sendto: Invalid Argument

Posted by Sylvain on Stack Overflow See other posts from Stack Overflow or by Sylvain
Published on 2010-04-23T08:07:58Z Indexed on 2010/04/23 8:13 UTC
Read the original article Hit count: 441

Filed under:
|

Hi,

I have a list<struct sockaddr_in> _peers I'd like to use for sendto()

the list is filled this way

  struct hostent *hp;
  hp = gethostbyname(hostname);

  sockaddr_in sin;
  bzero(&sin, sizeof(sin));
  sin.sin_family = AF_INET;
  sin.sin_port = htons(port);
  sin.sin_addr.s_addr = *(in_addr_t *)hp->h_addr;

  _peers.push_front(sin);

and here's how I try to send:

  for (list<struct sockaddr_in>::iterator it = _peers.begin(); it != _peers.end(); ++it) { 
    if (sendto(_s, "PING", 5, 0, (struct sockaddr *)&(*it), sizeof(struct sockaddr_in)) < 0) 
      perror("sendto"); 
  }

outputs:

sendto: Invalid argument

If I create the struct sockaddr_in right before sendto(), everything works fine, so I guess I fail at using the list properly ... I also tested using &_peers.front() directly and still get the same error ...

what am I doing wrong?

Thanks in advance,

© Stack Overflow or respective owner

Related posts about c++

Related posts about socket-programming