doubt in sizeof implementation
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by aks
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Published on 2010-04-09T14:43:47Z
Indexed on
2010/04/09
14:53 UTC
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Filed under:
c
Below is the program to find the size of a structure without using sizeof operator:
struct MyStruct
{
int i;
int j;
};
int main()
{
struct MyStruct *p=0;
int size = ((char*)(p+1))-((char*)p);
printf("\nSIZE : [%d]\nSIZE : [%d]\n", size);
return 0;
}
My doubt is:
Why is typecasting to char * required?
If I don't use the char* pointer, the output is 1 - WHY?
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