I'm trying to read in a multi line string then split it then print it .. here is the string :

1T1b5T!1T2b1T1b2T!1T1b1T2b2T!1T3b1T1b1T!3T3b1T!1T3b1T1b1T!5T1*1T

11X21b1X
4X1b1X

When I split the string with ! I get this without the last line string :

1T1b5T
1T1b5T1T2b1T1b2T
1T2b1T1b2T1T1b1T2b2T
1T1b1T2b2T1T3b1T1b1T
1T3b1T1b1T3T3b1T
3T3b1T1T3b1T1b1T
1T3b1T1b1T5T1*1T
5T1*1T11X21b1X
11X21b1X

Here is my code :

import java.io.BufferedInputStream;
import java.util.Scanner;

public class Main {

    public static void main(String args[]) {
        Scanner stdin = new Scanner(new BufferedInputStream(System.in));
        while (stdin.hasNext()) {
            for (String line : stdin.next().split("!")) {
                System.out.println(line);

                for (int i = 0; i < line.length(); i++) {
                    System.out.print(line.charAt(i));
                }
            }
        }
    }

}

Where did I make the mistake, why is not reading in the last line? After I read in all lines properly I should go trough each line if I encounter number I should print the next char the n times the number I just read, but that is long way ahead first I need help with this. Thank you

UPDATE :

Here is how the output should look like :

1T1b5T
1T2b1T1b2T
1T1b1T2b2T
1T3b1T1b1T
3T3b1T
1T3b1T1b1T
5T1*1T

11X21b1X
4X1b1X

Here is a solution in C(my friend solved it not me), but I'd stil wanted to do it in JAVA :

#include <stdio.h>

int main (void)
{
    char row[134];
    for (;fgets (row,134,stdin)!=NULL;)
    {
        int i,j=0;
        for (i=0;row[i]!='\0';i++)
        {
            if (row[i]<='9'&&row[i]>='1')
                j+=(row[i]-'0');
            else if ((row[i]<='Z'&&row[i]>='A')||row[i]=='*')
                for (;j;j--)
                    printf ("%c",row[i]);
            else if (row[i]=='b')
                for (;j;j--)
                    printf (" ");
            else if (row[i]=='!'||row[i]=='\n')
                printf ("\n");
        }
    }
    return 0;
}