DecimalFormat and Double.valueOf()
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        Published on 2010-04-22T13:09:30Z
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            13:13 UTC
        
        
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Hello. I'm trying to get rid of unnecessary symbols after decimal seperator of my double value. I'm doing it this way:
DecimalFormat format = new DecimalFormat("#.#####");
value = Double.valueOf(format.format(41251.50000000012343));
But when I run this code, it throws:
java.lang.NumberFormatException: For input string: "41251,5"
    at sun.misc.FloatingDecimal.readJavaFormatString(FloatingDecimal.java:1224)
    at java.lang.Double.valueOf(Double.java:447)
    at ...
As I see, Double.valueOf() works great with strings like "11.1", but it chokes on strings like "11,1". How do I work around this? Is there a more elegant way then something like
Double.valueOf(format.format(41251.50000000012343).replaceAll(",", "."));
Is there a way to override the default decimal separator value of DecimalFormat class?
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