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  • Fluent Nhibernate left join

    - by Ronnie
    I want to map a class that result in a left outer join and not in an innner join. My composite user entity is made by one table ("aspnet_users") and an some optional properties in a second table (like FullName in "users"). public class UserMap : ClassMap<User> { public UserMap() { Table("aspnet_Users"); Id(x => x.Id, "UserId").GeneratedBy.Guid(); Map(x => x.UserName, "UserName"); Map(x => x.LoweredUserName, "LoweredUserName"); Join("Users",mm=> { mm.Map(xx => xx.FullName); }); } } this mapping result in an inner join select so no result come out is second table as no data. I'd like to generate an left join. Is this possible only at query level?

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  • How to design this simple database?

    - by Vafello
    I have 2 tables - one storing user information (id, username, password) and the second one storing information about events (id, name, description, date, username(represents the user who created the event)). I would like to implement 'favourite events' functionality. This would allow the user to store his favourite events and later display them in a list. I am not sure how to implement this in terms of design. I need a simple solution. Something like storing the IDs of favourite events in a field in the user table. I am using mysql and php. Can anyone point me to the right direction?

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  • Why does Net::Twitter complain "HTTP::Message content not bytes"?

    - by Russell C.
    We have been using Perl's Net:Twitter CPAN module (version 3.12) and basic authentication (not OAuth) for almost a year now to syndicate updates from our site to our Twitter account. We just migrated to a new server last week and since the move our updates to Twitter have stopped and the following error is being reported whenever we try to post an update: HTTP::Message content not bytes at /usr/lib/perl5/site_perl/5.8.8/HTTP/Request/Common.pm line 90 Here is the code we're using the update our Twitter account: use Net::Twitter; my $twitter = Net::Twitter->new( traits => [qw/API::REST/], username => $username, password => $password, source => 'twitterfeed' ); my $result = $twitter->update($status); I have no idea what the issue is and was hoping that someone else has run into this issue and can provide a quick solution. Thanks in advance for your help!

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  • Mysqli prepared insert statements always returning false

    - by user1754679
    I'm writing prepared statements that are supposed to insert data into a table, on a database that's been pre-selected in the variable $GLOBALS['mysqli']. The connection has been tested, and that's not the problem I'm having. I'm only running into trouble whenever my prepared statement involves INSERT INTO. I know the tablename, and field names are correct, but $stmt is ALWAYS false. What gives? $stmt = $GLOBALS['mysqli']->prepare("INSERT INTO audit_RefreshCount (user, count, lastrefresh) values (?,?,?)"); if ($stmt == TRUE) { $stmt->bindParam('ssi', $_SESSION['username'], '0', time()); //$stmt->bind_Param('ssi', $_SESSION['username'], '0', time()); // Also doesn't work. $stmt->execute(); }

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  • jQuery append breaks my HTML form (with submit button)

    - by JimFing
    I'm trying to create a form with a submit button via jQuery using append(). So the following: out.append('<form name="input" action="/createuser" method="get">'); out.append('Username: <input type="text" name="user" />'); out.append('<input type="submit" value="Submit" />'); out.append('</form>'); However, clicking on submit, nothing happens! However if I do the following: var s = '<form name="input" action="/createuser" method="get">' + 'Username: <input type="text" name="user" />' + '<input type="submit" value="Submit" />' + '</form>'; out.html(s); Then the submit button works fine! I'm happy to use the 2nd method, but would rather know what the problem is here. Thanks

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  • How to receive the text which was sent by SendText

    - by thillai-selvan
    In asterisk I have sent a text message using SendText as follows I have two registered users in sip.conf file. sip.conf details [thillai] username=thillai secret=thillai host=dynamic type=friend allow=all context=test [selvan] username=selvan secret=selvan allow=all host=dynamic type=friend context=test Then I have created the necessary extensions like this extensions.conf file: [test] exten = 677,1,BackGround(thankyou) exten = 677,n,Dial(SIP/thillai) exten = 677,n,SendText('this is for testing') So when a caller is trying to call to extension 677 this text information will be sent. My question is how can I receive this text in the caller side? Any help will be much appreciated.

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  • Best practice for web server user/group permissions

    - by Poe
    What's the best practice in a secure manner to setup the user/group and permissions? Here's what we currently have; web server runs as www/www. Fastcgi Php runs as www/www. User's shell/ftp account is username/username. We want the user to be able to have full access to all files, including those created by the web server 'www' from the shell or ftp. Similarly, we want the scripts run by fastcgi/php to be able to create files in user created directories and modify user created files.

