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  • gauge chart is not displaying any thing

    - by Sandy
    i am trying to display the latest speed in mysql database on guage chart. i have tried so many things but gauge is not display plz any can help me...my code is attached and php part shows the correct value but dont know why guage is not display <?php $host="localhost"; // Host name $username="root"; // Mysql username $password=""; // Mysql password $db_name="mysql"; // Database name $tbl_name="gpsdb"; // Table name // Connect to server and select database. $con=mysql_connect("$host", "$username")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $data = mysql_query("SELECT speed FROM gpsdb WHERE DeviceId=1234 ORDER BY TIME DESC LIMIT 1") or die(mysql_error()); while ($nt = mysql_fetch_assoc($data)) { $speed = $nt['speed']; $jsonTable = json_encode($speed); echo $jsonTable; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="content-type" content="text/html; charset=utf-8"/> <title> Google Visualization API Sample </title> <script type="text/javascript" src="//www.google.com/jsapi"></script> <script type="text/javascript"> google.load('visualization', '1', {packages: ['gauge']}); </script> <script type="text/javascript"> function drawVisualization() { // Create and populate the data table. var data = new google.visualization.DataTable(<?=$speed?>); // Create and draw the visualization. new google.visualization.Gauge(document.getElementById('visualization')). draw(data); } google.setOnLoadCallback(drawVisualization); </script> </head> <body style="font-family: Arial;border: 0 none;"> <div id="visualization" style="width: 600px; height: 300px;"></div> </body> </html>

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  • Echo-ing Only Available Database Result

    - by Robert Hanson
    I have this Associative Array : $Fields = array("row0"=>"Yahoo ID", "row1"=>"MSN ID", "row2"=> "Gtalk ID"); on the other side, I have this SQL query : SELECT YahooID, MSNID, GTalkID From UserTable WHERE Username = '$Username' LIMIT 1; the result maybe vary, because some users only have Yahoo ID and some have others. for example if I have this result : $row[0] = NONE //means YahooID = NONE $row[1] = [email protected] $row[2] = [email protected] then how to have this as an output (echo) : MSN ID = [email protected] Gtalk ID = [email protected] since Yahoo ID is not exist, then the result will be MSN and Gtalk only. 'MSN ID' and 'Gtalk ID' is variable from Associative Array, while '[email protected]' and '[email protected]' from SQL result. thanks!

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  • Passing values between pages in JavaScript

    - by buni
    using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.UI; using System.Web.UI.WebControls; using System.Data.SqlClient; using System.Configuration; using System.Text; using System.Web.Services; using System.IO; namespace T_Smade { public partial class ConferenceManagement : System.Web.UI.Page { volatile int i = 0; protected void Page_Load(object sender, EventArgs e) { GetSessionList(); } public void GetSessionList() { string secondResult = ""; string userName = ""; try { if (HttpContext.Current.User.Identity.IsAuthenticated) { userName = HttpContext.Current.User.Identity.Name; } SqlConnection thisConnection = new SqlConnection(@"data Source=ZOLA-PC;AttachDbFilename=D:\2\5.Devp\my DB\ASPNETDB.MDF;Integrated Security=True"); thisConnection.Open(); SqlCommand secondCommand = thisConnection.CreateCommand(); secondCommand.CommandText = "SELECT myApp_Session.session_id FROM myApp_Session, myApp_Role_in_Session where myApp_Role_in_Session.user_name='" + userName + "' and myApp_Role_in_Session.session_id=myApp_Session.session_id"; SqlDataReader secondReader = secondCommand.ExecuteReader(); while (secondReader.Read()) { secondResult = secondResult + secondReader["session_id"].ToString() + ";"; } secondReader.Close(); SqlCommand thisCommand = thisConnection.CreateCommand(); thisCommand.CommandText = "SELECT * FROM myApp_Session;"; SqlDataReader thisReader = thisCommand.ExecuteReader(); while (thisReader.Read()) { test.Controls.Add(GetLabel(thisReader["session_id"].ToString(), thisReader["session_name"].ToString())); string[] compare = secondResult.Split(';'); foreach (string word in compare) { if (word == thisReader["session_id"].ToString()) { test.Controls.Add(GetButton(thisReader["session_name"].ToString(), "Join Session")); } } } thisReader.Close(); thisConnection.Close(); } catch (SqlException ex) { } } private Button GetButton(string id, string name) { Button b = new Button(); b.Text = name; b.ID = "Button_" + id + i; b.Command += new CommandEventHandler(Button_Click); b.CommandArgument = id; i++; return b; } private Label GetLabel(string id, string name) { Label tb = new Label(); tb.Text = name; tb.ID = id; return tb; } protected void Button_Click(object sender, CommandEventArgs e) { Response.Redirect("EnterSession.aspx?session=" + e.CommandArgument.ToString()); } } I have this code when a user clicks a button www.mypage/EnterSession.aspx?session=session_name in the EnterSession.aspx i have used the code below to track the current URL _gaq.push(['pageTrackerTime._trackEvent', 'Category', 'Action', document.location.href, roundleaveSiteEnd]); Now I would also like to track in the Action parameter the session_name from the previous page.see the code below from the previous page test.Controls.Add(GetButton(thisReader["session_name"].ToString(), "Join Session")); Some idea how to do it? Thanx

