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  • As a programmer, what are some telltale signs that you're about to get fired or laid off?

    - by plaureano
    If you have ever been fired from a job, did you notice anything different about the behavior of your peers or upper management just before your termination? What are some common signs to look for among your coworkers and project manager(s) that would indicate your position is severely at risk? EDIT: My instincts were right, and I opted to resign rather than face termination. I guess when you have that "gut feeling" that something is about to happen, it's a strong sign that you should be heading for the exit...

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  • focus doesn't work in IE

    - by Syom
    i have the following function function change() { var input=document.getElementById('pas'); var input2= input.cloneNode(false); input2.type='password'; input.parentNode.replaceChild(input2,input); input2.focus(); } but focus() doesn't work in ie7, so what can i do! i want to have the cursor inside of input! thanks

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  • how to get all 'username' from my model 'MyUser' on google-app-engine ..

    - by zjm1126
    my model is : class MyUser(db.Model): user = db.UserProperty() password = db.StringProperty(default=UNUSABLE_PASSWORD) email = db.StringProperty() nickname = db.StringProperty(indexed=False) and my method which want to get all username is : s=[] a=MyUser.all().fetch(10000) for i in a: s.append(i.username) and the error is : AttributeError: 'MyUser' object has no attribute 'username' so how can i get all 'username', which is the simplest way . thanks

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  • When is `x IS NOT NULL` not the same as `NOT(x IS NULL)`

    - by Mark Hurd
    For what x is The expression x IS NOT NULL is not equal to NOT(x IS NULL), as is the case in 2VL (quote from this answer, which is quoting Fabian Pascal Practical Issues in Database Management - A Reference for the Thinking Practitioner -- near the end of that answer) My guess is when x IS NULL is NULL, but I cannot guess when that would be (i.e. I haven't checked the SQL standard).

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  • Login system and sessions (php)

    - by Jonathan
    I've created a login page and registration page and now I want to use that to password protect pages and have pages which show information specific to that user. Would storing the user ID of the user logged in in a Session variable be a safe and correct way of doing this? How easy would it be for a user to change the session variable to a different ID and access another user's information, and not having to type the users login details in?

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  • Spring OpenSessionInViewFilter with @Transactional annotation

    - by Gautam
    This is regarding Spring OpenSessionInViewFilter using with @Transactional annotation at service layer. i went through so many stack overflow post on this but still confused about whether i should use OpenSessionInViewFilter or not to avoid LazyInitializationException It would be great help if somebody help me find out answer to below queries. Is it bad practice to use OpenSessionInViewFilter in application having complex schema. using this filter can cause N+1 problem if we are using OpenSessionInViewFilter does it mean @Transactional not required? Below is my Spring config file <context:component-scan base-package="com.test"/> <context:annotation-config/> <bean id="messageSource" class="org.springframework.context.support.ReloadableResourceBundleMessageSource"> <property name="basename" value="resources/messages" /> <property name="defaultEncoding" value="UTF-8" /> </bean> <bean id="propertyConfigurer" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer" p:location="/WEB-INF/jdbc.properties" /> <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close" p:driverClassName="${jdbc.driverClassName}" p:url="${jdbc.databaseurl}" p:username="${jdbc.username}" p:password="${jdbc.password}" /> <bean id="sessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean"> <property name="dataSource" ref="dataSource" /> <property name="configLocation"> <value>classpath:hibernate.cfg.xml</value> </property> <property name="configurationClass"> <value>org.hibernate.cfg.AnnotationConfiguration</value> </property> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">${jdbc.dialect}</prop> <prop key="hibernate.show_sql">true</prop> <!-- <prop key="hibernate.hbm2ddl.auto">create</prop> --> </props> </property> </bean> <tx:annotation-driven /> <bean id="transactionManager" class="org.springframework.orm.hibernate3.HibernateTransactionManager"> <property name="sessionFactory" ref="sessionFactory" /> </bean>

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  • Is it a good practice to always use smart pointers ?

    - by Dony Borris
    Hi, I find smart pointers to be a lot more comfortable than raw pointers. So is it a good idea to always use smart pointers? ( Please note that I am from Java background and hence don't much like the idea of explicit memory management. So unless there are some serious performance issues with smart pointers, I'd like to stick with them. ) Any advice would be greatly appreciated. Thanks.

