changed the password without informing others. So the other users would try to lo) You can unlock the account with the following options (use another admin account or connect via windows authentication) Alter account & unlock ALTER LOGIN sa WITH PASSWORD='password' UNLOCK Use another account Almost everyone is aware of the sa account. This can be the potential security risk. Even if you provide strong password hackers can lock the account by providing the wrong password. ( You can provide extra security by installing firewall or changing the default port but these measures are not always practical). As a best practice you can disable the sa account and use another account with same privileges.ALTER LOGIN sa DISABLE You can edit the lock-ot options using gpedit.msc( in command prompt type gpedit.msc and press enter). Navigate to Account Lokout policy as shown in the figure The Following options are available Account lockout threshold This security setting determines the number of failed logon attempts that causes a user account to be locked out. A locked-out account cannot be used until it is reset by an administrator or until the lockout duration for the account has expired. You can set a value between 0 and 999 failed logon attempts. If you set the value to 0, the account will never be locked out. Failed password attempts against workstations or member servers that have been locked using either CTRL+ALT+DELETE or password-protected screen savers count as failed logon attempts. Account lockout duration This security setting determines the number of minutes a locked-out account remains locked out before automatically becoming unlocked. The available range is from 0 minutes through 99,999 minutes. If you set the account lockout duration to 0, the account will be locked out until an administrator explicitly unlocks it. If an account lockout threshold is defined, the account lockout duration must be greater than or equal to the reset time. Default: None, because this policy setting only has meaning when an Account lockout threshold is specified. Reset account lockout counter after This security setting determines the number of minutes that must elapse after a failed logon attempt before the failed logon attempt counter is reset to 0 bad logon attempts. The available range is 1 minute to 99,999 minutes. If an account lockout threshold is defined, this reset time must be less than or equal to the Account lockout duration. Default: None, because this policy setting only has meaning when an Account lockout threshold is specified.When creating SQL user you can set CHECK_POLICY=on which will enforce the windows password policy on the account. The following policies will be applied Define the Enforce password history policy setting so that several previous passwords are remembered. With this policy setting, users cannot use the same password when their password expires.  Define the Maximum password age policy setting so that passwords expire as often as necessary for your environment, typically, every 30 to 90 days. With this policy setting, if an attacker cracks a password, the attacker only has access to the network until the password expires.  Define the Minimum password age policy setting so that passwords cannot be changed until they are more than a certain number of days old. This policy setting works in combination with the Enforce password historypolicy setting. If a minimum password age is defined, users cannot repeatedly change their passwords to get around the Enforce password history policy setting and then use their original password. Users must wait the specified number of days to change their passwords.  Define a Minimum password length policy setting so that passwords must consist of at least a specified number of characters. Long passwords--seven or more characters--are usually stronger than short ones. With this policy setting, users cannot use blank passwords, and they have to create passwords that are a certain number of characters long.  Enable the Password must meet complexity requirements policy setting. This policy setting checks all new passwords to ensure that they meet basic strong password requirements.  Password must meet the following complexity requirement, when they are changed or created: Not contain the user's entire Account Name or entire Full Name. The Account Name and Full Name are parsed for delimiters: commas, periods, dashes or hyphens, underscores, spaces, pound signs, and tabs. If any of these delimiters are found, the Account Name or Full Name are split and all sections are verified not to be included in the password. There is no check for any character or any three characters in succession. Contain characters from three of the following five categories:  English uppercase characters (A through Z) English lowercase characters (a through z) Base 10 digits (0 through 9) Non-alphabetic characters (for example, !, $, #, %) A catch-all category of any Unicode character that does not fall under the previous four categories. This fifth category can be regionally specific.

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  • Solution - Login failed for user x. Reason Token based server access validation failed and error - 18456

    - by simonsabin
    Had a very bizarre situation yesterday where a local machine account couldn’t access SQL Server and was getting Login failed for user <user>. Reason: Token-based server access validation failed with an infrastructure error. Check for previous errors. [CLIENT: <client ip>] along with Error: 18456, Severity: 14, State: 11. The user was in the logins even after a refresh, it was in the users for the database. I decided to delete and remove the login and heh presto it worked. I thought you...(read more)

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  • Why make the login page to a single page application a separate page?

    - by ryanzec
    I am wondering why it seems to be popular to have the login page of a SPA be a separate page that is not page of the SPA (as in loaded and send data through ajax requests)? I only thing I can think of is security but I can't think a specific security reason. I mean the only thing that come to mind is that if your login page in part of the SPA, it sends the username/password through ajax which can be seen by such tools like firebug or web inspector however even if you send it as a normal POST request, there are other tools that can easily capture this data (like fiddler, httpscoop, etc...). Is there something I am missing?

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  • How can I reduce the time taken to login by postponing/delaying some startup applications?

    - by koushik
    I have setup some applications to startup on each login (e.g., redshift-gtk, gtg) automatically but after adding these to startup applications (System -> Preferences -> Startup Applications) obviously the time taken to login has increased. Due to all this the time it takes for my panels, desktop etc to appear is too long - until which I am forced to wait. I don't need these apps to be available immediately, but it would be good if they startup eventually, meanwhile the ubuntu menu/panel is available for running other apps that I might need to. I tried using at command, with the intention of editing all startup applications to put the commands in the at queue, but this didn't work since the apps don't get the necessary environment variables (like DISPLAY). Is this what nice command is used for? Any other ideas how I can accomplish this? If possible, I would like to avoid editing the startup applications commands, since this would mean a lot of effort to replicate on other machines I use.

