Pointer Arithmetic & Signed / Unsigned Conversions!

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Published on 2010-04-05T12:54:19Z Indexed on 2010/04/05 13:03 UTC
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pointer-arithmetic

Incase of pointer arithmetic, are the integers automatically converted to their signed variants? If yes, why?

Suppose I do

pointer + uiVal

where pointer is a pointer to int and uiVal is initialized to -1, then I find that the address in pointers get decremented by 4. Why is the unsigned value of -1 not considered here?

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Pointer Arithmetic & Signed / Unsigned Conversions! - Developer IT

Pointer Arithmetic & Signed / Unsigned Conversions!

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