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  • get JSON object attribute name

    - by Laurent Luce
    I know that I can retrieve "session" by using item.fields.name but what if I don't know in advance that the attribute is called "name". How can I retrieve the list of the attributes names in fields first. [ { "pk": 2, "model": "auth.group", "fields": { "name": "session" } } ]

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  • Authorization error in facebook aplication

    - by bhaskaragr29
    require_login($required_permissions = 'email,photo_upload'); $auth= $facebook-do_get_session($_GET['auth_token']); $facebook-set_user($s['uid'], $s['session_key'], $s['expires'], $s['secret']) ? when ever i tries to login into my app it just refreshed and refresh with wih different auth_tokens. please help

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  • Django context processor gets AnonymousUser

    - by myfreeweb
    instead of User. def myview(request): return render_to_response('tmpl.html', {'user': User.objects.get(id=1}) works fine and passes User to template. But def myview(request): return render_to_response('tmpl.html', {}, context_instance=RequestContext(request)) with a context processor def user(request): from django.contrib.auth.models import User return {'user': User.objects.get(id=1)} passes AnonymousUser, so I can't get the variables I need :( What's wrong?

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  • create hgrc file for all paths on a machine

    - by noam
    I want to create a hgrc file to set the username and password for all paths on some machine, e.g no matter in which directory I am in, hg clone some_path will always work without prompting for a username and a password (this is for an auto-deploy script). I followed the instructions and created a file: /etc/mercurial/hgrc.d/deploy.rc it's contents: [auth] default.prefix= http://myrepo default.username = myuname default.password = pwd But when I do hg clone some_path I get abort: error: Connection refused. What Am i doing wrong?

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  • HQl equivalent of sql query

    - by kash
    String SQL_QUERY = "SELECT count(*) FROM (SELECT * FROM Url as U where U.pageType=" + 1 + " group by U.pageId having count(U.pageId) = 1)"; query = session.createQuery(SQL_QUERY); I am getting an error org.hibernate.hql.ast.QuerySyntaxException: unexpected token: ( near line 1, column 23 [ SELECT count() FROM (SELECT * FROM Url as U where U.pageType = 2 group by U.pageId having count(U.pageId) = 1)]

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  • need help with xpath expression

    - by geoff swartz
    I have an xml node that looks like <slot highcount="20" lowcount="10" /> I've tried the following xpath expression: XmlNode node = xdoc.SelectSingleNode("slot[@lowcount>=12] && slot[@highcount <=12]"); but I get an invalid token error and I don't have enough experience with this to know what I'm doing wrong. Any ideas?

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  • gcc check if file is main (#if __BASE_FILE__ == __FILE__)

    - by Marcin Raczkowski
    Hello. In ruby there's very common idiom to check if current file is "main" file: if __FILE__ == $0 # do something here (usually run unit tests) end I'd like to do something similar in C after reading gcc documentation I've figured that it should work like this: #if __FILE__ == __BASE_FILE__ // Do stuff #endif the only problem is after I try this: $ gcc src/bitmap_index.c -std=c99 -lm && ./a.out src/bitmap_index.c:173:1: error: token ""src/bitmap_index.c"" is not valid in preprocessor expressions Am I using #if wrong?

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  • Get Const / Static Name from Function / Method Call.

    - by Mark Tomlin
    I want to find the token's name passed by augment into a function. class Norm { const STR_NORM = 0; const INT_NORM = 0; } function foo($Arg1, $Arg2 = NULL) { getConstName($Arg1); # Should Return STR_NORM; return $Arg1, $Arg2; } echo foo(Norm::STR_NORM); Is there any way to impalement getConstName via the PHP Reflection API?

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  • Float conditional in bash

    - by Werner
    Hi, in bash I need to compare two float numbers, one which I define in the script and the other read as paramter, for that I do: if [[ $aff -gt 0 ]] then a=b echo "xxx "$aff #echo $CX $CY $CZ $aff fi but I get the error: [[: -309.585300: syntax error: invalid arithmetic operator (error token is ".585300") What is wrong? Thanks

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  • authlogic rails question - how to code for an API

    - by phil swenson
    I have authlogic going on my app, but now I need to have an an API. I don't want to establish a session, just want a user to send in data in a json request such as: {"type":"address","password":"mypassword","name":"my notificaiton name goes here","user":"myusername","text":"my interesting stuff goes here"} So questions - 1) is this a decent approach? 2) how do i do the auth inside my rails controller?

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  • How to protect an ASP Classic Page?

    - by SH
    How can I protect an ASP Classic page with either HTTP AUTH (you must provide a username and password to service) or a randomly generated access key that will be included as one of the parameters of the HTTP POST using the variable name access_key. Can anybody provide asp classic code in this regard? Quick help will be appreciated... PS: OrderGroove is a 3rd party service... neglect it.

