Loop with pointer arithmetic refuse to stay within boundary in C. Gives me segfault.

Posted by Fred on Stack Overflow See other posts from Stack Overflow or by Fred
Published on 2010-03-24T06:22:32Z Indexed on 2010/03/24 6:33 UTC
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pointers

Hi have made this function which is made to replicate an error that I can't get past. It looks like this:

void enumerate(double *c, int size){
    while(c < &c[size]){
            printf("%lf\n", *c);
            c++;
    }

}

I have added some printf's in there and it gives me:

Adressof c: 0x100100080, Adressof c + size: 0x1001000a8

I then also print the address of c for each iteration of the loop, it reaches 0x1001000a8 but continues past this point even though the condition should be false as far as I can tell until I get a segfault. If anyone can spot the problem, please tell me, I have been staring at this for a while now.

Thanks.

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Loop with pointer arithmetic refuse to stay within boundary in C. Gives me segfault. - Developer IT

Loop with pointer arithmetic refuse to stay within boundary in C. Gives me segfault.

c

pointers

Related posts about c

Related posts about pointers

C++ smart pointers: sharing pointers vs. sharing data

handling refrence to pointers/double pointers using SWIG [C++ to Java]

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