Arithmetic operators and function calling in C

Posted by Robert Dalton on Stack Overflow See other posts from Stack Overflow or by Robert Dalton
Published on 2010-05-26T01:05:07Z Indexed on 2010/05/26 1:11 UTC
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I'm not quite sure why I can't do

double a = (float) my_Function(45) / 2048 / 2340 / 90;
printf("%.4",a); // prints out 0.00

But instead I have to use one more variable as:

double a = (float) my_Function(45);
double b = (float) a  / 2048 / 2340 / 90;
printf("%.4",b);  // prints out the correct value

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