Why does one of these statements compile in Scala but not the other?

Posted by Jeff on Stack Overflow See other posts from Stack Overflow or by Jeff
Published on 2010-04-01T20:44:32Z Indexed on 2010/04/01 21:13 UTC
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(Note: I'm using Scala 2.7.7 here, not 2.8).

I'm doing something pretty simple -- creating a map based on the values in a simple, 2-column CSV file -- and I've completed it easily enough, but I'm perplexed at why my first attempt didn't compile. Here's the code:

// Returns Iterator[String]
private def getLines = Source.fromFile(csvFilePath).getLines

// This doesn't compile:
def mapping: Map[String,String] = {
    Map(getLines map { line: String =>
          val pairArr = line.split(",")
          pairArr(0) -> pairArr(1).trim()
        }.toList:_*)
  }

// This DOES compile
def mapping: Map[String,String] = {
    def strPair(line: String): (String,String) = {
      val pairArr = line.split(",")
      pairArr(0) -> pairArr(1).trim()
    }
    Map(getLines.map( strPair(_) ).toList:_*)
  }

The compiler error is

CsvReader.scala:16: error: value toList is not a member of (St ring) => (java.lang.String, java.lang.String) [scalac] possible cause: maybe a semicolon is missing before `value toList'? [scalac]
}.toList:_*) [scalac] ^
[scalac] one error found

So what gives? They seem like they should be equivalent to me, apart from the explicit function definition (vs. anonymous in the nonworking example) and () vs. {}. If I replace the curly braces with parentheses in the nonworking example, the error is "';' expected, but 'val' found." But if I remove the local variable definition and split the string twice AND use parens instead of curly braces, it compiles. Can someone explain this difference to me, preferably with a link to Scala docs explaining the difference between parens and curly braces when used to surround method arguments?

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