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  • Domain-Driven-Design question

    - by Michael
    Hello everyone, I have a question about DDD. I'm building a application to learn DDD and I have a question about layering. I have an application that works like this: UI layer calls = Application Layer - Domain Layer - Database Here is a small example of how the code looks: //****************UI LAYER************************ //Uses Ioc to get the service from the factory. //This factory would be in the MyApp.Infrastructure.dll IImplementationFactory factory = new ImplementationFactory(); //Interface and implementation for Shopping Cart service would be in MyApp.ApplicationLayer.dll IShoppingCartService service = factory.GetImplementationFactory<IShoppingCartService>(); //This is the UI layer, //Calling into Application Layer //to get the shopping cart for a user. //Interface for IShoppingCart would be in MyApp.ApplicationLayer.dll //and implementation for IShoppingCart would be in MyApp.Model. IShoppingCart shoppingCart = service.GetShoppingCartByUserName(userName); //Show shopping cart information. //For example, items bought, price, taxes..etc ... //Pressed Purchase button, so even for when //button is pressed. //Uses Ioc to get the service from the factory again. IImplementationFactory factory = new ImplementationFactory(); IShoppingCartService service = factory.GetImplementationFactory<IShoppingCartService>(); service.Purchase(shoppingCart); //**********************Application Layer********************** public class ShoppingCartService : IShoppingCartService { public IShoppingCart GetShoppingCartByUserName(string userName) { //Uses Ioc to get the service from the factory. //This factory would be in the MyApp.Infrastructure.dll IImplementationFactory factory = new ImplementationFactory(); //Interface for repository would be in MyApp.Infrastructure.dll //but implementation would by in MyApp.Model.dll IShoppingCartRepository repository = factory.GetImplementationFactory<IShoppingCartRepository>(); IShoppingCart shoppingCart = repository.GetShoppingCartByUserName(username); //Do shopping cart logic like calculating taxes and stuff //I would put these in services but not sure? ... return shoppingCart; } public void Purchase(IShoppingCart shoppingCart) { //Do Purchase logic and calling out to repository ... } } I've seem to put most of my business rules in services rather than the models and I'm not sure if this is correct? Also, i'm not completely sure if I have the laying correct? Do I have the right pieces in the correct place? Also should my models leave my domain model? In general I'm I doing this correct according DDD? Thanks!

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  • Can't select database table even though the code is right

    - by Lisa
    I am trying to display a list of my vbulliten threads on a non-vbulliten portion of my site. However I can't select the vbulliten database: <?php $host = "localhost"; $user = "my username"; $pass = "my password"; $dbname = "tableprefix_forum"; mysql_connect($host, $user, $pass) or die ("Could not connect to database server."); mysql_select_db($dbname) or die ("Could not select database."); ?> I am substituting some things here in this example but all my credentials are correct including my db server username, password and forum db name. So what is the problem? Is it due to some internal security feature in vbulliten, does this system not allow you to connect to it's db if the page trying to connect to it is a non-vbulliten page?