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  • String handle in C#

    - by Chelsea_cole
    I don't understand the use of "get" and "set" command, how to add a list of the accounts using the code below and someone give me some example to fix the error? Thanks! :( public class Account { public string UserName {get rerurn textBox1.Test; // error set UserName = textBox1.Text;} // error public string Password { get; set; } public string RePassword { get; set; } public string Name { get; set; } public string bd { get; set; } public string dt { get; set; } public string dc { get; set; } } public class ListAcc { static void Data() { List<Account> UserList = new List<Account>(); } }

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  • Add a new member to a Twitter List

    - by yc10
    I'm trying to add a user (by variable $id) to a Twitter List using PHP CURL, and I can't get it to work. $curl_handle = curl_init(); curl_setopt($curl_handle, CURLOPT_URL, "http://twitter.com/username/list/members.xml"); curl_setopt($curl_handle, CURLOPT_POST, 1); curl_setopt($curl_handle, CURLOPT_POSTFIELDS, "id=$id"); curl_setopt($curl_handle, CURLOPT_CONNECTTIMEOUT, 2); curl_setopt($curl_handle, CURLOPT_RETURNTRANSFER, 1); curl_setopt($curl_handle, CURLOPT_USERPWD, "username:password"); curl_setopt($curl_handle, CURLOPT_HTTP_VERSION, CURL_HTTP_VERSION_1_1); curl_setopt($curl_handle, CURLOPT_VERBOSE, 1); $result = curl_exec($curl_handle); // Look at the returned header $resultArray = curl_getinfo($curl_handle); curl_close($curl_handle); if($resultArray['http_code'] == "200"){ echo 'Success'; } else { echo var_dump($resultArray); } The var_dump reveals that the http_code of the return is 403.

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  • about the post_save signal and created argument

    - by panchicore
    the docs says: post_save django.db.models.signals.post_save created A boolean; True if a -new- record was create. and I have this: from django.db.models.signals import post_save def handle_new_user(sender, instance, created, **kwargs): print "--------> save() "+str(created) post_save.connect(handle_new_user, sender=User) when I do in shell: u = User(username="cat") u.save() >>> --------> save() True u.username = "dog" u.save() >>> --------> save() True I expect a -------- save() False when I save() the second time because is an update? not?

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  • C# - Getting record from a row using DataRow

    - by pinkcupcake
    I'm trying to get record of a row using DataRow. Here's what I've done so far: uID = int.Parse(Request.QueryString["id"]); PhotoDataSetTableAdapters.MembersTableAdapter mem = new PhotoDataSetTableAdapters.MembersTableAdapter(); PhotoDataSet.MembersDataTable memTable = mem.GetMemberByID(uID); DataRow[] dr = memTable.Select("userID = uID"); string uName = dr["username"].ToString(); Then I got the error: Cannot implicitly convert type 'string' to 'int' The error points to "username". I don't know what's wrong because I'm just trying to assign a string variable to a string value. Anyone figures out the reason of the error? Please help and thanks.

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  • How can I make email template in Zend Framework?

    - by Billy
    I want to make email templates in Zend Framework. For example, <html> <body> Dear {$username$}, <br> This is a invitation email sent by your {$friend$}.<br> Regards,<br> Admin </body> </html> I want to make this file, get it in Zend framework, set those parameters (username, friend) and then send the email. How can I do that? Does Zend support this?

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  • Using TFS Team Build 2010 to deploy to Dev site and create packages for Staging and Production sites

    - by Kb
    I am trying to configure a TFS Team Build 2010 to perform automatic deployment to development environment and creation of deployment packages for staging and production environment. In the field for MSBuildArguments in the build definition I have: /p:DeployOnBuild=True <br/> /p:DeployTarget=MsDeployPublish <br/> /p:MSDeployPublishMethod=RemoteAgent <br/> /p:CreatePackageOnPublish=True <br/> /p:DeployIISAppPath=devwebsitename<br/> /p:MsDeployServiceUrl=http://deployserver/MsDeployAgentService<br/> /p:UserName=username<br/> /p:Password=password<br/> Automatic deployment of dev web site is ok and I get a package for the web site generated How can I (the same build) get deploy packages for the other environments : Staging and Production? Or am I missing som basic concept here?

