Hey all,

If I have the following code:

main(int argc, char *argv[]){
 char serveradd[20];
 strcpy(serveradd, argv[1]);
 int port = atoi(argv[2]);
 printf("%s %d \n", serveradd, port);

The first two arguments to the command line are printed. However, if I do this:

 char serveradd[20];
 strcpy(serveradd, argv[1]);
 int port = atoi(argv[2]);
 char versionnum[1]; 
 strcpy(versionnum, argv[3]);
 printf("%s %d %s \n", serveradd, port, versionnum);`

The first argument (serveradd) does not print out to the screen and is not being stored... Why is this happening and how can I fix it? Thanks!