Why are function parameters of type size_t?

Posted by Grissiom on Stack Overflow See other posts from Stack Overflow or by Grissiom
Published on 2010-04-08T13:01:19Z Indexed on 2010/04/08 13:03 UTC
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size-t

The prototype of memset is void *memset(void *s, int c, size_t n);. So why the third parameter is of type size_t ? memset is just an example, I want more general reasons. Thanks in advance.

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Why are function parameters of type size_t? - Developer IT

Why are function parameters of type size_t?

c

size-t

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