Why do all procedures have to be defined before the compiler sees them?
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by incrediman
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Published on 2010-06-04T20:08:47Z
Indexed on
2010/06/08
1:52 UTC
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For example, take a look at this code (from tspl4):
(define proc1
(lambda (x y)
(proc2 y x)))
If I run this as my program in scheme...
#!r6rs
(import (rnrs))
(define proc1
(lambda (x y)
(proc2 y x)))
I get this error:
expand: unbound identifier in module in: proc2
...This code works fine though:
#!r6rs
(import (rnrs))
(define proc2
+)
(define proc1
(lambda (x y)
(proc2 y x)))
(display (proc1 2 3)) ;output: 5
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