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  • Javascript using asp.net

    - by jimson
    I have a Login Page Contains two text boxes one is user name,password and one button if the two textboxes are empty that time how i can avoid post back of the buuton if any value enterd that time only postback occuers,,,, not using required fiekd validator any method is avilable in javascript.......

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  • How to build this encryption system that allows multiple users/objects.

    - by Patrick
    Hello! I am trying to figure out how to create an optimal solution for my project. I made this simple picture in Photoshop to try to illustrate the problem and how i want it (if possible). Illustrative image Ill also try to explain it based on the picture. First off we have a couple of objects to the left, these objects all get encrypted with their own encryption key (EKey on the picture) and then stored in the database. On the other side we have different users placed into roles (one user can be in a lot of roles) and the roles are associated with different objects. So one person only has access the to the objects that the role provides. So for instance Role A might have access to Object A and B. Role B have access only to Object C and Role C have access to all objects. Nothing strange in that, right? Different roles have different objects that they can access. Now to the problem part. Each user has to login with his/her username/password and then he/she gets access to the objects that his/her roles provide. All the objects are encrypted so she needs to get a decryption key somehow. I don't want to store the encryption key as a text string on the server. It should be, if possible, decrypted using the users password (along with the role) or similar. That way you have to be a user on the server in order to decrypt an object an to work with it. I was thinking about making a public/private key encryption system, but i am kinda stuck on how to give the different users the decryption key to the objects. Since i need to be able to move users to and from roles, add new users, add new roles and create/delete objects. There will be one administrator that then adds some data to allow the users in that role to get the decryption key to decrypt the object. Nothing is static and i am trying to get a picture of how this can be built or if there is a far better solution. The only criteria are: -Encrypted objects. -Decryption key should not be stored as text. -Different users have access to different objects. -Does NOT have to have roles.

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  • Bypass Credential dialog box of internet explorer

    - by m23
    My c# application opens the Internet explorer for different web URL/ domains. And I have all those credential information (username, password and domain name) stored in the database for each web application. Now how I can authenticate automatically without entering credential in “Network Credential” dialog box using code or bypass that dialog box? In other words I need to store those credential on system so no need to enter. I am using c#

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  • PHP class function.

    - by Jordan Pagaduan
    What is wrong with this code? <?php class users { var $user_id, $f_name, $l_name, $db_host, $db_user, $db_name, $db_table; function user_input() { $this->$db_host = 'localhost'; $this->$db_user = 'root'; $this->$db_name = 'input_oop'; $this->$db_table = 'users'; } function userInput($f_name, $l_name) { $dbc = mysql_connect($this->db_host , $this->db_user, "") or die ("Cannot connect to database : " .mysql_error()); mysql_select_db($this->db_name) or die (mysql_error()); $query = "insert into $this->db_table values (NULL, \"$f_name\", \"$l_name\")"; $result = mysql_query($query); if(!$result) die (mysql_error()); $this->userID = mysql_insert_id(); mysql_close($dbc); $this->first_name = $f_name; $this->last_name = $l_name; } function userUpdate($new_f_name, $new_l_name) { $dbc = mysql_connect($this->db_host, $this->db_user, "") or die (mysql_error()); mysql_select_db($this->db_name) or die (mysql_error()); $query = "UPDATE $this->db_table set = \"$new_f_name\" , \"$new_l_name\" WHERE user_id = \"$this->user_id\""; $result = mysql_query($query); $this->f_name = $new_f_name; $this->l_name = $new_l_name; $this->user_id = $user_id; mysql_close($dbc); } function userDelete() { $dbc = mysql_connect($this->db_host, $this->db_user, "") or die (mysql_error()); mysql_select_db($this->db_name) or die (mysql_error()); $query = "DELETE FROM $this->db_table WHERE $user_id = \"$this->user_id\""; mysql_close($dbc); } } ?> The error is: Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\xampp\htdocs\jordan_pagaduan\class.php on line 21 Cannot connect to database : Access denied for user 'ODBC'@'localhost' (using password: NO) The code cannot define this "$this->db_host" as "localhost".

