What to pass parameters to start an workflow through WCF
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            by Rubens Farias
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        Published on 2010-03-26T03:36:54Z
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            2010/03/26
            3:43 UTC
        
        
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It's possible to define some start values to an workflow using WorkflowInstance.CreateWorkflow, like this:
using(WorkflowRuntime runtime = new WorkflowRuntime())
{
    Dictionary<string, object> parameters = new Dictionary<string, object>();
    parameters.Add("First", "something");
    parameters.Add("Second", 42);
    WorkflowInstance instance = 
        runtime.CreateWorkflow(typeof(MyStateMachineWorkflow), parameters);
    instance.Start();
    waitHandle.WaitOne();
}
This way, a MyStateMachineWorkflow instance is created and First and Second public properties gets that dictionary values.
But I'm using WCF; so far, I managed to create a Start method which accepts that two arguments and I set that required fields by using bind on my ReceiveActivity:
using (WorkflowServiceHost host = 
    new WorkflowServiceHost(typeof(MyStateMachineWorkflow)))
{
    host.Open();
    ChannelFactory<IMyStateMachineWorkflow> factory = 
        new ChannelFactory<IMyStateMachineWorkflow>("MyStateMachineWorkflow");
    IMyStateMachineWorkflow proxy = factory.CreateChannel();
    // set this values through binding on my ReceiveActivity
    proxy.Start("something", 42);
}
While this works, that create an anomaly: that method should be called only and exactly once.
How can I start an workflow instance through WCF passing those arguments? On my tests, I just actually interact with my workflow through wire after I call that proxy method. Is there other way?
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