SQL query for the latest record for each day

Posted by Mac on Stack Overflow See other posts from Stack Overflow or by Mac
Published on 2010-04-29T02:56:40Z Indexed on 2010/04/29 3:07 UTC
Read the original article Hit count: 151

Filed under:
|
|

I've got an Oracle 10g database with a table with a structure and content very similar to the following:

CREATE TABLE MyTable
(
    id         INTEGER PRIMARY KEY,
    otherData  VARCHAR2(100),
    submitted  DATE
);

INSERT INTO MyTable VALUES (1, 'a', TO_DATE('28/04/2010 05:13', ''DD/MM/YYYY HH24:MI));
INSERT INTO MyTable VALUES (2, 'b', TO_DATE('28/04/2010 03:48', ''DD/MM/YYYY HH24:MI));
INSERT INTO MyTable VALUES (3, 'c', TO_DATE('29/04/2010 05:13', ''DD/MM/YYYY HH24:MI));
INSERT INTO MyTable VALUES (4, 'd', TO_DATE('29/04/2010 17:16', ''DD/MM/YYYY HH24:MI));
INSERT INTO MyTable VALUES (5, 'e', TO_DATE('29/04/2010 08:49', ''DD/MM/YYYY HH24:MI));

What I need to do is query the database for the latest record submitted on each given day. For example, with the above data I would expect the records with ID numbers 1 and 4 to be returned, as these are the latest each for 28 April and 29 April respectively.

Unfortunately, I have little expertise as far as SQL is concerned. Could anybody possibly provide some insight as to how to achieve this?

Thanks in advance!

© Stack Overflow or respective owner

Related posts about sql

Related posts about oracle10g