Is there any sense in performing binary AND with a number where all bits are set to 1

Posted by n535 on Stack Overflow See other posts from Stack Overflow or by n535
Published on 2010-03-27T12:38:03Z Indexed on 2010/03/27 12:53 UTC
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Greetings everybody. I have seen examples of such operations for so many times that I begin to think that I am getting something wrong with binary arithmetic. Is there any sense to perform the following:

byte value = someAnotherByteValue & 0xFF;

I don't really understand this, because it does not change anything anyway. Thanks for help.

P.S. I was trying to search for information both elsewhere and here, but unsuccessfully.

EDIT: Well, off course i assume that someAnotherByteValue is 8 bits long, the problem is that i don't get why so many people ( i mean professionals ) use such things in their code. For example in Jon Skeet's MiscUtil there is:

uint s1 = (uint)(initial & 0xffff);

where initial is int.

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