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  • PHP/MySQL Database Issues

    - by queryne
    PHP/MySQL newbie question. I have a database I've imported into my local phpmyadmin. However it seems I can't access it from my a php application. The connection string seems right and when I try to authenticate user credentials to access database information, no problems. However authenticate everyone and knows when I put in fake credentials. Still it won't pull any other information from the database. For instance, once a users login they should see something like, "Hello username", that kind of thing. At this point I see "Hello" without the username. Any ideas what i might be missing?

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  • How do I specify (1) an order and (2) a meaninful string representation for users in my Django application?

    - by David Faux
    I have a Django application with users. I have a model called "Course" with a foreign key called "teacher" to the default User model that Django provides: class Course(models.Model): ... teacher = models.ForeignKey(User, related_name='courses_taught') When I create a model form to edit information for individual courses, the possible users for the teacher field appear in this long select menu of user names. These users are ordered by ID, which is of meager use to me. How can I order these users by their last names? change the string representation of the User class to be "Firstname Lastname (username)" instead of "username"?

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  • Computer Invisible On Domain

    - by Giawa
    Good afternoon, I'm sorry that this isn't a programming question specifically, but stackoverflow has been great at answering questions in the past, so I thought I'd give it a shot. One of our Linux users attempted to install Cygwin on our Windows Server 2008 Domain Controller. Now it is no longer possible to browse the domain and see all of the computers. For example, \\my_domain_name will just bring up a username/password dialog box (that will not accept any username or password, even the domain administrator) and no computers will ever be listed. However, I can still connect to computers based on their name or IP address. So \\eridanus or \\192.168.1.85 still work to connect to the shared directories of computers on our network. Does anyone know where I can find these settings? and how I can fix this problem? Thanks, Giawa

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  • [Android] How do I load URL that requires login into variable?

    - by bebeTech
    I am trying to port my usage meter from a JavaScript Gadget (win) / Widget (OSX) to Android. Total newbie when comes to JAVA + Eclipse + Android 2.1 SDK. Essentially what I want to do is load a page, pass through a username and password and load the resulting page into a array that I can then run some regular expressions through. My code from JavaScript (I've replace the actual URL with a dummy one) is: xmlhttp.open("post","https://acme.com.au/your_account/index.php?function=login",false); xmlhttp.setRequestHeader("If-Modified-Since", "Sat, 1 Jan 2000 00:00:00 GMT"); xmlhttp.setRequestHeader("Content-Type", "application/x-www-form-urlencoded"); xmlhttp.send("check_username=" + username + "&password=" + password); I need to know the Android equivalent to the above please. I've played around with WebView but that loads the page in a web browser which isn't what I want.

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  • having trouble with a mysql query

    - by chuck akers
    this keeps saying Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in directory here the error is near the login_query variable, can someone help me fix it. <?php if (isset($_POST['login_username'], $_POST['login_password'])) { $login_username = trim(mysql_real_escape_string(htmlentities($_POST['login_username']))); $login_password = md5(trim(mysql_real_escape_string(htmlentities($_POST['login_password'])))); if (!empty($login_username) && !empty($login_password)) { $login_query = mysql_query("SELECT user_id FROM username WHERE username='".$login_username."' AND password='".$login_password."'"); if (mysql_num_rows($login_query)==1) { $user_id = mysql_result($login_query, 0, 'user_id'); $_SESSION['user_id'] = $user_id; header('Location: index.php'); die(); } }} ?

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  • How to call a jquery function from an action method in controller?

    - by Hasan Fahim
    I have a requirement to open a popup from an action method in controller. The action method is basically registering a user. [HttpPost] public ActionResult Register(RegisterModel model) { if (ModelState.IsValid) { MembershipCreateStatus createStatus; Membership.CreateUser(model.UserName, model.Password, model.Email, null, null, true, null, out createStatus); if (createStatus == MembershipCreateStatus.Success) { FormsAuthentication.SetAuthCookie(model.UserName, false /* createPersistentCookie */); //------------------------------------------ //I need to call a jquery function from here //------------------------------------------ return RedirectToAction("Index", "Home"); } else { ModelState.AddModelError("", ErrorCodeToString(createStatus)); } } return View(model); } The jquery function, present in the view, would just make a hidden DIV, visible, and set the opacity, etc, to represent a popup. I need to call such a jquery function from the controller's action method shown above.