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  • $.post is not working

    - by BEBO
    i am trying to post data to Mysql using jquery $.post and php page. my code is not running and nothing is added to the mysql table. I am not sure if the path i am creating is wrong but any help would be appreciated. Jquery location: f_js/tasks/TaskTest.js <script type="text/javascript"> $(document).ready(function(){ $("#AddTask").click(function(){ var acct = $('#acct').val(); var quicktask = $('#quicktask').val(); var user = $('#user').val(); $.post('addTask.php',{acct:acct,quicktask:quicktask,user:user}, function(data){ $('#result').fadeIn('slow').html(data); }); }); }); </script> addTask.php (runs the jqeury code) <?php include 'dbconnect.php'; include 'sessions.php'; $acct = $_POST['acct']; $task = $_POST['quicktask']; $taskstatus = 'Active'; //get task Creator $user = $_POST['user']; //query task creator from users table $allusers = mysql_query("SELECT * FROM users WHERE username = '$user'"); while ($rows = mysql_fetch_array($allusers)) { //get first and last name for task creator $taskOwner = $rows['user_firstname']; $taskOwnerLast = $rows['user_lastname']; $taskOwnerFull = $taskOwner." ".$taskOwnerLast; mysql_query("INSERT INTO tasks (taskresource, tasktitle, taskdetail, taskstatus, taskowner, taskOwnerFullName) VALUES ('$acct', '$task', '$task', '$taskstatus', '$user', '$taskOwnerFull' )"); echo "inserted"; } ?> Accountview.php finally the front page <html> <div class="input-cont "> <input type="text" class="form-control col-lg-12" placeholder="Add a quick Task..." name ="quicktask" id="quicktask"> </div> <div class="form-group"> <div class="pull-right chat-features"> <a href="javascript:;"> <i class="icon-camera"></i> </a> <a href="javascript:;"> <i class="icon-link"></i> </a> <input type="button" class="btn btn-danger" name="AddTask" id="AddTask" value="Add" /> <input type="hidden" name="acct" id="acct" value="<?php echo $_REQUEST['acctname']?>"/> <input type="hidden" name="user" id="user" value="<?php $username = $_SESSION['username']; echo $username?>"/> <div id="result">result</div> </div> </div> <!-- js placed at the end of the document so the pages load faster --> <script src="js/jquery.js"></script> <script src="f_js/tasks/TaskTest.js"></script> <!--common script for all pages--> <script src="js/common-scripts.js"></script> <script type="text/javascript" src="assets/gritter/js/jquery.gritter.js"></script> <script src="js/gritter.js" type="text/javascript"></script> <script> </html> Firebug reponse: Response Headers Connection Keep-Alive Content-Length 0 Content-Type text/html Date Fri, 08 Nov 2013 21:48:50 GMT Keep-Alive timeout=5, max=100 Server Apache/2.4.4 (Win32) OpenSSL/0.9.8y PHP/5.4.16 X-Powered-By PHP/5.4.16 refresh 5; URL=index.php Request Headers Accept */* Accept-Encoding gzip, deflate Accept-Language en-US,en;q=0.5 Content-Length 13 Content-Type application/x-www-form-urlencoded; charset=UTF-8 Cookie PHPSESSID=6gufl3guiiddreg8cdlc0htnc6 Host localhost Referer http://localhost/betahtml/AccountView.php?acctname=client%201 User-Agent Mozilla/5.0 (Windows NT 6.3; WOW64; rv:25.0) Gecko/20100101 Firefox/25.0 X-Requested-With XMLHttpRequest

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  • problem with TEMPORARY TABLE

    - by Z77
    Within PHP I do: 1.) A temporary table is created: CREATE TEMP TABLE new_table AS SELECT .... FROM ...; 2.) AFter that I want to use this table to create a shape file: shell_exec ("pgsql2shp .... -u username -P password ...); Separetly those two things work, but by creating a temporary table and after that using this table in pgsql2shp does not work. I pressume this is because temporary table duration is to the end of session. But to create shp file I need to use username and password what means new session starts and temporary table is dropped before I use it for shape creation. Any tip how to solve it? Thank you!

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  • Admin panel - what is the best way to display "static" data in the layout?

    - by rkj
    I'm about to write a admin panel for my CMS written in CodeIgniter. There will be some user information visible at all time - both in the layout's header section and the sidebar. I'm used to do it in a way that I personally hope and think could be done a lot easier, since I'm tired of sending the same parametres to the view over and over again, when it's dynamic data that needs to be displayed on every page anyways (such as unread messages, username, name, status, etc). I'll need controllers and models, I know that, but do I have to pass, just for an example, the user's username, unread messages etc. every time I need to load a view? Should I do some kind of library for this? Now my question is: How would I do it when it comes to best practice and for making it easy to maintain in the future? I hope my question is understandable :)

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  • Create a complex SQL query?

