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Published on 2010-03-17T00:33:47Z
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2010/03/17
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I want to define the block as a string, then create the lambda. The following example does not work. Is something like this possible?
code_string = "|x|x*2"
l = lambda {eval(code_string)}
l.call(3) => 6
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Ok I followed the steps for setting up ruby and rails on my Vista machine and I am having a problem connecting to the database.
Contents of database.yml
development:
adapter: sqlserver
database: APPS_SETUP
Host: WindowsVT06\SQLEXPRESS
Username: se
Password: paswd
Run rake db:migrate…
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My application requires to keep large data objects in session. There are like 3-4 data objects each created by parsing a csv containing 150 X 20 cells having strings of 3-4 characters.
My application shows this error- "marshal data too short".
I tried this-
Deleting the old session table.
Deleting…
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I don't know is it my mistake or no. So i have that code:
<code>
post '/singin/get_token' do
content_type :xml
puts request.body.read
puts xmlRequest
xmlRequest = REXML::Document.new(request.body.read)
...
</code>
And when i post something like that:
<code>
<?xml…
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reading around the various ruby install tutorials it's required to change path from /usr/bin/ruby to /usr/local/bin/ruby but i cant seem to be able to do it. Ultimately i want to install Ruby 1.9.2, should i uninstall 1.8.7 or what? i tried to install Ruby 1.9.2 with macports, the installation seemed…
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i am getting a strange bundler error when running
bundle pack
with bundler 0.9.12
any ideas? (see pastie for a better formatted code: http://pastie.org/881328 )
/opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/site_ruby/1.8/rubygems/package/tar_input.rb:49:in `initialize': not in gzip format (Zlib::GzipFile::Error)
…
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Hello,
I'm writing an Expression Parser to make my API more refactor friendly and less error prone.
basicaly, I want the user to write code like that:
repository.Get(entity => entity.Id == 10);
instead of:
repository.Get<Entity>("Id", 10);
Extracting the member name from the left side…
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Hello, is there any way how to return lambda from another lambda recursively?
All I want to do is finite state machine, implemented as lambda, which returns lambda implementing another state (or null).
nesting Func< won't work as I want.
C#, .NET 3.5
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Hi All,
I have following query on lambda calculus which am not able to understand:
Here is the lambda calculus representation for the AND operator:
lambda(m).lambda(n).lambda (a).lambda (b). m(n a b) b
Can anyone help me in understanding this representation?
Regards,
darkie
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I'm trying to implement method Find that searches the database.
I want it to be like that:
var user = User.Find(a => a.LastName == "Brown");
Like it's done in List class. But when I go to List's source code (thanks, Reflector), I see this:
public T Find(Predicate<T> match)
{
if (match…
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Hi All,
I have following query on lambda calculus which am not able to understand:
Here is the lambda calculus representation for the AND operator:
lambda(m).lambda(n).lambda (a).lambda (b). m(n a b) b
Can anyone help me in understanding this representation?
Regards,
darkie
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