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  • How to query data from a password protected https website

    - by Addie
    I'd like my application to query a csv file from a secure website. I have no experience with web programming so I'd appreciate detailed instructions. Currently I have the user login to the site, manually query the csv, and have my application load the file locally. I'd like to automate this by having the user enter his login information, authenticating him on the website, and querying the data. The application is written in C# .NET. The url of the site is: https://www2.emidas.com/default.asp. I've tested the following code already and am able to access the file once the user has already authenticated himself and created a manual query. System.Net.WebClient Client = new WebClient(); Stream strm = Client.OpenRead("https://www3.emidas.com/users/<username>/file.csv"); Here is the request sent to the site for authentication. I've angle bracketed the real userid and password. POST /pwdVal.asp HTTP/1.1 Accept: image/jpeg, application/x-ms-application, image/gif, application/xaml+xml, image/pjpeg, application/x-ms-xbap, application/vnd.ms-excel, application/vnd.ms-powerpoint, application/msword, application/x-shockwave-flash, */* User-Agent: Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 6.1; Trident/4.0; SLCC2; .NET CLR 2.0.50727; .NET CLR 3.5.30729; .NET CLR 3.0.30729; Media Center PC 6.0; InfoPath.2; Tablet PC 2.0; OfficeLiveConnector.1.4; OfficeLivePatch.1.3; .NET4.0C; .NET4.0E) Content-Type: application/x-www-form-urlencoded Accept-Encoding: gzip, deflate Cookie: ASPSESSIONID<unsure if this data contained password info so removed>; ClientId=<username> Host: www3.emidas.com Content-Length: 36 Connection: Keep-Alive Cache-Control: no-cache Accept-Language: en-US client_id=<username>&password=<password>

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  • Find overdrawn accounts in SQL

    - by mazzzzz
    Hey guys, I have a program that allows me to run queries against a large database. I have two tables that are important right now, Deposits and withdraws. Each contains a history of every user. I need to take each table, add up every deposit and withdraws (per user), then subtract the withdraws from the deposits. I then need to return every user whos result is negative (aka they withdrew more then they deposited). Is this possible in one query? Example: Deposit Table: |ID|UserName|Amount| |1 | Use1 |100.00| |2 | Use1 |50.00 | |3 | Use2 |25.00 | |4 | Use1 | 5.00 | WithDraw Table: |ID|UserName|Amount| |2 | Use2 | 5.00 | |1 | Use1 |100.00| |4 | Use1 | 5.00 | |3 | Use2 |25.00 | So then the result would output: |OverWithdrawers| | Use2 | Is this possible (I sure don't know how to do it)? Thanks for any help, Max

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  • "SQLSTATE[23000]: Integrity constraint violation" in Doctrine

    - by rags
    Hi, i do get an Integrity constraint violation for Doctrine though i really can't see why. Schema.yml User: columns: id: type: integer primary: true autoincrement: true username: type: varchar(64) notnull: true email: type: varchar(128) notnull: true password: type: varchar(128) notnull: true relations: Websites: class: Website local: id foreign: owner type: many foreignType: one onDelete: CASCADE Website: columns: id: type: integer primary: true autoincrement: true active: type: bool owner: type: integer notnull: true plz: type: integer notnull: true longitude: type: double(10,6) notnull: true latitude: type: double(10,6) notnull: true relations: Owner: type: one foreignType: many class: User local: owner foreign: id And here's my data Fixtures (data.yml) Model_User: User_1: username: as email: as****.com password: ***** Model_Website: Website_1: active: true plz: 34222 latitude: 13.12 longitude: 3.56 Owner: User_1

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  • What does Apache need to support both mysqli and PDO?

    - by Nathan Long
    I'm considering changing some PHP code to use PDO for database access instead of mysqli (because the PDO syntax makes more sense to me and is database-agnostic). To do that, I'd need both methods to work while I'm making the changeover. My problem is this: so far, either one or the other method will crash Apache. Right now I'm using XAMPP in Windows XP, and PHP Version 5.2.8. Mysqli works fine, and so does this: $dbc = new PDO("mysql:host=$hostname;dbname=$dbname", $username, $password); echo 'Connected to database'; $sql = "SELECT * FROM `employee`"; But this line makes Apache crash: $dbc->query($sql); I don't want to redo my entire Apache or XAMPP installation, but I'd like for PDO to work. So I tried updating libmysql.dll from here, as oddvibes recommended here. That made my simple PDO query work, but then mysqli queries crashed Apache. (I also tried the suggestion after that one, to update php_pdo_mysql.dll and php_pdo.dll, to no effect.) Test Case I created this test script to compare PDO vs mysqli. With the old copy of libmysql.dll, it crashes if $use_pdo is true and doesn't if it's false. With the new copy of libmysql.dll, it's the opposite. if ($use_pdo){ $dbc = new PDO("mysql:host=$hostname;dbname=$dbname", $username, $password); echo 'Connected to database<br />'; $sql = "SELECT * FROM `employee`"; $dbc->query($sql); foreach ($dbc->query($sql) as $row){ echo $row['firstname'] . ' ' . $row['lastname'] . "<br>\n"; } } else { $dbc = @mysqli_connect($hostname, $username, $password, $dbname) OR die('Could not connect to MySQL: ' . mysqli_connect_error()); $sql = "SELECT * FROM `employee`"; $result = @mysqli_query($dbc, $sql) or die(mysqli_error($dbc)); while ($row = mysqli_fetch_array($result,MYSQLI_ASSOC)) { echo $row['firstname'] . ' ' . $row['lastname'] . "<br>\n"; } } What does Apache need in order to support both methods of database query?

