Parameters not being passed into template when using the .Net transform classes

Posted by Chris F on Stack Overflow See other posts from Stack Overflow or by Chris F
Published on 2010-03-08T16:00:18Z Indexed on 2010/03/08 16:06 UTC
Read the original article Hit count: 265

Filed under:

I am using the .Net XslCompiledTranform to run some simple XSLT (see below for a simplified example).

The example XSLT is meant to do simply show the value of the parameter that is passed in to the template. The output is what I expect it to be (i.e.

<result xmlns:p1="http://www.doesnotexist.com">
  <valueOfParamA>valueA</valueOfParamA>
</result>

when I use Saxon 9.0, but when I use XslCompiledTransform (XslTransform) in .net I get

<result xmlns:p1="http://www.doesnotexist.com">
  <valueOfParamA></valueOfParamA>
</result>

The problem is that that the parameter value of paramA is not being passed into the template when I use the .Net classes. I completely stumped as to why. when I step through in Visual Studio, the debugger says that the template will be called with paramA='valueA' but when execution switches to the template the value of paramA is blank.

Can anyone explain why this is happening? Is this a bug in the MS implementation or (more likely) am I doing something that is forbidden in XSLT?

Any help greatly appreciated.

This is the XSLT that I am using

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:extfn="http://exslt.org/common"  exclude-result-prefixes="extfn" xmlns:p1="http://www.doesnotexist.com">
<!-- 
    Replace msxml with
    xmlns:extfn="http://exslt.org/common" 
    xmlns:extfn="urn:schemas-microsoft-com:xslt" 
 -->
<xsl:output method="xml" indent="yes"/>
<xsl:template match="/">
    <xsl:variable name="resultTreeFragment">
        <p1:foo>
        </p1:foo>
    </xsl:variable>
    <xsl:variable name="nodeset" select="extfn:node-set($resultTreeFragment)"/>
    <result>
        <xsl:apply-templates select="$nodeset" mode="AParticularMode">
            <xsl:with-param name="paramA" select="'valueA'"/>
        </xsl:apply-templates>
    </result>
</xsl:template>

<xsl:template match="@* | node()" mode="AParticularMode">
    <xsl:param name="paramA"/>

    <valueOfParamA>
        <xsl:value-of select="$paramA"/>
    </valueOfParamA>
</xsl:template>
</xsl:stylesheet>

© Stack Overflow or respective owner

Related posts about xslt