    - by mazzzzz
    Hey guys, I have a program that allows me to run queries against a large database. I have two tables that are important right now, Deposits and withdraws. Each contains a history of every user. I need to take each table, add up every deposit and withdraws (per user), then subtract the withdraws from the deposits. I then need to return every user whos result is negative (aka they withdrew more then they deposited). Is this possible in one query? Example: Deposit Table: |ID|UserName|Amount| |1 | Use1 |100.00| |2 | Use1 |50.00 | |3 | Use2 |25.00 | |4 | Use1 | 5.00 | WithDraw Table: |ID|UserName|Amount| |2 | Use2 | 5.00 | |1 | Use1 |100.00| |4 | Use1 | 5.00 | |3 | Use2 |25.00 | So then the result would output: |OverWithdrawers| | Use2 | Is this possible (I sure don't know how to do it)? Thanks for any help, Max

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  • Jmeter Query new user

    - by Sri
    First of all apologies for the below question. Am from a Testing background for the past 8 years and very novice to Jmeter. I went through the Jmeter site, and ran a sample recording using the jmeter.apache.org site and it went fine. I want to test my knowledge and understanding. So, I did the following way. Created a thread group. Added a config element HTTP Default Requests with server name as mail.google.com. Added a Sampler as HTTP request, set the METHOD to POST and gave the username and password, and i ran the test. When i see the Results Viewer, i could see the login page of gmail, I need to know how to pass my username and password and simulate the clicking of Submit button and getting the next page. Please help, am very new and will really appreciate if it's explained as simple as possible.

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  • Linq to SQl Stored Procedure Problem( it can't figure out the return type)

    - by chobo2
    Hi I have this SP USE [Test] GO SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO CREATE PROCEDURE [dbo].[UsersInsert](@UpdatedProdData XML) AS INSERT INTO dbo.UserTable(UserId,UserName,LicenseId,Password,PasswordSalt,Email,IsApproved,IsLockedOut,CreateDate, LastLoginDate,LastLockOutDate,FailedPasswordAttempts,RoleId) SELECT @UpdatedProdData.value('(/ArrayOfUsers/Users/UserId)[1]', 'uniqueidentifier'), @UpdatedProdData.value('(/ArrayOfUsers/Users/UserName)[1]', 'varchar(20)'), @UpdatedProdData.value('(/ArrayOfUsers/Users/LicenseId)[1]', 'varchar(50)'), @UpdatedProdData.value('(/ArrayOfUsers/Users/Password)[1]', 'varchar(128)'), @UpdatedProdData.value('(/ArrayOfUsers/Users/PasswordSalt)[1]', 'varchar(128)'), @UpdatedProdData.value('(/ArrayOfUsers/Users/Email)[1]', 'varchar(50)'), @UpdatedProdData.value('(/ArrayOfUsers/Users/IsApproved)[1]', 'bit'), @UpdatedProdData.value('(/ArrayOfUsers/Users/IsLockedOut)[1]', 'bit'), @UpdatedProdData.value('(/ArrayOfUsers/Users/CreateDate)[1]', 'datetime'), @UpdatedProdData.value('(/ArrayOfUsers/Users/LastLoginDate)[1]', 'datetime'), @UpdatedProdData.value('(/ArrayOfUsers/Users/LastLockOutDate)[1]', 'datetime'), @UpdatedProdData.value('(/ArrayOfUsers/Users/FailedPasswordAttempts)[1]', 'int'), @UpdatedProdData.value('(/ArrayOfUsers/Users/RoleId)[1]', 'int') Now this SP creates just fine. It's when I go to VS2010 and try to drag this SP in my method panel of my linq to sql file in design view. It tells me that it can't figure out the return type. I try to go to the properties but it does not have "none" as a choice and I can't type it in. It should be "none" so how do I set it to "none"?

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  • How do search engines see dynamic profiles?

    - by Lumpy
    Recently search engines have been able to page dynamic content on social networking sites. I would like to understand how this is done. Are there static pages created by a site like Facebook that update semi frequently. Does Google attempt to store every possible user name? As I understand it, a page like www.facebook.com/username, is not an actual file stored on disk but is shorthand for a query like: select username from users and display the information on the page. How does Google know about every user, this gets even more complicated when things like tweets are involved.