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  • What is a good free ODBC viewer?

    - by wshato
    At my job I have to work with three different databases. One is a SQL Server 2008, for which I use SQL Server Management Studio, and another is MySQL, for which I use the MySQL tools. The third however is a Cache database that I can only access through a ODBC connection. Currently I use the SLIK software ODBC View tool to access it, but it is severely lacking when compared with the other two tools. Can anyone recommend a good tool for this type of work?

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  • how to manage 3000+ sound files

    - by iced
    This is more of a management issue... Anyway We're currently making quiz-like game which, well includes a LOT of sound files, and it's bogging down xcode. It's so slow that scrolling up and down takes minutes.

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  • Hardest concept to grasp as a beginner

    - by noizetoys
    When you were starting to program, what was the hardest concept for you to grasp? Was it recursion, pointers, linked lists, assignments, memory management? I was wondering what gave you headaches and how you overcame this issue and learned to love the bomb, I mean understand it. EDIT: As a followup, what helped you grok your hard-to-grasp concept?

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  • Accessing SVN from LAN

    - by Michael
    Hi, I am running a subversion service on my localhost, I want users on the LAN to be able to access this repository without being prompted for username and password. Is there any way to do this.

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  • What to Learn after C++?

    - by Stephen Whitmore
    I have been learning C++ for a while now, I find it very powerful. But, the problem is the the level of abstraction is not much and I have to do memory management myself. What are the languages that I can use which uses a higher level of abstraction.

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  • Generating SQL for website

    - by Ethan
    I am working on a webapplication How can i create SQL for the following Database Information User information Username - String Password - String Admin or Client - boolean Last login – Date/Time LogItem typeLogItem – String (Page name?) hitCount – int View PageURL UserID Transaction User – String DateTimeStamp SKU – int Purchase-boolean TransactionID-int Inventory information Sku number - int Item description - String Price to customer - double Count - in

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  • problem with get http request from IPhone

    - by user317192
    Hi, I am writing a sample PHP Web Service that is sending GET Http request from the iphone to the web server. The server side code is returning JSON Data to iphone, the server side code looks like: function getUsers(){ $con=mysql_connect("localhost","root","123456") or die(mysql_error()); if(!mysql_select_db("eventsfast",$con)) { echo "Unable to connect to DB"; exit; } $sql="SELECT * from users"; $result=mysql_query($sql); if(!$result) { die('Could not successfully run query Error:'.mysql_error()); } $data = array(); while($row = mysql_fetch_assoc($result)){ $data['username'][] = $row['username']; $data['password'][]= $row['password']; } mysql_close($con); //print_r(json_encode($data)); //return (json_encode($data)); return json_encode('success'); } getUsers(); ? Its a simple code that Fetches all the data from the user table and send it to the iphone application. *****************************************************IPHONE APPLICATION (void)viewDidLoad { [super viewDidLoad]; responseData = [[NSMutableData data] retain]; NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:@"http://localhost:8888/GetData.php"]]; [[NSURLConnection alloc] initWithRequest:request delegate:self]; } (void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response { [responseData setLength:0]; } (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data { [responseData appendData:data]; } (void)connection:(NSURLConnection *)connection didFailWithError:(NSError *)error { label.text = [NSString stringWithFormat:@"Connection failed: %@", [error description]]; } (void)connectionDidFinishLoading:(NSURLConnection *)connection { [connection release]; NSString *responseString = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding]; [responseData release]; NSError *error; SBJSON *json = [[SBJSON new] autorelease]; NSArray *luckyNumbers = [json objectWithString:responseString error:&error]; [responseString release]; if (luckyNumbers == nil) label.text = [NSString stringWithFormat:@"JSON parsing failed: %@", [error localizedDescription]]; else { NSMutableString *text = [NSMutableString stringWithString:@"Lucky numbers:\n"]; for (int i = 0; i < [luckyNumbers count]; i++) [text appendFormat:@"%@\n", [luckyNumbers objectAtIndex:i]]; NSLog(text); label.text = text; } } ********************PROBLEM**************** The problem is that nothing is coming on iphone side of the application........... the response doesn't contains anything.............. Please help..............

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