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Published on 2010-03-31T00:47:39Z
Indexed on
2010/03/31
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#include <stdio.h>
main()
{
int c ;
while ((c = getchar()) != EOF)
{
int isEOF = (c==EOF);
printf("is %c EOF: %d ", c, isEOF);
}
}
Why printf() method is called twice on every input char here?
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Sorry if I am not supposed to post beginner level questions here..I am new to this site
Please read the code below first
I am confused about getchar() 's role in the following code.. I mean I know its helping me see the output window which will only be closed when I press enter key
So getchar()…
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#include <stdio.h>
main()
{
int c ;
while ((c = getchar()) != EOF)
{
int isEOF = (c==EOF);
printf("is %c EOF: %d ", c, isEOF);
}
}
Why printf() method is called twice on every input char here?
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I have these two functions
void set_dram_channel_width(int channel_width){
printf("one\n");
getchar();
}
void set_dram_transaction_granularity(int cacheline_size){
printf("two\n");
getchar();
}
//output:
one
f //my keyboard input
two
…
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I am have a difficulty understanding getchar(). In the following program getchar works as expected:
#include <stdio.h>
int main()
{
printf("Type Enter to continue...");
getchar();
return 0;
}
However, in the following program, getchar does not create a delay and the program…
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Hi all,
i have some code that run repetedly :
printf("do you want to continue? Y/N: \n");
keepplaying = getchar();
in the next my code is running it doesnt wait for input.
i found out that getchar in the seconed time use '\n' as the charcter.
im gussing this is due to some buffer the sdio…
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