How can i convert from wostream to ostream

Posted by Avishay on Stack Overflow See other posts from Stack Overflow or by Avishay
Published on 2010-05-13T15:10:53Z Indexed on 2010/05/13 15:14 UTC
Read the original article Hit count: 130

Filed under:

c++

|

ostream

|

unicode

i am using a function that receives ostream but i have wostream is there a way to convert one to the other?

in particular i want to use boost::write_graphviz which takes ostream but i currently in << operator for wostream.

© Stack Overflow or respective owner

Related posts about c++

Which C++ book shold I get between "C++ Primer" vs "C++ Primer Plus"

as seen on Stack Overflow - Search for 'Stack Overflow'
I want to learn C++ by using Vim and MinGW as compiler. I'm interesting at "C++ Primer (4th Edition)" and "C++ Primer Plus (5th Edition)" but I don't know how about it different. It has no book store that I can review those books, so I want to know, what is the different between those book and which… >>> More
C++ : C++ Primer (Stanley Lipmann) or The C++ programming language (special edition)

as seen on Stack Overflow - Search for 'Stack Overflow'
I have a Computer Science degree (long2 time ago) .. I do know Java OOP but i am now trying to pick up C++. I do have C and of course data structure using C or pascal. I have started reading Bjarne Stroustrup book (The C++ Programming Language - Special Edition) but find it extremely difficult esp… >>> More
I need help on my C++ assignment using MS Visual C++

as seen on Stack Overflow - Search for 'Stack Overflow'
Ok, so I don't want you to do my homework for me, but I'm a little lost with this final assignment and need all the help I can get. Learning about programming is tough enough, but doing it online is next to impossible for me... Now, to get to the program, I am going to paste what I have so far. This… >>> More
Managed c++ std::string not accessible in unmanaged c++

as seen on Stack Overflow - Search for 'Stack Overflow'
In unmanaged c++ dll i have a function which takes constant std::string as argument Prototype : void read ( const std::string &imageSpec_ ) I call this function from managed c++ dll by passing a std::string. When i debug the unmanaged c++ code the parameter imageSpec_ shows the value correctly… >>> More
The Definitive C++ Book Guide and List

as seen on Stack Overflow - Search for 'Stack Overflow'
After more than a few questions about deciding on C++ books I thought we could make a better community wiki version. Providing QUALITY books and an approximate skill level. Maybe we can add a short blurb/description about each book that you have personally read / benefited from. Feel free to debate… >>> More

Related posts about ostream

Setting minimum number of decimal places for std::ostream precision

as seen on Stack Overflow - Search for 'Stack Overflow'
Hi, Is there a way to set the "minimum" number of decimal places that a std::ostream will output? For example, say I have two doubles that I want to print: double a = 0; double b = 0.123456789; I can set my maximum decimal precision so that I output b exactly std::cout << std::setprecision(9)… >>> More
Function that prints something to std::ostream and returns std::ostream?

as seen on Stack Overflow - Search for 'Stack Overflow'
I want to write a function that outputs something to a ostream that's passed in, and return the stream, like this: std::ostream& MyPrint(int val, std::ostream* out) { *out << val; return *out; } int main(int argc, char** argv){ std::cout << "Value: " << MyPrint(12,… >>> More
Error C2451: Illegal conditional expression of type 'UnaryOp<E1, Op>' in ostream - visual studio 9

as seen on Stack Overflow - Search for 'Stack Overflow'
I am getting a repeated error with VS 9. The code compiles under GNU C++, but I want debug with the VS IDE. Any idea what could be causing this error. Error 13 error C2451: conditional expression of type 'UnaryOp' is illegal \Microsoft Visual Studio 9.0\VC\include\ostream 512 //unary constraint template… >>> More
Templated << friend not working when in interrelationship with other templated union types

as seen on Stack Overflow - Search for 'Stack Overflow'
While working on my basic vector library, I've been trying to use a nice syntax for swizzle-based printing. The problem occurs when attempting to print a swizzle of a different dimension than the vector in question. In GCC 4.0, I originally had the friend << overloaded functions (with a body… >>> More
Why does operator<< not work with something returned by operator-?

as seen on Stack Overflow - Search for 'Stack Overflow'
Here's a small test program I wrote: #include <iostream> using namespace std; class A { public: int val; A(int _val=0):val(_val) { } A operator+(A &a) { return A(val + a.val); } A operator-(A &a) { return A(val - a.val); } friend ostream& operator<<(ostream… >>> More