Point-free in Haskell

Posted by wwrob on Stack Overflow See other posts from Stack Overflow or by wwrob
Published on 2010-03-17T17:25:48Z Indexed on 2010/03/17 19:01 UTC
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pointfree

I have this code that I want to make point-free;

(\k t -> chr $ a + flip mod 26 (ord k + ord t -2*a))

How do I do that?

Also are there some general rules for point free style other than "think about this amd come up with something"?

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Developer IT

Point-free in Haskell - Developer IT

Point-free in Haskell

haskell

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Point-free in Haskell

Using items in a list as arguments

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