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  • How do I change the color of the screen that is displayed before the login screen?

    - by Jake Newkirk
    How do I change the color that the system displays just before the login screen is displayed? Here is the boot sequence on my machine in the order that things are displayed: The BIOS screen is flashed. A Black screen is displayed for a few seconds. My Plymouth splash screen is displayed. Purple screen is displayed for a few seconds (This is what I want to change). Finally, the login screen is displayed. Please let me know if you require any additional information while addressing this problem and as always, thank you for your time.

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  • Internal Outlook clients prompted for OWA login when only accessing local internal Exchange server?

    - by TallGuy
    Hope someone can help with this one. Scenario is an internal Exchange 2003 server. OWA front end server in the DMZ. OWA logins work fine, with SSL configured. Over the last week (3 times so far) when an internal person opens their Outlook and then tries to open an email with JPG attachments they are prompted for the webmail login. Why? Even if they enter their valid webmail OWA login it fails and reprompts once for each attachment. Once they get through the multiple login prompts, they can double-click to open the attachments, but they are all blank. Any ideas on what could cause this? Why would someone accessing an email from an internal Outlook client get prompted for details of the OWA/webmail server login?

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  • How do I select DWM or fluxbox to start on login?

    - by axe
    I am trying to setup DWM in Ubuntu 10.10. The package is successfully built - and now I am trying to get it up and running. I created the dwm.desktop file with the proper text and the path to the dwm exec is correct. On login screen, I can see dwm as a alternate session : but if I select it, still gnome starts. I even tried another window manager (fluxbox) - same problem. I can see and select it in the login screen, but gnome starts up. Trying gconftool-2 -s /desktop/gnome/session/required_components/windowmanager dwm --type string also does nothing. Killing the windows manager just restarts it - even if I chvt first. Also, don't see the xinit daemon running. Any ideas ? This setup was trivial in Debian, and older versions of Ubuntu. What changed ? I am guessing gnome integration is to blame - but am clueless as of now.

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  • How do I get Ubuntu One on Win7 to authenticate my login?

    - by Fred jones
    I just got a new computer running Windows 7 home premium, I used to have Ubuntu One working great on my Ubuntu desktop, but now, running win7, I know my login email address and password is correct, but it still says 'Authentication failed'. Googling the problem, looks like it may be because a device was removed from my list of devices, but the only device listed is my previous Ubuntu workstation, and nothing has been removed. I also checked the windows firewall and Ubuntu One is allowed on all interfaces on incoming and outgoing, and still authentication fails. Web login to my Ubuntu One account works fine.

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  • How to implement login page using Spring Security so that it works with Spring web flow?

    - by simon
    I have a web application using Spring 2.5.6 and Spring Security 2.0.4. I have implemented a working login page, which authenticates the user against a web service. The authentication is done by defining a custom authentincation manager, like this: <beans:bean id="customizedFormLoginFilter" class="org.springframework.security.ui.webapp.AuthenticationProcessingFilter"> <custom-filter position="AUTHENTICATION_PROCESSING_FILTER" /> <beans:property name="defaultTargetUrl" value="/index.do" /> <beans:property name="authenticationFailureUrl" value="/login.do?error=true" /> <beans:property name="authenticationManager" ref="customAuthenticationManager" /> <beans:property name="allowSessionCreation" value="true" /> </beans:bean> <beans:bean id="customAuthenticationManager" class="com.sevenp.mobile.samplemgmt.web.security.CustomAuthenticationManager"> <beans:property name="authenticateUrlWs" value="${WS_ENDPOINT_ADDRESS}" /> </beans:bean> The authentication manager class: public class CustomAuthenticationManager implements AuthenticationManager, ApplicationContextAware { @Transactional @Override public Authentication authenticate(Authentication authentication) throws AuthenticationException { //authentication logic return new UsernamePasswordAuthenticationToken(principal, authentication.getCredentials(), grantedAuthorityArray); } The essential part of the login jsp looks like this: <c:url value="/j_spring_security_check" var="formUrlSecurityCheck"/> <form method="post" action="${formUrlSecurityCheck}"> <div id="errorArea" class="errorBox"> <c:if test="${not empty param.error}"> ${sessionScope["SPRING_SECURITY_LAST_EXCEPTION"].message} </c:if> </div> <label for="loginName"> Username: <input style="width:125px;" tabindex="1" id="login" name="j_username" /> </label> <label for="password"> Password: <input style="width:125px;" tabindex="2" id="password" name="j_password" type="password" /> </label> <input type="submit" tabindex="3" name="login" class="formButton" value="Login" /> </form> Now the problem is that the application should use Spring Web Flow. After the application was configured to use Spring Web Flow, the login does not work anymore - the form action to "/j_spring_security_check" results in a blank page without error message. What is the best way to adapt the existing login process so that it works with Spring Web Flow?

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