This an extract from an c program that should demonstrate a bufferoverflow.

void foo()
{
  char arr[8];
  printf(" enter bla bla bla");
  gets(arr);
  printf(" you entered %s\n", arr);
}

The question was "How many input chars can a user maximal enter without a creating a buffer overflow"

My initial answer was 8, because the char-array is 8 bytes long. Although I was pretty certain my answer was correct, I tried a higher amount of chars, and found that the limit of chars that I can enter, before I get a segmentation fault is 11. (Im running this on A VirtualBox Ubuntu)

So my question is: Why is it possible to enter 11 chars into that 8 byte array?