Why protected superclass member cannot be accessed in a subclass function when passed as an argument
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Published on 2010-04-01T03:18:22Z
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2010/04/01
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I get a compile error, which I'm slightly confused about. This is on VS2003.
error C2248: 'A::y' : cannot access protected member declared in class 'A'
class A
{
public:
A() : x(0), y(0) {}
protected:
int x;
int y;
};
class B : public A
{
public:
B() : A(), z(0) {}
B(const A& item) : A(), z(1) { x = item.y;}
private:
int z;
};
The problem is with x = item.y;
The access is specified as protected. Why doesn't the constructor of class B have access to A::y?
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