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  • can't save form content to database, help plsss!!

    - by dana
    i'm trying to save 100 caracters form user in a 'microblog' minimal application. my code seems to not have any mystakes, but doesn't work. the mistake is in views.py, i can't save the foreign key to user table models.py looks like this: class NewManager(models.Manager): def create_post(self, post, username): new = self.model(post=post, created_by=username) new.save() return new class New(models.Model): post = models.CharField(max_length=120) date = models.DateTimeField(auto_now_add=True) created_by = models.ForeignKey(User, blank=True) objects = NewManager() class NewForm(ModelForm): class Meta: model = New fields = ['post'] # widgets = {'post': Textarea(attrs={'cols': 80, 'rows': 20}) def save_new(request): if request.method == 'POST': created_by = User.objects.get(created_by = user) date = request.POST.get('date', '') post = request.POST.get('post', '') new_obj = New(post=post, date=date, created_by=created_by) new_obj.save() return HttpResponseRedirect('/') else: form = NewForm() return render_to_response('news/new_form.html', {'form': form},context_instance=RequestContext(request)) i didn't mention imports here - they're done right, anyway. my mistake is in views.py, when i try to save it says: local variable 'created_by' referenced before assignment it i put created_py as a parameter, the save needs more parameters... it is really weird help please!!

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  • Error in header function

    - by user1178695
    I'm using the php header function for the redirection but it is not working.I'm using the following code. $sql=mysql_query("select * from password where username='$email' and password1 = '$pwd'"); //echo "selct * from password where username='$email' and password = '$pwd'"; $row=mysql_fetch_row($sql); $fieldset=mysql_num_rows($sql); $host=$_SERVER['HTTP_HOST']."/beta/"; if($fieldset>0 && $conEmail !="") { $_SESSION['email']=$email; $_SESSION['Email']=$email; $_SESSION['memberID']=$id; $_SESSION['status']='Admin'; header("location:http://".$host."member.php"); }

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  • How do I require a login for a user in Django?

    - by Di Zou
    In my urls.py I have this: (r'^myapp/$', 'myapp.views.views.index'), (r'^myapp/login/$', 'myapp.views.views.login_user'), In my settings.py I have this: LOGIN_URL = '/myapp/login' In my views.py I have this: @login_required((login_url='/myapp/login/') def index(request): return render_to_response('index.html') def login_user(request): #login stuff return render(request, 'registration/login.html', {'state':state, 'username': username}) I can go to mysite.com/myapp/login and the login page works. However, when I go to mysite.com/myapp/index I do not get redirected to the login page even though I am logged out. Why is that and how do I fix it?

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  • In Java, how do I set a return type if an exception occurs?

    - by beagleguy
    hey all, I'm new to Java and was wondering if I define a method to return a database object like import java.sql.*; public class DbConn { public Connection getConn() { Connection conn; try { Class.forName("com.mysql.jdbc.Driver").newInstance(); if(System.getenv("MY_ENVIRONMENT") == "development") { String hostname = "localhost"; String username = "root"; String password = "root"; } conn = DriverManager.getConnection("jdbc:mysql:///mydb", username, password); return conn; } catch(Exception e) { throw new Exception(e.getMessage()); } } } if the connection fails when I try to create it what should I return? eclipse is telling me I have to return a Connection object but if it fails I'm not sure what to do. thanks!

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  • Support for multiple domains/subdomains in Rails

    - by thefactor
    I have a Rails app that has a similar setup to Tumblr, that is, you can have either: (1) Subdomain hosting (your-username.myapp.com) (2) Domain hosting (your-username.com) Both would forward to a personalized website for that user, created with my application. How can I accomplish this in Rails? I have been able to get (1) working with subdomain-fu, but I'm not sure how to get (2) working. Any pointers (plugins, gems, tutorials), etc. would be greatly helpful, I can't seem to find any. Thanks!

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  • Doctrine: Mixing YAML markup and db manager (navicat) editing?