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  • layout is not included in all pages in asp.net mvc4 application

    - by Ahmed
    I am developing an asp.net mvc4 application with Bootstrap 3 and i've _Layout.cshtml in "Shared" folder , in Views, i've two pages, "Index and "Register" and i've included Layout in both of these Views but It seems that Layout is included in only "Index and not in "Register" View. Following are my Index and Register Views @{ ViewBag.Title = "Index"; Layout = "~/Views/Shared/_Layout.cshtml"; } <h2 align="center" class="bg-info">Login</h2> <form class="form-horizontal" role="form"> <div class="form-group"> <label for="inputEmail3" class="col-sm-2 control-label"><strong>UserName : </strong></label> <div class="col-sm-10"> <input type="email" class="form-control" id="inputEmail3" placeholder="UserName"> </div> </div> <div class="form-group"> <label for="inputPassword3" class="col-sm-2 control-label"><strong>Password</strong></label> <div class="col-sm-10"> <input type="password" class="form-control" id="inputPassword3" placeholder="Password"> </div> </div> <div class="form-group"> <div class="col-sm-offset-2 col-sm-10"> <div class="checkbox"> <label> <input type="checkbox"> Remember me </label> </div> </div> </div> <div class="form-group"> <div class="col-sm-offset-2 col-sm-10"> <button type="submit" class="btn btn-primary">Sign in</button> </div> </div> <h2 align="center" class="bg-info">SignIn With Other Services</h2> </form> <form class="form-horizontal" role="form" method="post" action="/Home/FacebookLogin"> <div class="form-group"> <div class="col-sm-offset-2 col-sm-10"> <button type="submit" class="btn btn-primary">SignIn with Facebook</button> </div> </div> </form> <h2 align="center" class="bg-info">Don't Have an Account?</h2> <form class="form-horizontal" role="form" method="post" action="/Home/Register"> <div class="form-group"> <div class="col-sm-offset-2 col-sm-10"> <button type="submit" class="btn btn-primary">Register</button> </div> </div> </form> ![@{ ViewBag.Title = "Register"; Layout = "~/Views/Shared/_Layout.cshtml"; } <h2 align="center" class="bg-info">Register</h2> <form class="form-horizontal" role="form"> <div class="form-group"> <label for="inputEmail3" class="col-sm-2 control-label"><strong>UserName : </strong></label> <div class="col-sm-10"> <input type="email" class="form-control" id="uname" name="uname" placeholder="UserName"> <input type="button" class="btn btn-primary" id="check" value="Check Availability" > <h4 class="bg-warning"></h4> </div> </div> <div class="form-group"> <label for="inputPassword3" class="col-sm-2 control-label"><strong>Password</strong></label> <div class="col-sm-10"> <input type="password" class="form-control" id="upass" name="upass" placeholder="Password"> </div> </div> <div class="form-group"> <label for="inputPassword3" class="col-sm-2 control-label"><strong>Retype Password</strong></label> <div class="col-sm-10"> <input type="password" class="form-control" id="retype" placeholder="Password"> </div> </div> <div class="form-group"> <div class="col-sm-offset-2 col-sm-10"> <button type="submit" class="btn btn-primary">Register</button> </div> </div> </form>]

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  • Please clarify a few points concerning Java Servlets

    - by EugeneP
    suppose, I use Tomcat as a web container. Is it true that once all the servlets found in a web-app/WEBAPPNAME are init(IALIZED) then every change of a Servlet's property will be seen to every session. So session 1 changes a property userName of a Servlet1 from "user1" to "user2" session 1 is closed. session 2 starts. It will see "user2" as the only value of Servlet1.userName property?? Any change of a Servlet's field will be seen to all subsequent sessions? Are servlets singletons, aren't they?

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