Munging non-printable characters to dots using string.translate()

Posted by Jim Dennis on Stack Overflow See other posts from Stack Overflow or by Jim Dennis
Published on 2009-11-25T23:59:30Z Indexed on 2010/04/19 18:13 UTC
Read the original article Hit count: 336

Filed under:
|
|
|

So I've done this before and it's a surprising ugly bit of code for such a seemingly simple task.

The goal is to translate any non-printable character into a . (dot). For my purposes "printable" does exclude the last few characters from string.printable (new-lines, tabs, and so on). This is for printing things like the old MS-DOS debug "hex dump" format ... or anything similar to that (where additional whitespace will mangle the intended dump layout).

I know I can use string.translate() and, to use that, I need a translation table. So I use string.maketrans() for that. Here's the best I could come up with:

filter = string.maketrans(
   string.translate(string.maketrans('',''),
   string.maketrans('',''),string.printable[:-5]),
   '.'*len(string.translate(string.maketrans('',''),
   string.maketrans('',''),string.printable[:-5])))

... which is an unreadable mess (though it does work).

From there you can call use something like:

for each_line in sometext:
    print string.translate(each_line, filter)

... and be happy. (So long as you don't look under the hood).

Now it is more readable if I break that horrid expression into separate statements:

ascii = string.maketrans('','')   # The whole ASCII character set
nonprintable = string.translate(ascii, ascii, string.printable[:-5])  # Optional delchars argument
filter = string.maketrans(nonprintable, '.' * len(nonprintable))

And it's tempting to do that just for legibility.

However, I keep thinking there has to be a more elegant way to express this!

© Stack Overflow or respective owner

Related posts about code-golf

  • Code Golf: Collatz Conjecture

    as seen on Stack Overflow - Search for 'Stack Overflow'
    Inspired by http://xkcd.com/710/ here is a code golf for it. The Challenge Given a positive integer greater than 0, print out the hailstone sequence for that number. The Hailstone Sequence See Wikipedia for more detail.. If the number is even, divide it by two. If the number is odd, triple… >>> More

  • Code Golf - p day

    as seen on Stack Overflow - Search for 'Stack Overflow'
    The Challenge The shortest code by character count to display a representation of a circle of radius R using the *character, followed by an approximation of p. Input is a single number, R. Since most computers seem to have almost 2:1 ratio you should only output lines where y is odd. The approximation… >>> More

  • Code Golf - PI day

    as seen on Stack Overflow - Search for 'Stack Overflow'
    The Challenge The shortest code by character count to display a representation of a circle of radius R using the *character. Followed by an approximation of pi Input is a single number, R Since most computers seem to have almost 2:1 ratio you should only output lines where y is odd. The approximation… >>> More

  • Code Golf: Triforce

    as seen on Stack Overflow - Search for 'Stack Overflow'
    This is inspired by/taken from this thread: http://www.allegro.cc/forums/thread/603383 The Problem Assume the user gives you a numeric input ranging from 1 to 7. Input should be taken from the console, arguments are less desirable. When the input is 1, print the following: *********** *********… >>> More

  • Code Golf: Tic Tac Toe

    as seen on Stack Overflow - Search for 'Stack Overflow'
    Post your shortest code, by character count, to check if a player has won, and if so, which. Assume you have an integer array in a variable b (board), which holds the Tic Tac Toe board, and the moves of the players where: 0 = nothing set 1 = player 1 (X) 2 = player 2 (O) So, given the array b… >>> More

Related posts about obscure