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  • Android String.equals doesn't work when I trying to match from httpresponse

    - by user469652
    RestClient.post("auth/login/", loginparam, new AsyncHttpResponseHandler() { @Override public void onSuccess(String s) { Toast.makeText(getApplicationContext(), String.valueOf(s.toLowerCase().equals("ok")), Toast.LENGTH_LONG).show(); if (s.equals("ok")) { startActivity(new Intent(getApplication(), HomeActivity.class)); } } }); This is the code I used for login in android app, In the Toast text, I can see the server did returned "ok", but s.equals always failed in my case, can someone explain that? Thank you.

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  • Freshbooks oauth question

    - by Phil
    Very quick question for freshbooks oauth. When requesting a Request Token you need to provide (amoung others) the oauth_signature method. Is the signature the consumer key and the consumer secret seperated by an ampersand? e.g. _consumer_key_%26_consumer_secret_ where _consumer_key_ is the consumer key. _consumer_secret_ is the consumer secret and %26 is a urlencode ampersand.

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  • Web service security not working. Java

    - by Nitesh Panchal
    Hello, I have a ejb module which contains my ejbs as well as web services. I am using Netbeans 6.8 and Glassfish V3 I right clicked on my web service and clicked "edit web service attributes" and then checked "secure service" and then selected keystore of my server. This is my sun-ejb-jar.xml file :- <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE sun-ejb-jar PUBLIC "-//Sun Microsystems, Inc.//DTD Application Server 9.0 Servlet 2.5//EN" "http://www.sun.com/software/appserver/dtds/sun-web-app_2_5-0.dtd"> <sun-ejb-jar> <security-role-mapping> <role-name>Admin</role-name> <group-name>Admin</group-name> </security-role-mapping> <security-role-mapping> <role-name>General</role-name> <group-name>General</group-name> </security-role-mapping> <security-role-mapping> <role-name>Member</role-name> <group-name>Member</group-name> </security-role-mapping> <enterprise-beans> <ejb> <ejb-name>MemberBean</ejb-name> <webservice-endpoint> <port-component-name>wsMember</port-component-name> <login-config> <auth-method>BASIC</auth-method> <realm>file</realm> </login-config> </webservice-endpoint> </ejb> </enterprise-beans> </sun-ejb-jar> Here MemberBean is my ejb and wsMember is my webservice. Then i made another project and added web service client and again right clicked on "edit web service attributes" and gave password as test and test. This username and password (test) is in Glassfish server in file realm. But when i try to invoke my webservice i always get SEC5046: Audit: Authentication refused for [test]. SEC1201: Login failed for user: test What am i doing wrong? Am i missing something?

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  • How to hash a password and store for later verification with another digest

    - by oxygen8
    I am using gsoap's wsseapi plugin and would like to store hashed sha1 passwords rather than plain text. I have spent a rediculous amount of time experimenting with various methods of hashing the plain text password for storage. Can anyone suggest a way to hash a password so it can be later verified against a username token digest sent by the client. I can't seem to get the client password to authenticate against my stored hash

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  • How to stop Django "app not found" error?

    - by cml
    When I run python ./manage.py sql grading my django site comes up with: Error: App with label grading could not be found. Are you sure you INSTALLED_APPS setting is correct? I have the app grading with __init__.py and everything, and my INSTALLED APPS is: INSTALLED_APPS = ( 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'django.contrib.admin', 'teachline.courses', 'teachline.grading', ) Why isn't this working?

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  • How to fix a warning message associated with strlen() used in Yacc?

    - by user547894
    Hello! Please i need your help. Basically, I am facing this warning message upon compiling with gcc, and am not able to deduce the error: Here are the details: The warning message i am receiving is literrally as follows: y.tab.c: In function ‘yyparse’: y.tab.c:1317 warning: incompatible implicit declaration of built-in function ‘strlen’ My Lex File looks like: %{ #include <stdio.h> #include <stdlib.h> #include <ctype.h> #include "y.tab.h" void yyerror(const char*); char *ptrStr; %} %START nameState %% "Name:" { BEGIN nameState; } <nameState>.+ { ptrStr = (char *)calloc(strlen(yytext)+1, sizeof(char)); strcpy(ptrStr, yytext); yylval.sValue = ptrStr; return sText; } %% int main(int argc, char *argv[]) { if ( argc < 3 ) { printf("Two args are needed: input and output"); } else { yyin = fopen(argv[1], "r"); yyout = fopen(argv[2], "w"); yyparse(); fclose(yyin); fclose(yyout); } return 0; } My Yacc file is as follows: %{ #include <stdio.h> #include <stdlib.h> #include <ctype.h> #include "y.tab.h" void yyerror(const char*); int yywrap(); extern FILE *yyout; %} %union { int iValue; char* sValue; }; %token <sValue> sText %token nameToken %% StartName: /* for empty */ | sName ; sName: sText { fprintf(yyout, "The Name is: %s", $1); fprintf(yyout, "The Length of the Name is: %d", strlen($1)); } ; %% void yyerror(const char *str) { fprintf(stderr,"error: %s\n",str); } int yywrap() { return 1; } *I was wondering how to remove this warning message. Please any suggestions are highly appreciated! Thanks in advance.

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