XSLT: For each node transform, if A =2 and A=1 were both found do this else do that

Posted by Larry on Stack Overflow See other posts from Stack Overflow or by Larry
Published on 2010-03-19T15:04:13Z Indexed on 2010/03/19 15:51 UTC
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xslt

Example 1:

<time>
   <timestamp>01:00</timestamp>
   <event>arrived<event>
</time>
<time>
   <timestamp>02:00</timestamp>
   <event>left<event>
</time>

Example 2:

<time>
   <timestamp>02:00</timestamp>
   <event>left<event>
</time>

The XSLT needs to do:

FOR EACH node DO:
IF event=arrived THEN set eventtype=atdestination
IF event=left is found AND event=arrived is found THEN set new node type=leftdestination ELSE set type=left

XSLT applied to example 1:

<event>
   <time>01:00</time>
   <type>atdestination</type>
<event>
<event>
   <time>02:00</time>
   <type>leftdestination</type>
<event>

XSLT applied to example 2:

<event>
   <time>02:00</time>
   <type>left</type>
<event>

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Developer IT

XSLT: For each node transform, if A =2 and A=1 were both found do this else do that - Developer IT

XSLT: For each node transform, if A =2 and A=1 were both found do this else do that

xslt

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JQuery > XSLT Plugin > Component returned failure code: 0x80600011 [nsIXSLTProcessorObsolete.transfo

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