    - by ropstah
    I think the answer to this question should be: No. However I hope to be corrected. I'd like to edit our database using a mixture of YAML markup + Doctrine createTables() and Navicat editing. Can I maintain the inheritance which is marked up? Example (4 steps, at step 4, Doctrine is in no way able to re-create the inheritance schema... or is it?): Step 1: Create YAML with inheritance --- Entity: columns: username: string(20) password: string(16) created_at: timestamp updated_at: timestamp User: inheritance: extends: Entity type: column_aggregation keyField: type keyValue: 1 Group: inheritance: extends: Entity type: column_aggregation keyField: type keyValue: 2 Step 2: Create tables using Doctrine (and drop/create db if nessecary) Created sql: CREATE TABLE entity (id BIGINT AUTO_INCREMENT, username VARCHAR(20), password VARCHAR(16), created_at DATETIME, updated_at DATETIME, type VARCHAR(255), PRIMARY KEY(id)) ENGINE = INNODB Step 3: Edit table using Navicat Step 4: Refresh YAML file because of 'external' edits...

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  • Shouldn’t GridView’s RowStyle-HorizontalAlign property overwrite CSS’s text-align property?

    - by AspOnMyNet
    a) As far as I know, GridView’s RowStyle-HorizontalAlign property should overwrite CSS’s text-align property, and thus text inside GridView's cells should be located on the left side of the cells, but is instead moved to the right side. Why is that? b) Similarly, RowStyle-Font-Bold should overwrite CSS’s font-weight property and thus fonts shouldn’t be in bold. But again, CSS’s property overwrites RowStyle’s Font-Bold property. Why? <div id="someClass"> <asp:GridView ID="gvwShowUsers" runat="server" > <RowStyle BackColor="#FFFBD6" ForeColor="#333333" Font-Bold="false" HorizontalAlign="Left" /> <Columns> <asp:BoundField DataField="UserName" HeaderText="UserName" /> </Columns> </asp:GridView> </div> CSS file: #someClass td { font-weight:bolder; text-align:right; } thanx

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  • Joining two select queries and ordering results

    - by user1
    Basically I'm just unsure as to why this query is failing to execute: (SELECT replies.reply_post, replies.reply_content, replies.reply_date AS d, members.username FROM (replies) AS a INNER JOIN members ON replies.reply_by = members.id) UNION (SELECT posts.post_id, posts.post_title, posts.post_date AS d, members.username FROM (posts) as b WHERE posts.post_set = 0 INNER JOIN members ON posts.post_by = members.id) ORDER BY d DESC LIMIT 5 I'm getting this error: #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'a INNER JOIN members ON replies.re' at line 2 All I'm trying to do is select the 5 most recent rows (dates) from these two tables. I've tried Join, union etc and I've seen numerous queries where people have put another query after the FROM statement and that just makes no logical sense to me as to how that works? Am I safe to say that you can join the same table from two different but joined queries? Or am I taking completely the wrong approach, because frankly I can't seem see how this query is failing despite reading the error message. (The two queries on there own work fine)

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  • rake db:create not working for legacy rails app (2.3.5) using MySQL (5.5.28)

    - by ridicter
    I'm a new Rails Developer, and I'm working on a legacy Rails app. Whenever I run the rake db:create command, I get an error that the database couldn't be created. I have found many StackOverflow questions related to this, but in troubleshooting nearly all permutations of solutions, I couldn't resolve the issue. I created the three Dbs (dev, prod, test), created the user with all access privileges to these dbs, and ran rake db:create. I'm running Mac OS X Lion, MySQL 5.5.28, Rails 2.3.5, Ruby 1.8.7. Here are my settings development: adapter: mysql encoding: utf8 database: adva_development username: adva password: **** host: localhost socket: /tmp/mysql.sock Here's the error: Couldn't create database for {"adapter"=>"mysql", "username"=>"adva", "host"=>"localhost", "encoding"=>"utf8", "database"=>"adva_development", "socket"=>"/tmp/mysql.sock", "password"=>"****"}, charset: utf8, collation: utf8_unicode_ci (if you set the charset manually, make sure you have a matching collation) I have done the following troubleshooting: Verified user and password are correct, and the user has access to the DB. (Double checked user access with SELECT * FROM mysql.db WHERE Db = 'adva_development' \G; User has all privileges.) Verify the socket is correct. I don't really understand sockets, but I can plainly see it at /tmp/mysql.sock. Checked collation and character set. I found out I had created the DB in latin charset and collation, so I recreated them. I ran show variables like "collation_database"; and show variables like "character_set_database"; and came back with utf8 and utf8_unicode_ci respectively. I followed the instructions in this question. After uninstalling mysql gem, I ran the following but came up with the same error: gem install --no-rdoc --no-ri mysql -- --with-mysql-dir=/usr/local/mysql-5.5.28-osx10.6-x86_64/bin --with-mysql-config=/usr/local/mysql-5.5.28-osx10.6-x86_64/bin/mysql_config Following Matt's suggestion, here's what a rake --trace db:create reveals: ** Invoke db:create (first_time) ** Invoke db:load_config (first_time) ** Invoke rails_env (first_time) ** Execute rails_env ** Execute db:load_config ** Execute db:create Couldn't create database for {"database"=>"adva_development", "adapter"=>"mysql", "host"=>"127.0.0.1", "password"=>"woof2adva", "username"=>"adva", "encoding"=>"utf8"}, charset: utf8, collation: utf8_unicode_ci (if you set the charset manually, make sure you have a matching collation) After 3 days and six or seven hours, I have pretty much run out of options. I tried various random things, like replacing localhost with 127.0.0.1 to no avail. Could there be something wrong related to my specific environment? Mac OS X Lion + MySQL 5.5.28? I plan on trying on setting up everything in a Linux environment. Thanks!

