DWORD to bytes using bitwise shift operators
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by Dave18
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Published on 2010-04-22T17:52:16Z
Indexed on
2010/04/22
17:53 UTC
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Hit count: 131
Filed under:
c++
I can't get it to work correctly.
#include <windows.h>
int main()
{
DWORD i = 6521;
BYTE first = i >> 32;
BYTE second = i >> 24;
BYTE third = i >> 16;
BYTE fourth = i >> 8;
i = (((DWORD)fourth) << 24) | (((DWORD)third) << 16) | (((DWORD)second) << 8) | first;
}
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