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  • JFileChooser returns incorrect path in OS X (folders only mode)

    - by Virat Kadaru
    I have a problem in java swing where the user has to select a folder, so I am using the code below. JFileChooser fc = new JFileChooser(); fc.setFileSelectionMode(JFileChooser.DIRECTORIES_ONLY); if(fc.showDialog(singleton, SELECT) == JFileChooser.APPROVE_OPTION) { File folder = fc.getSelectedFile(); String path = folder.getPath() + File.separatorChar + MYAPPFOLDER; } Now there are 2 ways a user may select the folder Navigate to the folder and select the folder Navigate to the folder, go into the folder, and click select Both ways work fine on windows but on OS X, I get If I do 1 : path = Users/<username>/Desktop/MYAPPFOLDER If I do 2 : path = Users/<username>/Desktop/Desktop/MYAPPFOLDER How do I avoid this 2nd case? Thanks in advance.

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  • What do browsesr use to auto suggest values in web forms?

    - by nedlud
    If I come back to a web site after having filled in a form previously, the browser remembers my username (for example). I'm not talking about cookies remembering user names and passwords, but the way a browser will suggest a value for a previously submitted field. What controls this behaviour? My issue at the moment is that I have login forms on several small apps all running under the one domain. (eg www.example.com/app1/login/ and www.example.com/app2/login/). If I use my user name for app1, then go over to app2 where I use a different username, it only ever auto suggests my app1 user name. How can I change this behaviour? Do browsers use the fields ID to help remember this stuff? If I change the ID of the fields in the login form, will they auto suggest the correct values in future?

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  • PHP MySQL Insert Data

    - by happyCoding25
    Hello, Im trying to insert data into a table in MySQL. I found/modified some code from w3Schools and still couldn't get it working. Heres what I have so far: <?php $rusername=$_POST['username']; $rname=$_POST['name']; $remail=$_POST['emailadr']; $rpassword=$_POST['pass']; $rconfirmpassword=$_POST['cpass']; if ($rpassword==$rconfirmpassword) { $con = mysql_connect("host","user","password"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("mydbname ", $con); } mysql_query("INSERT INTO members (id, username, password) VALUES ('4', $rusername, $rpassword)"); ?> Did I mistype something? To my understanding "members" is the name of the table. If anyone knows whats wrong I appreciate the help. Thanks

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  • In PHP can I check a boolean on a function call?

    - by Chris
    I have a function which checks the passed value and returns false or true, if false I want it to add something to an array. The code I've written is below. if(!check_input($_POST['username'])){ $errors[] = "Username"; } Right now it adds to my array anyway, regardless of what is entered in the form. Is the way I've written that the correct way to check if the return from check_input() is false? I've checked the function's logic by altering the returns to echoes and it's returning the correct value, I'm just not sure if I'm checking it wrong. I'd previously attempted to write it as $X=check_input etc, and then if(check_value == false) but that doesn't seem to give me the desired result either. Hmmm a quick pointer please!

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